Energy Performance Certificate Forest Barn & Dairy, Forest Lane, High Ongar, ONGAR, CM5 9RS Dwelling type: Detached house Reference number: 8161-7633-6440-0496-4996 Date of assessment: 16 July 2019 Type of assessment: SAP, new dwelling Date of certificate: 16 July 2019 Total floor area: 240 m² Use this document to: • Compare current ratings of properties to see which properties are more energy efficient • Find out how you can save energy and money by installing improvement measures Estimated energy costs of dwelling for 3 years: £ 3,915 Over 3 years you could save £ 156 Estimated energy costs of this home Current costs Potential costs Potential future savings Lighting £ 351 over 3 years £ 351 over 3 years Heating £ 3,189 over 3 years £ 3,195 over 3 years Hot Water £ 375 over 3 years £ 213 over 3 years Totals £ 3,915 £ 3,759 You could save £ 156 over 3 years These figures show how much the average household would spend in this property for heating, lighting and hot water and is not based on energy used by individual households. This excludes energy use for running appliances like TVs, computers and cookers, and electricity generated by microgeneration. Energy Efficiency Rating The graph shows the current energy efficiency of your home. The higher the rating the lower your fuel bills are likely to be. The potential rating shows the effect of undertaking the recommendations on page 3. The average energy efficiency rating for a dwelling in England and Wales is band D (rating 60). The EPC rating shown here is based on standard assumptions about occupancy and energy use and may not reflect how energy is consumed by individual occupants. Actions you can take to save money and make your home more efficient Recommended measures Indicative cost Typical savings over 3 years 1 Solar water heating £4,000 - £6,000 £ 153 2 Solar photovoltaic panels, 2.5 kWp £3,500 - £5,500 £ 960 3 Wind turbine £15,000 - £25,000 £ 1,884 Page 1 of 4
Transcript
Energy Performance Certificate
Forest Barn & Dairy, Forest Lane, High Ongar, ONGAR, CM5 9RSDwelling type: Detached house Reference number: 8161-7633-6440-0496-4996Date of assessment: 16 July 2019 Type of assessment: SAP, new dwellingDate of certificate: 16 July 2019 Total floor area: 240 m²
Use this document to:• Compare current ratings of properties to see which properties are more energy efficient• Find out how you can save energy and money by installing improvement measures
Estimated energy costs of dwelling for 3 years: £ 3,915
Over 3 years you could save £ 156
Estimated energy costs of this home Current costs Potential costs Potential future savings
Lighting £ 351 over 3 years £ 351 over 3 years
Heating £ 3,189 over 3 years £ 3,195 over 3 years
Hot Water £ 375 over 3 years £ 213 over 3 years
Totals £ 3,915 £ 3,759
You couldsave £ 156
over 3 years
These figures show how much the average household would spend in this property for heating, lighting and hotwater and is not based on energy used by individual households. This excludes energy use for running applianceslike TVs, computers and cookers, and electricity generated by microgeneration.
Energy Efficiency RatingThe graph shows the current energy efficiency of yourhome.The higher the rating the lower your fuel bills are likely tobe.The potential rating shows the effect of undertaking therecommendations on page 3.The average energy efficiency rating for a dwelling inEngland and Wales is band D (rating 60).The EPC rating shown here is based on standardassumptions about occupancy and energy use andmay not reflect how energy is consumed by individualoccupants.
Actions you can take to save money and make your home more efficient
Recommended measures Indicative cost Typical savingsover 3 years
Energy Performance CertificateForest Barn & Dairy, Forest Lane, High Ongar, ONGAR, CM5 9RS
16 July 2019 RRN: 8161-7633-6440-0496-4996
Summary of this home's energy performance related featuresElement Description Energy Efficiency
Walls Average thermal transmittance 0.24 W/m²K
Roof Average thermal transmittance 0.18 W/m²K
Floor Average thermal transmittance 0.15 W/m²K
Windows High performance glazing
Main heating Boiler & underfloor, oil
Main heating controls Time and temperature zone control
Secondary heating None —
Hot water From main system
Lighting Low energy lighting in all fixed outlets
Air tightness (not tested) —
Thermal transmittance is a measure of the rate of heat loss through a building element; the lower the value the betterthe energy performance.
Current primary energy use per square metre of floor area: 133 kWh/m² per year
Low and zero carbon energy sourcesLow and zero carbon energy sources are sources of energy that release either very little or no carbon dioxideinto the atmosphere when they are used. Installing these sources may help reduce energy bills as well as cuttingcarbon. There are none provided for this home.
Your home's heat demandThis table shows the energy used for space and water heating by an average household in this property.
Heat demandSpace heating (kWh per year) 20,704
Water heating (kWh per year) 2,354
If you built your own home and, as part of its construction, you installed a renewable heating system, you couldreceive Renewable Heat Incentive (RHI) payments. The estimated energy required for space and water heating willform the basis of the payments. For more information, search for the domestic RHI on the www.gov.uk website.
Stroma FSAP 2012 Version: 1.0.4.18 (SAP9.92)
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Energy Performance CertificateForest Barn & Dairy, Forest Lane, High Ongar, ONGAR, CM5 9RS
16 July 2019 RRN: 8161-7633-6440-0496-4996
RecommendationsThe measures below will improve the energy performance of your dwelling. The performance ratings afterimprovements listed below are cumulative; that is, they assume the improvements have been installed in the orderthat they appear in the table. To receive advice on what measures you can take to reduce your energy bills, visitwww.simpleenergyadvice.org.uk or call freephone 0800 444202. Before installing measures, you should make sureyou have secured the appropriate permissions, where necessary. Such permissions might include permission fromyour landlord (if you are a tenant) or approval under Building Regulations for certain types of work.
Recommended measures Indicative cost Typical savingsper year
Rating afterimprovement
Solar water heating £4,000 - £6,000 £ 51
Solar photovoltaic panels, 2.5 kWp £3,500 - £5,500 £ 320
Wind turbine £15,000- £25,000 £ 628
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Energy Performance CertificateForest Barn & Dairy, Forest Lane, High Ongar, ONGAR, CM5 9RS
16 July 2019 RRN: 8161-7633-6440-0496-4996
About this document and the data in itThis document has been produced following an energy assessment undertaken by a qualified Energy Assessor,accredited by Stroma Certification. You can obtain contact details of the Accreditation Scheme at www.stroma.com.
A copy of this certificate has been lodged on a national register as a requirement under the Energy Performanceof Buildings Regulations 2012 as amended. It will be made available via the online search function atwww.epcregister.com. The certificate (including the building address) and other data about the building collectedduring the energy assessment but not shown on the certificate, for instance heating system data, will be madepublicly available at www.opendatacommunities.org.
This certificate and other data about the building may be shared with other bodies (including governmentdepartments and enforcement agencies) for research, statistical and enforcement purposes. Any personal data itcontains will be processed in accordance with the General Data Protection Regulation and all applicable laws andregulations relating to the processing of personal data and privacy. For further information about this and how dataabout the property are used, please visit www.epcregister.com. To opt out of having information about your buildingmade publicly available, please visit www.epcregister.com/optout.
Assessor's accreditation number: STRO004782Assessor's name: Keith LanePhone number: 07803677173E-mail address: [email protected] party disclosure: No related party
There is more information in the guidance document Energy Performance Certificates for the marketing, sale and letof dwellings available on the Government website at:www.gov.uk/government/collections/energy-performance-certificates. It explains the content and use of thisdocument, advises on how to identify the authenticity of a certificate and how to make a complaint.
About the impact of buildings on the environmentOne of the biggest contributors to global warming is carbon dioxide. The energy we use for heating, lighting andpower in homes produces over a quarter of the UK’s carbon dioxide emissions.
The average household causes about 6 tonnes of carbon dioxide every year. Based on this assessment, your homecurrently produces approximately 8.4 tonnes of carbon dioxide every year. Adopting the recommendations in thisreport can reduce emissions and protect the environment. If you were to install these recommendations you couldreduce this amount by 3.2 tonnes per year. You could reduce emissions even more by switching to renewableenergy sources.
The environmental impact rating is a measure of a home's impact on the environment in terms of carbon dioxide(CO2) emissions based on standardised assumptions about occupancy and energy use. The higher the rating theless impact it has on the environment.
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Regulations Compliance Report
Approved Document L1A, 2013 Edition, England assessed by Stroma FSAP 2012 program, Version: 1.0.4.18Printed on 16 July 2019 at 14:19:10Project Information:
Assessed By: Keith Lane (STRO004782) Building Type: Detached House
Dwelling Details:NEW DWELLING CREATED BY CHANGE OF USE Total Floor Area: 240.42m²Site Reference : Barn to Dwelling Conversion Plot Reference: Barn to Dwelling ConversionAddress : Forest Barn & Dairy, Forest Lane, High Ongar, ONGAR, CM5 9RS
Client Details:Name: Mr & Mrs TowlerAddress :
This report covers items included within the SAP calculations.It is not a complete report of regulations compliance.1a TER and DER
Address: Forest Barn & Dairy, Forest Lane, High Ongar, ONGAR, CM5 9RSLocated in: EnglandRegion: East AngliaUPRN: 6044464678Date of assessment: 16 July 2019Date of certificate: 16 July 2019Assessment type: New dwelling created by change of useTransaction type: New dwellingTenure type: Owner-occupiedRelated party disclosure: No related partyThermal Mass Parameter: Indicative Value MediumWater use <= 125 litres/person/day: TruePCDF Version: 444
Living area: 103.2 m² (fraction 0.429)Front of dwelling faces: East
Opening types:
Name: Source: Type: Glazing: Argon: Frame:Front Entrance SAP 2012 Solid MetalSide Entrance SAP 2012 Solid MetalLarge Front SAP 2012 Windows low-E, En = 0.05, soft coat Yes MetalTop Front Manufacturer Windows low-E, En = 0.05, soft coat Yes MetalLarge Side Manufacturer Windows low-E, En = 0.05, soft coat Yes MetalSmall Top Manufacturer Windows low-E, En = 0.05, soft coat Yes MetalLarge Top Manufacturer Windows low-E, En = 0.05, soft coat Yes MetalSmall Side Manufacturer Windows low-E, En = 0.05, soft coat Yes MetalSmall Side Manufacturer Windows low-E, En = 0.05, soft coat Yes MetalRoof Window Manufacturer Roof Windows low-E, En = 0.05, soft coat Yes WoodRoof Window Manufacturer Roof Windows low-E, En = 0.05, soft coat Yes WoodRoof Window Manufacturer Roof Windows low-E, En = 0.05, soft coat Yes WoodRoof Window Manufacturer Roof Windows low-E, En = 0.05, soft coat Yes Wood
Name: Gap: Frame Factor: g-value: U-value: Area: No. of Openings:Front Entrance mm 0.8 0 3 2.85 1Side Entrance mm 0.8 0 3 2.01 1Large Front 16mm or more 0.8 0.63 1.4 14.54 1Top Front 16mm or more 0.8 0.63 1.4 1.53 1Large Side 16mm or more 0.8 0.63 1.4 6.13 1Small Top 16mm or more 0.8 0.63 1.4 0.64 2Large Top 16mm or more 0.8 0.63 1.4 0.97 1Small Side 16mm or more 0.8 0.63 1.4 3.17 1Small Side 16mm or more 0.8 0.63 1.4 0.59 7Roof Window 16mm or more 0.7 0.63 1.3 0.74 1Roof Window 16mm or more 0.7 0.63 1.3 0.54 1Roof Window 16mm or more 0.7 0.63 1.3 0.3 1Roof Window 16mm or more 0.7 0.63 1.3 0.47 4
Name: Type-Name: Location: Orient: Width: Height:Front Entrance Door (1) Walls East 1.13 2.52Side Entrance Door (1) Walls North 1.02 1.97Large Front Windows (1) Walls East 4.75 3.06Top Front Windows (2) Walls East 0 0Large Side Windows (2) Walls North 2.47 2.48Small Top Windows (2) Walls North 1.28 0.5Large Top Windows (2) Walls North 1.93 0.5Small Side Windows (2) Walls North 1.28 2.48Small Side Windows (2) Walls South 0.39 1.5Roof Window Roof windows (1) Roof North 0.75 0.99Roof Window Roof windows (1) Roof North 0.55 0.99Roof Window Roof windows (1) Roof North 0.5 0.6Roof Window Roof windows (1) Roof North 0.39 1.2
Thermal bridges: No information on thermal bridging (y=0.15) (y =0.15)Ventilation:
Pressure test: No (Assumed)Ventilation: Natural ventilation (extract fans)Number of chimneys: 0Number of open flues: 00Number of fans: 4Number of passive stacks: 0Number of sides sheltered: 2Pressure test: 15Main heating system:
Main heating system: Boiler systems with radiators or underfloor heatingGas boilers and oil boilersFuel: heating oilInfo Source: Boiler DatabaseDatabase: (rev 444, product index 010594) Efficiency: Winter 74.9 % Summer: 86.6Brand name: WarmflowModel: UtilityModel qualifier: U90(Regular boiler)Underfloor heating and radiators, pipes in screed above insulationCentral heating pump : 2013 or laterDesign flow temperature: Design flow temperature<=35°CBoiler interlock: YesDelayed start
Main heating Control:
Main heating Control: Time and temperature zone control by suitable arrangement of plumbing and electrical
Water heating: From main heating systemWater code: 901Fuel :heating oilHot water cylinderCylinder volume: 300 litresCylinder insulation: Measured loss, 2.03kWh/dayPrimary pipework insulation: TrueCylinderstat: TrueCylinder in heated space: TrueSolar panel: False
Others:
Electricity tariff: Standard TariffIn Smoke Control Area: UnknownConservatory: No conservatoryLow energy lights: 100%Terrain type: RuralEPC language: EnglishWind turbine: NoPhotovoltaics: NoneAssess Zero Carbon Home: No
Forest Barn & DairyForest LaneHigh OngarONGARCM5 9RS
Dwelling type: Detached HouseDate of assessment: 16 July 2019Produced by: Keith LaneTotal floor area: 240.42 m²
This is a Predicted Energy Assessment for a property which is not yet complete. It includes a predicted energyrating which might not represent the final energy rating of the property on completion. Once the property iscompleted, an Energy Performance Certificate is required providing information about the energy performanceof the completed property.Energy performance has been assessed using the SAP 2012 methodology and is rated in terms of the energyuse per square metre of floor area, energy efficiency based on fuel costs and environmental impact based oncarbon dioxide (CO2) emissions.
Energy Efficiency Rating Environmental Impact (CO ) Rating2
The energy efficiency rating is a measure of the The environmental impact rating is a measure of aoverall efficiency of a home. The higher the rating home’s impact on the environment in terms ofthe more energy efficient the home is and the lower carbon dioxide (CO2) emissions. The higher thethe fuel bills are likely to be. rating the less impact it has on the environment.
SAP WorkSheet: New dwelling created by change of use
User Details:
Assessor Name: Keith Lane Stroma Number: STRO004782Software Name: Stroma FSAP 2012 Software Version: Version: 1.0.4.18
Property Address: Barn to Dwelling ConversionAddress : Forest Barn & Dairy, Forest Lane, High Ongar, ONGAR, CM5 9RS1. Overall dwelling dimensions:
Area(m²) Av. Height(m) Volume(m³)Ground floor (1a) x (2a) = (3a) 196.82 3.61 710.52
First floor (1b) x (2b) = (3b) 43.6 1.54 67.14
Total floor area TFA = (1a)+(1b)+(1c)+(1d)+(1e)+.....(1n) (4)240.42
2. Ventilation rate:main secondary other total m³ per hourheating heating
Number of chimneys + + = x 40 = (6a)0 0 0 0 0
Number of open flues + + = x 20 = (6b)0 0 0 0 0
Number of intermittent fans x 10 = (7a)4 40
Number of passive vents x 10 = (7b)0 0
Number of flueless gas fires x 40 = (7c)0 0
Air changes per hour
Infiltration due to chimneys, flues and fans = (6a)+(6b)+(7a)+(7b)+(7c) = (8)÷ (5) = 0.0540If a pressurisation test has been carried out or is intended, proceed to (17), otherwise continue from (9) to (16)
Number of storeys in the dwelling (ns) (9)0
Additional infiltration [(9)-1]x0.1 = 0 (10)
Structural infiltration: 0.25 for steel or timber frame or 0.35 for masonry construction (11)0if both types of wall are present, use the value corresponding to the greater wall area (afterdeducting areas of openings); if equal user 0.35
If suspended wooden floor, enter 0.2 (unsealed) or 0.1 (sealed), else enter 0 (12)0
If no draught lobby, enter 0.05, else enter 0 (13)0
Percentage of windows and doors draught stripped (14)0
Air permeability value, q50, expressed in cubic metres per hour per square metre of envelope area (17)15
If based on air permeability value, then (18) = [(17) ÷ 20]+(8), otherwise (18) = (16) (18)0.8Air permeability value applies if a pressurisation test has been done or a degree air permeability is being used
Number of sides sheltered (19)2Shelter factor (20) = 1 - [0.075 x (19)] = (20)0.85
b) If balanced mechanical ventilation without heat recovery (MV) (24b)m = (22b)m + (23b)(24b)(24b)m= 0 0 0 0 0 0 0 0 0 0 0 0
c) If whole house extract ventilation or positive input ventilation from outsideif (22b)m < 0.5 × (23b), then (24c) = (23b); otherwise (24c) = (22b) m + 0.5 × (23b)
(24c)(24c)m= 0 0 0 0 0 0 0 0 0 0 0 0
d) If natural ventilation or whole house positive input ventilation from loftif (22b)m = 1, then (24d)m = (22b)m otherwise (24d)m = 0.5 + [(22b)m² x 0.5]
SAP WorkSheet: New dwelling created by change of use
* for windows and roof windows, use effective window U-value calculated using formula 1/[(1/U-value)+0.04] as given in paragraph 3.2** include the areas on both sides of internal walls and partitions
Fabric heat loss, W/K = S (A x U) (26)…(30) + (32) = (33)175.84
Heat capacity Cm = S(A x k ) (34)((28)…(30) + (32) + (32a)…(32e) = 25360.81
Thermal mass parameter (TMP = Cm ÷ TFA) in kJ/m²K (35)Indicative Value: Medium 250
For design assessments where the details of the construction are not known precisely the indicative values of TMP in Table 1fcan be used instead of a detailed calculation.
Thermal bridges : S (L x Y) calculated using Appendix K (36)97.38
if details of thermal bridging are not known (36) = 0.05 x (31)
Total fabric heat loss (37)(33) + (36) = 273.21
Ventilation heat loss calculated monthly (38)m = 0.33 × (25)m x (5)
Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec225.11 221.36 217.67 200.37 197.13 182.05 182.05 179.26 187.86 197.13 203.68 210.53(38)m= (38)
Heat transfer coefficient, W/K (39)m = (37) + (38)m
Average = Sum(40) /12=1…12 (40)1.97Number of days in month (Table 1a)
Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec(41)m= 31 28 31 30 31 30 31 31 30 31 30 31 (41)
4. Water heating energy requirement: kWh/year:
Assumed occupancy, N (42)3.05if TFA > 13.9, N = 1 + 1.76 x [1 - exp(-0.000349 x (TFA -13.9)2)] + 0.0013 x (TFA -13.9)if TFA £ 13.9, N = 1
Annual average hot water usage in litres per day Vd,average = (25 x N) + 36 (43)106.74Reduce the annual average hot water usage by 5% if the dwelling is designed to achieve a water use target ofnot more that 125 litres per person per day (all water use, hot and cold)
Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov DecHot water usage in litres per day for each month Vd,m = factor from Table 1c x (43)
Total = Sum(44) =1…12 (44)1280.93Energy content of hot water used - calculated monthly = 4.190 x Vd,m x nm x DTm / 3600 kWh/month (see Tables 1b, 1c, 1d)
Total = Sum(45) =1…12 (45)1679.5If instantaneous water heating at point of use (no hot water storage), enter 0 in boxes (46) to (61)
(46)m= (46)26.12 22.84 23.57 20.55 19.72 17.02 15.77 18.09 18.31 21.34 23.29 25.3Water storage loss:Storage volume (litres) including any solar or WWHRS storage within same vessel (47)300
If community heating and no tank in dwelling, enter 110 litres in (47)Otherwise if no stored hot water (this includes instantaneous combi boilers) enter ‘0’ in (47)Water storage loss: a) If manufacturer’s declared loss factor is known (kWh/day): (48)2.03
SAP WorkSheet: New dwelling created by change of use
Energy lost from water storage, kWh/year (50)(48) x (49) = 1.1 b) If manufacturer’s declared cylinder loss factor is not known:Hot water storage loss factor from Table 2 (kWh/litre/day) (51)0If community heating see section 4.3Volume factor from Table 2a (52)0Temperature factor from Table 2b (53)0
Energy lost from water storage, kWh/year (47) x (51) x (52) x (53) = (54)0 Enter (50) or (54) in (55) (55)1.1
Water storage loss calculated for each month ((56)m = (55) × (41)m
Primary circuit loss calculated for each month (59)m = (58) ÷ 365 × (41)m(modified by factor from Table H5 if there is solar water heating and a cylinder thermostat)
Mean internal temperature in living area T1 (follow steps 3 to 7 in Table 9c)(87)(87)m= 19.13 19.27 19.54 19.94 20.32 20.65 20.81 20.77 20.49 20.01 19.54 19.15
Temperature during heating periods in rest of dwelling from Table 9, Th2 (°C)(88)(88)m= 19.29 19.3 19.31 19.35 19.36 19.41 19.41 19.41 19.39 19.36 19.34 19.33
Utilisation factor for gains for rest of dwelling, h2,m (see Table 9a)(89)(89)m= 1 1 0.99 0.97 0.92 0.78 0.58 0.65 0.9 0.98 1 1
Mean internal temperature in the rest of dwelling T2 (follow steps 3 to 7 in Table 9c)(90)(90)m= 16.87 17.07 17.47 18.09 18.63 19.1 19.25 19.23 18.9 18.2 17.49 16.92
fLA = Living area ÷ (4) = (91)0.43
Mean internal temperature (for the whole dwelling) = fLA × T1 + (1 – fLA) × T2(92)(92)m= 17.84 18.02 18.35 18.88 19.36 19.76 19.92 19.89 19.58 18.98 18.37 17.88
Apply adjustment to the mean internal temperature from Table 4e, where appropriate(93)(93)m= 17.69 17.87 18.2 18.73 19.21 19.61 19.77 19.74 19.43 18.83 18.22 17.73
8. Space heating requirementSet Ti to the mean internal temperature obtained at step 11 of Table 9b, so that Ti,m=(76)m and re-calculatethe utilisation factor for gains using Table 9a
Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov DecStroma FSAP 2012 Version: 1.0.4.18 (SAP 9.92) - http://www.stroma.com Page 8 of 11
SAP WorkSheet: New dwelling created by change of use
Monthly average external temperature from Table 8(96)(96)m= 4.3 4.9 6.5 8.9 11.7 14.6 16.6 16.4 14.1 10.6 7.1 4.2
Heat loss rate for mean internal temperature, Lm , W =[(39)m x [(93)m– (96)m ](97)(97)m= 6672.27 6412.55 5745.58 4656.1 3531.06 2283 1442.31 1513.26 2459.77 3871.18 5303.26 6543.33
Space heating requirement for each month, kWh/month = 0.024 x [(97)m – (95)m] x (41)m(98)m= 4062.18 3361.59 3064.97 2012.04 1170.09 0 0 0 0 1888.88 2962.7 4014.81
Total per year (kWh/year) = Sum(98) =1...5,9...12 (98)22537.28
Space heating requirement in kWh/m²/year (99)93.74
9a. Energy requirements – Individual heating systems including micro-CHP)Space heating:Fraction of space heat from secondary/supplementary system (201)0
Fraction of space heat from main system(s) (202)(202) = 1 – (201) = 1
Fraction of total heating from main system 1 (204) = (202) × [1 – (203)] = (204)1
Efficiency of main space heating system 1 (206)86.6
Efficiency of secondary/supplementary heating system, % (208)0
Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec kWh/yearSpace heating requirement (calculated above)
Space heating - main system 1 (211) x x 0.01 = (240)1415.745.44
Space heating - main system 2 (213) x x 0.01 = (241)00
Space heating - secondary (215) x x 0.01 = (242)013.19
Water heating cost (other fuel) (219) x 0.01 = (247)5.44 155.82
Pumps, fans and electric keep-hot (231) x 0.01 = (249)13.19 17.15
(if off-peak tariff, list each of (230a) to (230g) separately as applicable and apply fuel price according to Table 12aEnergy for lighting (232) x 0.01 = (250)13.19 87.55
Additional standing charges (Table 12) (251)0
Appendix Q items: repeat lines (253) and (254) as neededTotal energy cost (245)...(247) + (250)…(254) = (255)1676.25
11a. SAP rating - individual heating systems
Energy cost deflator (Table 12) (256)0.42
Energy cost factor (ECF) [(255) x (256)] ÷ [(4) + 45.0] = (257)2.47
SAP rating (Section 12) (258)65.59
12a. CO2 emissions – Individual heating systems including micro-CHP
Energy Emission factor EmissionskWh/year kg CO2/kWh kg CO2/year
Space heating (main system 1) (211) x = (261)0.298 7755.32
Space heating (secondary) (215) x = (263)0.519 0
Water heating (219) x = (264)0.298 853.56
Space and water heating (261) + (262) + (263) + (264) = (265)8608.88
Electricity for pumps, fans and electric keep-hot (231) x = (267)0.519 67.47
Electricity for lighting (232) x = (268)0.519 344.49
Total CO2, kg/year sum of (265)…(271) = (272)9020.84
CO2 emissions per m² (272) ÷ (4) = (273)37.52
EI rating (section 14) (274)58
13a. Primary Energy
Energy Primary P. EnergykWh/year factor kWh/year
Space heating (main system 1) (211) x = (261)1.1 28627.03
2. Ventilation rate:main secondary other total m³ per hourheating heating
Number of chimneys + + = x 40 = (6a)0 0 0 0 0
Number of open flues + + = x 20 = (6b)0 0 0 0 0
Number of intermittent fans x 10 = (7a)4 40
Number of passive vents x 10 = (7b)0 0
Number of flueless gas fires x 40 = (7c)0 0
Air changes per hour
Infiltration due to chimneys, flues and fans = (6a)+(6b)+(7a)+(7b)+(7c) = (8)÷ (5) = 0.0540If a pressurisation test has been carried out or is intended, proceed to (17), otherwise continue from (9) to (16)
Number of storeys in the dwelling (ns) (9)0
Additional infiltration [(9)-1]x0.1 = 0 (10)
Structural infiltration: 0.25 for steel or timber frame or 0.35 for masonry construction (11)0if both types of wall are present, use the value corresponding to the greater wall area (afterdeducting areas of openings); if equal user 0.35
If suspended wooden floor, enter 0.2 (unsealed) or 0.1 (sealed), else enter 0 (12)0
If no draught lobby, enter 0.05, else enter 0 (13)0
Percentage of windows and doors draught stripped (14)0
Air permeability value, q50, expressed in cubic metres per hour per square metre of envelope area (17)15
If based on air permeability value, then (18) = [(17) ÷ 20]+(8), otherwise (18) = (16) (18)0.8Air permeability value applies if a pressurisation test has been done or a degree air permeability is being used
Number of sides sheltered (19)2Shelter factor (20) = 1 - [0.075 x (19)] = (20)0.85
b) If balanced mechanical ventilation without heat recovery (MV) (24b)m = (22b)m + (23b)(24b)(24b)m= 0 0 0 0 0 0 0 0 0 0 0 0
c) If whole house extract ventilation or positive input ventilation from outsideif (22b)m < 0.5 × (23b), then (24c) = (23b); otherwise (24c) = (22b) m + 0.5 × (23b)
(24c)(24c)m= 0 0 0 0 0 0 0 0 0 0 0 0
d) If natural ventilation or whole house positive input ventilation from loftif (22b)m = 1, then (24d)m = (22b)m otherwise (24d)m = 0.5 + [(22b)m² x 0.5]
EPC Costs WorkSheet: New dwelling created by change of use
* for windows and roof windows, use effective window U-value calculated using formula 1/[(1/U-value)+0.04] as given in paragraph 3.2** include the areas on both sides of internal walls and partitions
Fabric heat loss, W/K = S (A x U) (26)…(30) + (32) = (33)175.84
Heat capacity Cm = S(A x k ) (34)((28)…(30) + (32) + (32a)…(32e) = 25360.81
Thermal mass parameter (TMP = Cm ÷ TFA) in kJ/m²K (35)Indicative Value: Medium 250
For design assessments where the details of the construction are not known precisely the indicative values of TMP in Table 1fcan be used instead of a detailed calculation.
Thermal bridges : S (L x Y) calculated using Appendix K (36)97.38
if details of thermal bridging are not known (36) = 0.05 x (31)
Total fabric heat loss (37)(33) + (36) = 273.21
Ventilation heat loss calculated monthly (38)m = 0.33 × (25)m x (5)
Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec207.06 200.37 200.37 184.92 184.92 171.34 173.9 176.55 179.26 184.92 184.92 193.96(38)m= (38)
Heat transfer coefficient, W/K (39)m = (37) + (38)m
Average = Sum(40) /12=1…12 (40)1.91Number of days in month (Table 1a)
Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec(41)m= 31 28 31 30 31 30 31 31 30 31 30 31 (41)
4. Water heating energy requirement: kWh/year:
Assumed occupancy, N (42)3.05if TFA > 13.9, N = 1 + 1.76 x [1 - exp(-0.000349 x (TFA -13.9)2)] + 0.0013 x (TFA -13.9)if TFA £ 13.9, N = 1
Annual average hot water usage in litres per day Vd,average = (25 x N) + 36 (43)106.74Reduce the annual average hot water usage by 5% if the dwelling is designed to achieve a water use target ofnot more that 125 litres per person per day (all water use, hot and cold)
Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov DecHot water usage in litres per day for each month Vd,m = factor from Table 1c x (43)
Total = Sum(44) =1…12 (44)1280.93Energy content of hot water used - calculated monthly = 4.190 x Vd,m x nm x DTm / 3600 kWh/month (see Tables 1b, 1c, 1d)
Total = Sum(45) =1…12 (45)1679.5If instantaneous water heating at point of use (no hot water storage), enter 0 in boxes (46) to (61)
(46)m= (46)26.12 22.84 23.57 20.55 19.72 17.02 15.77 18.09 18.31 21.34 23.29 25.3Water storage loss:Storage volume (litres) including any solar or WWHRS storage within same vessel (47)300
If community heating and no tank in dwelling, enter 110 litres in (47)Otherwise if no stored hot water (this includes instantaneous combi boilers) enter ‘0’ in (47)Water storage loss: a) If manufacturer’s declared loss factor is known (kWh/day): (48)2.03
EPC Costs WorkSheet: New dwelling created by change of use
Energy lost from water storage, kWh/year (50)(48) x (49) = 1.1 b) If manufacturer’s declared cylinder loss factor is not known:Hot water storage loss factor from Table 2 (kWh/litre/day) (51)0If community heating see section 4.3Volume factor from Table 2a (52)0Temperature factor from Table 2b (53)0
Energy lost from water storage, kWh/year (47) x (51) x (52) x (53) = (54)0 Enter (50) or (54) in (55) (55)1.1
Water storage loss calculated for each month ((56)m = (55) × (41)m
Primary circuit loss calculated for each month (59)m = (58) ÷ 365 × (41)m(modified by factor from Table H5 if there is solar water heating and a cylinder thermostat)
Mean internal temperature in living area T1 (follow steps 3 to 7 in Table 9c)(87)(87)m= 19.22 19.35 19.64 20.04 20.41 20.74 20.87 20.86 20.6 20.12 19.65 19.25
Temperature during heating periods in rest of dwelling from Table 9, Th2 (°C)(88)(88)m= 19.33 19.35 19.35 19.4 19.4 19.44 19.43 19.42 19.41 19.4 19.4 19.37
Utilisation factor for gains for rest of dwelling, h2,m (see Table 9a)(89)(89)m= 1 1 0.99 0.97 0.9 0.69 0.41 0.45 0.85 0.98 1 1
Mean internal temperature in the rest of dwelling T2 (follow steps 3 to 7 in Table 9c)(90)(90)m= 17.03 17.23 17.64 18.25 18.79 19.22 19.3 19.29 19.05 18.38 17.69 17.09
fLA = Living area ÷ (4) = (91)0.43
Mean internal temperature (for the whole dwelling) = fLA × T1 + (1 – fLA) × T2(92)(92)m= 17.97 18.14 18.5 19.02 19.49 19.87 19.98 19.96 19.72 19.13 18.53 18.01
Apply adjustment to the mean internal temperature from Table 4e, where appropriate(93)(93)m= 17.82 17.99 18.35 18.87 19.34 19.72 19.83 19.81 19.57 18.98 18.38 17.86
8. Space heating requirementSet Ti to the mean internal temperature obtained at step 11 of Table 9b, so that Ti,m=(76)m and re-calculatethe utilisation factor for gains using Table 9a
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EPC Costs WorkSheet: New dwelling created by change of use
Monthly average external temperature from Table 8(96)(96)m= 4.5 5 6.9 9.3 12.3 15.3 17.4 17.4 14.8 11.2 7.5 4.5
Heat loss rate for mean internal temperature, Lm , W =[(39)m x [(93)m– (96)m ](97)(97)m= 6397.87 6151.11 5421.8 4384.11 3223 1966.03 1084.87 1085.66 2156.13 3564.05 4984.86 6243.81
Space heating requirement for each month, kWh/month = 0.024 x [(97)m – (95)m] x (41)m(98)m= 3836.06 3181.61 2821.66 1793.61 960.24 0 0 0 0 1633.93 2701.95 3775.37
Total per year (kWh/year) = Sum(98) =1...5,9...12 (98)20704.43
Space heating requirement in kWh/m²/year (99)86.12
9a. Energy requirements – Individual heating systems including micro-CHP)Space heating:Fraction of space heat from secondary/supplementary system (201)0
Fraction of space heat from main system(s) (202)(202) = 1 – (201) = 1
Fraction of total heating from main system 1 (204) = (202) × [1 – (203)] = (204)1
Efficiency of main space heating system 1 (206)86.6
Efficiency of secondary/supplementary heating system, % (208)0
Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec kWh/yearSpace heating requirement (calculated above)
Space heating - main system 1 (211) x x 0.01 = (240)10404.35
Space heating - main system 2 (213) x x 0.01 = (241)00
Space heating - secondary (215) x x 0.01 = (242)017.56
Water heating cost (other fuel) (219) x 0.01 = (247)4.35 124.7
Pumps, fans and electric keep-hot (231) x 0.01 = (249)0 22.83
(if off-peak tariff, list each of (230a) to (230g) separately as applicable and apply fuel price according to Table 12aEnergy for lighting (232) x 0.01 = (250)0 116.56
Additional standing charges (Table 12) (251)0
Appendix Q items: repeat lines (253) and (254) as neededTotal energy cost (245)...(247) + (250)…(254) = (255)1304.09
11a. SAP rating - individual heating systems
Energy cost deflator (Table 12) (256)0.42
Energy cost factor (ECF) [(255) x (256)] ÷ [(4) + 45.0] = (257)2.3
SAP rating (Section 12) (258)67.95
12a. CO2 emissions – Individual heating systems including micro-CHP
Energy Emission factor EmissionskWh/year kg CO2/kWh kg CO2/year
Space heating (main system 1) (211) x = (261)0.298 7124.62
Space heating (secondary) (215) x = (263)0.519 0
Water heating (219) x = (264)0.298 854.29
Space and water heating (261) + (262) + (263) + (264) = (265)7978.91
Electricity for pumps, fans and electric keep-hot (231) x = (267)0.519 67.47
Electricity for lighting (232) x = (268)0.519 344.49
Total CO2, kg/year sum of (265)…(271) = (272)8390.87
Dwelling CO2 Emission Rate (272) ÷ (4) = (273)34.9
EI rating (section 14) (274)61
13a. Primary Energy
Energy Primary P. EnergykWh/year factor kWh/year
Space heating (main system 1) (211) x = (261)1.1 26298.93
2. Ventilation rate:main secondary other total m³ per hourheating heating
Number of chimneys + + = x 40 = (6a)0 0 0 0 0
Number of open flues + + = x 20 = (6b)0 0 0 0 0
Number of intermittent fans x 10 = (7a)4 40
Number of passive vents x 10 = (7b)0 0
Number of flueless gas fires x 40 = (7c)0 0
Air changes per hour
Infiltration due to chimneys, flues and fans = (6a)+(6b)+(7a)+(7b)+(7c) = (8)÷ (5) = 0.0540If a pressurisation test has been carried out or is intended, proceed to (17), otherwise continue from (9) to (16)
Number of storeys in the dwelling (ns) (9)0
Additional infiltration [(9)-1]x0.1 = 0 (10)
Structural infiltration: 0.25 for steel or timber frame or 0.35 for masonry construction (11)0if both types of wall are present, use the value corresponding to the greater wall area (afterdeducting areas of openings); if equal user 0.35
If suspended wooden floor, enter 0.2 (unsealed) or 0.1 (sealed), else enter 0 (12)0
If no draught lobby, enter 0.05, else enter 0 (13)0
Percentage of windows and doors draught stripped (14)0
Air permeability value, q50, expressed in cubic metres per hour per square metre of envelope area (17)5
If based on air permeability value, then (18) = [(17) ÷ 20]+(8), otherwise (18) = (16) (18)0.3Air permeability value applies if a pressurisation test has been done or a degree air permeability is being used
Number of sides sheltered (19)2Shelter factor (20) = 1 - [0.075 x (19)] = (20)0.85
b) If balanced mechanical ventilation without heat recovery (MV) (24b)m = (22b)m + (23b)(24b)(24b)m= 0 0 0 0 0 0 0 0 0 0 0 0
c) If whole house extract ventilation or positive input ventilation from outsideif (22b)m < 0.5 × (23b), then (24c) = (23b); otherwise (24c) = (22b) m + 0.5 × (23b)
(24c)(24c)m= 0 0 0 0 0 0 0 0 0 0 0 0
d) If natural ventilation or whole house positive input ventilation from loftif (22b)m = 1, then (24d)m = (22b)m otherwise (24d)m = 0.5 + [(22b)m² x 0.5]
TFEE WorkSheet: New dwelling created by change of use
* for windows and roof windows, use effective window U-value calculated using formula 1/[(1/U-value)+0.04] as given in paragraph 3.2** include the areas on both sides of internal walls and partitions
Fabric heat loss, W/K = S (A x U) (26)…(30) + (32) = (33)140.94
Heat capacity Cm = S(A x k ) (34)((28)…(30) + (32) + (32a)…(32e) = 25360.81
Thermal mass parameter (TMP = Cm ÷ TFA) in kJ/m²K (35)Indicative Value: Medium 250
For design assessments where the details of the construction are not known precisely the indicative values of TMP in Table 1fcan be used instead of a detailed calculation.
Thermal bridges : S (L x Y) calculated using Appendix K (36)32.46
if details of thermal bridging are not known (36) = 0.05 x (31)
Total fabric heat loss (37)(33) + (36) = 173.4
Ventilation heat loss calculated monthly (38)m = 0.33 × (25)m x (5)
Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec142.01 141.48 140.96 138.51 138.05 135.92 135.92 135.52 136.74 138.05 138.98 139.94(38)m= (38)
Heat transfer coefficient, W/K (39)m = (37) + (38)m
Average = Sum(40) /12=1…12 (40)1.3Number of days in month (Table 1a)
Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec(41)m= 31 28 31 30 31 30 31 31 30 31 30 31 (41)
4. Water heating energy requirement: kWh/year:
Assumed occupancy, N (42)3.05if TFA > 13.9, N = 1 + 1.76 x [1 - exp(-0.000349 x (TFA -13.9)2)] + 0.0013 x (TFA -13.9)if TFA £ 13.9, N = 1
Annual average hot water usage in litres per day Vd,average = (25 x N) + 36 (43)106.74Reduce the annual average hot water usage by 5% if the dwelling is designed to achieve a water use target ofnot more that 125 litres per person per day (all water use, hot and cold)
Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov DecHot water usage in litres per day for each month Vd,m = factor from Table 1c x (43)
Total = Sum(44) =1…12 (44)1280.93Energy content of hot water used - calculated monthly = 4.190 x Vd,m x nm x DTm / 3600 kWh/month (see Tables 1b, 1c, 1d)
Total = Sum(45) =1…12 (45)1679.5If instantaneous water heating at point of use (no hot water storage), enter 0 in boxes (46) to (61)
(46)m= (46)0 0 0 0 0 0 0 0 0 0 0 0Water storage loss:Storage volume (litres) including any solar or WWHRS storage within same vessel (47)150
If community heating and no tank in dwelling, enter 110 litres in (47)Otherwise if no stored hot water (this includes instantaneous combi boilers) enter ‘0’ in (47)Water storage loss: a) If manufacturer’s declared loss factor is known (kWh/day): (48)0
TFEE WorkSheet: New dwelling created by change of use
Energy lost from water storage, kWh/year (50)(48) x (49) = 0 b) If manufacturer’s declared cylinder loss factor is not known:Hot water storage loss factor from Table 2 (kWh/litre/day) (51)0If community heating see section 4.3Volume factor from Table 2a (52)0Temperature factor from Table 2b (53)0
Energy lost from water storage, kWh/year (47) x (51) x (52) x (53) = (54)0 Enter (50) or (54) in (55) (55)0
Water storage loss calculated for each month ((56)m = (55) × (41)m
(56)m= (56)0 0 0 0 0 0 0 0 0 0 0 0
If cylinder contains dedicated solar storage, (57)m = (56)m x [(50) – (H11)] ÷ (50), else (57)m = (56)m where (H11) is from Appendix H
(57)m= (57)0 0 0 0 0 0 0 0 0 0 0 0
Primary circuit loss (annual) from Table 3 (58)0
Primary circuit loss calculated for each month (59)m = (58) ÷ 365 × (41)m(modified by factor from Table H5 if there is solar water heating and a cylinder thermostat)
(59)m= (59)0 0 0 0 0 0 0 0 0 0 0 0
Combi loss calculated for each month (61)m = (60) ÷ 365 × (41)m(61)m= (61)0 0 0 0 0 0 0 0 0 0 0 0
Total heat required for water heating calculated for each month (62)m = 0.85 × (45)m + (46)m + (57)m + (59)m + (61)m(62)m= (62)148.01 129.45 133.58 116.46 111.74 96.43 89.35 102.53 103.76 120.92 132 143.34
Solar DHW input calculated using Appendix G or Appendix H (negative quantity) (enter '0' if no solar contribution to water heating)
Mean internal temperature in living area T1 (follow steps 3 to 7 in Table 9c)(87)(87)m= 19.3 19.44 19.72 20.11 20.51 20.81 20.94 20.9 20.62 20.13 19.65 19.28
Temperature during heating periods in rest of dwelling from Table 9, Th2 (°C)(88)(88)m= 19.83 19.83 19.83 19.84 19.84 19.85 19.85 19.85 19.85 19.84 19.84 19.84
Utilisation factor for gains for rest of dwelling, h2,m (see Table 9a)(89)(89)m= 1 1 1 0.99 0.95 0.81 0.6 0.7 0.94 1 1 1
Mean internal temperature in the rest of dwelling T2 (follow steps 3 to 7 in Table 9c)(90)(90)m= 18.27 18.41 18.69 19.09 19.47 19.75 19.83 19.82 19.59 19.11 18.62 18.25
fLA = Living area ÷ (4) = (91)0.43
Mean internal temperature (for the whole dwelling) = fLA × T1 + (1 – fLA) × T2(92)(92)m= 18.71 18.86 19.13 19.53 19.92 20.2 20.31 20.28 20.03 19.54 19.06 18.69
Apply adjustment to the mean internal temperature from Table 4e, where appropriate(93)(93)m= 18.71 18.86 19.13 19.53 19.92 20.2 20.31 20.28 20.03 19.54 19.06 18.69
8. Space heating requirementSet Ti to the mean internal temperature obtained at step 11 of Table 9b, so that Ti,m=(76)m and re-calculatethe utilisation factor for gains using Table 9a
Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov DecStroma FSAP 2012 Version: 1.0.4.18 (SAP 9.92) - http://www.stroma.com Page 8 of 9
TFEE WorkSheet: New dwelling created by change of use
2. Ventilation rate:main secondary other total m³ per hourheating heating
Number of chimneys + + = x 40 = (6a)0 0 0 0 0
Number of open flues + + = x 20 = (6b)0 0 0 0 0
Number of intermittent fans x 10 = (7a)4 40
Number of passive vents x 10 = (7b)0 0
Number of flueless gas fires x 40 = (7c)0 0
Air changes per hour
Infiltration due to chimneys, flues and fans = (6a)+(6b)+(7a)+(7b)+(7c) = (8)÷ (5) = 0.0540If a pressurisation test has been carried out or is intended, proceed to (17), otherwise continue from (9) to (16)
Number of storeys in the dwelling (ns) (9)0
Additional infiltration [(9)-1]x0.1 = 0 (10)
Structural infiltration: 0.25 for steel or timber frame or 0.35 for masonry construction (11)0if both types of wall are present, use the value corresponding to the greater wall area (afterdeducting areas of openings); if equal user 0.35
If suspended wooden floor, enter 0.2 (unsealed) or 0.1 (sealed), else enter 0 (12)0
If no draught lobby, enter 0.05, else enter 0 (13)0
Percentage of windows and doors draught stripped (14)0
Air permeability value, q50, expressed in cubic metres per hour per square metre of envelope area (17)15
If based on air permeability value, then (18) = [(17) ÷ 20]+(8), otherwise (18) = (16) (18)0.8Air permeability value applies if a pressurisation test has been done or a degree air permeability is being used
Number of sides sheltered (19)2Shelter factor (20) = 1 - [0.075 x (19)] = (20)0.85
b) If balanced mechanical ventilation without heat recovery (MV) (24b)m = (22b)m + (23b)(24b)(24b)m= 0 0 0 0 0 0 0 0 0 0 0 0
c) If whole house extract ventilation or positive input ventilation from outsideif (22b)m < 0.5 × (23b), then (24c) = (23b); otherwise (24c) = (22b) m + 0.5 × (23b)
(24c)(24c)m= 0 0 0 0 0 0 0 0 0 0 0 0
d) If natural ventilation or whole house positive input ventilation from loftif (22b)m = 1, then (24d)m = (22b)m otherwise (24d)m = 0.5 + [(22b)m² x 0.5]
DFEE WorkSheet: New dwelling created by change of use
* for windows and roof windows, use effective window U-value calculated using formula 1/[(1/U-value)+0.04] as given in paragraph 3.2** include the areas on both sides of internal walls and partitions
Fabric heat loss, W/K = S (A x U) (26)…(30) + (32) = (33)175.84
Heat capacity Cm = S(A x k ) (34)((28)…(30) + (32) + (32a)…(32e) = 25360.81
Thermal mass parameter (TMP = Cm ÷ TFA) in kJ/m²K (35)Indicative Value: Medium 250
For design assessments where the details of the construction are not known precisely the indicative values of TMP in Table 1fcan be used instead of a detailed calculation.
Thermal bridges : S (L x Y) calculated using Appendix K (36)97.38
if details of thermal bridging are not known (36) = 0.05 x (31)
Total fabric heat loss (37)(33) + (36) = 273.21
Ventilation heat loss calculated monthly (38)m = 0.33 × (25)m x (5)
Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec225.11 221.36 217.67 200.37 197.13 182.05 182.05 179.26 187.86 197.13 203.68 210.53(38)m= (38)
Heat transfer coefficient, W/K (39)m = (37) + (38)m
Average = Sum(40) /12=1…12 (40)1.97Number of days in month (Table 1a)
Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec(41)m= 31 28 31 30 31 30 31 31 30 31 30 31 (41)
4. Water heating energy requirement: kWh/year:
Assumed occupancy, N (42)3.05if TFA > 13.9, N = 1 + 1.76 x [1 - exp(-0.000349 x (TFA -13.9)2)] + 0.0013 x (TFA -13.9)if TFA £ 13.9, N = 1
Annual average hot water usage in litres per day Vd,average = (25 x N) + 36 (43)106.74Reduce the annual average hot water usage by 5% if the dwelling is designed to achieve a water use target ofnot more that 125 litres per person per day (all water use, hot and cold)
Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov DecHot water usage in litres per day for each month Vd,m = factor from Table 1c x (43)
Total = Sum(44) =1…12 (44)1280.93Energy content of hot water used - calculated monthly = 4.190 x Vd,m x nm x DTm / 3600 kWh/month (see Tables 1b, 1c, 1d)
Total = Sum(45) =1…12 (45)1679.5If instantaneous water heating at point of use (no hot water storage), enter 0 in boxes (46) to (61)
(46)m= (46)0 0 0 0 0 0 0 0 0 0 0 0Water storage loss:Storage volume (litres) including any solar or WWHRS storage within same vessel (47)300
If community heating and no tank in dwelling, enter 110 litres in (47)Otherwise if no stored hot water (this includes instantaneous combi boilers) enter ‘0’ in (47)Water storage loss: a) If manufacturer’s declared loss factor is known (kWh/day): (48)0
DFEE WorkSheet: New dwelling created by change of use
Energy lost from water storage, kWh/year (50)(48) x (49) = 0 b) If manufacturer’s declared cylinder loss factor is not known:Hot water storage loss factor from Table 2 (kWh/litre/day) (51)0If community heating see section 4.3Volume factor from Table 2a (52)0Temperature factor from Table 2b (53)0
Energy lost from water storage, kWh/year (47) x (51) x (52) x (53) = (54)0 Enter (50) or (54) in (55) (55)0
Water storage loss calculated for each month ((56)m = (55) × (41)m
(56)m= (56)0 0 0 0 0 0 0 0 0 0 0 0
If cylinder contains dedicated solar storage, (57)m = (56)m x [(50) – (H11)] ÷ (50), else (57)m = (56)m where (H11) is from Appendix H
(57)m= (57)0 0 0 0 0 0 0 0 0 0 0 0
Primary circuit loss (annual) from Table 3 (58)0
Primary circuit loss calculated for each month (59)m = (58) ÷ 365 × (41)m(modified by factor from Table H5 if there is solar water heating and a cylinder thermostat)
(59)m= (59)0 0 0 0 0 0 0 0 0 0 0 0
Combi loss calculated for each month (61)m = (60) ÷ 365 × (41)m(61)m= (61)0 0 0 0 0 0 0 0 0 0 0 0
Total heat required for water heating calculated for each month (62)m = 0.85 × (45)m + (46)m + (57)m + (59)m + (61)m(62)m= (62)148.01 129.45 133.58 116.46 111.74 96.43 89.35 102.53 103.76 120.92 132 143.34
Solar DHW input calculated using Appendix G or Appendix H (negative quantity) (enter '0' if no solar contribution to water heating)
Mean internal temperature in living area T1 (follow steps 3 to 7 in Table 9c)(87)(87)m= 18.49 18.67 19.03 19.58 20.1 20.57 20.8 20.74 20.33 19.67 19.03 18.51
Temperature during heating periods in rest of dwelling from Table 9, Th2 (°C)(88)(88)m= 19.29 19.3 19.31 19.35 19.36 19.41 19.41 19.41 19.39 19.36 19.34 19.33
Utilisation factor for gains for rest of dwelling, h2,m (see Table 9a)(89)(89)m= 1 1 1 0.99 0.95 0.84 0.65 0.73 0.95 0.99 1 1
Mean internal temperature in the rest of dwelling T2 (follow steps 3 to 7 in Table 9c)(90)(90)m= 17.06 17.25 17.61 18.19 18.71 19.18 19.35 19.33 18.96 18.3 17.64 17.11
fLA = Living area ÷ (4) = (91)0.43
Mean internal temperature (for the whole dwelling) = fLA × T1 + (1 – fLA) × T2(92)(92)m= 17.67 17.86 18.22 18.79 19.31 19.77 19.97 19.93 19.55 18.89 18.24 17.71
Apply adjustment to the mean internal temperature from Table 4e, where appropriate(93)(93)m= 17.67 17.86 18.22 18.79 19.31 19.77 19.97 19.93 19.55 18.89 18.24 17.71
8. Space heating requirementSet Ti to the mean internal temperature obtained at step 11 of Table 9b, so that Ti,m=(76)m and re-calculatethe utilisation factor for gains using Table 9a
Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov DecStroma FSAP 2012 Version: 1.0.4.18 (SAP 9.92) - http://www.stroma.com Page 8 of 9
DFEE WorkSheet: New dwelling created by change of use
2. Ventilation rate:main secondary other total m³ per hourheating heating
Number of chimneys + + = x 40 = (6a)0 0 0 0 0
Number of open flues + + = x 20 = (6b)0 0 0 0 0
Number of intermittent fans x 10 = (7a)4 40
Number of passive vents x 10 = (7b)0 0
Number of flueless gas fires x 40 = (7c)0 0
Air changes per hour
Infiltration due to chimneys, flues and fans = (6a)+(6b)+(7a)+(7b)+(7c) = (8)÷ (5) = 0.0540If a pressurisation test has been carried out or is intended, proceed to (17), otherwise continue from (9) to (16)
Number of storeys in the dwelling (ns) (9)0
Additional infiltration [(9)-1]x0.1 = 0 (10)
Structural infiltration: 0.25 for steel or timber frame or 0.35 for masonry construction (11)0if both types of wall are present, use the value corresponding to the greater wall area (afterdeducting areas of openings); if equal user 0.35
If suspended wooden floor, enter 0.2 (unsealed) or 0.1 (sealed), else enter 0 (12)0
If no draught lobby, enter 0.05, else enter 0 (13)0
Percentage of windows and doors draught stripped (14)0
Air permeability value, q50, expressed in cubic metres per hour per square metre of envelope area (17)15
If based on air permeability value, then (18) = [(17) ÷ 20]+(8), otherwise (18) = (16) (18)0.8Air permeability value applies if a pressurisation test has been done or a degree air permeability is being used
Number of sides sheltered (19)2Shelter factor (20) = 1 - [0.075 x (19)] = (20)0.85
b) If balanced mechanical ventilation without heat recovery (MV) (24b)m = (22b)m + (23b)(24b)(24b)m= 0 0 0 0 0 0 0 0 0 0 0 0
c) If whole house extract ventilation or positive input ventilation from outsideif (22b)m < 0.5 × (23b), then (24c) = (23b); otherwise (24c) = (22b) m + 0.5 × (23b)
(24c)(24c)m= 0 0 0 0 0 0 0 0 0 0 0 0
d) If natural ventilation or whole house positive input ventilation from loftif (22b)m = 1, then (24d)m = (22b)m otherwise (24d)m = 0.5 + [(22b)m² x 0.5]
DER WorkSheet: New dwelling created by change of use
* for windows and roof windows, use effective window U-value calculated using formula 1/[(1/U-value)+0.04] as given in paragraph 3.2** include the areas on both sides of internal walls and partitions
Fabric heat loss, W/K = S (A x U) (26)…(30) + (32) = (33)175.84
Heat capacity Cm = S(A x k ) (34)((28)…(30) + (32) + (32a)…(32e) = 25360.81
Thermal mass parameter (TMP = Cm ÷ TFA) in kJ/m²K (35)Indicative Value: Medium 250
For design assessments where the details of the construction are not known precisely the indicative values of TMP in Table 1fcan be used instead of a detailed calculation.
Thermal bridges : S (L x Y) calculated using Appendix K (36)97.38
if details of thermal bridging are not known (36) = 0.05 x (31)
Total fabric heat loss (37)(33) + (36) = 273.21
Ventilation heat loss calculated monthly (38)m = 0.33 × (25)m x (5)
Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec225.11 221.36 217.67 200.37 197.13 182.05 182.05 179.26 187.86 197.13 203.68 210.53(38)m= (38)
Heat transfer coefficient, W/K (39)m = (37) + (38)m
Average = Sum(40) /12=1…12 (40)1.97Number of days in month (Table 1a)
Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec(41)m= 31 28 31 30 31 30 31 31 30 31 30 31 (41)
4. Water heating energy requirement: kWh/year:
Assumed occupancy, N (42)3.05if TFA > 13.9, N = 1 + 1.76 x [1 - exp(-0.000349 x (TFA -13.9)2)] + 0.0013 x (TFA -13.9)if TFA £ 13.9, N = 1
Annual average hot water usage in litres per day Vd,average = (25 x N) + 36 (43)106.74Reduce the annual average hot water usage by 5% if the dwelling is designed to achieve a water use target ofnot more that 125 litres per person per day (all water use, hot and cold)
Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov DecHot water usage in litres per day for each month Vd,m = factor from Table 1c x (43)
Total = Sum(44) =1…12 (44)1280.93Energy content of hot water used - calculated monthly = 4.190 x Vd,m x nm x DTm / 3600 kWh/month (see Tables 1b, 1c, 1d)
Total = Sum(45) =1…12 (45)1679.5If instantaneous water heating at point of use (no hot water storage), enter 0 in boxes (46) to (61)
(46)m= (46)26.12 22.84 23.57 20.55 19.72 17.02 15.77 18.09 18.31 21.34 23.29 25.3Water storage loss:Storage volume (litres) including any solar or WWHRS storage within same vessel (47)300
If community heating and no tank in dwelling, enter 110 litres in (47)Otherwise if no stored hot water (this includes instantaneous combi boilers) enter ‘0’ in (47)Water storage loss: a) If manufacturer’s declared loss factor is known (kWh/day): (48)2.03
DER WorkSheet: New dwelling created by change of use
Energy lost from water storage, kWh/year (50)(48) x (49) = 1.1 b) If manufacturer’s declared cylinder loss factor is not known:Hot water storage loss factor from Table 2 (kWh/litre/day) (51)0If community heating see section 4.3Volume factor from Table 2a (52)0Temperature factor from Table 2b (53)0
Energy lost from water storage, kWh/year (47) x (51) x (52) x (53) = (54)0 Enter (50) or (54) in (55) (55)1.1
Water storage loss calculated for each month ((56)m = (55) × (41)m
Primary circuit loss calculated for each month (59)m = (58) ÷ 365 × (41)m(modified by factor from Table H5 if there is solar water heating and a cylinder thermostat)
Mean internal temperature in living area T1 (follow steps 3 to 7 in Table 9c)(87)(87)m= 19.06 19.2 19.46 19.88 20.27 20.62 20.78 20.74 20.44 19.95 19.47 19.08
Temperature during heating periods in rest of dwelling from Table 9, Th2 (°C)(88)(88)m= 19.29 19.3 19.31 19.35 19.36 19.41 19.41 19.41 19.39 19.36 19.34 19.33
Utilisation factor for gains for rest of dwelling, h2,m (see Table 9a)(89)(89)m= 1 1 0.99 0.98 0.94 0.83 0.63 0.71 0.93 0.99 1 1
Mean internal temperature in the rest of dwelling T2 (follow steps 3 to 7 in Table 9c)(90)(90)m= 16.75 16.96 17.36 17.99 18.56 19.06 19.24 19.21 18.84 18.11 17.39 16.81
fLA = Living area ÷ (4) = (91)0.43
Mean internal temperature (for the whole dwelling) = fLA × T1 + (1 – fLA) × T2(92)(92)m= 17.74 17.92 18.27 18.8 19.29 19.73 19.9 19.87 19.53 18.9 18.28 17.78
Apply adjustment to the mean internal temperature from Table 4e, where appropriate(93)(93)m= 17.59 17.77 18.12 18.65 19.14 19.58 19.75 19.72 19.38 18.75 18.13 17.63
8. Space heating requirementSet Ti to the mean internal temperature obtained at step 11 of Table 9b, so that Ti,m=(76)m and re-calculatethe utilisation factor for gains using Table 9a
Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov DecStroma FSAP 2012 Version: 1.0.4.18 (SAP 9.92) - http://www.stroma.com Page 8 of 10
DER WorkSheet: New dwelling created by change of use
Monthly average external temperature from Table 8(96)(96)m= 4.3 4.9 6.5 8.9 11.7 14.6 16.6 16.4 14.1 10.6 7.1 4.2
Heat loss rate for mean internal temperature, Lm , W =[(39)m x [(93)m– (96)m ](97)(97)m= 6624.17 6365.6 5701.78 4618.43 3501.56 2265.66 1434.35 1502.04 2432.35 3833.31 5260.45 6497.26
Space heating requirement for each month, kWh/month = 0.024 x [(97)m – (95)m] x (41)m(98)m= 4251.98 3529.48 3238.37 2158.58 1287.28 0 0 0 0 2043.29 3131.74 4201.16
Total per year (kWh/year) = Sum(98) =1...5,9...12 (98)23841.88
Space heating requirement in kWh/m²/year (99)99.17
9a. Energy requirements – Individual heating systems including micro-CHP)Space heating:Fraction of space heat from secondary/supplementary system (201)0
Fraction of space heat from main system(s) (202)(202) = 1 – (201) = 1
Fraction of total heating from main system 1 (204) = (202) × [1 – (203)] = (204)1
Efficiency of main space heating system 1 (206)86.6
Efficiency of secondary/supplementary heating system, % (208)0
Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec kWh/yearSpace heating requirement (calculated above)
2. Ventilation rate:main secondary other total m³ per hourheating heating
Number of chimneys + + = x 40 = (6a)0 0 0 0 0
Number of open flues + + = x 20 = (6b)0 0 0 0 0
Number of intermittent fans x 10 = (7a)4 40
Number of passive vents x 10 = (7b)0 0
Number of flueless gas fires x 40 = (7c)0 0
Air changes per hour
Infiltration due to chimneys, flues and fans = (6a)+(6b)+(7a)+(7b)+(7c) = (8)÷ (5) = 0.0540If a pressurisation test has been carried out or is intended, proceed to (17), otherwise continue from (9) to (16)
Number of storeys in the dwelling (ns) (9)0
Additional infiltration [(9)-1]x0.1 = 0 (10)
Structural infiltration: 0.25 for steel or timber frame or 0.35 for masonry construction (11)0if both types of wall are present, use the value corresponding to the greater wall area (afterdeducting areas of openings); if equal user 0.35
If suspended wooden floor, enter 0.2 (unsealed) or 0.1 (sealed), else enter 0 (12)0
If no draught lobby, enter 0.05, else enter 0 (13)0
Percentage of windows and doors draught stripped (14)0
Air permeability value, q50, expressed in cubic metres per hour per square metre of envelope area (17)5
If based on air permeability value, then (18) = [(17) ÷ 20]+(8), otherwise (18) = (16) (18)0.3Air permeability value applies if a pressurisation test has been done or a degree air permeability is being used
Number of sides sheltered (19)2Shelter factor (20) = 1 - [0.075 x (19)] = (20)0.85
b) If balanced mechanical ventilation without heat recovery (MV) (24b)m = (22b)m + (23b)(24b)(24b)m= 0 0 0 0 0 0 0 0 0 0 0 0
c) If whole house extract ventilation or positive input ventilation from outsideif (22b)m < 0.5 × (23b), then (24c) = (23b); otherwise (24c) = (22b) m + 0.5 × (23b)
(24c)(24c)m= 0 0 0 0 0 0 0 0 0 0 0 0
d) If natural ventilation or whole house positive input ventilation from loftif (22b)m = 1, then (24d)m = (22b)m otherwise (24d)m = 0.5 + [(22b)m² x 0.5]
TER WorkSheet: New dwelling created by change of use
* for windows and roof windows, use effective window U-value calculated using formula 1/[(1/U-value)+0.04] as given in paragraph 3.2** include the areas on both sides of internal walls and partitions
Fabric heat loss, W/K = S (A x U) (26)…(30) + (32) = (33)140.94
Heat capacity Cm = S(A x k ) (34)((28)…(30) + (32) + (32a)…(32e) = 25360.81
Thermal mass parameter (TMP = Cm ÷ TFA) in kJ/m²K (35)Indicative Value: Medium 250
For design assessments where the details of the construction are not known precisely the indicative values of TMP in Table 1fcan be used instead of a detailed calculation.
Thermal bridges : S (L x Y) calculated using Appendix K (36)32.46
if details of thermal bridging are not known (36) = 0.05 x (31)
Total fabric heat loss (37)(33) + (36) = 173.4
Ventilation heat loss calculated monthly (38)m = 0.33 × (25)m x (5)
Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec142.01 141.48 140.96 138.51 138.05 135.92 135.92 135.52 136.74 138.05 138.98 139.94(38)m= (38)
Heat transfer coefficient, W/K (39)m = (37) + (38)m
Average = Sum(40) /12=1…12 (40)1.3Number of days in month (Table 1a)
Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec(41)m= 31 28 31 30 31 30 31 31 30 31 30 31 (41)
4. Water heating energy requirement: kWh/year:
Assumed occupancy, N (42)3.05if TFA > 13.9, N = 1 + 1.76 x [1 - exp(-0.000349 x (TFA -13.9)2)] + 0.0013 x (TFA -13.9)if TFA £ 13.9, N = 1
Annual average hot water usage in litres per day Vd,average = (25 x N) + 36 (43)106.74Reduce the annual average hot water usage by 5% if the dwelling is designed to achieve a water use target ofnot more that 125 litres per person per day (all water use, hot and cold)
Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov DecHot water usage in litres per day for each month Vd,m = factor from Table 1c x (43)
Total = Sum(44) =1…12 (44)1280.93Energy content of hot water used - calculated monthly = 4.190 x Vd,m x nm x DTm / 3600 kWh/month (see Tables 1b, 1c, 1d)
Total = Sum(45) =1…12 (45)1679.5If instantaneous water heating at point of use (no hot water storage), enter 0 in boxes (46) to (61)
(46)m= (46)26.12 22.84 23.57 20.55 19.72 17.02 15.77 18.09 18.31 21.34 23.29 25.3Water storage loss:Storage volume (litres) including any solar or WWHRS storage within same vessel (47)150
If community heating and no tank in dwelling, enter 110 litres in (47)Otherwise if no stored hot water (this includes instantaneous combi boilers) enter ‘0’ in (47)Water storage loss: a) If manufacturer’s declared loss factor is known (kWh/day): (48)2.11
TER WorkSheet: New dwelling created by change of use
Energy lost from water storage, kWh/year (50)(48) x (49) = 1.14 b) If manufacturer’s declared cylinder loss factor is not known:Hot water storage loss factor from Table 2 (kWh/litre/day) (51)0If community heating see section 4.3Volume factor from Table 2a (52)0Temperature factor from Table 2b (53)0
Energy lost from water storage, kWh/year (47) x (51) x (52) x (53) = (54)0 Enter (50) or (54) in (55) (55)1.14
Water storage loss calculated for each month ((56)m = (55) × (41)m
Primary circuit loss calculated for each month (59)m = (58) ÷ 365 × (41)m(modified by factor from Table H5 if there is solar water heating and a cylinder thermostat)
Mean internal temperature in living area T1 (follow steps 3 to 7 in Table 9c)(87)(87)m= 19.33 19.48 19.75 20.14 20.53 20.83 20.94 20.91 20.65 20.16 19.68 19.31
Temperature during heating periods in rest of dwelling from Table 9, Th2 (°C)(88)(88)m= 19.83 19.83 19.83 19.84 19.84 19.85 19.85 19.85 19.85 19.84 19.84 19.84
Utilisation factor for gains for rest of dwelling, h2,m (see Table 9a)(89)(89)m= 1 1 1 0.99 0.94 0.79 0.58 0.67 0.93 0.99 1 1
Mean internal temperature in the rest of dwelling T2 (follow steps 3 to 7 in Table 9c)(90)(90)m= 17.6 17.81 18.21 18.78 19.34 19.72 19.83 19.81 19.51 18.81 18.11 17.57
fLA = Living area ÷ (4) = (91)0.43
Mean internal temperature (for the whole dwelling) = fLA × T1 + (1 – fLA) × T2(92)(92)m= 18.34 18.52 18.87 19.37 19.85 20.19 20.31 20.28 20 19.39 18.78 18.32
Apply adjustment to the mean internal temperature from Table 4e, where appropriate(93)(93)m= 18.34 18.52 18.87 19.37 19.85 20.19 20.31 20.28 20 19.39 18.78 18.32
8. Space heating requirementSet Ti to the mean internal temperature obtained at step 11 of Table 9b, so that Ti,m=(76)m and re-calculatethe utilisation factor for gains using Table 9a
Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov DecStroma FSAP 2012 Version: 1.0.4.18 (SAP 9.92) - http://www.stroma.com Page 8 of 10
TER WorkSheet: New dwelling created by change of use
Monthly average external temperature from Table 8(96)(96)m= 4.3 4.9 6.5 8.9 11.7 14.6 16.6 16.4 14.1 10.6 7.1 4.2
Heat loss rate for mean internal temperature, Lm , W =[(39)m x [(93)m– (96)m ](97)(97)m= 4428.73 4289.73 3888.71 3264.66 2538.87 1729.99 1146.75 1199.35 1829.58 2737.51 3649.68 4423.16
Space heating requirement for each month, kWh/month = 0.024 x [(97)m – (95)m] x (41)m(98)m= 2644.14 2172.73 1951.23 1264.74 675.6 0 0 0 0 1274.57 2000.92 2680.42
Total per year (kWh/year) = Sum(98) =1...5,9...12 (98)14664.36
Space heating requirement in kWh/m²/year (99)60.99
9a. Energy requirements – Individual heating systems including micro-CHP)Space heating:Fraction of space heat from secondary/supplementary system (201)0
Fraction of space heat from main system(s) (202)(202) = 1 – (201) = 1
Fraction of total heating from main system 1 (204) = (202) × [1 – (203)] = (204)1
Efficiency of main space heating system 1 (206)93.5
Efficiency of secondary/supplementary heating system, % (208)0
Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec kWh/yearSpace heating requirement (calculated above)
SAP 2012 Overheating AssessmentCalculated by Stroma FSAP 2012 program, produced and printed on 16 July 2019
Property Details: Barn to Dwelling Conversion
Dwelling type: Detached HouseLocated in: EnglandRegion: East AngliaCross ventilation possible: YesNumber of storeys: 2Front of dwelling faces: EastOvershading: Average or unknownOverhangs: NoneThermal mass parameter: Indicative Value MediumNight ventilation: FalseBlinds, curtains, shutters: Dark-coloured curtain or roller blindVentilation rate during hot weather (ach): 4 ( Windows open half the time)Overheating Details:
Summer ventilation heat loss coefficient: 1026.52 (P1)Transmission heat loss coefficient: 273.2Summer heat loss coefficient: 1299.73 (P2)
June July AugustInternal gains 746.28 716.62 727.73Total summer gains 2209.87 2087.23 1887.69 (P5)Summer gain/loss ratio 1.7 1.61 1.45 (P6)Mean summer external temperature (East Anglia) 15.4 17.6 17.6Thermal mass temperature increment 0.25 0.25 0.25Threshold temperature 17.35 19.46 19.3 (P7)Likelihood of high internal temperature Not significant Not significant Not significant
Assessment of likelihood of high internal temperature: Not significant
