© University of South Carolina Board of Trustees Chapt. 16 More Acids and Bases Sec. 2 Titration:...

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Chapt. 16More Acids and Bases

Sec. 2Titration:

Strong Acid + Strong Base

Calculate the pH in the titration of 100.0 mL of 0.200 M HCl with 0.400 M NaOH after

a) 0.00 mLb) 25.00 mLc) 50.00 mLd) 75.00 mL

of base are added.

Calculating a Titration Curve:Strong Acid + Strong Base

Titration of aStrong Acid with Strong Base

a) 0.00 mLb) 25.00 mLc) 50.00 mLd) 75.00 mL

of base are added.

a) 0.00 mL strong acid problem

b) 25.00 mLc) 50.00 mLd) 75.00 mL

of base are added.

a) 0.00 mL strong acid problem pH = 0.7b) 25.00 mLc) 50.00 mLd) 75.00 mL

of base are added.

a) 0.00 mL strong acid problem pH = 0.7b) 25.00 mLc) 50.00 mLd) 75.00 mL

of base are added.

a) 0.00 mL strong acid problem pH = 0.7b) 25.00 mL strong acid problem

c) 50.00 mLd) 75.00 mL

of base are added.

a) 0.00 mL strong acid problem pH = 0.7b) 25.00 mL strong acid problem pH = 1.1c) 50.00 mLd) 75.00 mL

of base are added.

a) 0.00 mL strong acid problem pH = 0.7b) 25.00 mL strong acid problem pH = 1.1c) 50.00 mLd) 75.00 mL

of base are added.

a) 0.00 mL strong acid problem pH = 0.7b) 25.00 mL strong acid problem pH = 1.1c) 50.00 mL water + spectators

d) 75.00 mL

of base are added.

a) 0.00 mL strong acid problem pH = 0.7b) 25.00 mL strong acid problem pH = 1.1c) 50.00 mL water + spectators pH = 7.0d) 75.00 mL

of base are added.

pH = 7.0

a) 0.00 mL strong acid problem pH = 0.7b) 25.00 mL strong acid problem pH = 1.1c) 50.00 mL water + spectators pH = 7.0d) 75.00 mL

of base are added.

a) 0.00 mL strong acid problem pH = 0.7b) 25.00 mL strong acid problem pH = 1.1c) 50.00 mL water + spectators pH = 7.0d) 75.00 mL strong base problem

of base are added.

a) 0.00 mL strong acid problem pH = 0.7b) 25.00 mL strong acid problem pH = 1.1c) 50.00 mL water + spectators pH = 7.0d) 75.00 mL strong base problem pH =12.8

of base are added.

excess acid strong acid only

excess base strong base only

Titration of a Strong Base with Strong Acid

excess acid strong acid only

excess base strong base only

equivalence point

Student Example

Calculate the pH in the titration of 20.0 mL of 0.150 M NaOH with 0.200 M HCl after 25.00 mL of acid are added.

Chapt. 16More Acids and Bases

Sec. 4-5Titration:

Weak Acid + Strong Base ( or weak base + strong acid)

Titration of aWeak Acid with Strong Base

Calculate the pH in the titration of 25.00 mL of 0.200 M acetic acid (Ka = 1.8 x10-5) with 0.500 M NaOH after

a) 0.00 mL b) 5.00 mL c) 10.00 mL d) 15.00 mL

of base are added.

Calculating a Titration Curve:Weak Acid + Strong Base

a) 0.00 mL b) 5.00 mL c) 10.00 mL d) 15.00 mL

of base are added.

a) 0.00 mL weak acid problem

b) 5.00 mL c) 10.00 mL d) 15.00 mL

of base are added.

a) 0.00 mL weak acid problem pH = 2.72

b) 5.00 mL c) 10.00 mL d) 15.00 mL

of base are added.

Weak Acid Titration Curve

© University of South Carolina Board of Trustees Chapt. 16 More Acids and Bases Sec. 2 Titration:...

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