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KURT ROSENTRATERIOWA STATE UNIVERSITY

DISTILLERS GRAINS

TECHNOLOGY COUNCIL

ASSOCIATE PROFESSOR

FACILITY DESIGN

MAXIMIZING EFFICIENCY AND THROUGHPUT

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TODAY’S TOPICS

• Facility goals

• Overview of facilities

• Historical perspectives

• Efficiencies in design, construction, & operations

• Recap from 2018

• Receiving

• Loadout

• Conveyors

• Final thoughts

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FACILITY GOALS

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FACILITY GOALS• Existing facilities upgraded/expanded each year• New facilities constructed each year• Continual need to service grain, feed, food, biofuels

industries

• Design data, information & procedures are critical• Substantial focus on farm-scale

• Commercial-scale scientific knowledge needs more• Anecdotal

• Proprietary

• Official standards

• Cost reductions

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FACILITY GOALS

• Overarching goals for grain storage facilities

• Protect grain

• Weather, insects, rodents, birds, mold

• Maintain quality after harvest

• Storage cannot improve upon quality

• But: poor storage can result in reduction in quality (deterioration)

• Repository for local grain supplies

• Storage for processing operations

• Shipping point to end-use destinations via

• Trucks, rail cars, ships

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OVERVIEW OF FACILITIES

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OVERVIEW OF FACILITIES

• Modern facilities have much greater

• Storage capacities

• Equipment capacities

• Yearly throughputs

• Dust control systems

• Safety measures

• Automations & controls

• Efficiencies

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OVERVIEW OF FACILITIES

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OVERVIEW OF FACILITIES

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OVERVIEW OF FACILITIES

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OVERVIEW OF FACILITIES

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OVERVIEW OF FACILITIES

• Regardless of type, arrangement, or size

• Proper selection, sizing, and location are essential to successful grain storage

• All components must work together

• Only as strong as the weakest link

• Only as fast as your slowest operation

• Want an efficient, cost-effective operation

• Commercial facilities

• Typically handle more than 20,000 bu/hr

• Can store from several thousand, up to several million, bushels at one time

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FACILITY OVERVIEW

• Many common components and systems

• Primary components

• Receiving

• Distribution

• Storage

• Reclaim

• Loadout

• All facilities utilize these components

• Many of these can drive design choices

Receiving

Distribution

Storage

Reclaim

Loadout

Incoming Grain

Outgoing Grain

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FACILITY OVERVIEW

• Many common components and systems

• Secondary components

• Cleaning

• Aeration

• Drying

• Dust control

• Sampling

• Instrumentation and controls

• Not all facilities utilize these components to the same degree

• Don’t drive the design choices

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FACILITY OVERVIEW

Receiving

Distribution

Storage

Reclaim

Loadout

Incoming Grain

Outgoing Grain

Large Grains Elevator

Reclaim

Receiving

Loadout

Storage

Distribution

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FACILITY OVERVIEW

Receiving

Loadout

Storage

Reclaim

Distribution

Small Grains Elevator

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FACILITY OVERVIEW

• Many types, arrangements, and sizes are available for commercial operations

• Choices depend on

• Individual client needs and requirements / opinions

• Operational flexibility

• Future expansion

• Creativity and imagination

• Cost

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HISTORICAL PERSPECTIVES

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HISTORICAL PERSPECTIVES

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HISTORICAL PERSPECTIVES

• The Young Mill-Wright and Miller’s Guide

• Oliver Evans, 1795

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EFFICIENCIES IN DESIGN, CONSTRUCTION & OPERATIONS

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RECAP FROM 2018

• Receiving systems

• Distribution systems

• Storage systems

• Reclaim systems

• Loadout systems

Specifically timing

studies & throughput

This year:- More specifics about design

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RECEIVING SYSTEMS• Purpose

• Introduce incoming grain into the storage facility• Transfer grain to distribution system

• Grain typically delivered with wagons or trucks (rail cars)

• Design considerations• Maximize throughput; minimize wait (esp. harvest)

• Hopper volume: up to 1200 bu or more

• Capacity: ~ 20,000 bu/hr• Orifices, gates, spouts, conveyors

• Valley angle: > angle of repose • Limiting factor, not side slopes

• Want to minimize height of hoppers• Minimize costs ….bucket elevator height & boot pit depth

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RECEIVING SYSTEMS

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RECEIVING SYSTEMS

q

b

a

a

b

c

tan b = h/b

cot b = b/h

b = h*cot b

tan a = h/a

cot a = a/h

a = h*cot a

tan q = h/c

cot q = c/h

c = h*cot q

a2 + b2 = c2

(h/tan a)2 + (h/tan b)2 = (h/tan q)2

h

(tan q)2 = (tan a)2 * (tan b)2

(tan a)2 + (tan b)2

q = tan-1 (tan a)2 * (tan b)2

(tan a)2 + (tan b)2

1/2

* Note: h does not matter

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RECEIVING SYSTEMS

• Valley angles:

• http://bulksolidsflow.com.a

u/free_programs/valley_an

gles/valley_angles.html50

40

5040

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RECEIVING SYSTEMS

• Valley angles:

• http://bulksolidsflow.com.a

u/free_programs/valley_an

gles/valley_angles.html50

40

2070

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RECEIVING SYSTEMS

• Capacities:

V = L * w * h V = h/3 * (B1 + B2 + (B1 * B2)1/2)

http://www.mathinary.com/pyramid__frustum_the_volume_of_a_frustum_of_a_pyramid.jsp

L

w

h

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RECEIVING SYSTEMS• 2 most common types = gravity vs. mechanical

• Tradeoffs

• Gravity hopper only

• Deeper pit, or

• Higher receiving floor (ramp/earth work), and

• Taller bucket elevator

• Hopper + conveyor

• Shallower pit

• Potential carryover/cleanout issues

• Maintenance

• Potential grain damage

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RECEIVING SYSTEMSGravity Mechanical

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RECEIVING SYSTEMS

Mechanical: Above ground vs. underground

Gravity

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RECEIVING SYSTEMS

Tower:

12” x 0.23” x 6.5” = $50/ft

4 columns x 1ft x $50/ft = $200 / 1 ft height

Boot Pit:

10 ft x 10 ft x 1 ft thick

= 44 ft3 / 1 ft depth

Concrete = $3.7 / ft3

$163 / 1 ft depth

10 ft x 10 ft x 0.5 ft thick

= 21 ft3 / 1 ft depth

Concrete = $3.7 / ft3

$78 / 1 ft depth

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LOADOUT SYSTEMS• Purpose

• Transfer grain to shipping containers

• Typically rail cars (sometimes trucks)

• Design considerations

• Equipment sized for speed and labor efficiency

• Typically ≥ reclaim rate (≥ 50,000 bu/hr)

• 110-car unit trains in < 15 hr

• Typical equipment used

• Overhead surge bins within support structures vs. mechanical fill

• Can be system bottleneck

• Bulk weigh scales

• Spouting

• 3 common options

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LOADOUT SYSTEMS• 3 common types

Mechanical Overhead surge Mechanical

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LOADOUT SYSTEMS

Gravity Mechanical

Mechanical

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LOADOUT SYSTEMS

• Example: 80,000 bph

• Upper garner = 1400 ft3 (143%)

• 1125 bu

• Scale hopper = 980 ft3

• 788 bu

• Lower garner = 1200 ft3 (122%)

• 964 bu

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LOADOUT SYSTEMS

• Mechanical loadout

• 60,000 bph

• Use shipping bin as upper garner

• 14,000 bu / 60,000 bph = 14 min

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LOADOUT SYSTEMS• Use upper annex bin as upper garner

• 172,000 bu / 60,000 bph = 2.9 hr

• Still have to mechanically lift

• 60,000 bph x 12.5 hr = 726,000 bu

• Bucket elevator size = ?

• 20,000 bph x 12.5 hr = 250,000 bu

• 40,000 bph x 12.5 hr = 500,000 bu

• 50,000 bph x 12.5 hr = 625,000 bu

• 55,000 bph x 12.5 hr = 687,000 bu

• 60,000 bph x 12.5 hr = 750,000 bu

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LOADOUT SYSTEMS

• Use upper annex bin as upper garner

• 320,000 bu / 60,000 bph = 5.3 hr

• Still have to mechanically lift

• 9.7 hr x 60,000 bph = 580,000 bu

• Bucket elevator size = ?

• 40,000 bph x 9.7 hr = 388,000 bu

• 50,000 bph x 9.7 hr = 485,000 bu

• 60,000 bph x 9.7 hr = 582,000 bu

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CONVEYORS

• Bucket elevators

• Drag conveyors

• Belt conveyors

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Bucket Elevator Calculations

• For engineers, 2 key calculations include:

• Capacity – determines how much grain you can move/transport

• Power required – determines how big a motor you need

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Bucket Elevator Calculations• Capacity

• Q is the volumetric capacity of the bucket elevator (bu/h),

• Cc is the capacity of each cup (in3/cup),

• Cf is the fill of each cup (%, expressed as a decimal),

• Cs is the linear spacing of cups per unit length of belt (number of cups/ft),

• Cr is the number of cup rows across the width of the belt,

• V is the linear belt speed (ft/min),

• C1 is a conversion factor of 60 (min/h),

• C2 is a conversion factor of 2150.42 (in3/bu)

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2

1rsfc

C

CVCCCCQ

=

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Bucket Elevator Calculations• Power

• P is the power required to drive the elevator shaft (hp),

• Q is the volumetric capacity of the elevator (bu/h),

• Tw is the grain test weight (lb/bu),

• H is the total vertical distance between the head and tail shafts of the elevator (ft),

• Sf is an empirical service factor of 1.1(-),

• C1 is a conversion factor of 33,000 (ft.lb/min/hp),

• C2 is a conversion factor of 60 (min/h),

• R1 is the efficiency of the motor speed reducer (which typically ranges from 0.75 to 0.95)

• An additional 10% is added to empirically account for friction losses within the elevator

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121

fw

RCC

SHTQP

=Potential energy

(mgh / time)

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Bucket Elevator Calculations• Power

• P is the power required to drive the elevator shaft (hp),

• Q is the volumetric capacity of the elevator (ft3/h),

• BD is the bulk density of the grain (lb/ft3),

• H is the total vertical distance between the head and tail shafts of the elevator (ft),

• C1 is a conversion factor of 33,000 (ft.lb/min/hp),

• C2 is a conversion factor of 60 (min/h),

• R1 is the efficiency of the motor speed reducer (which typically ranges from 0.75 to 0.95)

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121 R

1

2490

Q

CC

HBDQ1.1P

+

=

Potential energy Friction

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Bucket Elevator Calculations

• Power

• P is the power required to drive the elevator shaft (hp),

• Q is the volumetric capacity of the elevator (bu/h),

• H is the total vertical distance between the head and tail shafts of the

elevator (ft),

• Da is an additional distance of 5 ft, which empirically accounts for frictional

losses within the elevator

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( ) 000036.0DHQP a += (simplified)

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Drag Conveyor Calculations

• Capacity:

• Q is the volumetric throughput (bu/min) of the conveyor,

• V is the linear chain speed (ft/min),

• h is the height of the grain mass at a given cross section inside the

conveyor (ft),

• is a function of the height of the flighting/paddles used,

• w is the width of the conveyor (ft),

• C1 is a conversion factor of 0.8036 (bu/ft3)

1CwhVQ =

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Drag Conveyor Calculations• Power required: [book’s approach] – theoretical

• P is the power required to drive the conveyor (hp),

• L is the conveyor length, from head shaft to tail shaft (ft),

• Wc is the weight of the chain and flighting per unit length of conveyor (lb/ft),

• Fc is the coefficient of kinetic friction between the chain and flights and the conveyor floor (-),

• q is the slope of the conveyor relative to a horizontal plane (o),

• Wm is the weight of the grain per unit length of conveyor (lb/ft),

• Fm is the coefficient of kinetic friction between the grain and the conveyor floor (-),

• h is the average depth of the grain in the conveyor (ft),

• V is the linear chain speed (ft/min),

• C1 is a conversion factor of 33,000 (ft.lb/min/hp),

• R1 is the efficiency of the motor speed reducer (which typically ranges from 0.85 to 0.95)

( ) ( ) ( )( ) V

RC

h044.0sincosFWsincosFWsincosFWL1.1P

11

2

ccmmcc

+q−q+q+q+q+q=

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Drag Conveyor Calculations• Power required: [industry approach]

• (for horizontal use with soybeans, this equation has been empirically adapted to a simpler form)

• P is the power required to drive the conveyor (hp),

• Q is the volumetric capacity of the conveyor (bu/h),

• L is the length of the conveyor (ft)

• R1 is the efficiency of the motor speed reducer (which typically ranges from 0.85 to 0.95)

1*56000 R

LQP

=

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Drag Conveyor Calculations• Power required: [industry approach]

• (for horizontal use with corn or small grains, this equation has been empirically adapted to a simpler form)

• P is the power required to drive the conveyor (hp),

• Q is the volumetric capacity of the conveyor (bu/h),

• L is the length of the conveyor (ft)

• R1 is the efficiency of the motor speed reducer (which typically ranges from 0.85 to 0.95)

1*75000 R

LQP

=

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Drag Conveyor Calculations• Power required: [industry approach]

• If the conveyor is at an incline, then previous empirical equations must be modified to account for the change in potential energy in the system.

• This is accomplished by increasing them by adding an additional power requirement

• Pa is the additional power required due to the conveyor’s incline (hp),

• Q is the volumetric capacity of the conveyor (bu/h),

• H is the change in elevation from the conveyor’s tail shaft to head shaft (ft)

30000

HQPa

=

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Belt Conveyor Calculations

• Capacity (bu/h or bu/min):

• How would you calculate this?

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Angle of Surcharge

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Belt Conveyor Calculations

• Capacity:

• Q is the volumetric throughput (bu/min) of the conveyor,

• V is the linear belt speed (ft/min),

• A is the cross-sectional area of grain on the belt (which will assume the shape of a combination of trapezoidal area with a circular segment area on top [ft2]),

• Circular area depends on surcharge/slump (grain & moisture)

• C1 is a conversion factor of 0.8036 (bu/ft3)

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1CAVQ =

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Belt Conveyors

CEMA

https://www.cemanet.org

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Belt Conveyor Calculations• Power required:

• P is the power required to drive the conveyor head shaft (hp), THIS IS THE MOTOR SIZE

• L is the conveyor length, defined from head pulley shaft to tail pulley shaft (ft),

• Kt is the temperature correction factor, which is related to belt thermal expansion and flexibility (-),

• Kx is the frictional resistance factor that accounts for the interaction between the belt and the idlers (lb/ft),

• Ky is the factor that accounts for the resistance of the grain load to flexure as it passes over the idlers (-),

• Wm is weight of the grain per unit length of belt (lb/ft),

• Wb is the weight of the belt per unit length (lb/ft),

• H is the change in vertical height from the tail shaft to the head shaft (ft),

• Tp is the tension force resulting from the belt’s resistance to bending around the head and tail pulleys (lb),

• Tam is the tension force resulting from the force necessary to accelerate grain as it is fed onto the belt (lb),

• Tac is the tension force resulting from conveyor accessories such as plows, trippers, and belt cleaning devices (lb),

• V is the linear belt speed (ft/min),

• C1 is a conversion factor of 33,000 (ft.lb/min/hp),

• R1 is the efficiency of the motor speed reducer (which typically ranges from 0.75 to 0.95)

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( ) ( ) V

RC

TTTHKLWW015.0WKKKLP

11

acampymbbyxt

++++++=

Te = effective tension, lb

P = (Te x V) / (C1 x R1)

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Belt Conveyor Calculations

• Power required:

• P is the power required to drive the conveyor (hp), MOTOR SIZE

• L is the conveyor length, defined from head pulley shaft to tail pulley shaft (ft),

• Wm is weight of the grain per unit length of belt (lb/ft),

• Wb is the weight of the belt per unit length (lb/ft),

• H is the change in vertical height from the tail shaft to the head shaft (ft),

• V is the linear belt speed (ft/min),

• C1 is a conversion factor of 33,000 (ft.lb/min/hp),

• R1 is the efficiency of the motor speed reducer (which typically ranges from 0.75 to 0.95)

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( ) ( ) V

RC

225HL035.0W58.0W05.0W00068.0LP

11

mbm

++++=

(simplified)

Te = effective tension, lb

P = (Te x V) / (C1 x R1)

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FINAL THOUGHTS

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FINAL THOUGHTS

• Make sure everyone reads the blueprints CORRECTLY

• Contractors

• Subcontractors

• Equipment vendors

• Field staff

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FINAL THOUGHTS

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FINAL THOUGHTS

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FINAL THOUGHTS

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FACILITY DESIGN

• Dynamic process

• 5 main stages

Flow Diagram

Bin Layout/Arrangement Bin Sizes/Capacities

Facility Layout

Process Design

Primary Systems

Secondary Systems

Client Req. Building Codes Standards

Structural Design

Final Design

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FINAL THOUGHTS

• Brief overview of design & operation considerations

• Each commercial facility is unique

• Many styles, layouts, and options

• Many common features and equipment

• Ultimately, design and operation based on client’s preferences

• Detailed knowledge of design processes is extremely important

• Hopefully these thoughts will be useful

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THANK YOU!

Questions?