Post on 07-Aug-2015
transcript
1: Functions1: Functions
© Christine Crisp
““Teach A Level Maths”Teach A Level Maths”
Vol. 2: A2 Core Vol. 2: A2 Core ModulesModules
Functions
Module C3
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Functions
e.g. and are functions.12)( xxf xxg sin)(
A function is a rule , which calculates values of for a set of values of x.
)(xf
is often replaced by y.)(xf
Another Notation
12: xxf 12)( xxfmeans
is called the image of x)(xf
Functions
)(f 12 xxx )(xf1
0
.
.
2.1...
.
1.5.
.
.
.
.
A few of the possible values of x
3.2...
2..
1..
3.
.
.
.
We can illustrate a function with a diagram
The rule is sometimes called a mapping.
Functions
We say “ real ” values because there is a branch of mathematics which deals with
numbers that are not real.
A bit more jargonTo define a function fully, we need to know the values of x that can be used.
The set of values of x for which the function is defined is called the domain.
In the function any value can be substituted for x, so the domain consists of
all real values of x
2)( xxf
means “ belongs to ”So, means x is any real number
x
stands for the set of all real numbers
We write x
Functions
0)( xf
If , the range consists of the set of y-values, so
)(xfy
Tip: To help remember which is the domain and which the range, notice that d comes
before r in the alphabet and x comes before y.
domain: x-values
range: y-values
e.g. Any value of x substituted into gives a positive ( or zero ) value.
2)( xxf
The range of a function is the set of values given by .
)(xf)(xf
So the range of is2)( xxf
Functions
Tip: To help remember which is the domain and which the range, notice that d comes
before r in the alphabet and x comes before y.
0)( xf
If , the range consists of the set of y-values, so
)(xfy
e.g. Any value of x substituted into gives a positive ( or zero ) value.
2)( xxf
So the range of is2)( xxf
The range of a function is the set of values given by .
)(xf)(xf
domain: x-values
range: y-values
Functions
The range of a function is the set of values given by the rule.
domain: x-values
range: y-values
The set of values of x for which the function is defined is called the domain.
Functions
Solution: The quickest way to sketch this quadratic function is to find its vertex by completing the square.
142 xxy 2)2( xy 4 1
5)2( 2 xy
14)( 2 xxxfe.g. 1 Sketch the function where
and write down its domain and range.
)(xfy
5
2This is a translation from of2xy
)5,2( so the vertex is .
Functions
so the range is
5y
So, the graph of is 142 xxy
The x-values on the part of the graph we’ve sketched go from 5 to 1 . . . BUT we could have drawn the sketch for any values of x.
( y is any real number greater than, or equal to, 5 )
BUT there are no y-values less than 5, . . .
)5,2( x
142 xxy
domain:
So, we get ( x is any real number )
x
Functions
3 xy
domain: x-values
range: y-values3x 0y
e.g.2 Sketch the function where .Hence find the domain and range of .
3)( xxf)(xfy )(xf
0
3
so the graph is:
( We could write instead of y )
)(xf
Solution: is a translation from ofxy )(xfy
Functions
SUMMARY
• To define a function we need a rule and a set of values.
)(xfy • For ,
the x-values form the domain
2)( xxf 2: xxf
• Notation:
means
the or y-values form the range)(xf
e.g. For , the domain isthe range is or
2)( xxf
0y0)( xfx
Functions
(b) xy sin3xy (a)
Exercise
For each function write down the domain and range
1. Sketch the functions where
xxfbxxfa sin)()()()( 3 and
Solution:
)(xfy
range: 11 y
domain:
x domai
n:x
range: y
Functions
3xSo, the domain is
03x 3x
We can sometimes spot the domain and range of a function without a sketch.
e.g. For we notice that we can’t square root a negative number ( at least not if we want a real number answer ) so,
3)( xxf
x + 3 must be greater than or equal to zero.
3xThe smallest value of is zero.Other values are greater than zero.So, the range is
0y
Functions
then,
)(f 3
Suppose and2)( xf x )(xg 3xFunctions of a Function
x is replaced by 3
Functions
)(xgand f
2)( 3
Suppose and2)( xf )(xg
)(f 1
then,
)(f 32)( 191
x 3xFunctions of a Function
x is replaced by 1x is replaced by )(xg
Functions
3x)(xgand f
is “a function of a function” or compound function.
f )(xg
2)( 3x
962 xx
f
2)( 3
Suppose and2)( xf )(xg
)(f 1
then,
)(f 32)( 191
x 3x
We read as “f of g of x” )(xgf
x is “operated” on by the inner function first.
is the inner function and the outer.)(xg )(xf
So, in we do g first. )(xgf
Functions of a Function
Functions
Notation for a Function of a Function
When we meet this notation it is a good idea to change it to the full notation.
is often written as . f )(xg )(xfg
does NOT mean multiply g by f.)(xfg
I’m going to write always !
f )(xg
Functions
Solution:
)()()()( xggxffxgfxfg (iv)(iii)(ii)(i)
2)( 2 xfx
g1
)( e.g. 1 Given that and find x x
fxfg )((i) )(xg
Functions
x
1)(xg
xg
1)(
)()()()( xggxffxgfxfg (iv)(iii)(ii)(i)
2)( 2 xfe.g. 1 Given that and find x x
Solution: fxfg )((i)
)()()()( xggxffxgfxfg (iv)(iii)(ii)(i)
x
f
Functions
x
1)(xgSolution: fxfg )((i)
)()()()( xggxffxgfxfg (iv)(iii)(ii)(i)
2)( 2 xfx
g1
)( e.g. 1 Given that and find x x
f 2
2
x
1
Functions
Solution: fxfg )((i)
)()()()( xggxffxgfxfg (iv)(iii)(ii)(i)
2)( 2 xfx
g1
)( e.g. 1 Given that and find x x
f
x
1)(xg 22
x
1
gxgf )((ii) )(xf
212
x
Functions
)(xf
Solution: fxfg )((i)
)()()()( xggxffxgfxfg (iv)(iii)(ii)(i)
2)( 2 xfx
g1
)( e.g. 1 Given that and find x x
f
x
1)(xg 22
x
1
gxgf )((ii) )(g 22 x
212
x
Functions
22 x)(xf
Solution:
)()()()( xggxffxgfxfg (iv)(iii)(ii)(i)
2)( 2 xfx
g1
)( e.g. 1 Given that and find x x
f
x
1)(xg 22
x
1
gxgf )((ii) )(g
)(xgfN.B. is not the same as )(xfg
fxfg )((i)
2
12
x
212
x
Functions
212
x
2
12
x
Solution:
)()()()( xggxffxgfxfg (iv)(iii)(ii)(i)
2)( 2 xfx
g1
)( e.g. 1 Given that and find x x
f
x
1)(xg 22
x
1
gxgf )((ii) )(xf )(g 22 x
)(xgfN.B. is not the same as )(xfg
fxfg )((i)
Functions
2
12
x
Solution: fxfg )((i)
)()()()( xggxffxgfxfg (iv)(iii)(ii)(i)
2)( 2 xfx
g1
)( e.g. 1 Given that and find x x
f
x
1)(xg 22
x
1
)()( xffxff(iii)
212
x
gxgf )((ii) )(xf )(g 22 x
Functions
22 x
gxgf )((ii) )(xf )(g 22 x
Solution: fxfg )((i)
)()()()( xggxffxgfxfg (iv)(iii)(ii)(i)
2)( 2 xfx
g1
)( e.g. 1 Given that and find x x
f
x
1)(xg 22
x
1
)()()( fxffxff(iii)
212
x
2
12
x
Functions
64 24 xx
gxgf )((ii) )(xf )(g 22 x
Solution: fxfg )((i)
)()()()( xggxffxgfxfg (iv)(iii)(ii)(i)
2)( 2 xfx
g1
)( e.g. 1 Given that and find x x
f
x
1)(xg 22
x
1
)()()( fxffxff(iii) 22 x 2)( 2 22 x
212
x
2
12
x
Functions
gxgf )((ii) )(xf )(g 22 x
Solution: fxfg )((i)
)()()()( xggxffxgfxfg (iv)(iii)(ii)(i)
2)( 2 xfx
g1
)( e.g. 1 Given that and find x x
f
x
1)(xg 22
x
1
)()()( fxffxff(iii) 22 x 2)( 2 22 x
212
x
)()( xggxgg(iv)64 24 xx
2
12
x
Functions
1
x1x
1
gxgf )((ii) )(xf )(g 22 x
Solution: fxfg )((i)
)()()()( xggxffxgfxfg (iv)(iii)(ii)(i)
2)( 2 xfx
g1
)( e.g. 1 Given that and find x x
f
x
1)(xg 22
x
1
)()()( fxffxff(iii) 22 x 2)( 2 22 x
212
x
)()( xggxgg(iv)
g
xg
1)( e.g. 1 Given that and find x
x64 24 xx
2
12
x
Functions
gxgf )((ii) )(xf )(g 22 x
Solution: fxfg )((i)
)()()()( xggxffxgfxfg (iv)(iii)(ii)(i)
2)( 2 xfx
g1
)( e.g. 1 Given that and find x x
f
x
1)(xg 22
x
1
)()()( fxffxff(iii) 22 x 2)( 2 22 x
212
x
)()( xggxgg(iv)
g
xg
1)( e.g. 1 Given that and find
x
1 1
x1
x64 24 xx
2
12
x
Functions
SUMMARY• A compound function is a function of a
function.
• It can be written as which means)(xfg .)(xgf
• is not usually the same as )(xgf .)(xfg
• The inner function is .)(xg
• is read as “f of g of x”. )(xgf
FunctionsExercise
,1)( 2 xxf
1. The functions f and g are defined as follows:
(a) The range of f is
Solution:
x 0x,
1)(
xxg
(a) What is the range of f ?
(b) Find (i) and (ii))(xfg )(xgf
1y
xf1
11
2
x
12xg1
12 x
(b) (i)
)(xgf)(xfg
(ii) )(xfg)(xgf
112
x
Functions
Periodic FunctionsFunctions whose graphs have sections which repeat are called periodic functions.
e.g.xy cos
This has a period of 3.
repeats every radians.
xcos2
It has a period of 2
Functions
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Functions
Some functions are even
Even functions are symmetrical about the y - axis
e.g. 2)( xxf
xxf cos)(
So, )()( xfxf e.g.
)2()2( ff
)()( ff
e.g.
Functions
Others are odd
Odd functions have 180 rotational symmetry about the origin
e.g.3)( xxf
xxf sin)(
)()( xfxf e.g.
)2()2( ff
e.g.
22 ff
Functions
Many functions are neither even nor odd e.g.
xxxf 2)( 2
Try to sketch one even function, one odd and one that is neither. Ask your partner to check.
Functions