ELECTRICAL INSTALLATION PLANNING

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ELECTRICAL INSTALLATION PLANNING. LSEGG307A 9080F. Lesson Content. Describe the acceptable methods for determining the maximum demand on an installation’s consumer’s mains. Calculate the maximum demand for the consumer's mains for given installations up to 400 A per phase. Maximum Demand - PowerPoint PPT Presentation

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LSEGG307A9080F

• Describe the acceptable methods for determining the maximum demand on an installation’s consumer’s mains.

• Calculate the maximum demand for the consumer's mains for given installations up to 400 A per phase.

Maximum Maximum Demand Demand

Non-DomesticNon-Domestic

Load are generally heavier

Stay on for longer periods of time

Heating & cooling has an effect on load

ResidentiaResidential Instillationsl Instillations

• Hotels

• Boarding Houses

• Hospitals

• Motels

• etc

AS/NZS 3000Table C2Colum 2

ResidentiaResidential Instillationsl Instillations

AS/NZS 3000Table C2Colum 2

Lighting Load group A

75% connected load

Note BIncandescent Lamps = 60W

Unless the fitting restricts the wattage to less

Track lights = 0.5A/m

ResidentiaResidential Installationsl Installations10A Power Points

Load group B

If this section of buildingDOES NOT HAVE

fixed heating/cooling

Load Group Bi

20 Double power points20 x 2 = 40 Points 1000W + (39 x 400W) =

First Point

Balance

16600230 = 72.2A

ResidentiaResidential Installationsl Installations10A Power Points

Load group B

If this section of buildingDOES NOT HAVE

fixed heating/cooling

Load Group Bi

20 Double power points20 x 2 = 40 Points 1000W + (39 x 100W) =

First Point

Balance

4900230 = 72.2A

HAS

Load Group Bii

21.3A1000W + (39 x 400W) =16600230 =

ResidentiaResidential Installationsl Installations

Load group Biii

1st = full current of highest

2 x 20A power points2 x 15A power points

Power Points Larger than 10A

2nd = 50% x full current

3rd = 50% x full current

20A0.5 x 20 = 10A

0.5 x 15A = 7.5A0.5 x 15A = 7.5A

45A

ResidentiaResidential Installationsl Installations

Power Points 3 Outlets

Load Group B

10A 3 Outlet

A1 Point

B C1 Point 1 Point

30 x Light points

40 x Lights

6 x 400W mercury vapour flood lights

15 x Double power points (p/p)

10 x Single p/p & 15 x Double p/p

3 x 15A Single p/p

1 x 10A 3 outlet

An air conditioned motel consists of the following:A

A

A

Bii

Bii

Biii

Bii

((30x60)230)x0.75 = 5.87A

17.4A

23.3A

A

B

C

A

B

C

A

B

C

7.83A

21.7A

7.83A

34.3A

((6x400)230)x0.75 =

31P(1000+(30x100))230 =

11+30P(1000+(40x100))230 =

(1000230)+15+((2x15)x0.5) =

29.5A 42.1A

((40x60)230)x0.75 =

NSW S&IRClause 1.10.3

Less than 25A difference

FactoriesFactories

• Shops

• Offices

• Schools

• Churches

AS/NZS 3000Table C2Colum 3

FactoriesFactories

AS/NZS 3000Table C2Colum 3

Lighting Load group A

100% connected load

Note BIncandescent Lamps = 60W

Unless the fitting restricts the wattage to less

Track lights = 0.5A/m

FactoriesFactories

10A Power Points Load group B

If this section of buildingDOES NOT HAVE

fixed heating/cooling

Load Group Bi

20 Double power points20 x 2 = 40 Points 1000W + (39 x 750W) =

First Point

Balance

30250230 = 131.5A

Calculation Assessment Measuremen

t Limitation

AS/NZS 30002.2.2.

FactoriesFactories

10A Power Points Load group B

If this section of buildingDOES NOT HAVE

fixed heating/cooling

Load Group Bi

20 Double power points20 x 2 = 40 Points 1000W + (39 x 100W) =

First Point

Balance

4900230 = 131.5A

HAS

Load Group Bii

21.3A1000W + (39 x 750W) =30250230 =

FactoriesFactories

Load group Biii

1st = full current of highest

2 x 20A power points2 x 15A power points

Power Points Larger than 10A

2nd = 75% x full current

3rd = 75% x full current

20A0.75 x 20 = 15A

0.75 x 15A = 11.25A0.75 x 15A = 11.25A

57.5A

3 x 20A 3 WeldersMajority of welders only use 2 phases

W 3

A B C

Only 2 welders on each phase

AS/NZS 3000C2.5.2.2 (b)

20A + 20A = 40 Amps Per Phase

W 1 W 2

Used to give a “Ball Park” figure of maximum demand when actual loads are not available in the initial design stages

Values are given in VA per m2 of floor area

10 metre x 10 metre air conditioned shop

From C310 x 10 = 100 m2

Light & power (average value)= 70 VA/m2

Air conditioning= 30 VA/m2

100 VA/m2

100 m2 x 100 VA/m2 = 10kVA

400 x √3= 14.4A /

• Single items on circuit

• Multiple items on circuit

• Diversity may be applied

Current rating of appliance

Limit by circuit breaker

• Welders• Domestic cooking appliances

Final Sub-circuits

• Arc Welding Machines• Stick• MIG• TIG

Types

1st Machine2nd

3rd

4th

5th + more

100%100%85%70%60%

Highest

Lowest

• Rated Primary Current• Actual Primary Current

• Arc Welding Machines

• Resistance Welding Machines

• Stick• MIG• TIG

Spot welders

Types

• Rated Primary Current• Actual Primary current• Duty Cycle

• Individual Machines

• Variable Operation

• Specific (fixed) Operation

• Seam welders• Auto feed welders• Manual welders• Non-Auto Welders

70%

50%

x Rated Primary Current

Actual Primary current x Multiplier

Very few welders operate at 100% all of the time

• Changing the electrodes• Repositioning the job• Starting a new job

Ratio of ON TIME/OFF TIME in 1 minute

Weld for 30 secondsOff for 30 seconds 30/30 =50% Duty Cycle

• Individual Machines

• Groups of machines

• Variable Operation

• Specific (fixed) Operation

• Seam welders• Auto feed welders• Manual welders• Non-Auto Welders

70%

50%

x Rated Primary Current

Actual Primary current x Multiplier

1st Machine2nd + More

100%60%

Highest

Lowest

Table C4

4.8kW wall oven =6.8kW wall oven =

9kW wall oven + 4.8kW hotplate =

16A20A13.8kW = 40A

TEST