PRIMING ACTIVITY

DEPARTMENT OF EDUCATION

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Lesson 1: Illustrations of Quadratic Equations

Lesson 2: Solving Quadratic Equations

Extracting Square Roots Factoring Completing the square Using the Quadratic Formula

Lesson 3 : Nature of Roots of Quadratic Equations

Lesson 4: Sums and Product of the Roots of Quadratic Equations

Lesson 5: Equations Transformable to Quadratic Equations (Including Algebraic Equations)

Lesson 6 : Applications of Quadratic Equations and Rational Algebraic Equations

Lesson 7 : Quadratic Inequalities

1.Choose a leader2.Secretary3.2 Presenters

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1. How did you find the product?

2. In finding each product, what mathematics concepts or principles did you apply? Explain how you applied these mathematics concepts or principles?

3. How would you describe the products obtained?

4. Are the products polynomials? If YES, what common characteristics do these polynomials have?

1. How do you describe Linear equation?

2. How are these equations different from those which are linear?

3. What common characteristics do these equations have?

Activity1: Find My RootsDirections: Find the following square roots.

1.) 16

2. ) – 25

3.) 49

4.) – 64

5.) 121

6.) – 289

7.) 0.16

8.) ± 36

9.) 16 25

10.) ± 169 256

= 4

= –5

= 7

= –8

= 11

= – 17

= 0.4

= ± 6

= 4 5

± 13 = 16

Extracting Square RootsQuadratic equations that can be written in the form x2 = k ca be solve by applying the following properties:

1.) If k > 0, then x2 = k has two real solutions or roots: x = ± k 2.) If k = 0, then x2 = k has one real solutions or root: x = 03.) If k < 0, then x2 = k has no real solutions or roots: Examples:

x2 – 16 = 0x2 = 16x = ± 16x = ± 4

x2 + 10 = 10x2 = 10 – 10x2 = 0x = 0

x2 + 9 = 0x2 = –9no real roots

1.) x2 + 8x – 9

x x

Factors of – 9

9 ; -1-9 ; 1

Sum of factors8

-8

+ 9

– 1

OR x2

-9-x

9xx 9

x

-1( x + 9 ) ( x – 1 )

-3 ; 3

0

2.) 3x2 – x – 10

– 30x2

-30x2

=

factors Sum of factors-30x ; x

30x ; -x-15x ; 2x15x ; -2x-6x ; 5x6x ; -5x

-29x29x-13x13x-x x

3x2 – 6x + 5x – 10 (3x2 – 6x) + (5x – 10)3x(x – 2) + 5(x – 2)

OR

3x2

-105x

-6x

x -2

3x

5