1 Calorimetry. Calorimetry - the accurate and precise measurement of heat change for chemical and...

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Calorimetry

Calorimetry

• Calorimetry - the accurate and precise measurement of heat change for chemical and physical processes.

• The device used to measure the absorption or release of heat in chemical or physical processes is called a Calorimeter

Calorimetry

• Foam cups are excellent heat insulators, and are commonly used as simple calorimeters

A Cheap Calorimeter

• For systems at constant pressure, the heat content is the same as a property called Enthalpy (H) of the system

Calorimetry

• Changes in enthalpy = H• q = H These terms will be used

interchangeably in this textbook• Thus, q = H = m x C x TH is negative for an exothermic

reactionH is positive for an endothermic

reaction

Calorimetry

• Calorimetry experiments can be performed at a constant volume using a device called a “bomb calorimeter” - a closed system

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In terms of bonds

COO C

O

O

Breaking this bond will require energy.

CO

OOO C

Making these bonds gives you energy.In this case making the bonds gives you more energy than breaking them.

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Exothermic

• The products are lower in energy than the reactants

• Releases energy

2Al (s) + 3Cl2 (g) --> 2 AlCl3 (s) + 1408 kJ

∆H=1408 kJ

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C + O2 CO2E

nerg

y

Reactants Products

C + O2

C O2

395kJ

+ 395 kJ

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Endothermic

• The products are higher in energy than the reactants

• Absorbs energy

2 H2O + 575 kJ ------> 2 H2 + 1 O2 (g)

∆H = + 572 kJ

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CaCO3 CaO + CO2E

nerg

y

Reactants Products

CaCO3

CaO + CO2

176 kJ

CaCO3 + 176 kJ CaO + CO2

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Chemistry Happens in

MOLES• An equation that includes energy is called

a thermochemical equation

• CH4 + 2O2 CO2 + 2H2O + 802.2 kJ

• 1 mole of CH4 releases 802.2 kJ of energy.

• When you make 802.2 kJ you also make 2 moles of water

• What is the molar enthalpy of CO2 (g) in the reaction for the burning of butane below?

2 C4H10 +13 O2 8 CO2 +10 H2O

∆H=-5315 kJ

Answer: Molar enthalpy is the enthalpy change in equation divided by the balance of CO2

• Molar enthalpy, ∆H substance = 5315 kJ ÷ 8 mol

• = 664 kJ / mol.

• For each of the following rewrite the equation in " H " notation, for one mole of the underlined substance.

Fe2O3 (s)+3CO(g)→3CO2(g)+2Fe(s)+25kJ

• Answer:1/3 Fe2O3 (s)+CO(g)CO2(g)+2/3 Fe(s) ∆H = - 8.3 KJ 

4 NH3(g)+5O2 (g)→4 NO(g)+6H2O(l)+1170kJ  

2 HCl (g)+96 KJ → H2 (g)+Cl2 (g)

N2 (g)+3 H2 (g) → 2 NH3 (g)+92 KJ

2 CO2 (g)+566 KJ →2 CO (g)+ O2 (g)

4 Al (s) +3 O2 (g) →2 Al2O3 (s)+3360 KJ

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Thermochemical Equations

• A heat of reaction is the heat change for the equation, exactly as written– The physical state of reactants and

products must also be given.

– Standard conditions for the reaction is 101.3 kPa (1 atm.) and 25 oC

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CH4 + 2 O2 CO2 + 2 H2O + 802.2 kJ

• If 10. 3 grams of CH4 are burned completely, how much heat will be produced?

10. 3 g CH4

16.05 g CH4

1 mol CH4

1 mol CH4

802.2 kJ

= 514 kJ

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CH4 + 2 O2 CO2 + 2 H2O + 802.2 kJ

• How many liters of O2 at STP would be required to produce 23 kJ of heat?

• How many grams of water would be produced with 506 kJ of heat?

• How much heat will be released if 65 grams of butane is burned in a lighter according the equation:

2 C4H10 +13 O2 8 CO2 +10 H2O

∆H=-5315 kJ

= 2976.4 kJ

= 3.0 MJ

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104104 2

5315

14.58

165

HmolC

kJ

g

HmolCHgC

• Calculate the heat released when 120 grams of Iron (III) oxide is formed by the following equation 

2 Fe2O3 (s) → 4 Fe(s)+3 O2 (g)

∆H=1625 kJ

mol

kJ

g

OmolFeOgFe

2

1625

70.159

1120 32

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= 610.5 kJ= 610 kJ

• Q = n ∆H (substance)

Where n = # of moles

• What mass of carbon dioxide must form to create 1200 kJ of heat when the following reaction occurs?

C6H12O6(s)+6O2(g)→6CO2(g)+6H2O(l) 

∆H=- 2808kJ

Answer: 110 grams

• 3) What mass of oxygen is needed to completely react and release 550 kJ of heat in the following reaction?

• 4Fe (s)+3O2 (g) → 2 Fe2O3 (s)

∆H=- 1625 kJ

Answer: 32 grams

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Summary, so far...

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Enthalpy• The heat content a substance has at a

given temperature and pressure• Can’t be measured directly because

there is no set starting point• The reactants start with a heat content• The products end up with a heat content• So we can measure how much enthalpy

changes

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Enthalpy• Symbol is H• Change in enthalpy is H (delta H)• If heat is released, the heat content of

the products is lowerH is negative (exothermic)

• If heat is absorbed, the heat content of the products is higherH is positive (endothermic)

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Ene

rgy

Reactants Products

Change is down

H is <0

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Ene

rgy

Reactants Products

Change is upH is > 0

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Heat of Reaction• The heat that is released or absorbed in a

chemical reaction• Equivalent to H

• C + O2(g) CO2(g) + 393.5 kJ

• C + O2(g) CO2(g) H = -393.5 kJ

• In thermochemical equation, it is important to indicate the physical state

• H2(g) + 1/2O2 (g) H2O(g) H = -241.8 kJ

• H2(g) + 1/2O2 (g) H2O(l) H = -285.8 kJ

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Heat of Combustion• The heat from the reaction that

completely burns 1 mole of a substance

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• OBJECTIVES:– Classify, by type, the heat changes

that occur during melting, freezing, boiling, and condensing.

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• OBJECTIVES:– Calculate heat changes that occur

during melting, freezing, boiling, and condensing.

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Heats of Fusion and Solidification

• Molar Heat of Fusion (Hfus) - the heat absorbed by one mole of a substance in melting from a solid to a liquid

• Molar Heat of Solidification (Hsolid) - heat lost when one mole of liquid solidifies

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Heats of Fusion and Solidification

• Heat absorbed by a melting solid is equal to heat lost when a liquid solidifies– Thus, Hfus = -Hsolid

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Heats of Vaporization and Condensation

• When liquids absorb heat at their boiling points, they become vapors.

• Molar Heat of Vaporization (Hvap) - the amount of heat necessary to vaporize one mole of a given liquid.

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Heats of Vaporization and Condensation

• Condensation is the opposite of vaporization.

• Molar Heat of Condensation (Hcond) - amount of heat released when one mole of vapor condenses

• Hvap = - Hcond

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Heats of Vaporization and Condensation

The large values for Hvap and Hcond are the reason hot vapors such as steam is very dangerous– You can receive a scalding burn from

steam when the heat of condensation is released!

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Heats of Vaporization and Condensation

• H20(g) H20(l) Hcond = - 40.7kJ/mol

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Heat of Solution

• Heat changes can also occur when a solute dissolves in a solvent.

• Molar Heat of Solution (Hsoln) - heat change caused by dissolution of one mole of substance

• Sodium hydroxide provides a good example of an exothermic molar heat of solution:

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Heat of Solution

NaOH(s) Na1+(aq) + OH1-

(aq)

Hsoln = - 445.1 kJ/mol

• The heat is released as the ions separate and interact with water, releasing 445.1 kJ of heat as Hsoln thus becoming so hot it steams

H2O(l)