3 phase load flow 2

Post on 21-Jul-2016

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3 phase load flow 2

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Three phase models of Transformer

• Being a balanced 3 phase device it is represented by its eqvt. sequence network.

• Also modeled in phase coordinate method based on primitive admittance matrix.

• Primitive Admittance model of 3 phase transformer Consider a 2 winding 3 phase transformer

The primitive network and primitive admittance matrix is given by

• Assuming flux path to be symmetrically distributed between windings

• If inter phase coupling neglected, the coupling is modeled as for a single phase unit

• Admittance matrix is

• Admittance model of actual connected network is formed by linear transformation.

Consider a star-star connected transformer with neutral solidly grounded

• The connection matrix is given by

• Nodal admittance matrix is

• Similarly for a star G-delta transformer

• Two winding transformer represented as two compound coils

Sequence component modeling of 3 phase Transformer

• With reference to star G-delta connection, its y node can be partitioned into self and mutual elements and transformation can be applied to obtain the sequence admittance submatrces.

Three phase load flow solution

• For assessing the unbalanced operation of an interconnected system and any significant load unbalance, three phase LF algorithm is necessary.

• Formulation of unbalanced load flow problem requires the formation of nodal admittance matrix of the unbalanced network.

• This is assembled by taking one element at a time and modifying the matrix of partial network to reflect the addition. The process is continued till all elements such as machines, lines, transformers, shunt parameters etc are considered.

• Overall system admittance matrix is formed by combining the subsystem admittance matrix.

>The self admittance of any bus bar is the sum of all the individual self admittance matrices at that bus bar.

>The mutual admittance between any two bus bars is the sum of the individual mutual admittance matrices from all the subsystems containing those two nodes.

• Three phase system behavior is given by the nodal equation,

[I] - [Y] [V]=0Where Y is the nodal admittance matrix or system

admittance matrix containing all sort of unbalances of the system.

• Each bus bar is represented by three nodes, each representing a phase.

• Each neutral is a node if not solidly grounded.• Each load is assumed decoupled in to three parts and

each is connected to a node.

Notations used

• AC system is considered to have a total of ‘n’ bus bars, n=nb + ng nb=no. of actual system bus bars ng=no. of synch machines i, j - system bus bars• i=1, nb all load bus bars+ all generator terminal bus bar• i=nb+1, nb+ng-1 all generator internal bus bar except the

slack machine• i=nb + ng internal bus bar at slack machine

• reg- voltage regulator• Int- internal bus bar at a generator• gen- generator• p, m- three phases at a particular bus

The minimum and sufficient set of variables to define the three-phase system under steady-state operation.

• The slack generator internal bus bar voltage magnitude V int j where j = nb + ng.

(The angle θint j is taken as a reference.)

• The internal busbar voltage magnitude V int j and angles θint j at all other generators,

i.e. j = nb + 1, nb + ng - 1. (Only two variables are associated with each generator internal bus bar as the

three-phase voltages are balanced)

• The three voltage magnitudes (Vip) and angles (θ i

p ) at every generator terminal bus bar and every load bus bar in the system, i.e. i = 1, nb and p = 1,3

The equations necessary to solve for the above set of variables are derived from the specified operating conditions,

• The individual phase real and reactive power loading at every system bus bar.

• The voltage regulator specification for every synchronous machine.

• The total real power generation of each synchronous machine, with the exception of slack machine.

• At slack machine, fixed voltage in phase and magnitude, is applicable to the three-phase load

flow.

The mathematical statement of the specified conditions in terms of Y matrix is as follows

1. For each of the three phases ( p ) at every load and generator terminal bus bar (i),

2. For every generator j,

where k is the bus number of the jth generator’s terminal

bus bar.

3. For every generator j , with the exception of the slack machine, i.e. j ≠ nb + ng,

the mutual terms Gjk and Bjk are nonzero only when k is the terminal bus bar of the jth generator.

• The mathematical formulation of 3 phase LF problem is given by the above three set of independent algebraic eqn in terms of system variables.

• Load Flow solution is the set of variables which makes up on substitution the mismatches in the eqn equal to zero.

• The solution is obtained in an iterative manner using the Fast Decoupled algorithm.

• The problem is defined as

• The effects of Δθ on reactive power flows and ΔV on real power flows are ignored, therefore

[ I ] = [M] = [J] = [ N ] = 0 and [C] = [GI = 0.

• In addition, the voltage regulator specification is assumed to be in terms of the terminal voltage magnitudes only and therefore

[D] = [H] = 0.

• The equation in decoupled form is

for i, k = 1, nb and j, I = 1, ng - 1 (i.e. excluding the slack generator), ‘l ‘ refers to generator internal bus bar

and

for i, k = 1, nb and j , I = 1, ng (i.e. including the slack generator).

Jacobian elements are given as follows Consider for a generator internal bus bar ‘l’

the sub matrix A &B is given by

Similarly E & F is given by

Where [Fjl]=0 for all j≠l because the jth generator has no connection with the lth generators internal bus bar

Sub matrix K,P,L&R is given by

[Lm

jk ]=0, when k is not the terminal bus bar of jth generator

[R jl]=0 for all j, l as the voltage regulator specification does not include the variables V int

Jacobian approximations1. At all nodes (all phases of all bus bars)

2. Between connected nodes of same phase,

3. The phase angle unbalance at any busbar will be small

4. The angle between different phases of connected bus bars will be 120o i.e.

Applying approximation to the jacobians we get the eqns as

where

• All the terms in matrix [M] are constant and is same as –[B] matrix except for the off diagonal terms which connects nodes of different phases.

• The reliability and speed of convergence can be improved with some modification in the defining function.

1. The left-hand side defining functions are redefined as [ΔPp

i / Vpi] , [ΔPgen j /V int j] and [Qp

i / Vpi]

2. In equation (1), the remaining right-hand-side V terms are set to 1 p.u.

3. In equation(2), the remaining right-hand-side V terms are cancelled by the corresponding terms in the right-hand-side vector.

There fore the eqn becomes,

• As Vreg is normally a simple linear function of the terminal voltages, [L’] will be a constant matrix• Therefore, the Jacobian matrices [B’] and [ B’’ ] in

equations have been approximated to constants.

• The final algorithmic eqn may be written as

• The eqns are now solved iteratively using the algorithms

Starting values for the iterations are assigned as

1. The non voltage-controlled bus bars are assigned 1 p.u. on all phases.

2. At generator terminal bus bars all voltages are assigned values according to the voltage regulator specifications.

3. All system bus bar angles are assigned 0, - 1200, + 1200 for the three phases respectively.

4. The generator internal voltages and angles are calculated from the specified real power.

5. For the slack machine the real power is estimated as the difference between total load and total generation plus a small percentage (say 8%) of the total load to allow for losses

• Form the system admittance model from the raw data for each system component.

• Constant Jacobians B' and B" are formed from the system admittance matrix.

• Each equation are then solved using the iterative technique.

• The iterative solution process yields the values of the system voltages which satisfy the specified system conditions of load, generation and system configuration.

• The three-phase bus bar voltages, the line power flows and the total system losses are calculated.