Lesson 14: Secant Lines; Secant Lines That Meet Inside a Circle

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NYS COMMON CORE MATHEMATICS CURRICULUM M5 Lesson 14

GEOMETRY

Lesson 14: Secant Lines; Secant Lines That Meet Inside a Circle

180

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Lesson 14: Secant Lines; Secant Lines That Meet Inside a

Circle

Student Outcomes

Students understand that an angle whose vertex lies in the interior of a circle intersects the circle in two points

and that the edges of the angles are contained within two secant lines of the circle.

Students discover that the measure of an angle whose vertex lies in the interior of a circle is equal to half the

sum of the angle measures of the arcs intercepted by it and its vertical angle.

Lesson Notes

Lesson 14 begins the study of secant lines. The study actually began in Lessons 4โ€“6 with inscribed angles, but we did not

call the lines secant then. Therefore, students have already studied the first case, lines that intersect on the circle. In

this lesson, students study the second case, secants intersecting inside the circle. The third case, secants intersecting

outside the circle, is introduced in Lesson 15.

Classwork

Opening Exercise (5 minutes)

This exercise reviews the relationship between tangent lines and inscribed angles, preparing students for work in

Lesson 14. Have students work on this exercise individually, and then compare answers with a neighbor. Finish with a

class discussion.

Opening Exercise

๐‘ซ๐‘ฉ โƒก is tangent to the circle as shown.

a. Find the values of ๐’‚ and ๐’ƒ.

๐’‚ = ๐Ÿ๐Ÿ‘, ๐’ƒ = ๐Ÿ–๐ŸŽ

b. Is ๐‘ช๐‘ฉฬ…ฬ… ฬ…ฬ… a diameter of the circle? Explain.

No, if ๐‘ช๐‘ฉฬ…ฬ… ฬ…ฬ… was a diameter, then ๐’Žโˆ ๐‘ช๐‘ฌ๐‘ฉ would be ๐Ÿ—๐ŸŽยฐ.

NYS COMMON CORE MATHEMATICS CURRICULUM M5 Lesson 14

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Lesson 14: Secant Lines; Secant Lines That Meet Inside a Circle

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Discussion (10 minutes)

In this discussion, we remind students of the definitions of tangent and secant lines and

then have students draw circles and lines to see the different possibilities of where

tangent and secant lines can intersect with respect to a circle. Students should classify

and draw the sketches called for and talk about why the classifications were chosen.

Draw a circle and a line that intersects the circle.

Students draw a circle and a line.

Have students tape their sketches to the board.

Letโ€™s group together the diagrams that are alike.

Students should notice that some circles have lines that intersect the circle twice and others only touch

the circle once, and students should separate them accordingly.

Explain how the groups are different.

A line and a circle in the same plane that intersect can intersect in one or two points.

Does anyone know what we call each of these lines?

A line that intersects a circle at exactly two points is called a secant line.

A line in the same plane that intersects a circle at exactly one point is called a tangent line.

Label each group of diagrams as secant lines and tangent lines. Then, as a class, write your own definition of

each.

SECANT LINE: A secant line to a circle is a line that intersects a circle in exactly two points.

TANGENT LINE: A tangent line to a circle is a line in the same plane that intersects the circle in one and

only one point.

This lesson focuses on secant lines. We studied tangent lines in Lessons 11โ€“13.

Starting with a new piece of paper, draw a circle and draw two secant lines. (Check to make sure that students

are drawing two lines that each intersects the circle twice. This is an informal assessment of their

understanding of the definition of a secant line.)

Students draw a circle and two secant lines.

Again, have students tape their sketches to the board.

Letโ€™s group together the diagrams that are alike.

Scaffolding:

Post the theorem definitions

from previous lessons in this

module on the board so that

students can easily review

them if necessary. Add

definitions and theorems as

they are studied.

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NYS COMMON CORE MATHEMATICS CURRICULUM M5 Lesson 14

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Students should notice that some lines intersect outside of the circle, others inside the circle, others on the circle, and

others are parallel and do not intersect. Teachers may want to have a case of each prepared ahead of time in case all

are not created by students.

We have four groups. Explain the differences among the groups.

Some lines intersect outside of the circle, others inside the circle, others on the circle, and others are

parallel and do not intersect.

Label each group as intersect outside the circle, intersect inside the circle, intersect on the circle, and parallel.

Show students that the angles formed by intersecting secant lines have edges that are contained in the secant lines.

Today, we will talk about three of the cases of secant lines of a circle and the angles that are formed at the

point of intersection.

Exercises 1โ€“2 (5 minutes)

Exercises 1โ€“2 deal with secant lines that are parallel and secant lines that intersect on the circle (Lessons 4โ€“6). When

exercises are presented, students should realize that we already know how to determine the angles in these cases.

Exercises 1โ€“2

1. In circle ๐‘ท, ๐‘ท๐‘ถฬ…ฬ… ฬ…ฬ… is a radius, and ๐’Ž๐‘ด๏ฟฝฬ‚๏ฟฝ = ๐Ÿ๐Ÿ’๐Ÿยฐ. Find ๐’Žโˆ ๐‘ด๐‘ถ๐‘ท, and explain how

you know.

๐’Žโˆ ๐‘ด๐‘ถ๐‘ท = ๐Ÿ๐Ÿ—ยฐ

Since ๐‘ท๐‘ถฬ…ฬ… ฬ…ฬ… is a radius and extends to a diameter, the measure of the arc

intercepted by the diameter is ๐Ÿ๐Ÿ–๐ŸŽยฐ. ๐’Ž๐‘ด๏ฟฝฬ‚๏ฟฝ = ๐Ÿ๐Ÿ’๐Ÿยฐ, so the arc intercepted by

โˆ ๐‘ด๐‘ถ๐‘ท is ๐Ÿ๐Ÿ–๐ŸŽยฐ โˆ’ ๐Ÿ๐Ÿ’๐Ÿยฐ or ๐Ÿ‘๐Ÿ–ยฐ. โˆ ๐‘ด๐‘ถ๐‘ท is inscribed in this arc, so its measure is

half the degree measure of the arc or ๐Ÿ๐Ÿ

(๐Ÿ‘๐Ÿ–ยฐ) = ๐Ÿ๐Ÿ—ยฐ.

2. In the circle shown, ๐’Ž๐‘ช๏ฟฝฬ‚๏ฟฝ = ๐Ÿ“๐Ÿ“ยฐ. Find ๐’Žโˆ ๐‘ซ๐‘ฌ๐‘ญ and ๐’Ž๐‘ฌ๏ฟฝฬ‚๏ฟฝ. Explain your answer.

๐’Žโˆ ๐‘ซ๐‘ฌ๐‘ญ = ๐Ÿ๐Ÿ•. ๐Ÿ“ยฐ

๐’Ž๐‘ฌ๏ฟฝฬ‚๏ฟฝ = ๐Ÿ“๐Ÿ“ยฐ

๐’Ž๐‘ช๏ฟฝฬ‚๏ฟฝ = ๐’Ž๐‘ซ๏ฟฝฬ‚๏ฟฝ and ๐’Ž๐‘ซ๏ฟฝฬ‚๏ฟฝ = ๐’Ž๐‘ฌ๏ฟฝฬ‚๏ฟฝ because arcs between parallel lines are equal

in measure.

By substitution, ๐’Ž๐‘ฌ๏ฟฝฬ‚๏ฟฝ = ๐Ÿ“๐Ÿ“ยฐ.

๐’Ž๐‘ซ๏ฟฝฬ‚๏ฟฝ = ๐Ÿ“๐Ÿ“ยฐ, so ๐’Žโˆ ๐‘ซ๐‘ฌ๐‘ญ =๐Ÿ๐Ÿ

(๐Ÿ“๐Ÿ“ยฐ) = ๐Ÿ๐Ÿ•. ๐Ÿ“ยฐ because it is inscribed in a ๐Ÿ“๐Ÿ“ยฐ arc.

NYS COMMON CORE MATHEMATICS CURRICULUM M5 Lesson 14

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Example (12 minutes)

In this example, students are introduced for the first time to secant lines that intersect inside a circle.

Example

a. Find ๐’™. Justify your answer.

๐Ÿ–๐ŸŽยฐ. If you draw โ–ณ ๐‘ฉ๐‘ซ๐‘ฎ, ๐’Žโˆ ๐‘ซ๐‘ฉ๐‘ฎ = ๐Ÿ๐ŸŽยฐ and

๐’Žโˆ ๐‘ฉ๐‘ซ๐‘ฎ = ๐Ÿ”๐ŸŽยฐ because they are half of the measures of their

inscribed arcs. That means ๐’Žโˆ ๐‘ฉ๐‘ฎ๐‘ซ = ๐Ÿ๐ŸŽ๐ŸŽยฐ because the

sums of the angles of a triangle total ๐Ÿ๐Ÿ–๐ŸŽยฐ. โˆ ๐‘ซ๐‘ฎ๐‘ฉ and โˆ ๐‘ฉ๐‘ฎ๐‘ฌ

are supplementary, so ๐’Žโˆ ๐‘ฉ๐‘ฎ๐‘ฌ = ๐Ÿ–๐ŸŽยฐ.

What do you think the measure of โˆ ๐ต๐บ๐ธ is?

Responses will vary, and many will just guess.

This is not an inscribed angle or a central angle, and the chords are not congruent, so students will not

actually know the answer. That is what we want them to realizeโ€”they do not know.

Is there an auxiliary segment you could draw that would help determine the measure of โˆ ๐ต๐บ๐ธ?

Draw chord ๐ต๐ทฬ…ฬ… ฬ…ฬ… .

Can you determine any of the angle measures in โ–ณ ๐ต๐ท๐บ? Explain.

Yes, all of them. ๐‘šโˆ ๐ท๐ต๐ถ = 20ยฐ because it is half of the degree measure of the intercepted arc, which

is 40ยฐ. ๐‘šโˆ ๐ต๐ท๐ธ = 60ยฐ because it is half of the degree measure of the intercepted arc, which is 120ยฐ.

๐‘šโˆ ๐ท๐บ๐ต = 100ยฐ because the sum of the angles of a triangle are 180ยฐ.

Does this help us determine ๐‘ฅ?

Yes, โˆ ๐ท๐บ๐ต and โˆ ๐ต๐ท๐ธ are supplementary, so their sum is 180ยฐ. That means ๐‘šโˆ ๐ต๐บ๐ธ = 80ยฐ.

The angle โˆ ๐ต๐บ๐ธ in part (a) above is often called a secant angle because its sides are contained in two secants

of the circle such that each side intersects the circle in at least one point other than the angleโ€™s vertex.

Is the vertical angle โˆ ๐ท๐บ๐ถ also a secant angle?

Yes, ๐บ๐ท and ๐บ๐ถ intersect the circle at points ๐ท and ๐ถ, respectively.

Letโ€™s try another problem. Have students work in groups to go through the same process

to determine ๐‘ฅ.

b. Find ๐’™.

๐Ÿ‘๐Ÿ. ๐Ÿ“ยฐ

Scaffolding:

Advanced students should

determine ๐‘ฅ and the

general result

independently.

Which auxiliary segments

will help determine ๐‘ฅ?

(Segments ๐ต๐ท and ๐ธ๐ถ)

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Can we determine a general result?

What equation would represent the result we are looking to

prove?

๐‘ฅ =๐‘Ž+๐‘

2

Draw ๐ต๐ทฬ…ฬ… ฬ…ฬ… .

Students draw chord ๐ต๐ทฬ…ฬ… ฬ…ฬ… .

What are the measures of the angles in โ–ณ ๐ต๐ท๐บ?

๐‘šโˆ ๐บ๐ต๐ท =12

๐‘Ž

๐‘šโˆ ๐ต๐ท๐บ =12

๐‘

๐‘šโˆ ๐ต๐บ๐ท = 180 โˆ’12

๐‘Ž โˆ’12

๐‘

What is ๐‘ฅ?

๐‘ฅ = 180 โˆ’ (180 โˆ’12

๐‘Ž โˆ’12

๐‘)

Simplify that.

๐‘ฅ =12

๐‘Ž +12

๐‘ =๐‘Ž+๐‘

2

What have we just determined? Explain this to your neighbor.

The measure of an angle whose vertex lies in the interior of

a circle is equal to half the sum of the angle measures of

the arcs intercepted by it and its vertical angle.

Does this formula also apply to secant lines that intersect on the

circle (an inscribed angle) as in Exercise 1?

Look at Exercise 1 again.

What are the angle measures of the two intercepted arcs?

There is only one intercepted arc, and its measure is 38ยฐ.

The vertical angle does not intercept an arc since its vertex lies on

the circle. Suppose for a minute, however, that the arc is that vertex point. What would the angle measure of

that arc be?

It would have a measure of 0ยฐ.

Does our general formula still work using 0ยฐ for the measure or the arc given by the vertical angle?

38ยฐ + 0ยฐ

2= 19ยฐ. It does work.

Explain this to your neighbor.

The measure of an inscribed angle is a special case of the general formula when suitably interpreted.

We can state the results of part (b) of this example as the following theorem:

SECANT ANGLE THEOREMโ€”INTERIOR CASE: The measure of an angle whose vertex lies in the interior of a circle is equal to half

the sum of the angle measures of the arcs intercepted by it and its vertical angle.

NYS COMMON CORE MATHEMATICS CURRICULUM M5 Lesson 14

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Exercises 3โ€“7 (5 minutes)

The first three exercises are straightforward, and all students should be able to use the formula found in this lesson to

solve. The final problem is a little more challenging. Assign some students only Exercises 3โ€“5 and others 5โ€“7. Have

students complete these individually and then compare with a neighbor. Walk around the room, and use this as an

informal assessment of student understanding.

Exercises 3โ€“7

In Exercises 3โ€“5, find ๐’™ and ๐’š.

3.

4.

๐’™ = ๐Ÿ๐Ÿ๐Ÿ“, ๐’š = ๐Ÿ”๐Ÿ“

๐’™ = ๐Ÿ“๐Ÿ—, ๐’š = ๐Ÿ•๐Ÿ”

5.

๐’™ = ๐Ÿ‘๐Ÿ’, ๐’š = ๐Ÿ๐Ÿ’๐Ÿ”

6. In the circle shown, ๐‘ฉ๐‘ชฬ…ฬ… ฬ…ฬ… is a diameter. Find ๐’™ and ๐’š.

๐’™ = ๐Ÿ๐Ÿ’, ๐’š = ๐Ÿ“๐Ÿ‘

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7. In the circle shown, ๐‘ฉ๐‘ชฬ…ฬ… ฬ…ฬ… is a diameter. ๐‘ซ๐‘ช: ๐‘ฉ๐‘ฌ = ๐Ÿ: ๐Ÿ. Prove ๐’š = ๐Ÿ๐Ÿ–๐ŸŽ โˆ’๐Ÿ‘๐Ÿ

๐’™ using a two-column proof.

๐‘ฉ๐‘ชฬ…ฬ… ฬ…ฬ… is a diameter of circle ๐‘จ Given

๐’Žโˆ ๐‘ซ๐‘ฉ๐‘ช = ๐’™ยฐ Given

๐’Ž๐‘ซ๏ฟฝฬ‚๏ฟฝ = ๐Ÿ๐’™ยฐ Arc is double angle measure of

inscribed angle

๐’Ž๐‘ฉ๏ฟฝฬ‚๏ฟฝ = ๐’™ยฐ ๐‘ซ๐‘ช: ๐‘ฉ๐‘ฌ = ๐Ÿ: ๐Ÿ

๐’Ž๐‘ฉ๐‘ซ๏ฟฝฬ‚๏ฟฝ = ๐’Ž๐‘ฉ๐‘ฌ๏ฟฝฬ‚๏ฟฝ = ๐Ÿ๐Ÿ–๐ŸŽยฐ Semicircle measures ๐Ÿ๐Ÿ–๐ŸŽยฐ

๐’Ž๐‘ซ๏ฟฝฬ‚๏ฟฝ = ๐Ÿ๐Ÿ–๐ŸŽยฐ โˆ’ ๐Ÿ๐’™ยฐ Arc addition

๐’Ž๐‘ฌ๏ฟฝฬ‚๏ฟฝ = ๐Ÿ๐Ÿ–๐ŸŽยฐ โˆ’ ๐’™ยฐ Arc addition

๐’Žโˆ ๐‘ฉ๐‘ญ๐‘ซ =๐Ÿ๐Ÿ

(๐Ÿ๐Ÿ–๐ŸŽยฐ โˆ’ ๐Ÿ๐’™ยฐ + ๐Ÿ๐Ÿ–๐ŸŽยฐ โˆ’ ๐’™ยฐ) Measure of angle whose vertex lies in a circle is half the angle

measures of arcs intercepted by it and its vertical angles

๐’šยฐ = ๐Ÿ๐Ÿ–๐ŸŽยฐ โˆ’๐Ÿ‘๐Ÿ

๐’™ยฐ Substitution and simplification

Closing (3 minutes)

Project the circles below on the board, and have a class discussion with the following questions.

What types of lines are drawn through the three circles?

Secant lines

Explain the relationship between the angles formed by the secant lines and the intercepted arcs in the first two

circles.

The first circle has angles with a vertex inside the circle. The measure of an angle whose vertex lies in

the interior of a circle is equal to half the sum of the angle measures of the arcs intercepted by it and its

vertical angle.

The second circle has an angle on the vertex, an inscribed angle. Its measure is half the angle measure

of its intercepted arc.

How is the third circle different?

The lines are parallel, and no angles are formed. The arcs are congruent between the lines.

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Exit Ticket (5 minutes)

Lesson Summary

THEOREM:

SECANT ANGLE THEOREMโ€”INTERIOR CASE: The measure of an angle whose vertex lies in the interior of a

circle is equal to half the sum of the angle measures of the arcs intercepted by it and its vertical angle.

Relevant Vocabulary

TANGENT TO A CIRCLE: A tangent line to a circle is a line in the same plane that intersects the circle in one

and only one point. This point is called the point of tangency.

TANGENT SEGMENT/RAY: A segment is a tangent segment to a circle if the line that contains it is tangent to

the circle and one of the end points of the segment is a point of tangency. A ray is called a tangent ray

to a circle if the line that contains it is tangent to the circle and the vertex of the ray is the point of

tangency.

SECANT TO A CIRCLE: A secant line to a circle is a line that intersects a circle in exactly two points.

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Name Date

Lesson 14: Secant Lines; Secant Lines That Meet Inside a Circle

Exit Ticket

1. Lowell says that ๐‘šโˆ ๐ท๐น๐ถ =12

(123) = 61ยฐ because it is half of the intercepted arc. Sandra says that you cannot

determine the measure of โˆ ๐ท๐น๐ถ because you do not have enough information. Who is correct and why?

2. If ๐‘šโˆ ๐ธ๐น๐ถ = 9ยฐ, find and explain how you determined your answer.

a. ๐‘šโˆ ๐ต๐น๐ธ

b. ๐‘š๐ต๏ฟฝฬ‚๏ฟฝ

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Exit Ticket Sample Solutions

1. Lowell says that ๐’Žโˆ ๐‘ซ๐‘ญ๐‘ช =๐Ÿ๐Ÿ

(๐Ÿ๐Ÿ๐Ÿ‘) = ๐Ÿ”๐Ÿยฐ because it is half of the intercepted arc. Sandra says that you cannot

determine the measure of โˆ ๐‘ซ๐‘ญ๐‘ช because you do not have enough information. Who is correct and why?

Sandra is correct. We would need more information to determine

the answer. Lowell is incorrect because โˆ ๐‘ซ๐‘ญ๐‘ช is not an inscribed

angle.

2. If ๐’Žโˆ ๐‘ฌ๐‘ญ๐‘ช = ๐Ÿ—๐Ÿ—ยฐ, find and explain how you determined your

answer.

a. ๐’Žโˆ ๐‘ฉ๐‘ญ๐‘ฌ

๐Ÿ–๐Ÿยฐ, ๐’Žโˆ ๐‘ฌ๐‘ญ๐‘ช + ๐’Žโˆ ๐‘ฉ๐‘ญ๐‘ฌ = ๐Ÿ๐Ÿ–๐ŸŽยฐ (supplementary angles), so ๐Ÿ๐Ÿ–๐ŸŽยฐ โˆ’ ๐Ÿ—๐Ÿ—ยฐ = ๐’Žโˆ ๐‘ฉ๐‘ญ๐‘ฌ.

b. ๐’Ž๐‘ฉ๏ฟฝฬ‚๏ฟฝ

๐Ÿ‘๐Ÿ—ยฐ, ๐Ÿ–๐Ÿยฐ =๐Ÿ๐Ÿ

(๐’Ž๐‘ฉ๏ฟฝฬ‚๏ฟฝ + ๐Ÿ๐Ÿ๐Ÿ‘ยฐ) using the formula for an angle with vertex inside a circle.

Problem Set Sample Solutions

Problems 1โ€“4 are more straightforward. The other problems are more challenging and could be given as a student

choice or specific problems assigned to different students.

In Problems 1โ€“4, find ๐’™.

1.

2.

๐’™ = ๐Ÿ–๐Ÿ“ ๐’™ = ๐Ÿ”๐Ÿ“

NYS COMMON CORE MATHEMATICS CURRICULUM M5 Lesson 14

GEOMETRY

Lesson 14: Secant Lines; Secant Lines That Meet Inside a Circle

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3.

4.

๐’™ = ๐Ÿ• ๐’™ = ๐Ÿ—

5. Find ๐’™ (๐’Ž๐‘ช๏ฟฝฬ‚๏ฟฝ) and ๐’š (๐’Ž๐‘ซ๏ฟฝฬ‚๏ฟฝ).

๐Ÿ”๐ŸŽ =๐Ÿ

๐Ÿ(๐’š + ๐Ÿ๐ŸŽ)

๐’™ + (๐Ÿ–๐Ÿ“ + ๐’™)

๐Ÿ= ๐Ÿ—๐ŸŽ

๐’™ = ๐Ÿ•๐ŸŽ, ๐’š = ๐Ÿ๐ŸŽ๐ŸŽ

6. Find the ratio of ๐’Ž๐‘ฌ๏ฟฝฬ‚๏ฟฝ: ๐’Ž๐‘ซ๏ฟฝฬ‚๏ฟฝ.

๐Ÿ‘: ๐Ÿ’

NYS COMMON CORE MATHEMATICS CURRICULUM M5 Lesson 14

GEOMETRY

Lesson 14: Secant Lines; Secant Lines That Meet Inside a Circle

191

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This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.

7. ๐‘ฉ๐‘ชฬ…ฬ… ฬ…ฬ… is a diameter of circle ๐‘จ. Find ๐’™.

๐’™ = ๐Ÿ๐ŸŽ๐Ÿ–

8. Show that the general formula we discovered in Example 1 also works for central angles. (Hint: Extend the radii to

form two diameters, and use relationships between central angles and arc measure.)

Extend the radii to form two diameters.

Let the measure of the central angle be equal to ๐’™ยฐ.

The measure ๐‘ฉ๏ฟฝฬ‚๏ฟฝ = ๐’™ยฐ because the angle measure of the arc

intercepted by a central angle is equal to the measure of the

central angle.

The measure of the vertical angle is also ๐’™ยฐ because vertical angles

are congruent.

The angle of the arc intercepted by the vertical angle is also ๐’™ยฐ.

The measure of the central angle is half the sum of the angle

measures of the arcs intercepted by the central angle and its

vertical angle.

๐’™ =๐Ÿ

๐Ÿ(๐’™ + ๐’™)

This formula also works for central angles.