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15.Math-Review 2
Consider the function f(x)=x2 over the interval [-1,1]. Is this function convex or concave? Prove it.
Convexity and Concavity
15.Math-Review 3
The derivative The derivative of a function at a point is the instantaneous slope
of the function at that point. This is, the slope of the tangent line to the function at that point.
Differentiation
x
xfxf
x
y
d
)(d)('
d
d
Notation: for a function y = f(x), the derivative of f with respect to
x can be written as:
15.Math-Review 4
This graphically:
Differentiation
t
f(t)
y= (x-t)f’(t)+f(t)
s
f(s)y= (x-s)f’(s)+f(s)
y
x
y=f(x)
15.Math-Review 5
Rules of differentiation:(a) f(x) = k => f’(x) = 0
(b) f(x) = ax => f’(x) = a
(c) f(x) = xn => f’(x) = nxn–1
Example:f(x) = x
f(x) = x5
f(x) = x2/3
f(x) = x–2/5
Differentiation
15.Math-Review 6
Rules of differentiation:(d) f(x) = g(x) + h(x) => f’(x) = g’(x) + h’(x)
(e) f(x) = kg(x) => f’(x) = kg’(x)
(f) f(x) = g(x)n => f’(x) = n g’(x)g(x)n–1
Differentiation
g(x)f(x)
1
2g(x)
g'(x)f '(x)
Inverse rule as a special case of this:
Example:f(x) = 3x2
f(x) = 3x3 – 4 x2 + 6x – 20
f(x) = (3–7x)–3
15.Math-Review 7
More rules of differentiation:(g) f(x) = g(x)h(x) => f’(x) = g’(x)h(x)+ g(x)h’(x)
Differentiation
2g(x)
g'(x)f '(x)
g(x)f(x)
1
Inverse rule as a special case of this:
Example: product, quotient and chain for the following:g(x) = x+2, h(x) = 3x2
g(x) = 3x2 + 2, h(x) = 2x – 5
g(x) = 6x2, h(x) = 2x + 1
g(x) = 3x, h(x) = 7x2 – 10
g(x) = 3x + 6, h(x) = (2x2 + 5).(3x – 2)
2h(x)
g(x)h'(x)g'(x)h(x)- f '(x)
h(x)
g(x)f(x) (h)
(i) f(x) = g(h(x)) => f’(x) = g’(h(x))h’(x)
15.Math-Review 8
Even more rules of differentiation:(j) f(x) = ax => f’(x) = ln(a)ax
(k) f(x) = ln(x) => f’(x) = 1/x
Differentiation
142 23 xx ef(x)
Example: f(x) = ex
f(x) = ln(3x3 + 2x+6)
f(x) = ln(x-3)
15.Math-Review 9
Example: logs, rates and ratios: For the following examples we will consider y a function of x, ( y(x) ). Compute:
Differentiation
)ln(
)ln(
)ln(
)ln(
xd
yddx
xddx
yd
For this last example find an expression in terms of rates of changes of x and y.
15.Math-Review 10
A non-linear model of the demand for door knobs, relating the quantity Q to the sales price P was estimated by our sales team as Q = e9.1 P-0.10
Derive an expression for the rate of change in quantity to the rate of change in price.
Differentiation
15.Math-Review 11
To differentiate is a trade….
Differentiation
xxf(x)
13 2
10
for expressionan get to)(' use )(i
i
i
i ixxfxxf
xx eef(x) 2221
))1)(1((log5 xxf(x)
15.Math-Review 12
Higher order derivatives: The second derivative of f(x) is the derivative of f’(x). It is the
rate of change of function f’(x). Notation, for a function y=f(x), the second order derivative with
respect to x can be written as:
Differentiation
2
2
2
2
dx
f(x)d
dx
df'(x)f''(x)
dx
yd
n
n)(n-(n)
dx
f(x)d
dx
(x)df(x)f
1
Higher order derivatives are defined analogously.
Example: Second order derivative of f(x) = 3x2-12x +6f(x) = x3/4-x3/2 +5x
15.Math-Review 13
Application of f’’(x) We have that f’(t) f’(t+) This means that the rate of
change of f’(x) around t is
negative. f’’(t) 0
We also note that around t, f is a concave function.
Therefore: f’’(t) 0 is equivalent to f a concave function around t. f’’(t) 0 is equivalent to f a convex function around t.
Differentiation
y=f(x)
slope=f’(t +)
t
slope=f’(t)
t+
15.Math-Review 14
Partial derivatives: For functions of more than one variable, f(x,y), the rate of change
with respect to one variable is given by the partial derivative.
The derivative with respect to x is noted:
The derivative with respect to y is noted:
Differentiation
x
yxf
),(
y
yxf
),(
Example: Compute partial derivatives w/r to x and y.f(x,y) = 2x + 4y2 + 3xy
f(x,y) = (3x – 7)(4x2 – 3y3)
f(x,y) = exy
15.Math-Review 15
Maximum A point x is a local maximum of f, if for every point y ‘close
enough’ to x, f(x) > f(y). A point x is a global maximum of f, if f(x) > f(y) for any point y
in the domain. In general, if x is a local maximum, we have that:
f’(x)=0, and f’’(x)<0.
Graphically:
Stationary Points
Global Maximum
Local MaximumLocal Maximum
15.Math-Review 16
Minimum A point x is a local minimum of f, if for every point y ‘close
enough’ to x, f(x) < f(y). A point x is a global minimum of f, if f(x) < f(y) for any point y
in the domain. In general, if x is a local minimum, we have that:
f’(x)=0, and f’’(x)>0.
Graphically:
Stationary Points
Local Minimum
Global Minimum
15.Math-Review 17
Example: Consider the function defined over all x>0, f(x) = x - ln(x). Find any local or global minimum or maximum points. What
type are they?
Stationary Points
15.Math-Review 18
Consider the following example: The function is only defined in [a1, a4].
Points a1 and a3 are maximums.
Points a2 and a4 are minimums.
And we have:f’(a1) < 0 and f’’ (a1) ? 0
f’(a2) = 0 and f’’ (a2) 0
f’(a3) = 0 and f’’ (a3) 0
f’(a4) < 0 and f’’ (a4) ? 0
The problem arises in points that are in the boundary of the domain.
Stationary Points
a1 a2 a3 a4
15.Math-Review 19
Example: Consider the function defined over all x[-3,3], f(x) = x3-3x+2.
Find any local or global minimum or maximum points. What type are they?
Stationary Points
15.Math-Review 20
Points of Inflection. Is where the slope of f shifts from increasing to decreasing or
vice versa. Or where the function changes from convex to concave or v.v. In other words f’’(x) = 0!!
Stationary Points
Points of InflectionPoints of Inflection
15.Math-Review 21
Finding Stationary Points Given f(x), find f’(x) and f”(x). Solve for x in f’(x) = 0. Substitute the solution(s) into f”(x).
If f”(x) 0, x is a local minimum. If f”(x) 0, x is a local maximum. If f”(x) = 0, x is likely a point of inflection.
Example: f(x) = x2 – 8x + 26
f(x) = x3 + 4x2 + 4x
f(x) = 2/3 x3 – 10 x2 + 42x – 3
Stationary Points
15.Math-Review 22
Application of derivative: L’Hopital rule.
Tough examples to kill time
)('
)('lim
)(
)(lim)(lim
thathave then we
)(lim and ,)(lim If
xh
xg
xh
xgxf
xhxg
xxx
xx
Use this rule to find a limit for f(x)=g(x)/h(x):
xexhxxg
xxhxxg
)( and 1,-4)( If
)( and ,)ln()( If2
0001.
15.Math-Review 23
Example: Let us consider the function
Obtain a sketch of this function using all the information about stationary points you can obtain.
Tough examples to kill time
2
)2(
2
)(
x
exf
xexxf )3()( 2 Sketch the function
Hint: for this we will need to know that the ex ‘beats’ any polynomial for very large and very small x.