Post on 21-Dec-2015
transcript
1
Announcements
• Review session next Friday 03/11• Homework 5 due on Friday 03/04• Project 3 due Wednesday 03/16
The Network Layer
3
Purpose of Network layer
• Given a packet, send it across the network to destination• 2 key issues:
– Portability: • connect different technologies
– Scalability• To the Internet scale
networkdata linkphysical
networkdata linkphysical
networkdata linkphysical
networkdata linkphysical
networkdata linkphysical
networkdata linkphysical
networkdata linkphysical
networkdata linkphysical
application
transportnetworkdata linkphysical
application
transportnetworkdata linkphysical
4
What does it involve?
Two important functions:• routing: determine path from source to dest. • forwarding: move packets from router’s input to output
T1T3
Sts-1
T3
T1
5
Network service model
Q: What service model for “channel” transporting packets from sender to receiver?
• guaranteed bandwidth?• preservation of inter-packet
timing (no jitter)?• loss-free delivery?• in-order delivery?• congestion feedback to
sender?
? ??virtual circuit
or datagram?
The most important abstraction provided
by network layer:
serv
ice a
bst
ract
ion
Which things can be “faked” at the transport layer?
6
Two connection models• Connectionless (or “datagram”):
– each packet contains enough information that routers can decide how to get it to its final destination
• Connection-oriented (or “virtual circuit”)– first set up a connection between two nodes– label it (called a virtual circuit identifier (VCI))– all packets carry label
BAb b
C
BA1 1
C
1
7
Virtual circuits: signaling protocols
• used to setup, maintain teardown VC• setup gives opportunity to reserve resources• used in ATM, frame-relay, X.25• not used in today’s Internet
application
transportnetworkdata linkphysical
application
transportnetworkdata linkphysical
1. Initiate call 2. incoming call
3. Accept call4. Call connected5. Data flow begins 6. Receive data
8
Virtual circuit switching• Forming a circuit:
– send a connection request from A to B. Contains VCI + address of B– rule: VCI must be unique on the link its used on– switch creates an entry mapping input messages with VCI to output
port– switch picks a new VCI unique between it and next switch
a b
25
21
c12
1
9
(Input link,VCI) (output link, new VCI)(1, 2) (?, ?)(1, 5) (?, ?)
Virtual circuit forwarding• For each VCI switch has a table which maps input link to
output link and gives the new VCI to use– if a’s messages come into switch 1 on link 2 and go out on link 3 then
the table will be:
a b
25
21
c12
1
Switch 1
Switch 2
Switch 3
10
Virtual Circuits: Discussion
• Plusses: easy to associate resources with VC– Easy to provide QoS guarantees (bandwidth, delay)– Very little state in packet
• Minuses:– Not good in case of crashes
• Requires explicit connect and teardown phases
– What if teardown does not get to all routers?– What if one switch crashes?
• Will have to teardown and rebuild route
11
Datagram networks• no call setup at network layer• routers: no state about end-to-end connections
– no network-level concept of “connection”
• packets typically routed using destination host ID– packets between same source-dest pair may take different paths
• Best effort: data corruption, packet drops, route loops
application
transportnetworkdata linkphysical
application
transportnetworkdata linkphysical
1. Send data 2. Receive data
12
Datagrams: Forwarding
How does packet get to the destination?• switch creates a “forwarding table”, mapping destinations to output
port (ignores input ports)• when a packet with a destination address in the table arrives, it
pushes it out on the appropriate output port• when a packet with a destination address not in the table arrives, it
must find out more routing information (next problem)
a b
c1d
22
00S1
S2
S3
1
01
13
Datagrams
• Plusses:– No round trip connection setup time– No explicit route teardown– No resource reservation each flow could get max bandwidth– Easily handles switch failures; routes around it
• Minuses– Difficult to provide resource guarantees– Higher per packet overhead
• Internet uses datagrams: IP (Internet Protocol)
14
Datagrams Forwarding
• How to build forwarding tables?– Manually enter it
• What if nodes crashed
• What about scale?
• The graph-theoretic routing problem– Given a graph, with vertices (switches), edges (links), and edge
costs (cost of sending on that link)– Find the least cost path between any two nodes
• Path cost = (cost of edges in path)
15
Simple Routing Algorithm
• Choose a central node– All nodes send their (nbr, cost) information to this node– Central node uses info to learn entire topology of the network– It then computes shortest paths between all pairs of nodes
• Using All Pair Shortest Path Algorithm
– Sends the new matrix to every node
• Nice, simple, elegant!• What is the problem?
– Scalability: centralization hurts scalability– Central node is “crushed” with traffic
16
Link State Routing
• Basic idea:– Every node propagates its (nbr, cost) information– This information at all nodes is enough to construct topology– Can use a graph algorithm to find the shortest routes
• Mechanisms required:– Reliable flooding of link information– Method to calculate shortest route (Dijkstra’s algorithm)
• Example link state update packet:– [node id, (nbr, cost) list, seq. no., ttl]
• Seq. no. to identify latest updates, ttl specifies when to stop msg.
17
Reliable flooding
receive(pkt) If already have a copy of LSP from pkt.ID
if pkt’s sequence number <= copy’sdiscard pkt
elsedecrement pkt.TTLreplace copy with pktforward pkt to all links besides the one that we received it on
# done every 10 minutes or sogen_LSP()
increment node’s sequence # by onerecompute cost vectorsend created LSP to all neighbors
18
Discussion: Link-State Routing
• Plusses: – Simple, determines the optimal route most of the time– Used by OSPF
• Minuses:– Might have oscillations
– Avoid using load as cost metric, reduce herding effect
A
D
C
B1 1+e
e0
e
1 1
0 0
A
D
C
B2+e 0
001+e1
A
D
C
B0 2+e
1+e10 0
A
D
C
B2+e 0
e01+e1
Initially start withalmost equal routes
… everyone goes with least loaded
… recomputeLeast loaded =>
Most loaded
… recompute
19
Is our routing algo scalable?
• Route table size grows with size of network– Because our address structure is flat!
• Solution: have a hierarchical structure– Used by OSPF– Divide the network into areas, each area has unique number
• Nodes carry their area number in the address 1.A, 2.B, etc.
– Nodes know complete topology in their area– Area border routers (ABR) know how to get to any other area
20
Hierarchical Addressing
1.a3.b
2.b11.b2
2
00S1
S2
S3
1
01
2.a
3
3.a
2
Zone 3
Zone 2
Forwarding table for switch 1Destination switch port
2. ?3. ? 1.b ? 1.a ?
21
IP has 2-layer addressing
• Each IP address is 32 bits– Network part: which network the host is on?– Host part: identifies the host.
• All hosts on same network have the same network part
• 3 classes of addresses: A, B and C
18.26.0.1
network 32-bits host
0 net host
1 7 24 bits
1 0 net host
2 14 16 bits
110 net host
3 21 8 bits
22
IP addressing
• The different classes:
• Problems: inefficient, address space exhaustion
0network host
10 network host
110 network host
1110 multicast address
A
B
C
D
class1.0.0.0 to127.255.255.255
128.0.0.0 to191.255.255.255
192.0.0.0 to223.255.255.255
224.0.0.0 to239.255.255.255
32 bits
Unicast
Multicast
1111 reservedE 240.0.0.0 to255.255.255.255Reserved
23
IP addressing: CIDR
• Classless InterDomain Routing– network portion of address of arbitrary length– address format: a.b.c.d/x, where x is # bits in network portion
– Examples:• Class A: /8• Class B: /16• Class C: /24
11001000 00010111 00010000 00000000
networkpart
hostpart
200.23.16.0/23
24
Internet Protocol Datagram
ver length
32 bits
data (variable length,typically a TCP
or UDP segment)
16-bit identifier
Internet checksum
time tolive
32 bit source IP address
IP protocol versionNumber
header length
max numberremaining hops
(decremented at each router)
forfragmentation/reassembly
total datagramlength (bytes)
upper layer protocolto deliver payload to
head.len
type ofservice
“type” of data flgsfragment
offsetupper layer
32 bit destination IP address
Options (if any) E.g. timestamp,record routetaken, pecifylist of routers to visit.
25
Datagram Portability
• IP Goal: To create one logical network from multiple physical networks– All intermediate routers should understand IP– IP header information sufficient to carry the packet to destination– Goal: Run over anything!
• Problem:– Physical networks have different MTUs– “max. transmission unit”: 1500 for Ethernet, 48 for ATM
• Solution 1:– Fit everything in the MTU (!)
26
IP Fragmentation & Reassembly
• Solution 2: (the one used)– If packet size > MTU of network, then fragment into pieces
• Each fragment is less than MTU size
• Each has IP headers + frag bit set + frag id + offset
– Packets may get refragmented on the way to destination– Reassembly only done at the destination– What is a good initial packet size?
fragmentation: in: one large datagramout: 3 smaller datagrams
reassembly