Section 1-5

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Solving Equations

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Section 1-5Solving Equations

Warm-upMatt Mitarnowski won a raffle. He put one third of his

winnings into the bank, used one half of the money for a car payment, and used the rest to buy some comic

books. If Matt spent $75 on comics, how much money did he win?

Warm-upMatt Mitarnowski won a raffle. He put one third of his

winnings into the bank, used one half of the money for a car payment, and used the rest to buy some comic

books. If Matt spent $75 on comics, how much money did he win?

x = money won

Warm-upMatt Mitarnowski won a raffle. He put one third of his

winnings into the bank, used one half of the money for a car payment, and used the rest to buy some comic

books. If Matt spent $75 on comics, how much money did he win?

x = money won

13

x + 12

x + 75 = x

Warm-upMatt Mitarnowski won a raffle. He put one third of his

winnings into the bank, used one half of the money for a car payment, and used the rest to buy some comic

books. If Matt spent $75 on comics, how much money did he win?

x = money won

13

x + 12

x + 75 = x

56

x + 75 = x

Warm-upMatt Mitarnowski won a raffle. He put one third of his

winnings into the bank, used one half of the money for a car payment, and used the rest to buy some comic

books. If Matt spent $75 on comics, how much money did he win?

x = money won

13

x + 12

x + 75 = x

56

x + 75 = x

75 = 16

x

Warm-upMatt Mitarnowski won a raffle. He put one third of his

winnings into the bank, used one half of the money for a car payment, and used the rest to buy some comic

books. If Matt spent $75 on comics, how much money did he win?

x = money won

13

x + 12

x + 75 = x

56

x + 75 = x

75 = 16

x

6i75 = 16

xi6

Warm-upMatt Mitarnowski won a raffle. He put one third of his

winnings into the bank, used one half of the money for a car payment, and used the rest to buy some comic

books. If Matt spent $75 on comics, how much money did he win?

x = money won

13

x + 12

x + 75 = x

56

x + 75 = x

75 = 16

x

6i75 = 16

xi6

x = 450

Warm-upMatt Mitarnowski won a raffle. He put one third of his

winnings into the bank, used one half of the money for a car payment, and used the rest to buy some comic

books. If Matt spent $75 on comics, how much money did he win?

x = money won

13

x + 12

x + 75 = x

56

x + 75 = x

75 = 16

x

6i75 = 16

xi6

x = 450

Matt won $450.

What did we do to solve this problem?

What did we do to solve this problem?

Read the problem

What did we do to solve this problem?

Read the problem

Make sure to solve for what is being asked

What did we do to solve this problem?

Read the problem

Make sure to solve for what is being asked

Identify variables

What did we do to solve this problem?

Read the problem

Make sure to solve for what is being asked

Identify variables

Set up the problem

What did we do to solve this problem?

Read the problem

Make sure to solve for what is being asked

Identify variables

Set up the problem

Solve

What did we do to solve this problem?

Read the problem

Make sure to solve for what is being asked

Identify variables

Set up the problem

Solve

Answer the question

Example 13x + 7 = 25

Example 13x + 7 = 25

-7

Example 13x + 7 = 25

-7 -7

Example 13x + 7 = 25

-7 -7

Example 13x + 7 = 25

-7 -7

3x

Example 13x + 7 = 25

-7 -7

3x =

Example 13x + 7 = 25

-7 -7

3x = 18

Example 13x + 7 = 25

-7 -7

3x = 183 3

Example 13x + 7 = 25

-7 -7

3x = 183 3

x = 6

Distributive Property:

Distributive Property: For real numbers a, b, and c:

c(a + b) = ac + bc

Distributive Property: For real numbers a, b, and c:

c(a + b) = ac + bc

Opposite of a Sum Theorem:

Distributive Property: For real numbers a, b, and c:

c(a + b) = ac + bc

Opposite of a Sum Theorem:

For real numbers a, and b:

-(a + b) = -a + -b

Distributive Property: For real numbers a, b, and c:

c(a + b) = ac + bc

Opposite of a Sum Theorem:

For real numbers a, and b:

-(a + b) = -a + -b

Note: The “-” here stands for “opposite”

Example 2

f (x ) = 5x − (3 − 2x ) Suppose f (x ) = 46 Find x..

Example 2

f (x ) = 5x − (3 − 2x ) Suppose f (x ) = 46 Find x..

46 = 5x − (3 − 2x )

Example 2

f (x ) = 5x − (3 − 2x ) Suppose f (x ) = 46 Find x..

46 = 5x − (3 − 2x )

46 = 5x − 3 + 2x

Example 2

f (x ) = 5x − (3 − 2x ) Suppose f (x ) = 46 Find x..

46 = 5x − (3 − 2x )

46 = 5x − 3 + 2x

46 = 7x − 3

Example 2

f (x ) = 5x − (3 − 2x ) Suppose f (x ) = 46 Find x..

46 = 5x − (3 − 2x )

46 = 5x − 3 + 2x

46 = 7x − 3

49 = 7x

Example 2

f (x ) = 5x − (3 − 2x ) Suppose f (x ) = 46 Find x..

46 = 5x − (3 − 2x )

46 = 5x − 3 + 2x

46 = 7x − 3

49 = 7x

x = 7

Clearing out fractions

Clearing out fractions

Face it, most of you hate them, so how do you get rid of them?

Clearing out fractions

Face it, most of you hate them, so how do you get rid of them?

Multiply both sides of the equation by a common denominator

Example 3

Example 3

16

a + 25

a +10 = 346

Example 3

16

a + 25

a +10 = 346

30( 16

a + 25

a +10) = 30(346)

Example 3

16

a + 25

a +10 = 346

30( 16

a + 25

a +10) = 30(346)

5a +12a + 300 = 10380

Example 3

16

a + 25

a +10 = 346

30( 16

a + 25

a +10) = 30(346)

5a +12a + 300 = 10380

17a + 300 = 10380

Example 3

16

a + 25

a +10 = 346

30( 16

a + 25

a +10) = 30(346)

5a +12a + 300 = 10380

17a + 300 = 10380

17a = 10080

Example 3

16

a + 25

a +10 = 346

30( 16

a + 25

a +10) = 30(346)

5a +12a + 300 = 10380

17a + 300 = 10380

17a = 10080

a =

10080

17

Example 4

.04b + .08(b − 3) = 12

Example 4

.04b + .08(b − 3) = 12

100[.04b + .08(b − 3)] = 100(12)

Example 4

.04b + .08(b − 3) = 12

100[.04b + .08(b − 3)] = 100(12)

4b + 8(b − 3) = 1200

Example 4

.04b + .08(b − 3) = 12

100[.04b + .08(b − 3)] = 100(12)

4b + 8(b − 3) = 1200

4b + 8b − 24 = 1200

Example 4

.04b + .08(b − 3) = 12

100[.04b + .08(b − 3)] = 100(12)

4b + 8(b − 3) = 1200

4b + 8b − 24 = 1200

12b − 24 = 1200

Example 4

.04b + .08(b − 3) = 12

100[.04b + .08(b − 3)] = 100(12)

4b + 8(b − 3) = 1200

4b + 8b − 24 = 1200

12b − 24 = 1200

12b = 1224

Example 4

.04b + .08(b − 3) = 12

100[.04b + .08(b − 3)] = 100(12)

4b + 8(b − 3) = 1200

4b + 8b − 24 = 1200

12b − 24 = 1200

12b = 1224

b = 102

Homework

Homework

p. 33 #1 - 27