BJT Emitter Stabilized Bias ELEC 121. January 2004ELEC 1212 Improved Bias Stability The addition of...

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BJT Emitter Stabilized Bias

ELEC 121

January 2004 ELEC 121 2

Improved Bias Stability

The addition of RE to the Emitter circuit improves the stability of a transistor output

Stability refers to a bias circuit in which the currents and voltages will remain fairly constant over a wide range of temperatures and transistor forward current gain ()The temperature (TA or ambient temperature) surrounding the transistor circuit is not always constantTherefore, the transistor is not a constant value

January 2004 ELEC 121 3

BJT Emitter Bias• Draw Equivalent Input circuit• Draw Equivalent Output circuit• Write necessary KVL and KCL Equations• Determine the Quiescent Operating Point

– Graphical Solution using Loadlines– Perform a Computational Analysis

January 2004 ELEC 121 4

Emitter-Stabilized Bias Circuit

Adding an emitter resistor to the circuit between the emitter lead and ground stabilizes the bias circuit over Fixed Bias

January 2004 ELEC 121 5

Base-Emitter Loop

January 2004 ELEC 121 6

Equivalent Network

January 2004 ELEC 121 7

Reflected Input impedance of RE

January 2004 ELEC 121 8

Base-Emitter Loop

Applying Kirchoffs voltage law: - VCC + IB RB + VBE +IE RE = 0

Since: IE = ( + 1) IB

We can write: - VCC + IB RB + VBE + ( + 1) IB RE = 0

Grouping terms and solving for IB:

Or we could solve for IE with:

CC BEB

B E

V - VI =

R + (β+1)R

BCC E BE E E

R- V + I + V + I R = 0

( + 1)

January 2004 ELEC 121 9

Collector-Emitter Loop

January 2004 ELEC 121 10

Collector-Emitter Loop

Applying Kirchoff’s voltage law: - VCC + IC RC + VCE + IE RE = 0

Assuming that IE IC and solving for VCE: VCE = VCC – IC (RC + RE)

If we can not use IE IC the IC = IE and: VCE = VCC – IC (RC + RE)

Solve for VE: VE = IE RE

Solve for VC: VC = VCC - IC RC or

VC = VCE + IE RE

Solve for VB: VB = VCC - IB RB or

VB = VBE + IE RE

January 2004 ELEC 121 11

Transistor Saturation

CC CE CSAT

C E

V - VI =

R + R

At saturation, VCE is at a minimum

We will find the value VCEsat = 0.2V

For load line analysis, we use VCE = 0

To solve for ICSAT, use the output KVL equation:

January 2004 ELEC 121 12

Load Line Analysis

The load line end points can be calculated:

At cutoff:

At saturation:

C CE CC I = 0 mAV V |

CE

CCC V = 0V

C E

VI =

R + R|

January 2004 ELEC 121 13

Emitter Stabilized Bias Circuit Example

January 2004 ELEC 121 14

Design of an Emitter Bias CE Amplifier

Where .1VCC VE .2VCC

And .4VCC VC .6VCC

January 2004 ELEC 121 15

Emitter Bias with Dual Supply

January 2004 ELEC 121 16

Emitter Bias with Dual Supply

Input Output