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Centres at: MUKHERJEE NAGAR MUNIRKA UTTAM NAGAR DILSHAD GARDEN ROHINI BADARPUR JAIPUR GURGAON LAXMI NAGARGHAZIABAD NOIDA MEERUT VARANASI ROHTAK PANIPAT SONEPAT PATNA AGRA CHANDIGARH LUCKNOW ALLAHABAD
SBI ASSOCIATE JUNIOR ASST - 2 [PH-I] (SOLUTION)
MATHS31. (2) (12 × 19) + (13 × 8) = (15 × 14) + ?
228 + 104 = 210 + x332 = 210 + xx = 122
32. (3) 15% of 524 – 2% of 985 + ? = 20%of 423
5 2 20524 985 423
100 100 100x
78.6 – 19.7 + x = 84.6–19.7 + x = 84.6 – 78.6x = 84.6 – 78.6 + 19.7x = 25.7
33. (3) 1521 225 ?
2 2(39) (15) x
39 + 15 = x54 = x
34. (1) (7)8.9 ÷ (343)1.7 × (49)4.8 = 7?
(7)8.9 ÷ (73)1.7 × (72)4.8 = 7x
(7)8.9 ÷ (7)5.1 × (7)9.6 = 7x
8.99.6
5.1
(7)(7) 7
(7)x
(7)8.9 × (7)–5.1 × (7)9.6 = 7x(7)13.4 = (7)xx = 13.4
35. (1) 152 × 8 = (228 ÷ 19)2 = ?
1216 + 228 22919 19
= x
1216 + 144 = xx = 1360
36. (2) 417.25 – 41.72 – 4.53 = ?417.25 – 46.25 = x371.00 = xx = 371
37. (4) 72 + 34 – 43 = ? – 112
49 + 81 – 64 = x – 121130 – 64 = x – 12166 + 121 = xx = 187
38. (1) (504.14 ÷ 14) ÷ 13) = ?504.14
14 13 100x
x = 277100
x = 2.7739. (5) 342 ÷ 6 × 28 = 1099 + ?
3426 × 28 = 1099 + x
1596 = 1099 + xx = 8497
40. (5)15 of
27 of
83 of 4095 = ?
15 ×
27 ×
83 × 4095 = x
x = 62441. (3)
Hence, the wrong number is 38.Right number = 12 × 3 + 3 = 36 +3 = 39
42. (3)
Hence, the wrong number is 56.Right number= 32 + (5)2
= 32 + 25= 57
43. (5)
Hence, the wrong number is 78.Right number = 59 + 19 = 78
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Centres at: MUKHERJEE NAGAR MUNIRKA UTTAM NAGAR DILSHAD GARDEN ROHINI BADARPUR JAIPUR GURGAON LAXMI NAGARGHAZIABAD NOIDA MEERUT VARANASI ROHTAK PANIPAT SONEPAT PATNA AGRA CHANDIGARH LUCKNOW ALLAHABAD
44. (4)
So, the wrong number is 32.Right number= 9 × 2 + 2 × 6= 18 + 12= 30
45. (2)
So, the wrong number is 34650.Right number = 17325 × 3 = 51975
46. (1) According to the question,Average age of man and his twin sons = 30Total age = 30 × 3 = 90 yrAccording to the question,Ratio of father and one son = 5 : 2Ratio of father and both thesons = 5 : 2 : 2(As sons are born on the same day)5x + 2x + 2x = 90 or 9x = 90x = 10Age of father = 5 × 10 = 50 yr
47. (4) Let usual speed and usual timetaken by the jogger are x and t,respectively. Let his new speed x.Then
xt = x' 34 t x =
34 x' x =
43 x
Thus, he has to increase hisspeed by43 100%x x
x
i.e. 1
33 %3
48. (4) Let quantitites of two types of teacosting ` 18 per kg and ` 20 perkg be 5x kg and 3x kg respectively.Then,CP of tea = 18 × 5x + 20 × 3x
= 90x + 60x= 150x
SP of tea = 21 × 8x = 168xProfit per cent
= 168 150100%
150x x
x
= 18150× 100% = 12%
49. (2) Let sum = P, then for 20 yr,SI = (3P – P) = 2P
2P = P × R ×20
100
2 = R5 R = 10%
Again, for another time (T),SI = (2P – P) = P
P = P ×10 × T
100 T = 10 yrsFast track methed:-Here, n = 3, m = 2, T1 = 20 yr
T2 = m –1n –1 × T1
= 2 13 1
× 20 = 10 yr
50. (3) Given, P = 185220, R = 5%(increases)and n = 3 yrAcording to the formula,
Population n yr ago = 2
PR
1+100
(by Technique 5)
= 3
1855205
1100
= 185220
21 21 2120 20 20
= 85220 20 20 2021 21 21
= 20 × 20 × 20 × 20= 160000
51. (4) 4 leaps of cat = 3 leaps of dog
1 leap of cat = 34 leap of dog
Cat takes 5 leaps feor every 4 leaps of dogRequired ratio= (5 × Cat's leap) : (4 × Dog's leap)
= 3
5 dog's leap4
: (4 × Dog's leap)
= 15 : 16Direct Approach
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Centres at: MUKHERJEE NAGAR MUNIRKA UTTAM NAGAR DILSHAD GARDEN ROHINI BADARPUR JAIPUR GURGAON LAXMI NAGARGHAZIABAD NOIDA MEERUT VARANASI ROHTAK PANIPAT SONEPAT PATNA AGRA CHANDIGARH LUCKNOW ALLAHABAD
52. (3) Let the container initally contains16L of liquid.Let a L of liquid be compressing water.Quantity of water in the new mixture
= 6a
6 – + a16
L
Quantity of milk in the new mixture
= 10a
10 –16
L
According to the question,
6 – 6a16 + a = 10 × 10a
16 96 – 6a + 16a = 160 – 10a 96 + 10a = 160 – 10a 20a = 64
a = 6420 = 16
5Part of mixture replaced
= 1 1616 5 = 1
553. (2) Let age of Purvi = x yr
Then, age of Anil = 1.5x yrAccording to the question,1.5 8 25
8 18xx
27x + 144 = 25x + 200
x = 562
= 28
54. (4) Given, M1 = 120, M2 = 120 – xD1 = 64, D2 = 60
W1 = 23
and W2 = 13
According to the formula,
2 21 1
1 2
M DM DW W
120 64 (120 ) 602 13 3
x
120 64
(120 )2 60
x
(120 – x) = 64x = 120 – 64 = 56Now, 56 men can discharged tofinish the work in time.
55. (2) Let the certain distance be d andtime t.Now, by given condition,d3 = (t + 15) min = (t +15)
60 h
20d = t + 15 t = 20d – 15
and d4 = (t – 15) min
= (t –15)
60 h
15d = t – 15 t = 15d + 15From Eqs (i) and (ii), we get20d – 15 = 5d + 15 5d = 30d = 6 km
56. (3) Relative speed of train= Speed of train + Speed of car 90 = Speed of train + 15Speed of train= 90 – 15 = 75 km/hr
57. (1) Given,Summer's speed in still water= x = 9 km/hRate of stream = y = 6 km/hSpeed of downstream= x + y = 9 + 6 = 15 km/h
58. (3) There is a 7 digit telephonenumber but exreme right andextreme left positions are fixed.i.e. 6 × × × × × 5i.e. Required number of ways= 8 × 7 × 6 × 5 × 4 = 6720
59. (2) Required probabilityGiven, n = 5 and r = 3
Then, success P = 34
Failure, q = 1 – 34 = 1
4Man hit the target thrice
=5C3
3 23 14 4 + 5C4
33 14 4 + 5C5
534
= 2701024 + 405
1024 + 2431024 = 918
1024 = 459512
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Centres at: MUKHERJEE NAGAR MUNIRKA UTTAM NAGAR DILSHAD GARDEN ROHINI BADARPUR JAIPUR GURGAON LAXMI NAGARGHAZIABAD NOIDA MEERUT VARANASI ROHTAK PANIPAT SONEPAT PATNA AGRA CHANDIGARH LUCKNOW ALLAHABAD
60. (c) The bells will toll together aftertime in seconds equal to the LCMof 9, 6, 4, 10 and 8.LCM of 9, 6, 5, 10 and 8 is
LCM = 2 × 2 × 3 × 3 × 5 × 2 = 360In one hour, the rings will toll
together 3600360 times = 10 times
61. (1) Total length of roads in 2006 fromthe bar garp is 3000,000 kms. Fromthe pie chart the proportion oflength of highways in 2006 is 86%.Hence the length of highways in2006 =3000,00 × 86%=2580,000 kms
62. (2) From the pie-chart, it can be seenthat the highways constitute 86%and urban roads constitute 7% ofthe total road lengths. Hence, theratio of Highways to Urban Roads
is 786
12 : 163. (3) Assessment value of Highways in 2006
= 0.86 × 3,0000 × 1.5 lakh= ` 3870000 lakh
Assessment value of Urban Roads in 2006=0.07 × 3,000,000 × 1 lakh= ` 210000 lakh
Assessment value of Project Roads in 2006= 0.07 × 3,000,000 × 0.75 lakh= ` 157500 lakh
Total value= 3870000 + 210000 + 157500= ` 4237500 lakh
64. (1) In the year 2003, the total length was25,00,000 kms and the highwaysformed 80% of the same, which isequal to 20,00,000 kms. The highwayswere 25,80,000 kms in the year 2006.Hence, the increase in the length ofhighways was (25,80,000 – 20,00,000)= 5,80,000 kms.Thus, the increase in percentageterms
= 000,00,20000,80,5
× 100 = 29%
65. (2) One knows that for every % theangle substended is 3.6 degreesin a pie-chart. Thus, theproportion of the Urban Roads
from the year would be 6.372
= 20%.
In the year 2002, the total roadlength as can be seen from thebar chart = 24,00,000 kms. Thus20% of 24,00,000 = 480,000 kms.
REASONING(66-70):66. (1) Find the corresponding letters
from the right.67. (5) The first letter follows +1, +2, +3,
+4, ... The second follows +2, +3,+4, +5, ...
68. (2) Move two letters backward in thealphabetical series for eachcorresponding letter.
69. (5)
Hence P is either son or daughterof Q.
70. (3)
(71-74):ze lo ka gi = must save some money
... (i)fe ka so ni = he made good money
... (ii)ni lo da so = he must be good
... (iii)we so ze da = be good save grace
... (iv)From (i) and (iii), lo = must
... (v)From (i) and (iv), ze = save
... (vi)From (ii), (iii) and (iv), so = good
... (vii)From (i) and (ii), ka = money
... (viii)
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Centres at: MUKHERJEE NAGAR MUNIRKA UTTAM NAGAR DILSHAD GARDEN ROHINI BADARPUR JAIPUR GURGAON LAXMI NAGARGHAZIABAD NOIDA MEERUT VARANASI ROHTAK PANIPAT SONEPAT PATNA AGRA CHANDIGARH LUCKNOW ALLAHABAD
From (i), (v), (vi) and (viii), gi = some... (ix)
From (ii), (iii) and (vii), ni = he... (x)
From (ii), (vii), (viii) and (x), fe = made... (xi)
From (iii), (v), (vii) and (x), da = beFrom (iv), (vi), (vii) and (vii), we = grace
... (xiii)71. (3) 72. (5) 73. (1) 74 (4)(75-79):75. (5) R < P < U < K
U < LI. K > R is true.II. L > R is true.
76. (3) H = I < R < MHence M > II. M = III. M > IEither I or II is true.
77. (2) D > H > NH > I < SI. N < S is not true.II. I < D is true.
78. (2) W < Y < P < O < II. Y < I is false.II. O > W is true.
79. (5) A > B > C > FE > D > C > ZI. A > Z is true.II. F < E is true.
(80-84): On the basis of the giveninformation we have the followingtable:
80. (1) From the table C's compulsorysubject is History.
81. (4) The female member is the personwho teaches English i.e. D.
82. (5) None of the teachers have the samecompulsory and optional subjects.
83. (3) E and F have Physics andMathematics as the compulsoryand optional subjects.
84. (4) A, B and C have History as compulsorysubject, from the above table.
(85-90):85. (5) All squares are rings + All rings are
triangles = A + A = A = All squaresare triangles conversion Sometriangles are squares. Henceconclusion II ('At least sometriangles are squares', i.e. ('Sometriangles are squares') follows.Again, No rectangle is a triangles+ Some triangles are rings(converse of 'All rings are triangles')= E + I = O* = Some rings are notrectangle. Now, draw the allpossible venn diagrams for theabove conclusion as given below:
(Some rings are rectangles.)We don't need to draw otherpossibilities. Therefore, the possibility,i.e. conclusion I follows.
86.(4) No flat is an appartment + Someapartments are bunglaows(conversion of 'Some bunglaowsare apartments) = E + I = O* =Some bungalows are not flats.Therefore neither conclusion Inor conclusion II follows.
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Centres at: MUKHERJEE NAGAR MUNIRKA UTTAM NAGAR DILSHAD GARDEN ROHINI BADARPUR JAIPUR GURGAON LAXMI NAGARGHAZIABAD NOIDA MEERUT VARANASI ROHTAK PANIPAT SONEPAT PATNA AGRA CHANDIGARH LUCKNOW ALLAHABAD
87. (1) Some solids are liquids + All
liquids are water = I + A = I =
Some solids are water. Now, draw
all possible venn diagrams for the
above conclusions as given below:
Possibility I:
[Some water is solids.]
Possibility II:
[All gases are water.]
Possibility III:
[All water is gas.]
It is clear from the above that
conclusion I, i.e. 'All solids being
water is a possibility' follows.
Again, from the given premise,
'some solids are liquid', we can
have the possibility of being 'All
solids are liquids'. Therefore, All
such solids which are not water
can be liquids. Hence, Conclusion
II does not follow.
88. (1) All XYZ are alphabets (A)
conversion Some alphabetsare XYZ (I) + No XYZ is a day (E) =I + E = O = Some alphabets arenot days. Therefore conclusion Idoes not follow. Again, All ABCare XYZ + All XYZ are alphabets= A + A = A = All ABC arealphabets conversion Somealphabets are ABC (I). Therefore,conclusion II follows.
89. (1) From the statement 'Someteachers are professors' there arepossibility that 'All teachers areprofessors' and 'All professors areteachers'. Similarly from thestatement 'Some lecturers areteachers' there is a possibilitythat 'All teachers are lecturers'.Again, All professors are teachers+ All teachers are lecturers = A +A = A = All professors arelecturers is a possibility. Butconclusion II does not follow.
90. (2) From the above conclusion I doesnot follow. Again, from the above,we have the following possibility:'All lecturers are teachers' and 'Allteachers are professors'. Now, Alllecturers are teachers + Allteachers are professors = A + A =A = 'All lecturers are professors.Therefore conclusion II, i.e. 'Alllecturers being professor is apossibility' follows.
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Centres at: MUKHERJEE NAGAR MUNIRKA UTTAM NAGAR DILSHAD GARDEN ROHINI BADARPUR JAIPUR GURGAON LAXMI NAGARGHAZIABAD NOIDA MEERUT VARANASI ROHTAK PANIPAT SONEPAT PATNA AGRA CHANDIGARH LUCKNOW ALLAHABAD
(91-95):
91. (5) Between P and R is S.92. (4) T is at the third place, from the
above.93. (1) P is certainly greater than R.94. (4) U is the tallest, hence he plays
basketball.95. (4) We have not information about S,
hence he can play either cricketor badminton.
(96-100):96. (2) The driver does not have control
on what the auto driver will do.Hence I is not implicit. But II isimplicit as one assumes theoutcome while taking an action.
97. (5) I is implicit in the very giving of
the advice. II is implicit in the
condition attached.
98. (1) I is implicit: when you urge
someone to do something, you
assume a positive response. For
some reason, II is not implicit.
99. (2) If I were implicit, such decision
would not be taken. II is implicit
in the purpose of fund-rasing that
has been mentioned in the
statement.
100. (4)When a warning is given, it is
assumed that it will be heeded
to. Hence I is implicit. II is not
believed to the motive behind a
warning (even though the police
often create such an impression
among the people that they are
seen as extorionists; well! Let that
be on a lighter note.)
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Centres at: MUKHERJEE NAGAR MUNIRKA UTTAM NAGAR DILSHAD GARDEN ROHINI BADARPUR JAIPUR GURGAON LAXMI NAGARGHAZIABAD NOIDA MEERUT VARANASI ROHTAK PANIPAT SONEPAT PATNA AGRA CHANDIGARH LUCKNOW ALLAHABAD
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1. (5)2. (3)3. (4)4. (5)5. (3)6. (2)7. (1)8. (5)9. (1)10. (2)11. (3)12. (2)13. (4)14. (1)15. (5)16. (1)17. (5)18. (1)19. (2)20. (4)
21. (1)22. (5)23. (4)24. (3)25. (2)26. (1)27. (5)28. (2)29. (5)30. (3)31. (2)32. (3)33. (3)34. (1)35. (1)36. (2)37. (4)38. (1)39. (5)40. (5)
SBI ASSOCIATE JUNIOR ASST - 2 (PH-I] [ANSWER KEY]
41. (3)42. (1)43. (5)44. (4)45. (2)46. (2)47. (4)48. (4)49. (2)50. (3)51. (3)52. (4)53. (2)54. (4)55. (2)56. (3)57. (1)58. (3)59. (2)60. (3)
61. (1)62. (2)63. (3)64. (1)65. (2)66. (1)67. (5)68. (2)69. (5)70. (3)71. (3)72. (5)73. (1)74. (4)75. (5)76. (3)77. (2)78. (2)79. (5)80. (1)
81. (4)82. (5)83. (3)84. (4)85. (5)86. (4)87. (1)88. (1)89. (1)90. (2)91. (5)92. (4)93. (1)94. (4)95. (4)96. (2)97. (5)98. (1)99. (2)100. (4)