AOSS 401, Fall 2006 Lecture 8 September 24, 2007 Richard B. Rood (Room 2525, SRB) rbrood@umich.edu...

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AOSS 401, Fall 2006Lecture 8

September 24, 2007

Richard B. Rood (Room 2525, SRB)rbrood@umich.edu

734-647-3530Derek Posselt (Room 2517D, SRB)

dposselt@umich.edu734-936-0502

Class News

• Contract with class.– First exam October 10.

• Homework 3 is posted.– Due Friday

• Solution sets for Homework 1 and 2 are posted.

Outline

• Vertical Structure Reset

• Stability and Instability– Wave motion

• Balances

• Thermal Wind

• Maps

Full equations of motion

1 and

)1

(

)()cos(21v

)v()sin(21v)tan(v

)()cos(2)sin(v21)vtan(

222

22

2

RTp

JDt

Dp

Dt

DTc

Dt

D

wΩugz

p

a

u

Dt

Dw

Ωuy

p

a

w

a

u

Dt

D

uΩwΩx

p

a

uw

a

u

Dt

Du

v

u We saw that the first two equations were dominated by the geostrophic balance. What do we do for the vertical motion?

Thermodynamic equation(Use the equation of state)

T

J

Dt

pDR

Dt

TDRc

T

J

Dt

Dp

p

R

Dt

DT

T

Rc

v

v

)(ln)(ln)(

)(

Definition of potential temperature

)/()( RcRsfc v

p

pT

This is the temperature a parcel would have if it was moved from some pressure and temperature to the surface.

This is Poisson’s equation.

This is a very important point.

• Even in adiabatic motion, with no external source of heating, if a parcel moves up or down its temperature changes.

• What if a parcel moves about a surface of constant pressure?

Adiabatic lapse rate.

For an adiabatic, hydrostatic atmosphere the temperature decreases with height.

Rc

g

z

Tz

v

0

Another important point

• If the atmosphere is in adiabatic balance, the temperature still changes with height.

• Adiabatic does not mean isothermal. It means that there is no external heating or cooling.

The parcel method

• We are going displace this parcel – move it up and down.– We are going to assume that the pressure adjusts

instantaneously; that is, the parcel assumes the pressure of altitude to which it is displaced.

– As the parcel is moved its temperature will change according to the adiabatic lapse rate. That is, the motion is without the addition or subtraction of energy. J is zero in the thermodynamic equation.

Parcel cooler than environment

z

Warmer

Cooler

If the parcel moves up and finds itself cooler than the environment then it will sink. (What is its density? larger or smaller?)

Parcel cooler than environment

z

Warmer

Cooler

If the parcel moves up and finds itself cooler than the environment, then it will sink. (What is its density? larger or smaller?)

Parcel warmer than environment

z

Warmer

Cooler

If the parcel moves up and finds itself warmer than the environment then it will go up some more. (What is its density? larger or smaller?)

Parcel cooler than environment

z

Warmer

Cooler

If the parcel moves up and finds itself cooler than the environment, then it will sink. (What is its density? larger or smaller?)

This is our first example of “instability” – a perturbation that grows.

Let’s quantify this.

zzTzzT

Tz z zz

TzTT

sfcsfc

sfc

)()(T

ist environmen theof in change then the,Δ to from go weif So

rate lapse constant

Under consideration of T changing with a constant linear slope (or lapse rate).

Let’s quantify this.

rate lapse adiabatic

T

is parcel theof in change then the,Δ to from go weif So

)()(

pd

dzparceldzparcel

c

g

zTzT

Tz z z

Under consideration of T of parcel changing with the dry adiabatic lapse rate

Stable: temperature of parcel cooler than environment.

d

tenvironmenparcel TT

Unstable: temperature of parcel greater than environment.

d

tenvironmenparcel TT

Stability criteria from physical argument

stable

neutral

unstable

d

d

d

Let’s return to the vertical momentum equation

What are the scales of the terms?

2H

WW*U/L

U*U/a

UfgH

Psfc

10-7

10-5 10

10-3

10 10-15

)()cos(21v 2

22

wΩugz

p

a

u

Dt

Dw

What are the scales of the terms?

2H

WW*U/L

U*U/a

UfgH

Psfc

10-7

10-5 10

10-3

10 10-15

)()cos(21v 2

22

wΩugz

p

a

u

Dt

Dw

Vertical momentum equation Hydrostatic balance

gz

p

wΩugz

p

a

u

Dt

Dw

10

balance chydrostati

)()cos(21v 2

22

Hydrostatic balance

gz

penv

env

1

0

balance chydrostatiin t environmen

But our parcel experiences an acceleration

gz

p

Dt

zD

Dt

Dw env

parcel

1

2

2

Assumption of adjustment of pressure.

Solve for pressure gradient

z

pg

gz

p

envenv

env

env

1

0

balance chydrostatiin t environmen

But our parcel experiences an acceleration

)()1(

or )()1(

2

2

2

2

2

2

tenvironmen

tenvironmenparcel

tenvironmen

parcel

parcel

parcelenv

parcel

env

parcel

env

ggDt

zD

ggDt

zD

gg

Dt

zD

Dt

Dw

Again, our pressure of parcel and environment are the same so

)()(2

2

tenvironmen

tenvironmenparcel

tenvironmen

tenvironmenparcel

T

TTgg

Dt

zD

So go back to our definitions of temperature and temperature change above

zzT

g

zzT

g

T

TTg

Dt

zD

d

dntdisplacemez

tenvironmen

tenvironmenparcel

)(

)(

)(

0

@

2

2

Use binomial expansion

)1(11

and small is ntsdisplaceme smallfor

)1(

11

000

0

00

0

T

z

TzT

T

z

Tz

TzT

So go back to our definitions of temperature and temperature change above

zT

z

Tg

zzT

g

Dt

zD

d

d

))(1(1

)(

00

02

2

Ignore terms in z2

0)(

)()(

02

2

002

2

zT

g

Dt

zD

or

zT

gz

T

g

Dt

zD

d

dd

For stable situation

0)( and

0)(

0

02

2

dd

d

T

g

zT

g

Dt

zD

Seek solution of the form

tBtAz

2

sin2

cos

For stable situation

Seek solution of the form

)(

2

2sin

2cos

0

dTg

tBtAz

Parcel cooler than environment

z

Warmer

Cooler

If the parcel moves up and finds itself cooler than the environment then it will sink. (What is its density? larger or smaller?)

Example of such an oscillation

For unstable situation

0)( and

0)(

0

02

2

dd

d

T

g

zT

g

Dt

zD

Seek solution of the form

tiez

Parcel cooler than environment

z

Warmer

Cooler

If the parcel moves up and finds itself cooler than the environment, then it will sink. (What is its density? larger or smaller?)

This is our first example of “instability” – a perturbation that grows.

This is our first explicit solution of the wave equation

• These are called buoyancy waves or gravity gaves.

• The restoring force is gravity, imbalance of density in the fluid.

• We extracted an equation through scaling and use of balances.– This is but one type of wave that is supported by the

equations of atmospheric dynamics.

• Are gravity waves important in the atmosphere?

Near adiabatic lapse rate in the troposphere

Troposphere: depth ~ 1.0 x 104 m

Troposphere------------------ ~ 2Mountain

Troposphere------------------ ~ 1.6 x 10-3

Earth radius

GTQ: What if we assumed that the atmosphere was constant density? Is there a depth the atmosphere cannot exceed?

Looking at the atmosphere

• What does the following map tell you?

Forced Ascent/Descent

WarmingCooling

An Eulerian Map

Let us return to the horizontal motions

Some meteorologist speak

• Zonal = east-west• Meridional = north-south• Vertical = up and down

What are the scales of the terms?

2H

U

)v()sin(21v)tan(v

)()cos(2)sin(v21)vtan(

22

2

Ωuy

p

a

w

a

u

Dt

D

uΩwΩx

p

a

uw

a

u

Dt

Du

U*U/L

U*U/a

U*W/a

Uf WfL

P

10-4

10-5

10-8

10-3 10-310-6 10-12

What are the scales of the terms?

2H

U

)v()sin(21v)tan(v

)()cos(2)sin(v21)vtan(

22

2

Ωuy

p

a

w

a

u

Dt

D

uΩwΩx

p

a

uw

a

u

Dt

Du

U*U/L

U*U/a

U*W/a

Uf WfL

P

10-4

10-5

10-8

10-3 10-310-6 10-12

Largest Terms

Geostrophic balance

High Pressure

Low Pressure

Atmosphere in balance

• Hydrostatic balance• Geostrophic balance• Adiabatic lapse rate

• We can use this as a paradigm for thinking about many problems, other atmospheres. Suggests a set of questions for thinking about observations. What is the rotation? How does it compare to acceleration, represented by the spatial and temporal scales?

Atmosphere in balance

• Hydrostatic balance• Geostrophic balance• Adiabatic lapse rate

• But what we are really interested in is the difference from this balance. And this balance is like a strong spring, always pulling back. It is easy to know the approximate state. Difficult to know and predict the actual state.

Let’s think about another possible balance

Thermodynamic balance(velocity and acceleration = 0)

1 and

0

10

10

10

RTp

Jt

Tc

t

gz

p

y

p

x

p

v

Compare with geostrophic balance.

Specify something for J

heating frictionaltyconductivi thermal

heatlatent radiation

J

Jt

Tcv

Specify something for J

TJ

Jt

Tcv

flux) (radiative div

Where we ignore for latent heat release for convenience (e.g. dry atmosphere). We know frictional heating is zero for no velocity.

We can show

• Horizontal gradients of both pressure and density must equal zero.– Hence horizontal temperature gradient must be zero.

T=T(z)

• If there is a horizontal temperature gradient then there is motion. If differential heating in the horizontal then temperature gradient. Hence motion.

Transfer of heat north and south is an important element of the climate at the Earth’s surface.

Redistribution by atmosphere, ocean, etc.

SURFACE

Top of Atmosphere / Edge of Space

ATMOSPHERECLOUD

heat is moved to poles

cool air moved towards equator cool air moved towards equator

This is a transfer. Both ocean and atmosphere are important!

Hurricanes and heat

Middle latitude cyclones

Thermodynamic Balance

• The atmosphere and ocean are NOT in thermodynamic balance.

• If there is a temperature gradient, then there is motion.

• Temperature gradients are always being forced.

Return to the Geostrophic Balance

The geostrophic balance

2H

U

)v()sin(21v)tan(v

)()cos(2)sin(v21)vtan(

22

2

Ωuy

p

a

w

a

u

Dt

D

uΩwΩx

p

a

uw

a

u

Dt

Du

U*U/L

U*U/a

U*W/a

Uf WfL

P

10-4

10-5

10-8

10-3 10-310-6 10-12

Largest Terms

The geostrophic balance

y

pfu

x

pfv

Ωf

Ωuy

p

Ωx

p

1

1

)sin(2

)sin(21

0

)sin(v21

0

The geostrophic balance

y

pfu

x

pfv

1

1How do we link the horizontal and vertical balances?

The geostrophic balance

y

pfu

z

x

pfv

z

1

1

Take a vertical derivative of the equation.

The geostrophic balance

y

T

fT

g

z

u

x

T

fT

g

z

v

z

T

T

u

y

T

fT

g

z

u

z

T

T

v

x

T

fT

g

z

v

Use equation of state to eliminate density.

Thermal wind relationship in height (z) coordinates

moving block

Shear? (1)

stationary surface

There is force due to fact that there is a velocity and when the moving blocks are in contact the interfaces experience a force – say , friction, the surfaces can distort. One form of distortion is shearing.

moving fluid

Shear? (2)

• Shear is a word used to describe that velocity varies in space.

more slowly moving fluid

There is force due to fact that there is a velocity gradient, and because our fluid is a fluid, the fluid surface responds to this gradient, which is called the shear.

moving fluid

Shear? (3)

• Shear is a word used to describe that velocity varies in space.

more slowly moving fluid

wind.zonal ofshear vertical

z

u

z

The geostrophic balance

y

T

fT

g

z

u

What does this equation tell us?

Thermal wind relationship in height (z) coordinates

Can we start to relate vertical structure and wind?

Troposphere: depth ~ 1.0 x 104 m

Troposphere------------------ ~ 2Mountain

Troposphere------------------ ~ 1.6 x 10-3

Earth radius

An estimate of the January mean temperature

northwinter

southsummer

tropopause

stratopause

mesosphere

stratosphere

troposphere

note where the

horizontal temperature gradients are

large

An estimate of the January mean zonal wind

northwinter

southsummer

note the jet streams

An estimate of the July mean zonal wind

northsummer

southwinter

note the jet streams

Gosh, that’s a lot

• Think about it!

• Do your homework?

• This is new material now?

• From that July wind field, what are the differences between January and July temperatures.