Review Chapter 7 Algebra II JEOPARDY Jeopardy Review.

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ReviewReviewChapter 7 Algebra II

JEOPARDY

Jeopardy Review

LogarithmsExponential Growth and

Decay

ExponentialFunctions

Solving Solving LogarithmicLogarithmicEquationsEquations

Solving Solving ExponentialExponentialEquationsEquations

200 200 200 200 200

400 400 400 400 400

600 600 600 600 600

800 800 800 800 800

1000 1000 1000 1000 1000

Logarithms200

log3 (1/9) =

A: -2

Jeopardy Review

Logarithms 400

A: -3

log .001

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Logarithms 600

A: 1.699

Use the change of base formula to evaluate: log6 21

Jeopardy Review

Jeopardy Review

Logarithms800

A: 2 log x + log y – log z

Jeopardy Review

Using the properties of logarithms, expand log (x2y/z)

Logarithms1000

A: log (m4n2/k3)

Write as a single logarithm:

y = 4 log m + 2 log n – 3 log k

S2C13 Jeopardy Review

Exponential Growth & Decay

200

A: 52%

Identify the percent of decay in the equation: y = 6000 (.48)x

S2C13 Jeopardy Review

Exponential Growth & Decay

400

A: y = 22,000 (1.06)x

Write the equation that models exponential growth of 6% per year with a starting population of 22,000.

S2C13 Jeopardy Review

Exponential Growth & Decay

600

A: 2.62 million

Predict the population in the year 2006 if a countries population (in millions) is growing by 4% each year, and is modeled by the equation y = 1.4 (1.04)x where x represents the years after 1990.

S2C13 Jeopardy Review

Exponential Growth & Decay

800

A: 2022

A city’s population is modeled by the equation

y = 14,000 (.98)x, where x represents the number of years after the year 2000. Predict during which year the population will decrease to 8,900.

S2C13 Jeopardy Review

Exponential Growth & Decay

1000

A: a) growth b) 2.58 c) 158%

In the equation: y = 13 (2.58)x, Identify

a) Growth or decay

b) Growth or decay factor

c) Percent of growth or decay

S2C13 Jeopardy Review

Exponential Functions 200

A: y = ½, 1, and 4

Evaluate y = 2x for x = -1, 0, and 2.

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Exponential Functions 400

A: y = (7/16)(2)x

Write the equation to describe the exponential function with a base of 2, passing through the point (4,7).

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Exponential Functions 600

A: 20,000 e^(.06*5) = $26,977.18

Find the amount of money you have if you invest $20,000 for 5 years at 6% compounded continuously.

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Exponential Functions800

A: 3000 e (.05)(3) = $3485.50

Find the amount of money you have if you invest $3000 for 3 years at 5% compounded continuously.

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Exponential Functions 1000

A: 2500 = 2000 e (.03t) t = 7.44 years

You invest $2000 in an account earning 3% interest compounded continuously. How long will it be until you have $2500?

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Solving Logarithmic Equations

200

A: log28 = 3

2 log24 – log22 =

S2C13 Jeopardy Review

Solving Logarithmic Equations

400

A: 1

log9 √81

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Solving Logarithmic Equations

600

A: 102 = 5x x = 20

Solve for x.

log 5x = 2

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Solving Logarithmic Equations

800

A: ln (3x/2) = 6 x = 268.953

Solve for x.

ln 3 + ln x – ln 2 = 6

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Solving Logarithmic Equations

1000

A: ln (x2 + 3x) = 2 x = 1.6, using quadratic formula

ln x + ln (x + 3) = 2

S2C13 Jeopardy Review

Solving Exponential Equations

200

A: 7 or -7

x2 = 49

S2C13 Jeopardy Review

Solving Exponential Equations

400

A: x = 11.18

4x⅔ = 20

S2C13 Jeopardy Review

Solving Exponential Equations

600

A: x = 2.096

3x – 4 = 6

S2C13 Jeopardy Review

Solving Exponential Equations

800

A: m = 16

4√m3 + 2 = 10

S2C13 Jeopardy Review

e4x = 10

Solving Exponential Equations

1000

A: 4x = ln 10 x = .576S2C13 Jeopardy Review