Trees, Part 1

transcript

Trees, Part 1

CSCI 2720University of GeorgiaSpring 2007

Tree Properties and Definitions

• Composed of nodes and edges• Node

• Any distinguishable object• Edge

• An ordered pair <u,v> of nodes• Illustrated by an arrow with tail at u and head at v• u = tail of <u,v>• v = head of <u,v>

• Root • A distinguished node, depicted at the top of the tree

Recursive Definition of a Tree

1. A single node, with no edges, is a tree. The root of the tree is its unique node.

2. Let T1, …, Tk (k >=1) be trees with no nodes in common, and let r1, …,rk be the roots of those trees, respectively. Let r be a new node. Then there is a tree T consisting of the nodes and edges of T1, …, Tk , the new node r and the edges <r,r1>,…,<r,rk>. The root of T is r and T1, …,Tk are called the subtrees of T.

Tree definitions and terminology

• r is called the parent of r1, …, rk

• r1, …, rk are the children of r

• r1, …, rk are the siblings of one another

• Node v is a descendant of u if• u = v or• v is a descendant of a child of u• A path exists from u to v.

Recursive definition

Before:

The trees T1, …, Tk, with roots r1, …, rk

After:

new tree T rooted at r with subtreesT1, …, Tk,

What do we mean by a path from u to v?

• You can get from u to v by following a sequences of edges down the tree, starting with an edge whose tail is u, ending with an edge whose head is v, and with the head of each edge but the last being the tail of the next.

Tree terminology

• Every node is a descendant of itself.• If v is a descendant of u, then u is an

ancestor of v.• Proper descendants:

• The descendants of a node, other than the node itself.

• Proper ancestors• The ancestors of a node, other than the

node itself.

Tree terminology & properties

• Leaf• a node with no children

• Num_nodes = Num_edges + 1• Every tree has exactly one more node than

edge• Every edge, except the root, is the head of

exactly one of the edges

Tree terminology & properties

• Height of a node in a tree• Length of the longest path from that node to

a leaf

• Depth of a node in a tree• Length of the path from the root of the tree

to the node

Tree terminologyroot

leafleaf

Tree terminology

A path from u to v. Node u is the ancestor of node v.

Tree terminology

• w has depth 2• u has height 3• tree has height 4u

Special kinds of trees

• Ordered v. unordered• Binary tree• Empty v non-empty• Full • Perfect • Complete

Ordered trees

• Have a linear order on the children of each node

• That is, can clearly identify a 1st, 2nd, …, kth child

• An unordered tree doesn’t have this property

Binary tree

• An ordered tree with at most two children for each node

• If node has two child, the 1st is called the left child, the 2nd is called the right child

• If only one child, it is either the right child or the left child

Two trees are not equivalent …One has only a left child; the other has only a right child

Empty binary tree

• Convenient to define an empty binary tree, written , for use in this definition:• A binary tree is either or is a node with left

and right subtrees, each of which is a binary tree.

Full binary tree

• Has no nodes with only one child• Each node either a leaf or it has 2 children

• # leaves = #non-leaves + 1

Perfect binary tree

• A full binary tree in which all leaves have the same depth

• Perfect binary tree of height h has:• 2h+1 -1 nodes• 2h leaves• 2h -1 non-leaves

• Interesting because it is “fully packed”, the shallowest tree that can contain that many nodes. Often, we’ll be searching from the root. Such a shallow tree gives us minimal number of accesses to nodes in the tree.

Perfect binary trees

Complete binary tree

• Perfect binary tree requires that number of nodes be one less than a power of 2.

• Complete binary tree is a close approximation, with similar good properties for processing of data stored in such a tree.

• Complete binary tree of height h:• Perfect binary tree of height h-1• Add nodes from left at bottom level

More formally, …

• A complete binary tree of height 0 is any tree consisting of a single node.

• A complete binary tree of height 1 is a tree of height 1 with either two children or a left child only.

• For height h >= 2, a complete binary tree of height h is a root with two subtrees satisfying one of these two conditions:

• Either the left subtree is perfect of height h-1 and the right is complete of height h-1 OR

• The left is complete of height h-1 and the right is perfect of height h-2.

Complete binary trees

Tree terminology

• Forest• A finite set of trees• In the case of ordered trees, the trees in the

forest must have a distinguishable order as well.

Tree Operations

• Parent(v)• Children(v)• FirstChild(v)• RightSibling(v)• LeftSibling(v)• LeftChild(v)• RightChild(v)• isLeaf(v)• Depth(v)• Height(v)

Parent(v)

• Return the parent of node v, or if v is the root.

Children(v)

• Return the set of children of node v (the empty set, if v is a leaf).

FirstChild(v)

• Return the first child of node v, or if v is a leaf.

RightSibling(v)

• Return the right sibling of v, or if v is the root or the rightmost child of its parent.

LeftSibling(v)

• Return the left sibling of v, or if v is the root or the leftmost child of its parent

LeftChild(v)

• Return the left child of node v;• Return if v has no left or right child.

RightChild(v)

• Return the right child of node v; • return if v has no right child

isLeaf(v)

• Return true if node v is a leaf, false if v has a child

Depth(v)

• Return the depth of node v in the tree.

Height(v)

• Return the height of node v in the tree.

Arithmetic Expression Tree

• Binary tree associated with an arithmetic expression

• internal nodes: operators• external nodes: operands• Example: arithmetic

expression tree for the infix expression:

• (2 × (a − 1) + (3 × b))• Note: infix expressions

require parentheses• ((2 x a) – (1+3) * b) is a

different expression tree

Evaluating Expression Trees

function Evaluate(ptr P): integer/* return value of expression represented by tree

with root P */if isLeaf(P) return Label(P)else

xL <- Evaluate(LeftChild(P))

xR <- Evaluate(RightChild(P))op <- Label(P)

return ApplyOp(op, xL, xR)

Example

- Evaluate (A) Evaluate(B)

Evaluate(D) => 2 Evaluate(E)

Evaluate(H)=> a Evaluate(I) => 1 ApplyOp(-,a,1) => a-1ApplyOp(x,2,(a-1)) => (2 x (a-

1)) Evaluate(C)

Evaluate(F) => 3Evaluate(G) => bApplyOp(x,3,b) => 3 x b

ApplyOp(+,(2 x (a-1)),(3 x b)) =>(2 x (a-1)) + (3 x b)

D E F G

Traversals

• Traversal = any well-defined ordering of the visits to the nodes in a tree

• PostOrder traversal • Node is considered after its children have been

considered

• PreOrder traversal• Node is considered before its children have been

considered

• InOrder traversal (for binary trees)• Consider left child, consider node, consider right child

PostOrder Traversal

procedure PostOrder(ptr P):foreach child Q of P, in order, do

PostOrder(Q)

Visit(P)

PostOrder traversal gives:

2, a, 1, -, x, 3, b, x, +

Nice feature: unambiguous … doesn’t need parentheses

-- often used with scientific calculators

-- simple stack-based evaluation

Evaluating PostOrder Expressions

procedure PostOrderEvaluate(e1, …, en):

for i from 1 to n do

if ei is a number, then push it on the stack

else• Pop the top two numbers from the stack• Apply the operator ei to them, with the right operand being the

first one popped• Push the result on the stack

PreOrder Traversal

procedure PreOrder(ptr P):Visit(P)

foreach child Q of P, in order, doPreOrder(Q)

PreOrder Traversal:

+, x, 2, -, a, 1, x, 3, b

Nice feature: unambigous, don’t need parentheses

-- Outline order

InOrder Traversal

procedure InOrder(ptr P):// P is a pointer to the root of a binary tree

if P = then returnelse

InOrder(LeftChild(P))Visit(P)InOrder(RightChild(P))

InOrder Traversal:

2 x a – 1 + 3 x b

Binary Search Trees

• Use binary trees to store data that is linearly ordered

• A linear order is a relation < such that for any x, y, and z• If x and y are different then either x<y or y<x• If x<y and y < z then x< z

• An inorder traversal of a binary search tree yields the labels on the nodes, in linear order.

Binary Search Trees, examples

Inorder traversal yields: 20, 30, 40, 50, 60, 70

Level-order traversal

breadth-first or level-order traversal yields:

A, B, C, D, E, F

a.k.a. breadth-first traversal

Tree Implementations

• General Binary Tree• General Ordered Trees• Complete Binary Trees

Binary Trees:“Natural Representation”

• LC : contains pointer to left child

• RC: contains pointer to right child

• Info: contains info or pointer to info

• LeftChild(p), RightChild(p): (1)

• Parent(p): not (1) unless we also add a parent pointer to the node

LC info RC

Parent(p): not (1) unless we also add a parent pointer to the nodeCan use xor trick to store parent-xor-left,Parent-xor-right, and use only two fields

Ordered Tree representation

• Binary tree: array of 2 ptrs to 2 children • Ternary tree: array of 3 ptrs to 3 children• K-ary trees: k pointers to k children• What if there is no bound on the number

of children?• Use binary tree representation of ordered

tree:First Info RightChild Sibling

Example

• General ordered tree • Binary tree rep

Complete Binary Tree: Implicit representation

Binary Search Trees, example50

0 1 2 3 4 5

[50 | 30 | 70 | 20 | 40| 60]

Implicit rep of complete binary trees

• isLeaf(i) : • 2i + 1 >= n

• LeftChild(i) :• 2i + 1 (none if 2i + 1 >= n)

• RightChild(i) : • 2i + 2 (none if 2i + 2 >= n)

• LeftSibling(i): • i-1 (none if i=0 or i is odd)

• RightSibling(i):• i+1 (none if i=n-1 or i is even)

• Parent(i): • floor((i-1)/2) (none if i=0)

• Depth(i):• floor (lg(i+1))

• Height(i): • ceil(lg((n+1)/(i+1))) - 1

Tree Traversals and Scans

• Stack-based Traversals• Link-Inversion Traversal• Scanning in Constant Space• Threaded Trees• Level-Order Traversal

Stack-based Traversals

procedure Traverse(ptr P)//traverse binary tree with root P

if P != thenPreVisit(P)

Traverse(LC(P))

InVisit(P)

Traverse(RC(P))

PostVisit(P)

• Provide functions for Previsit(P),Invisit(P), and/or PostVisit(P)

• Some can be null (do-nothing) functions

• Implements all 3 traversal (inorder, preorder, postorder) … just depends on which functions have “real” bodies

Traverse(LC(P))

InVisit(P)

Traverse(RC(P))

PostVisit(P)

• O(n) time to visit all nodes

• Height of the stack is proportional to the height of the tree

• If structure is large, height of stack can be problematic

• For pre-order and inorder, one of the calls to Traverse is tail-recursive & we can eliminate it

Traverse(LC(P))

InVisit(P)

Traverse(RC(P))

PostVisit(P)

While P != doPreVisit(P)Traverse(LC(P))InVisit(P)P <- RC(P)

- demo difference in stack heights for small example

Stack during recursive in-order traversal

B C D E F

Height of stack for “improved” algorithm

• How high does the stack get for this alg?

• Depends on “max left height” -- proportional to the height of the corresponding ordered tree

• OrdHt(P):• if P =

• 0 • if LC(P) ==

• OrdHt(RC(P)) • Otherwise

• Max(1 + OrdHt(LC(P)), OrdHt(RC(P)))

• Example: calculate ordered height for medium-sized BT

Link-Inversion Traversal

• Use same ideas from link-inversion traversal of list

• Stores contents of stack in tree itself

• Use tag bit to indicate whether to follow LC or RC at this point

tag LC info RC

Tag also indicates:

•When recursive invocation finishes

•Which of the two recursive calls in the body caused that invocation

•Where in the body the execution should continue

Link Inversion Traversal

procedure LinkInvTrav(ptr Q)

// initially Q points to root

P <- repeat forever

// descend to left afap

while Q != do

PreVisit(Q)

Tag(Q) <- 0

descend_to_left

// ascend from right afap

while P != and Tag(P) == 1 do

ascend_from_right

PostVisit(Q)

if P == then return

ascend_from_left

InVisit(Q)

Tag(Q) <- 1

descend_to_right

Ascend/ Descend functions

descend_to_left

ascend_from_left

descend_to_right

Ascend_from_right

Example

• Demo on small - midsized tree

One more twist

• Actually, don’t really need to store the tag bits in the nodes themselves … can just place them in a stack at the time the algorithm runs!

Scanning in Constant Space

• Can visit each node in a tree, at least once, using only a few temporary variables

• Catch: not a standard traversal order• In fact - visits each node three times• “walks around” the tree, keeping nodes

and edges to its left

Constant Space Scan

50, 30, 20, 20, 20, 30, 40, 40, 40, 30, 50, 70, 60, 60, 60, 70, 70, 5050, 30, 20, 40, 70, 60 20 30 40 50 60 70 20 40 30 60 70 50

Trees, example50

Constant Space Scan

procedure ConstantSpaceScan(ptr Q): is a distinguished valueInitially Q points to rootP <- While Q != do

If Q != thenVisit(Q)

elseP <-> Q

Threaded Trees

• Inorder traversal is a common operation• Recursive methods have disadvantages:

• Require extra memory to store a stack• Can’t start from an arbitrary node … need to

start at the root

• Want to make it easier to find inorder successor of a node• Inorder predecessor would be nice too!

Threaded Trees

40 200 | 40 | 300

| 50 | 500400 | 30 |

| 60| | 10 | 600

| 20 |

200 300

500400

Hmmmm … that’s quite a few null pointers!

In fact, in binary tree with n nodes, there are 2n pointers .. And n+1 of these are … maybe we can make use of this memory ….

Threaded Trees

• If a node has no right child, store a pointer to the node’s inorder successor

• If a node has no left child, store a pointer to the node’s inorder predecessor

• Need to keep a threat bit to distinguish between “regular” pointers and threads

Threaded Trees

40 200 | 40 | 300

| 50 | 500400 | 30 |

| 60| | 10 | 600

| 20 |

200 300

500400

On board .. Sketch out threaded equivalent of this tree ….

InOrder Successor

function InorderSuccessor(ptr N): ptr//return the inorder successor of N or if none exists

P <- RC(N)

if P = then return else if P is not a thread then

while LC(P) is not a thread or do

P <- LC(P)

return P

Threaded Insert

Procedure ThreadedInsert(ptr P,Q):// Make node Q the inorder successor of node P

if RC(Q) is not a thread thenLC(InOrderSuccessor(Q)) <- (thread)Q

(child)Q

(thread)P

Threaded Trees

200 | 40 | 300

| 50 | 500400 | 30 |

| 60| | 10 | 600

| 20 |

200 300

500400

Level-Order Traversal

Procedure LevelOrder(ptr R):

//R is a ptr to the root of the tree

L <- MakeEmptyQueue()

Enqueue(R, L)

Until IsEmptyQueue(L)P <- Dequeue(L)

Visit(P)

Foreach child Q of P, in order, doEnqueue(Q,L)

Trees, Part 1

Documents