Pg 30

# 10 .V

, = 6. one [ [ ]

Vz -

. 7 . 3mg [ w ]

at = O.O 94 s2

sigdg= 8±

*

= 7.3÷ [w] - 6.0 ;fE]

÷ 945= 7.33 [ w ] + 6.0 m [ D

to

8=13.3z[w÷

094 s

Er = 141mg , [ w ]

at = / 40 mg [ w ]

Pg 30 # 5

V ,= 10 Ys [ N

Vz = 10 mls [ ST* Acceleration is a change in speed

OR direction

UNIT #1 KINEMATICS The Big 5

Uniform Acceleration

� acceleration is constant

� 5 Kinematic equations...much easier than graphical analysis!

Equation #1

� v-t graph, straight line (uniform acceleration)

� Δd = area under graph Δd=Atriangle + Arectangle

A- .

bh÷tense.Vz .Vw2

A÷st #,

An vi at

Id=th¥ at tv ,at

Eds 'r⇐) at + v , at

= ⇐⇒ at +2£ at

= '⇐€vpattv , At

= that tau ,at tv

,at

= tgvz at ttv ,at

= to at ( k th )Id = (Et¥ at

Equation #2

� we know that

� we can say,

� rearranging, we get

→ >aat=v . IFtaat . Es

Equation #3

� we can use equations (1) and (2) to derive equation (3)

(1) (2)

→ isd

.fntsaI)#sorzgbtetagtlEd =P, at ttsaat

The Big Five

Equation Missing Variable

(1)

(2)

(3)

(4)

(5)

pg -

37

Examples

1. A car accelerates at 3m/s2 from rest for 10s. How far does it travel?

2. A car is moving at 100km/h. It stops in 5.0s.

What is the car’s acceleration?

3.0 mlsh 10.05

: =0 mlsloookmk

1. GRASS

I . Given: Vi . Omls

V¥a =3

.com/s2si2sig

At = laosdigs

ad = ?

Reidy ad

Analysisad=Yatt£aaE

Stepsaol.to#iiosttEoaDfo.oj/d=o+tsL3oOs*1oosYDd=150m

* 2 Given v ,= 100.0km/h

k= 0ms( stopped)

AtisosezsigRequired : £

dis'

Analysisi_jz.T.tcatioo5EtexTog@x6hEnxxtEsvi-27M3hE8.t

-aDt4=27.8 }l 0=27.8 ztalsos)sssigdigsh C5.07%2385.465%2

Homework

� Read 1.5

� p.39#1-6