2/9/2016 IB Math SL1 - Santowski 1 T6.1 – Grouped & Cumulative data IB Math SL1 - Santowski.

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2/9/2016 IB Math SL1 - Santowski 3 Example to start with (a) Determine the mean, median, mode, IQR, range, quartiles, IQR from the data list 8.74 m10.39 m8.79 m m10.86 m9.39 m m10.94 m9.94 m m9.00 m10.97 m m9.15 m9.72 m m9.35 m8.49 m m9.35 m9.63 m m8.45 m9.83 m m8.85 m9.49 m m8.95 m8.82 m m9.10 m9.24 m m10.20 m9.13 m8.47 mean = median =9.35 mode =9.35 Q1 = Q2 =9.35 Q3 = Q4 =10.97 Range = IQR =

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05/03/23 IB Math SL1 - Santowski 1

T6.1 – Grouped & Cumulative data

IB Math SL1 - Santowski

05/03/23 IB Math SL1 - Santowski 2

Example to start with Given the following data set for

all of my shot put athletes:

(a) Determine the mean, median, mode, IQR, range, quartiles, IQR from the data list

(b) organize into intervals of 0.25 m

(c) Determine the frequency in each interval

(d) prepare a histograph (e) Prepare a cumulative

frequency distribution (f) use the CFD to determine

the median. Compare to Q(a)

8.74 m 10.39 m 8.79 m 9.35

8.94 m 10.86 m 9.39 m 8.53

9.66 m 10.94 m 9.94 m 9.96

10.01 m 9.00 m 10.97 m 10.05

10.01 m 9.15 m 9.72 m 9.30

8.43 m 9.35 m 8.49 m 10.20

10.25 m 9.35 m 9.63 m 9.59

10.14 m 8.45 m 9.83 m 8.56

9.04 m 8.85 m 9.49 m 8.98

9.30 m 8.95 m 8.82 m 9.52

8.69 m 9.10 m 9.24 m 10.93

8.85 m 10.20 m 9.13 m 8.47

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Example to start with (a) Determine the mean,

median, mode, IQR, range, quartiles, IQR from the data list

8.74 m 10.39 m 8.79 m 9.35

8.94 m 10.86 m 9.39 m 8.53

9.66 m 10.94 m 9.94 m 9.96

10.01 m 9.00 m 10.97 m 10.05

10.01 m 9.15 m 9.72 m 9.30

8.43 m 9.35 m 8.49 m 10.20

10.25 m 9.35 m 9.63 m 9.59

10.14 m 8.45 m 9.83 m 8.56

9.04 m 8.85 m 9.49 m 8.98

9.30 m 8.95 m 8.82 m 9.52

8.69 m 9.10 m 9.24 m 10.93

8.85 m 10.20 m 9.13 m 8.47

mean = 9.448542

median = 9.35

mode = 9.35

Q1 = 8.9175

Q2 = 9.35

Q3 = 9.9725

Q4 = 10.97

Range = 8.43 - 10.97

IQR = 8.9175 - 9.9725

Example to start with

(b) organize into intervals of 0.25 m

(c) Determine the frequency in each interval

Grouped Data Frequency

8.25 - 8.49 48.50 - 8.74 48.75 - 8.99 79.00 - 9.24 69.25 - 9.49 79.50 - 9.74 59.75 - 9.99 3

10.00 - 10.24 710.25 - 10.49 110.50 - 10.74 010.75 - 10.99 4

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Example to start with

(d) Histograph

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Example to start with

(e) Cumulative Frequency Distribution

Grouped Data FrequencyCumulativeFrequency

8.25 - 8.49 4 48.50 - 8.74 4 88.75 - 8.99 7 159.00 - 9.24 6 219.25 - 9.49 7 289.50 - 9.74 5 339.75 - 9.99 3 36

10.00 - 10.24 7 4310.25 - 10.49 1 4410.50 - 10.74 0 4410.75 - 10.99 4 48

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Example to start with

(e) Cumulative Frequency Distribution as a graph

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Example to Start with

(1) Determine the mean from the grouped data

(2) Determine the mean from the CFD graph

(3) compare all three means

Why would they be different? Why would they be the same??

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Example to start with

(1) Determine the mean from the grouped data

9.4325 m

Grouped Data FrequencyCumulativeFrequency

8.25 - 8.49 4 8.37 x 48.50 - 8.74 4 8.62 x 4

8.75 - 8.99 7 8.87 x 79.00 - 9.24 6 9.12 x 69.25 - 9.49 7 9.37 x 7

9.50 - 9.74 5 9.62 x 59.75 - 9.99 3 9.87 x 3

10.00 - 10.24 7 10.12 x 710.25 - 10.49 1 10.37 x 110.50 - 10.74 0 0

10.75 - 10.99 4 10.87 x 4452.76/48 = 9.4325

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Example to start with

Determine the mean from the CFD graph

A bit harder ….

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Class work

S18B.3, Q3

S18C, Q3

S18D.2, Q8

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Homework

HW

Ex 18B.3 #5, 6; Ex 18C #4,6; Ex 18D.2 #7 - 10

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