Database Relational Model. The Relational Data Model Data Modeling Data Modeling Relational Schema...

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Database

Relational Model

The Relational Data Model

DataModeling

DataModeling

Relational Schema

Relational Schema

Physicalstorage

Physicalstorage

E/R diagrams Tables: column names: attributes

rows: tuples

Complexfile organization

and index structures.

Relational Data Model

Core of majority of modern databases

Virtually all business relies on some form of relational database

Solid theoretical/mathematical foundation

Relational Model Concepts

The relational Model of Data is based on the

concept of a Relation.

A Relation is a mathematical concept based

on the ideas of sets. Order of tuples not important

Order of attributes not important (in theory)

RELATION

RELATION is A table of values

A relation may be thought of as a set of

rows.

A relation may alternately be though of as a

set of columns.

Relation InstanceName Address Telephone

Ahmed 123 Main St 555-1234

Hassan 12 State St 555-1235

Ahmed 123 Main St 555-1235

Mona 456 Main St 555-2221

Sally 456 Main St 555-2221

Sally 456 Main St 555-2223

Hassan 12 State St 555-1235

ExampleState

Example Schema

Schema

The schema of a relation is the name of the relation followed by a parenthesized list of attributes (+ types of attributes).

CoursesTaken(Student, Course, Grade) A design in a relational model consists of a set of

schemas. Such a set of schemas is called a relational database

schema.

Relation Schema

StockItem

Attribute DomainItemID string(4)Description string(50)Price currency/dollarsTaxable boolean

relationname

set of attributes

attributedomains

attributenames

Relational schema

Is a direct map from ER diagram into basic table

For example, the schema (ID, phone, name,

birth_date, address)

Banking Example

branch (branch_name, branch_city, assets)

customer (customer_name, customer_street, customer_city)

account (account_number, branch_name, balance)

loan (loan_number, branch_name, amount)

depositor (customer_name, account_number)

borrower (customer_name, loan_number)

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Example Database Schema

Student (Id: INT, Name: STRING, Address: STRING, Status: STRING)

Professor (Id: INT, Name: STRING, DeptId: DEPTS)

Course (DeptId: DEPTS, CrsName: STRING, CrsCode: COURSES)

Transcript (CrsCode: COURSES, StudId: INT, Grade: GRADES, Semester: SEMESTERS)

Department (DeptId: DEPTS, Name: STRING)

Key Constraints

key of R: A set of attributes SK of R such that no two tuples will have the same value for SK

If a relation has several candidate keys, one is chosen arbitrarily to be the primary key. The primary key attributes are underlined.

Indicate a key by underlining the key attributes. Example: If name is a key for Beers:

Beers(name, manf)

Entity Set to Relation

Product

name category

price

Product(name, category, price)

name category price

gizmo gadgets $19.99

Relationships to Relations

makes Company

Product

name category

Stock price

name

Makes(product-name, product-category, company-name, year) Product-name Product-Category Company-name Starting-year

gizmo gadgets gizmoWorks 1963

Start Year

price

Relationships to Relations

makes Company

Product

name category

Stock price

name

No need for Makes. Modify Product:

name category price StartYear companyName

gizmo gadgets 19.99 1963 gizmoWorks

Start Year

price

uses

carriesAircraft

Airport

Flight

Flight (flight#, arrival_airport, depart_airport, arrival_time, depart_time)

Airport (code, city)

Aircraft (aircraft, no_of_seats)

Identifier of flight seems strange. ‘Flight_no’ alone should identify a flight.

ERD FROM DATASTORES FLIGHTS

carries

Stops_at

Aircraft

Airport

Stopover

Flight (flight#, arrival_airport, depart_airport, arrival_time, depart_time)

Stopover (flight_no, code, arrival_time, depart_time)

Airport (code, city)

Aircraft (aircraft, no_of_seats)

Flight

Leaves_from

Departs_from

Arrives_at

ERD FROM DATASTORES FLIGHTS

Multi-way Relationships to Relations

Purchase

Product

Person

Storename price

ssn name

name address

Purchase( , , )

Drinkers

For one-one relation Married, we can choose either husband or wife as key.

Likes(drinker, beer)Favorite(drinker, beer)Married(husband, wife)Buddies(name1, name2)

BeersLikes

name manfname addr

Buddies

Married

Favorite

1 2

husband wife

Weak Entity Sets, Relationships Relations

Relation for a weak E.S. must include its full key (i.e., attributes of related entity sets) as well as its own attributes.

A supporting (double-diamond) relationship yields a relation that is actually redundant and should be deleted from the database schema.

Representing Entity Sets With Simple AttributesRepresenting Entity Sets With Simple Attributes

A strong entity set reduces to a schema with the same attributesstudent(ID, name, tot_cred)

A weak entity set becomes a table that includes a column for the primary key of the identifying strong entity set section ( course_id, sec_id, sem, year )

Example

Hosts(hostName)

Logins(loginName, hostName)

At(loginName, hostName, hostName2) In At, hostName and hostName2 must be the

same host, so delete one of them. Then, Logins and At become the same

relation; delete one of them. In this case, Hosts’ schema is a subset of Logins’ schema. Delete Hosts?

Logins Hosts@@

name name

Converting Non-identifying Attributes Single-valued (standard attribute)

Create a table column for each

Derived Omit: these values are not stored in our tables

Later, we can produce these values using a query

Multi-valued Relational model does not directly support! However, as we have discussed, a multi-valued

attribute can be conceptualized as a new (weak) entity, thus implying a separate table.

Composite and Multivalued Attributes

Composite attributes are flattened out by creating a separate attribute for each component attribute Example: given entity set instructor with

composite attribute name with component attributes first_name and last_name the schema corresponding to the entity set has two attributes name_first_name and name_last_name

Prefix omitted if there is no ambiguity Ignoring multivalued attributes, extended

instructor schema is instructor(ID,

first_name, middle_initial, last_name, street_number, street_name, apt_number, city, state, zip_code, date_of_birth)

Composite and Multivalued Attributes

A multivalued attribute M of an entity E is represented by a separate schema EM Schema EM has attributes corresponding to the

primary key of E and an attribute corresponding to multivalued attribute M

Example: Multivalued attribute phone_number of instructor is represented by a schema: inst_phone= ( ID, phone_number)

Each value of the multivalued attribute maps to a separate tuple of the relation on schema EM

For example, an instructor entity with primary key 22222 and phone numbers 456-7890 and 123-4567 maps to two tuples: (22222, 456-7890) and (22222, 123-4567)

One-to-one relationships Consider the 2 associated entity tables. The foreign key column(s) can be with either entity

As before, copy the primary key column(s) of the related table

Note: in a 1:1 relationship, the two entities often use the same identifier, in which case the existing primary key columns serve the “dual role” of both primary and foreign keys A separate foreign key column is then unnecessary!

Converting Binary Relationships

One-to-many relationships Consider the 2 associated entity tables. Within the “many side” entity’s table, we need to have

foreign key column(s) referring to the related “one side” entity instances

We use the identifier of the related entity to define the foreign key column(s)

In other words, we include a column (a “copy”) of primary key values from the related table

The copied primary key values we call “foreign keys.”

Converting Binary Relationships

Schema Diagram

Reverse engineer this relational schema to find an equivalent ER schema.

REVIEW

Many-to-many relationships Relational model does not directly support! However, each many-to-many relationship can be

conceptualized as a new (associative) entity, thus implying a separate table.

The identifier for the associative entity is the combination of the identifiers for the two related entities.

Thus, for the separate table we create for an M:M relationship, its primary key columns include the primary key columns for both of the related tables.

Converting Binary Relationships

Finding the Keys

PersonbuysProduct

name

price name ssn

buys(name, ssn, date)

date

If the relation comes from a many-many relationship, the key of the relation is the set of all attribute keys in the relations corresponding to the entity sets

PREVIEW: ER to Relational

EER Bank Schema

Step 1: Regular Entities

Regular entity types become relations include all simple attributes include only components of compound

attributes keys become primary keys if multiple keys (candidates) select a primary

key

CUSTOMER(Ssn, Name, Addr, Phone)

Step 1: Regular Entities

ACCOUNT(Acct_no, Type, Balance)

LOAN(Loan_no, Type, Amount)

BANK(Code, Name, Addr)

Step 2: Weak Entities Weak entity types become relations

include all simple attributes include only components of compound attributes create a primary key from partial key

and key of owning entity type (through identifying relationship)

attributes acquired through identifying relationship become a foreign key*

* typically, deletions and insertions will be propagated

through this foreign key

Step 2: Weak Entities Weak entity types become relations

BANK_BRANCH(Bank_code, Branch_No, Addr)

BANK(Code, Name, Addr)

FK

Step 3: Binary 1:1 Relationships Approach 1: Foreign Key

EMPLOYEE(Ssn, Name, …)

DEPARTMENT(Name, Number, Mgr, Mgr_start_date)

FK

Step 3: Binary 1:1 Relationships Approach 2: Merged Relation

AJB(x, y, p, q, r)

or

AJB(x, y, p, q, r)

Step 4: Binary 1:N Relationships 1:N Relationships become foreign key at N side

any relationship attributes also go to N side

LOAN(Loan_no, Type, Amount, Bank, Branch)

BANK_BRANCH(Bank_code, Branch_No, Addr)

Step 4: Binary 1:N Relationships 1:N Relationships become foreign key at N side

any relationship attributes also go to N side

ACCOUNT(Acct_no, Type, Balance, Bank, Branch)

BANK_BRANCH(Bank_code, Branch_No, Addr)

Step 5: Binary M:N Relationships M:N Relationships must become a new relation

contains FKs to both related entities combined FKs become PK for new relations relationship attributes go in new relation

CUSTOMER(Ssn, Name, Addr, Phone)

ACCOUNT(Acct_no, Type, Balance, Bank, Branch)

A_C(Acct, Cust)

Step 6: Multivalued Attributes Multivalued attributes must become new

relations FK to associated entity type PK is whole relation

DEPT_LOCATIONS(DName, Dno, Location)

DEPARTMENT(Name, Number, Mgr, Mgr_start_date)

Step 7: N-ary Relationships Non-Binary Relationships become new relations

FKs to all participating entity types Combine FKs to make a PK

(exclude entities with max participation of 1) Include any relationship attributes

SUPPLY(SName, PName, Part, Quantity)

SUPPLIER(SName)

PROJECT(Proj_name)PART(Part_no)

Completed Bank Schema

CUSTOMER(Ssn, Name, Addr, Phone)BANK(Code, Name, Addr)ACCOUNT(Acct_no, Type, Balance, Bank, Branch)LOAN(Loan_no, Type, Amount, Bank, Branch)BANK_BRANCH(Bank_code, Branch_No, Addr)A_C(Acct, Cust)L_C(Loan, Cust)

BANK_BRANCH(Bank_code) refers to BANKLOAN(Bank,Branch) refers to BANK_BRANCHACCOUNT(Bank,Branch) refers to BANK_BRANCHA_C(Acct) refers to ACCOUNTA_C(Cust) refers to CUSTOMERL_C(Loan) refers to LOANL_C(Cust) refers to CUSTOMER

Bank Schema: MS Access

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Exercise A university database contains information about professors

(identified by social security number) and courses (identified by courseid). Professors teach courses; each of the following situations concerns the Teaches relationship set. For each situation, draw an ER diagram that describes it.

Professors can teach the same course in several semesters, and each offering must be recorded.

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Professors can teach the same course in several semesters, and only the most recent such offering needs to be recorded.

Exercise

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Every professor teaches exactly one course (no more, no less)

Every professor teaches exactly one course (no more, no less), and every course must be taught by some professor

Exercise

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Practice

Professors have an SSN, a name, an age, a rank, and a research specialty. Projects have a project number, a sponsor name (e.g., NSF), a starting date, an

ending date, and a budget.

Graduate students have an SSN, a name, an age, and a degree program Each project is managed by exactly one professor (known as PI) Each project is worked in by one or more professors (known as Co-PIs) Each project is worked on by one or more graduate students (known as

RAs)

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When graduate students work on a project, a professor must supervise their work on the project. Graduate students can work on multiple projects, in which case they will have a potentially different supervisor for each project.

Departments have a department number, a department name, and a main office. Department has a professor (known as Chairman) who runs the department.

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Professors work in one or more departments, and for each department that they work in, a time percentage is associated with their job

Graduate students have one major department in which they are working on their degree.

Each graduate student must have another, more senior graduate student as an advisor.

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A company database needs to store information about employees (identified by ssn, with salary and phone as attributes), departments (identified by dno, with dname and budget as attributes), and children of employees (with name and age as attributes).

Exercise

A company database needs to store information about employees (identified by ssn, with salary and phone as attributes), departments (identified by dno, with dname and budget as attributes), and children of employees (with name and age as attributes). Employees work in departments; each department is managed by an employee; a child must be identified uniquely by name when the parent (who is an employee; assume that only one parent works for the company) is known.

Draw an ER diagram that captures this information.

Employees work in departments; each department is managed by an employee;

a child must be identified uniquely by name when the parent (who is an employee; assume that only one parent works for the company) is known.

Exercise

You set up a database company, ArtBase, that builds a product for art galleries. The core of this product is a database with a schema that captures all the information that galleries need to maintain.

Galleries keep information about artists, their names (which are unique), birthplaces, age, and style of art. For each piece of artwork, the artist, the year it was made, its unique title, its type of art (e.g., painting, lithograph, sculpture, photograph), and its price must be stored. Pieces of artwork are also classified into groups of various kinds, for example, portraits, still lifes, works by Picasso, or works of the 19th century; a given piece may belong to more than one group. Each group is identified by a name (like those just given) that describes the group. Finally, galleries keep information about customers. For each customer, galleries keep that person’s unique name, address, total amount of dollars spent in the gallery (very important!), and the artists and groups of art that the customer tends to like. Draw the ER diagram for the database

• Galleries keep information about artists, their names (which are unique), birthplaces, age, and style of art .

• For each piece of artwork, the artist, the year it was made, its unique title, its type of art (e.g., painting, lithograph, sculpture, photograph), and its price

must be stored .

• Pieces of artwork are also classified into groups of various kinds, for example, portraits, still lifes, works by Picasso, or works of the 19th century; a given piece may belong to more than one group. • Each group is identified by a name (like those just given) that describes the group.

• Finally, galleries keep information about customers. For each customer, galleries keep that person’s unique name, address, total amount of dollars spent in the gallery (very important!), • and the artists and groups of art that the customer tends to like

Subclasses Relations

1. Object-oriented: each entity is in one class. Create a relation for each class, with all the attributes for that class.

2. E/R style: an entity is in a network of classes related by isa. Create one relation for each E.S. An entity is represented in the relation for each subclass

to which it belongs. Relation has only the attributes attached to that E.S. +

key.

3. Use nulls. Create one relation for the root class or root E.S., with all attributes found anywhere in its network of subclasses. Put NULL in attributes not relevant to a given entity.

Example

name manfBeers

Alescolor

isa

OO-Style

E/R Style

name manf

Bud A.B.

Beers Ales

name manf color

SummerBrew Pete's dark

name manf

Bud A.B.SummerBrew Pete's

name Color

SummerBrew dark

Beers Ales

name manf color

Bud A.B. NULLSummerBrew Pete's dark

Beers

Using NULLS

Design Issues Use of entity sets vs. attributes

Use of phone as an entity allows extra information about phone numbers (plus multiple phone numbers)

Design Issues Use of entity sets vs. relationship sets

Possible guideline is to designate a relationship set to describe an action that occurs between entities

Preview: Queries

•Read the following database case and then draw the EERD for that case. After that, transform that EERD into a relational

model. Assume from 3-5 attributes for each entity type .

ABC is a company whose business is to deliver shipments. The company has many branches in Egypt each of which has many stores. Each store has many employees working for it. A store receives many customer shipments to deliver to destinations. A customer is able to send many shipments and for each he/she is expecting a confirmation on delivery. A fare is payable for each delivery. However, when the shipment is lost an apology is to replace the confirmation. ABC is using many vehicles including aircrafts, trucks and ships for sending the customer shipments.