Post on 20-Dec-2015
transcript
ENGR 150Engineering Graphics
REVIEW
Station Point
Vanishing Point
Picture Plane
Horizon Line
Ground Line
a b c
a’ b’c’
1-Point Perspective
Picture Plane
Ground Line
2-Point Perspective
SP
Horizon Line Vanishing Point Vanishing Point
ParallelParallel
Station Point
Picture Plane
Horizon Line
Ground Line
1-Point Perspective
vp
Station Point
Picture Plane
Horizon Line
Ground Line
1-Point Perspective
vp
Isometric
Isometric Ellipse
Isometric Ellipse (4-center method)
1. Draw an isometric equilateral parallelogram with sides equal to diameter of circle.
2. Join the mid-point of each side to the nearer end-point of the opposite side.
3. Draw arcs of radius r and radius R.
r
R
True length line
H1
H
FAF
BH
AH
BF
1 2
True Length line and Point View
• True Length:– Place an auxiliary view
parallel to the line– Project line on to the auxiliary
view.
• Point View:– Find true length first– Place auxiliary view
perpendicular to true length line
– Project line on to 2nd auxiliary view.
H1
H
FAF
BH
AH
BF
1 2
Edge View and True Shape Plane
• Edge View– Draw a line in the plane
parallel to a “folding line”– Project this line into the
adjacent view.– Find a point view of the this
line and project the other points of the plane.
• True Shape– Place an auxiliary view
parallel to the edge view– Project the plane into
auxiliary viewAF
F
H
BF
CH
CF
AH
BH
C1
A1
B1
1HT.L.
12
C2
B2
A2
Angle Between Planes
C
A
D
A
F
H
B
B
D
C
T.L.
E.V
.
E.V.
Exercise
1F
F
H
21
23TS
TS
θ
C
B,D
A,E
B,F
B
A
FE
C D
F
E
CDA,C
A,B
E
F
D
C
DB
A
Intersection and Visibility
AF
CF
BF
DF
CH
BH
AH
DH
F
H
EF
GF
FF
HF
GH FH
EH
HH
F
H
GH lies in front of EF
GH lies on top of EF
Intersection of Line and PlaneCutting Plane Method
AF
F
H
BF
CF
GF
LF
AH
BH
CH
GH
LH
Step 1
Step 2
Step 3
Intersection of Two PlanesCutting Plane Method
BF
F
H
AF
CF
XF
YF
BH
CH
AH
YH
ZH
ZF
XH
BF
F
H
AF
CF
XF
YF
BH
CH
AH
YH
ZH
ZF
XH
a2
c2
b2
d2
500 m a3
c3
500 m
c5
b5
Solution to 6-19
e,f2
500
m
250
m
d4
e4
b,f4
Gradient Problem: solution