Functions and Their
Graphs
Types of Functions
2. Quadratic FunctionsA quadratic function is a function of the form f(x) = ax2 +bx +c where a, b and c are real numbers and a ≠ 0.Domain: the set of real numbersGraph: parabolaExamples: parabolas parabolas
opening upward opening downward
The graph of any quadratic function is called a parabola. Parabolas are shaped like cups, as shown in the graph below. If the coefficient of x2 is positive, the parabola opens upward; otherwise, the parabola opens downward. The vertex (or turning point) is the minimum or maximum point.
Graphs of Quadratic Functions
Graphing Parabolas Given f(x) = ax2 + bx +c1. Determine whether the parabola opens upward or
downward. If a > 0, it opens upward. If a < 0, it opens downward.
2. Determine the vertex of the parabola. The vertex is
3. The axis of symmetry is
The axis of symmetry divides the parabola into two equal parts such that one part is a mirror image of the other.
a
bacab
44,
2
2
abx2
Graphing Parabolas Given f(x) = ax2 + bx +c4. Find any x-intercepts by replacing f (x) with 0.
Solve the resulting quadratic equation for x. 5. Find the y-intercept by replacing x with zero. 6. Plot the intercepts and vertex. Connect these
points with a smooth curve that is shaped like a cup.
Graph: f(x) = x2 x 2 1. Determine the values of a, b, c. a = 1, b = -1, c = -2 2. Determine whether the parabola opens
upward or downward. Since a > 0, then parabola opens
upward. 3. Find the vertex of the parabola.
abx2
21
)1(2)1(
x
492
21
21
21 2
f
Graph: f(x) = x2 x 2 4. Find the intercepts, if any. x – intercepts: If y = 0, then x = 2, – 1. y – intercept: If x = 0, then y = –2. 5. Plot the intercepts and vertex. Connect
these points with a smooth curve that is shaped like a cup.
Graph: f(x) = x2 x 23
2
1
-1
-2
-3
-6 -4 -2 2 4 6
(0.5,-2.25)
(2,0)(-1,0)
(0,-2)
Graph: f(x)=15 2xx2 1. Determine the values of a, b, c. a = -1, b = -2, c = 15 2. Determine whether the parabola opens
upward or downward. Since a < 0, then parabola opens
downward. 3. Find the vertex of the parabola. vertex (-1, 16)
Graph: f(x)=15 2xx2 4. Find the intercepts, if any. x – intercepts: If y = 0, then x = 3, –5. y – intercept: If x = 0, then y = 15. 5. Plot the intercepts and vertex. Connect
these points with a smooth curve that is shaped like a cup.
Graph: f(x)=15 2xx2 16
14
12
10
8
6
4
2
-15 -10 -5 5 10 15(3,0)(-5,0)
(-1,16)
Example The function f(x) = 1 - 4x - x2 has its
vertex at _____. A. (2,11) B. (2,-11) C.( -2,-3) D.(-2,5)
Example Identify the graph of the given function: y = 3x2 -
3.
Example Identify the graph of the given function: 4y = x2.
Example Identify the graph of the given function: y = (x -
2)(x – 2).
Graph of : f(x)=ax2 + bx +c, a ≠ 0
Parabola
a > 0 opens upward
a < 0 opens downward
Vertex (-b/2a, f(-b/2a)
b2-4ac > 0 2 x – intercepts
b2-4ac = 0 1 x – intercept
b2-4ac < 0 No x – intercept
X – intercepts (x, 0)
Y – intercept c
Standard Form of Quadratic Functions
A quadratic function of the form f(x) = ax2 +bx +c where a, b and c are real numbers and a ≠ 0, is in standard form if it is written as f(x) = a(x – h)2 + k , a ≠ 0.
The vertex is at (h, k).
Example: Express f(x) = x2 - x - 2 in standard form. Solution: f(x) = (x2 - x) – 2 By completing the square, f(x) = (x2 - x + (-1/2)2) – 2 - (-1/2)2
f(x) = (x - 1/2)2 – 2 - (-1/2)2
f(x) = (x – 0.5)2 – 2.25 Where (h, k) = (0.5, -2.25)
Graph: f(x) = x2 x 23
2
1
-1
-2
-3
-6 -4 -2 2 4 6
(0.5,-2.25)
(2,0)(-1,0)
(0,-2)
Example: Express f(x) = 15 – 2x – x2 in standard
form. Solution: f(x) = – (x2 + 2x) + 15 By completing the square, f(x) = –(x2 +2x + (1)2) + (15 +1) f(x) = –(x + 1)2 + 16 Where (h, k) = (-1, 16)
Graph: f(x)=15 2xx2 16
14
12
10
8
6
4
2
-15 -10 -5 5 10 15(3,0)(-5,0)
(-1,16)
Exercises: (page 37) Graph each of the given equation. Find its vertex,
axis of symmetry, x and y intercepts, and domain and range.
2. f(x) = x2 + x – 2 3. f(x) = – x2 + 10x – 25 4. f(x) = – 4x2 - 20x – 24 5. f(x) = 6x2 – 7x – 5
More on Parabolas
Relations and Functions
More on Parabolas Parabola Opens Upward/Downward
o f(x) = a(x – h)2 + k , a ≠ 0o (y – k) = a(x – h)2 , a ≠ 0
Parabola Opens to the right/ left x = a(y – k)2 + h , a ≠ 0 (x – h) = a(y – k)2 , a ≠ 0
Graph the following: 1. x2 = 16y 2. y2 = – 12x 3. 2x2 + 5y = 0 4. (x – 3 )2 = 10 (y + 2) 5. y2 – 12x +48 = 0
Graph the following: 1. (x + 3 )2 – 8 (y + 6) = 02. y2 = – 32x3. x2 – 2x – y – 1 = 04. y2 – 4x – 8y + 24 = 05. y2 – 4x – 8y + 7 = 06. x2 – 4x – 12y – 32 = 07. x2 + 4x – 16y +4 = 0
Exercises
More Exercises: Activity Sheet 1.4 pages 365 – 366 # 1, 2,
3, 4, 5
References: (Online Graphing Utility)
http://rechneronline.de/function-graphs/ http://www.coolmath.com/graphit/