Warm Up 4/14 How many protons and neutrons would an H+ ion have?

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Warm Up 4/14 How many protons and neutrons would an H+ ion have?. Acids. Bases. Definitions. Neutralization. Strong vs Weak. Litmus Paper. Intro to Acids & Bases . Common Acids. Properties of Acids. - Corrosive (burns skin and “eats” metals) - Sour taste - PowerPoint PPT Presentation

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Warm Up 4/14

How many protons and neutrons would an H+

ion have?

Acids Bases

Definitions

Neutralization

Strong vs Weak

Litmus Paper

Intro to Acids & Bases

Common Bases

Properties of Bases-Caustic (leaves a white residue on metals)-Bitter taste-Slippery feeling-Turns red litmus blue-Electrolyte-pH greater than 7

Neutralization Reaction – When an acid and base react to form a neutral solution (water and a salt).Examples:• NaOH + HCl → H2O + NaCl• 2NaOH + H2SO4 → 2H2O + Na2SO4

Acids and bases can be classified as weak or strong.

Strong acid/base- ionizes (dissociates) completely

ex.: HCl + H2O → H+(aq) + Cl-(aq)

Weak acid/base- only ionizes (dissociates) partially

ex.: HF + H2O → H+(aq) + F-(aq) + HF

Warm Up 3/26

Give the salt that will be formed in the following neutralization reaction:

2 HBr + Ba(OH)4 → 2 H2O + ___?___

Calculating pH

• pH or “power of hydronium” is based on the concentration of H3O+ ions

• H3O+ is another way to write H+

• Formula: pH = -log [H+]

Calculator Steps

1)Press the (-) button (not the minus sign button!)

2)Press the Log button3)Enter the concentration and

close the parenthesis

Example #1Calculate the pH of a solution

whose [H+] = 1.0 x 10-4

Example #2 Calculate the pH of a solution

whose [H+] = 3.1 x 10-4

Left Side PracticeFind the pH of these concentrations of H+, and tell whether it’s an acid or a base.1) [H+] = 1.0 ×10−6 M 2) [H+] = 2.19 ×10−4 M 3) [H+] = 9.18 ×10−11 M 4) [H+] = 4.71 ×10−7 M 5) [H+] = 1.0 M

K = [H+][OH-] = 1.0 ×10−14 w

Ionization Constant of Water:

(We will be using this in our calculations)

Finding pH from [OH-] •Divide 1.0 ×10−14 by the [OH-] concentration.

•Then solve like a regular H+ problem: -log [H+]

Example: Calculate the pH of a solution with an [OH-] of 1.0 ×10−3 .

pOH CalculationsFormula: pOH = -log [OH-]

• If given the [OH-], then just put that number in the parenthesis.

• If given the [H+], then divide it by 1.0 ×10−14 and put the answer in the parenthesis.

Example: Calculate the pOH of a solution with an [OH-] of 2.7×10−4 .

Example: Calculate the pOH of a solution with an [H+] of 9.18 ×10−11 .

To go from pH back to [H+] (or from pOH back to [OH-]) just put in: 10^- given

Example: Calculate the [H+] of a solution whose pH = 6.3

Calculating pOH

pOH or “power of hydroxide ion”Formula:

pOH = -log [OH-]

Example #3

What is the pH of a 0.250M solution of KOH?

Example Problem #4

Calculate the pH and pOH of a 0.315M H2SO4 solution.