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March 1, 2002 1
(1) Heat Exchanger Types
(2) Heat Exchanger Analysis Methods• Overall Heat Transfer Coefficient
»fouling, enhanced surfaces
• LMTD Method
• Effectiveness-NTU Method
(3) Homework #4
Outline
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Introduction• Heat exchangers are devices that provide the flow
of thermal energy between two or more fluids at different temperatures.
• Used in wide range of applications
• Classified according to:• Recuperators/Regenerators
• Transfer processes: direct and indirect contact
• Construction Geometry: tubes, plates, extended surfaces
• Heat Transfer Mechanisms: single and two phase
• Flow arrangements: parallel, counter, cross-flow
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HX Classifications
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HX Classifications
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Concentric tube (double piped)Heat Exchanger Types
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Concentric tube (double piped)• One pipe is placed concentrically within the
diameter of a larger pipe• Parallel flow versus counter flow
Heat Exchanger Types
Fluid A
Fluid B
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Concentric tube (double piped)• used when small heat transfer areas are
required (up to 50 m2)
• used with high P fluids
• easy to clean (fouling)
• bulky and expensive per unit heat transfer area
• Flexible, low installation cost, simple construction.
Heat Exchanger Types
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Shell and TubeHeat Exchanger Types
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Shell and Tube• most versatile (used in process industries,
power stations, steam generators, AC and refrigeration systems)
• large heat transfer area to volume/weight ratio
• easily cleaned
Heat Exchanger Types
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Compact Heat Exchangers• generally used in gas flow applications
• surface density > 700 m2/m3
• the surface area is increased by the use of fins
• plate fin or tube fin geometry
Heat Exchanger Types
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Compact Heat
Exchangers
Heat Exchanger Types
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Cross Flow• finned versus unfinned
• mixed versus unmixed
Heat Exchanger Types
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Heat Exchanger Types
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Heat Exchanger Types
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Heat Exchanger Applications
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Heat Exchanger Analysis
• Overall Heat Transfer Coefficient
• LMTD
• Effectiveness-NTU
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Overall Heat Transfer Coefficient
hoho
hfw
co
cf
co hAA
RR
A
R
hAUA )(
1
)()()(
11 ,,
The overall coefficient is used to analyze heat ex-changers. It contains the effect of hot and cold side convection, conduction as well as fouling and fins.
factor fouling fR
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Fouling Factors
Heat exchanger surfaces are subject to fouling by fluid impurities, rust formation, or reactions between the fluid and the wall.
factor fouling fR
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Enhanced Surfaces
Fins are often added to the heat exchange surfaces to enhance the heat transfer by increasing the surface area. The overall surface efficiency is:
)(
)1(1
TThAQ
A
A
bo
ff
o
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Enhanced Surfaces
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Log-Mean Temperature DifferenceNeed to relate the total heat transfer rate to inlet and outlet fluid temperatures. Apply energy balance:
)()(
)()(
,,,,,
,,,,,
ociccpcocicc
ohihhphohihh
TTcmiimQ
TTcmiimQ
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Log-Mean Temperature DifferenceWe can also relate the total heat transfer rate to the temperature difference between the hot and cold fluids.
LM
ch
TUAQ
TTTlet
The log mean temperature difference depends on the heat exchanger configuration.
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Apply energy balance:Assume:• insulated• no axial conduction• PE, KE negligible
• Cp constant
• U constant
LMTD Parallel-Flow HX
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LMTD Parallel-Flow HX
)12
12
,
,
/ln(
:get toIntegrate
TT
TTUAQ
TTTTdAUdQ
dTCdTcmdQ
dTCdTcmdQ
ch
ccccpc
hhhhph
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LMTD Parallel-Flow HX
ocohch
icihch
LMLM
TTTTT
TTTTT
TT
TTTTUAQ
,,2,2,2
,,1,1,1
)12
12
:Flow Parallelfor Where
/ln(
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LMTD Counter-Flow HX
Tlm,CF > Tlm,PF
FOR SAME U:
ACF < APF
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LMTD Counter-Flow HX
icohch
ocihch
LMLM
TTTTT
TTTTT
TT
TTTTUAQ
,,2,2,2
,,1,1,1
)12
12
:FlowCounter for Where
/ln(
Tlm,CF > Tlm,PF FOR SAME U: ACF < APF
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LMTD- Multi-Pass and Cross-Flow
CFLMLMLM TFTTUAQ ,
Apply a correction factor to obtain LMTD
t: Tube Side
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LMTD MethodSIZING PROBLEMS:• Calculate Q and the unknown outlet temperature.
• Calculate DTlm and obtain the correction factor (F) if necessary
• Calculate the overall heat transfer coefficient.• Determine A.
The LMTD method is not as easy to use for performance analysis….
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The Effectiveness-NTU Method• If the inlet temperatures are unknown then
the LMTD method requires iteration.
• Preferable to use the -NTU method under these conditions.
• Define Qmax
for Cc < Ch Qmax = Cc(Th,i - Tc,i)
for Ch < Cc Qmax = Ch(Th,i - Tc,i)
or Qmax = Cmin(Th,i - Tc,i)
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The Effectiveness-NTU Method• Now define the heat exchanger effectiveness, .
• The effectiveness is by definition between 0 & 1
• The actual heat transfer rate is:
Q = Cmin(Th,i - Tc,i)
)(
)(
)(
)(
,,min
,,
,,min
,,
max icih
icocc
icih
ohihh
TTC
TTC
TTC
TTC
q
q
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The Effectiveness-NTU Method• For any heat exchanger:
f(NTU,Cmin/Cmax)
• NTU (number of transfer units) designates the nondimensional heat transfer size of the heat exchanger:
minC
UANTU
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The Effectiveness-NTU Method
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The Effectiveness-NTU MethodPERFORMANCE ANALYSIS
• Calculate the capacity ratio Cr = Cmin/Cmax and NTU = UA/Cmin from input data
• Determine the effectiveness from the appropriate charts or -NTU equations for the given heat exchanger and specified flow arrangement.
• When is known, calculate the total heat transfer rate
• Calculate the outlet temperature.
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The Effectiveness-NTU MethodSIZING ANALYSIS
• When the outlet and inlet temperatures are known, calculate
• Calculate the capacity ratio Cr = Cmin/Cmax
• Calculate the overall heat transfer coefficient, U
• When and C and the flow arrangement are known, determine NTU from the -NTU equations.
• When NTU is known, calculate the total heat transfer surface area.
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Homework Number 4COMPLETE PARTs 1&2 BEFORE CLASS ON THURSDAY. WE WILL USE CLASS/LAB TIME ON Tuesday TO WORK ON PARTS 3 and 4.Part 1:Review Chapter 11 of Incropera and Dewitt. Work through Example Problems 11.3, 11.4, 11.5.Part 2:To ventilate a factory building, 5 kg/s of factory air at a temperature of 27 oC is exhausted and an identical flow rate of outdoor air at a temperature of -12 oC is introduced to take its place. To recover some of the heat of the exhaust air, heat exchangers are placed in the exhaust and ventilation air ducts and 2 kg/s of ethylene glycol is pumped between the two heat exchangers. The UA value of both of these crossflow heat exchangers is 6.33 kW/K. What is the temperature of the air entering the factory?
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Homework Number 4Part 3:Calculate the UA value for the cross flow heat exchanger specified above. The heat exchanger is 1m high by 1 m wide by 1 m long (in flow direction) and contains a tube bank heat transfer surface. The ethylene glycol flows through the tubes and the air flow around them (i.e. figure 11.2B in Incropera and Dewitt). The tubes are made of 1" diameter thin walled copper and are mounted in an aligned pattern (3 inches apart center to center – Review tube bank heat transfer data in Chapter 7 of Incropera and Dewitt). Use the data for internal tube heat transfer coefficient given in the Project 4 technical specifications.
Part 4:Calculate the pressure drop for the ethylene glycol and the air. Use the data for ethylene glycol friction factor given in the Project 4 technical specifications.