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GEOMETRY DAY 11 Deductive Reasoning Sept 17 w_comments.notebook
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September 17, 2018
Assignment Due Today: #9 Conditional stmnt. pp. 8587 14,16,21,22,2429,32,34,3841,42,44,46,50,52,56And practice C, Challenge and Problem solve.
Assignment Due Next time: #10. Deductive Reasoning pp.9193 9,10,1518,20,23,27,28
GeometryDay 11 MONDAY
Sept 17Test Tomorrow on Chap 1
Through Assignment 10
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If not P, then TIf not M, then not TIf P, then not Q If A, then RIf R, then not M
Given the following, what conclusion can you draw if Q happens
If q, then ~PIf ~p, then TIf T, then MIf M, then ~RIf ~R, then ~A
Conlusion:: So If Q happens then A does not happen! Use contrapositive to solve this!
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#9 Conditional stmnt. pp. 8587 14,16,21,22,2429,32,34,3841,42,44,46,50,52,56
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Your test is tomorrow.
It is on Assignments 1 through 10.
You must know how to find the area and perimeter (circumference) of triangles, rectangle and circles as a base knowledge. In other words, whether it comes up in class specifically or not, it is fair game on tests and quizzes.
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Answer on next slide... be careful!
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Answer on next slide
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This is HUGE!!!!!
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True! It is valid
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Biconditional
A biconditional statement is defined to be true whenever both parts have the same truth value. The biconditional operator is denoted by a doubleheaded arrow . The biconditional pq represents "p if and only if q," where p is a hypothesis and q is a conclusion. The following is a truth table for biconditional pq.
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