Post on 04-Nov-2015
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Configuring the computers Below are the steps involved in configuring your computer to connect them on a LAN using Ethernet cable.
Step 1. In order to start the connection, youll have to assign different IP address for both computers. To change the IP address of your computers for the LAN connection, you should make changes in the LAN adapter settings.
Open Control panel from the start menu and click on Network and Internet and click on Network and Sharing center. From the left sidebar, click on Change adapter settings.
Under the Network connections window select the appropriate icon for your LAN adapter and right-click on it, then choose Properties.
A Local Area Connection Properties box appears.
Under the Network tab select Internet Protocol Version 4 (TCP/IPv4) and click on the Properties button. Now set the addresses as mentioned below in each computer and click OK.
At the first computer ( say, Computer 1):
IP address: 192.168.0.1
Subnet mask: 255.255.255.0
At the second computer ( say, Computer 2):
IP address: 192.168.0.2
Subnet mask: 255.255.255.0
Step 2. Now, connect one end of the cable into the Ethernet port of Computer 1 and the other end with the same of the Computer 2 and apply the following steps in both the computers.
Right-click on Computer from the start menu and select Properties. The system properties Control Panel window opens as shown below.
Click on Change settings and the System properties dialog box appears. under the Computer Name tab, click on on the Change button to assign a WORKGROUP. Assign the same workgroup name for both computers otherwise it wont work.
Restart each computer. It does not matter which computer you restart first. After starting both the computer, double-click on the Computer icon at the start menu and then click on Network from the left side of the explorer window.
In the computer 1, you should see an icon denoting your second computers name under the Network window. Similarly, you can see that the first computer has been appeared under the Network window of your second computer.
If they do not appear, you should get a message prompting to turn on Network Discovery and file Sharing. Click that security pop-up and select make the network a private network. In case, you may have to restart your computers.
Once you see the other computer in your Network computer window, just double click on it. If the other computer is password protected, you will have to enter the exact user name and password of that computer to get access of the shared folder.
If you want to share some files or folder of a computer with the other computer on the network, right-click on that and select Share with > Homegroup. Even you can share a total drive by right-clicking on it.
Let me know if you face any problem when sharing files between two computers on LAN.
Also check out how to share Internet connection using an Ethernet cable.
Formula for finding out problems on train
1. km/hr to m/s conversion: a km/hr = (a*(5/18))m/s.
2. m/s to km/hr conversion: a m/s = (a*(18/5))km/hr.
3. Time taken by a train of length l metres to pass a pole or standing man or
a signal post is equal to the time taken by the train to cover l metres.
4. Time taken by a train of length l metres to pass a stationery object of
length bmetres is the time taken by the train to cover (l + b) metres.
5. Suppose two trains or two objects bodies are moving in the same direction
at u m/s and v m/s, where u > v, then their relative speed is = (u - v) m/s.
6. Suppose two trains or two objects bodies are moving in opposite directions
at u m/s and v m/s, then their relative speed is = (u + v) m/s.
7. If two trains of length a metres and b metres are moving in opposite
directions at um/s and v m/s, then:
The time taken by the trains to cross each other = (a + b) sec.
(u + v)
8. If two trains of length a metres and b metres are moving in the same
direction at um/s and v m/s, then:
The time taken by the faster train to cross the slower train = (a + b) sec.
(u - v)
9. If two trains (or bodies) start at the same time from points A and B
towards each other and after crossing they take a and b sec in reaching B and
A respectively, then:
(A's speed) : (B's speed) = (b : a)
10. Speed = distance/time s = d/t
11. velocity = displacement/time v = d/t.
12. Time taken by a train x meters long to pass a pole or standing man or a
post
= Time taken by the train to travel x meters.
13. Suppose two trains or two objects are moving in the same direction at v1
m/s and v2 m/s where v1 > v2,
then their relative speed = (v1 v2) m/s
14. Suppose two trains or two objects are moving in opposite directions at v1
m/s and v2 m/s ,
then their relative speed = (v1+ v2) m/s
15. Assume two trains of length x metres and y metres are moving in opposite
directions at v1 m/s and v2 m/s, Then
The time taken by the trains to cross each other = (x+y) / (v1+v2) seconds
16. 10. Assume two trains of length x metres and y metres are moving in the
same direction at at v1 m/s and v2 m/s where v1 > v2, Then
The time taken by the faster train to cross the slower train = (x+y) / (v1-
v2) seconds
17. Suppose 2 Trains begins at the same time from X and Y towards each other
and after crossing they take x & y secs in reaching Y and X correspondingly,
then:
(Xs speed) : (Ys speed) = SQRT(y) : SQRT(x)
18. Rule 1: When two trains are moving in opposite diections, then relatve
speed will be the addition of their individiual speeds.
19. Rule 2: When two trains are moving in same diection, then relatve speed
will be the subtrction of their individiual speeds.
20. Rule 3: On passing a platform by a certain train the net distance
travelled is the sum of length of train and the length of platform both.
21. Rule 4: When a train passes through a pole or person standing, net
distance travelled to pass is the length of the train
Sample Example
Ex
A train 120 m long is running at the speed of 54 km /hr. Find the time taken it to pass a man standing near the railway track ?
A
speed of train = [54 * ( 5 / 18 ) ] = 15 m / sec
length of train = 120 m , So required time :
Time taken = (120/15) = 8 sec.
Ex
train is moving at a speed of 54 km / hr. If the length of the train is 100 meters, how long will it take to cross a railway platform 110 meters long ?
A
speed of train = [54 * ( 5 / 18 ) ] = 15 m / sec
Distance covered in passing the platform = 100 + 110 = 210 m
therefore Time taken = (210/15) = 14 sec.
Ex
Two trains 125 m and 100 m in length respectively are running in opposite directions, one at the rate of 50 km / hr and the other at the rate of 40 km /hr. At what time they will clear each other from the moment they meet ?
A
Relative speed of trains = (50 + 40) km / hr = [90 * ( 5 / 18 ) ] = 25 m /
sec
Total length to be travelled = 125 + 100 = 225 m
therefore Time taken = (225/25) = 9 sec.
Ex
Two trains 110 m and 100 m in length respectively are running in same directions, one at the rate of 100 km / hr and the other at the rate of 64 km / hr. At what time faster train will clear other train from the moment they meet ?
A
Since trains are running in same direction, so relative speed = 100-64 = 36
km / hr = [ 36 * ( 5 / 18 )] = 10 m / sec
Total length to be travelled = 110 + 100 = 210 m
therefore Time taken = (210/10) = 21 sec.
Ex
A train passes a standing pole on the platform in 5 seconds and passes the platform completely in 20 seconds. If the length of the platform is 225 meters. Then find the length of the train ?
A
Let the length of the train is x meter
So speed of train =( x / 5 ) m / sec
Also speed of train = ( 225 + x ) / 20 m/sec
x/5 = (225+x)/20, therfore x = 75 m.
Ex
Two trains of length 115 m and 110 m respectively run on parallel rails. When running in the same direction the faster train passes the slower one in 25 seconds, but when they are running in opposite directions with the same speeds as earlier, they pass each other in 5 seconds. Find the speed of each train ?
A
Let the speed of trains be x m/sec and y m/sec espectively.
When they move in same direction their relative speed is : x - y
When they moves in opposite direction their relative speed is : x + y
x-y = (115+110)/25, x+y = (115+110)/5
On solving two equations x=27 m/s and y=18 m/sec
Ex
The product of two numbers is 60480 and their HCF is 12 . Find the numbers ?
A
Since HCF s 12, so the two numbers will be multiple of their HCF
let the first number is 12P and the second number be 12Q
12P 12Q = 60480
P Q = 420
Now pair of numbers whose product is 420 is
( 420, 1 ) ( 210, 2 ) ( 140, 3 ) ( 105, 4 ) ( 60, 7 )
( 20, 21 )
Out of these ( 210, 2 ) is not prime so neglected
Now the required numbers will be ( 42012, 112 ) ( 14012, 312 ) (
10512, 412) ( 60 12 , 712 ) ( 2012, 2112 )
( 5040, 12 ) (1680, 36) ( 1260, 48) ( 720, 84 ) ( 240, 252 ) be the
required numbers
Ex
Find the greatest number that will divide 37, 109 and 157 so as to leave the same remainder in each case ?
A
Let the remainder be x, then the numbers :
( 37 - x ) ( 109 - x ) ( 157 - x ) must be divisible by the
required number.
Also if two numbers are divisible by the certain number then their
difference is also divisible by that number
( 109 - x ) - ( 37 - x ) = 72
( 157 - x ) - ( 109 - x ) = 48
( 157 - x ) - ( 37 - x ) = 120
So, the numbers 72, 48, 120 will also be divisible by that number, So HCF
of 72, 48, 120 is 24, therefore required number will be 24
Serial Word Antonyms Synonyms
1 Combat Harmony , Peace , Concord , Amity , Cooperation , Surrender , Compromise
War , Fighting , Battle , Encounter , Contest , Fight , Conflict
2 Brevity Confused , Longevity , Loquacious , Verbosity , Garrulity Short , Laconic , Concise , Brief
3 Alarming Hopeful , Comforting , Auspicious , Encouraging , Optimistic
Frightful , Dreadful , Terrible , Shocking , Ominous , Awful , Threatening , Scary
4 Feeble Strong , Forceful , Vigorous , Firm , Muscular , Powerful , Robust
Weak , Fragile , Impotent , Languid , Frail
5 Miserable Happy , Jocund , Cheerful , Glad , Joyous , Prosperous , Dignified , Blessed
Forlorn , Melancholy , Unhappy , Sad , Dismal , Pathetic , Wretched , Oppressive
6 Splendid Dull , Ordinary , Dark , Humble , Dim , Dreadful , Cloudy , Terrible Resplendent , Marvellous , Radiant , Magnificent , Brilliant , Wonderful , Shining , Great , Excellent
7 Vague Clear , Evident , Defined , Obvious , Sharp , Certain , Distinct , Definite
Dim , Obscure , Nebulous , Indefinite , Doubtful , Ambiguous , Unclear , Abstruse
8 Controversy Agreement , Peace , Compromise , Concord , Accord , Harmony Dispute , Strife , Argument , Discord , Contention , Conflict , Debate , Quarrel
9 Elegant Inexpensive , Ugly , Simple , Awkward , Usual , Rough , Vulgar , Rude , Coarle
Luxurious , Polished , Dignified , Fine , Graceful , Refined , Exquisite , Polite
10 Horrible Agreeable , Attractive , Pleasant , Fascinating , Delightful , Pleasing , charming
Frightful , Horrid , Ghastly , Horrifying , Fearful , Terrific , Ugly , Awful
11 Fame Disrepute , Dishonour , Notoriety , Obscurity , Oblivion Esteem , Repute , Credit , Prestige , Glory , Honour , Reputation , Renown
12 Scanty Ample , Plentiful , Excessive , Abundant , Sufficient , Deficient , Narrow , Slender , Limited , Meagre , Sparse , Poor, Inadequate , Few , Small ,
13 Worthless Excellent , Useful , Good , Worthwhile , Valuable , Admirable Cheap , Futile , Base , Useless , Valueless , Contemptible
14 Inclement Genial , Temperate , Mild , Favourable , Pleasant Rough , Severe , Stormy , Harsh , Unpleasant , Unfavourable
15 Hazard Certainty , Surety , Protection , Security Danger , Threat , Jeopardy , Peril , Venture , Risk
16 Brutal Tender , Merciful , Compassionate , Humane , Sympathetic , Gentle , Kind
Savage , Inhuman , Bestial , Merciless , Cruel , Barbarous
17 Audacious Courteous , Humble , Polite , Intrepid , Adventurous , Daring , Bold ,
Serial Word Antonyms Synonyms Modest , Fearful , Timid Courageous , Insolent , Impudent
18 Wicked Just , Moral , Good , Virtuous , Upright , Malevolent , Evil , Heinous , Criminal , Vicious , Corrupt , Immoral , Bad
19 Abhor Devotion , Fondness , Passion , Love , Attachment , Admiration , Affection
Disdain , Hate , Abominate , Dislike , Scorn , Despise
20 Filthy Immaculate , Clean , Virtuous , Pure , Decent , Spotless Nasty , Foul , Unclean , Putrid , Dirty , Impure , Polluted , Corrupt
Configuring the computersFormula for finding out problems on trainSample ExampleA train 120 m long is running at the speed of 54 km /hr. Find the time taken it to pass a man standing near the railway track ?train is moving at a speed of 54 km / hr. If the length of the train is 100 meters, how long will it take to cross a railway platform 110 meters long ?Two trains 125 m and 100 m in length respectively are running in opposite directions, one at the rate of 50 km / hr and the other at the rate of 40 km /hr. At what time they will clear each other from the moment they meet ?Two trains 110 m and 100 m in length respectively are running in same directions, one at the rate of 100 km / hr and the other at the rate of 64 km / hr. At what time faster train will clear other train from the moment they meet ?A train passes a standing pole on the platform in 5 seconds and passes the platform completely in 20 seconds. If the length of the platform is 225 meters. Then find the length of the train ?Two trains of length 115 m and 110 m respectively run on parallel rails. When running in the same direction the faster train passes the slower one in 25 seconds, but when they are running in opposite directions with the same speeds as earlier, they pa...The product of two numbers is 60480 and their HCF is 12 . Find the numbers ?Find the greatest number that will divide 37, 109 and 157 so as to leave the same remainder in each case ?