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1) Active Filters, Part I 2) Active Filters, Part IIkentesar/ELEN457/ELEN457_4.pdfActive Filters...

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Kamran Entesari, ELEN 457 Texas A & M University Section 3 1) Active Filters, Part I 2) Active Filters, Part II
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Page 1: 1) Active Filters, Part I 2) Active Filters, Part IIkentesar/ELEN457/ELEN457_4.pdfActive Filters High-pass KRC filter • At high frequencies, the equal component design becomes too

Kamran Entesari, ELEN 457 Texas A & M University

Section 3

1) Active Filters, Part I

2) Active Filters, Part II

Page 2: 1) Active Filters, Part I 2) Active Filters, Part IIkentesar/ELEN457/ELEN457_4.pdfActive Filters High-pass KRC filter • At high frequencies, the equal component design becomes too

Kamran Entesari, ELEN 457 Texas A & M University

Active Filters

1 ) The transfer function

Common frequency response:

1. Low pass 2. High pass 3. Band pass 4. Band reject 5. All pass

Practical filters: Approximation of the brick-wall magnitude filters

Active filters: no inductance implementation, providing gain, excellent for belowMHz applications such as audio and instrumentation applications

H (s) : The circuit transfer function

Roots: They are characteristic frequencies. They can be real or complex (conjugatePairs)

Page 3: 1) Active Filters, Part I 2) Active Filters, Part IIkentesar/ELEN457/ELEN457_4.pdfActive Filters High-pass KRC filter • At high frequencies, the equal component design becomes too

Kamran Entesari, ELEN 457 Texas A & M University

Active Filters

H (s) and stability:

An stable system has a bounded input to any bounded output. The response of aL.T.I system to an impulse input ( h(t) ) is determined by the poles of the circuit(Natural Response).

RLC circuits are always stable. If circuit contains dependent circuits such as op ampsIts pole may split into right half of the complex plane (RHP) and we have an unstableCircuit.

H (s) and frequency response:

The complex response; xo (t), consists of transient and steady-state responses.If all poles of the system are in LHP, the transient response dies, leaving the steadyState component.

Page 4: 1) Active Filters, Part I 2) Active Filters, Part IIkentesar/ELEN457/ELEN457_4.pdfActive Filters High-pass KRC filter • At high frequencies, the equal component design becomes too

Kamran Entesari, ELEN 457 Texas A & M University

Active Filters

2 ) First order active filters

Differentiator

H (s) =Vo / Vi = - (RC)s,

H (jω) = - j . (ω / ω0) , ω0 = 1 / (RC)

Miller integrator (inverting)

H (s) =Vo / Vi = - 1 / (RC)s,

H (jω) =[ (- 1) / j . (ω / ω0)] , ω0 = 1 / (RC)

Deboo integrator (non-inverting)

H (s) =Vo / Vi = 1 / (RC)s,

We use the Howland current pump circuit

Page 5: 1) Active Filters, Part I 2) Active Filters, Part IIkentesar/ELEN457/ELEN457_4.pdfActive Filters High-pass KRC filter • At high frequencies, the equal component design becomes too

Kamran Entesari, ELEN 457 Texas A & M University

Active Filters

Low-pass filter with gain

H (s) = ( - R2 / R1) . ( 1 / (R2Cs + 1)),

H (jω) = H0 / ( 1 + j . (ω / ω0)) , ω0 = 1 / (R2C)

High-pass filter with gain

Crude approximation of the brick-wall filter

H (s) = ( - R2 / R1) . ((R1Cs) / (R1Cs + 1))

H (jω) = H0 . ( j . (ω / ω0)) / ( 1 + j . (ω / ω0))

ω0 = 1 / (R1C)

Page 6: 1) Active Filters, Part I 2) Active Filters, Part IIkentesar/ELEN457/ELEN457_4.pdfActive Filters High-pass KRC filter • At high frequencies, the equal component design becomes too

Kamran Entesari, ELEN 457 Texas A & M University

Active Filters

Phase shifter

H (s) = (- RCs + 1) / (RCs + 1)

H (jω) = ( 1 - j . (ω / ω0)) / ( 1 + j . (ω / ω0))

ω0 = 1 / (RC)

Band-pass filter (wide band)

H (s) = ( - R2 / R1) . [(R1C1s) / ((R1C1s + 1) . (R2Cs + 1))]

H (jω) = H0 . ( j . (ω / ωL)) / [( 1 + j . (ω / ωL)) . ( 1 + j . (ω .ωH))]

ωL = 1 / (R1C1) , ωH = 1 / (R2C2)

Good for audio applications

Page 7: 1) Active Filters, Part I 2) Active Filters, Part IIkentesar/ELEN457/ELEN457_4.pdfActive Filters High-pass KRC filter • At high frequencies, the equal component design becomes too

Kamran Entesari, ELEN 457 Texas A & M University

Active Filters

3 ) Standard second order response (Biquadratic function)

• Q is a measure of filter selectivity• In practice; 0.5 < Q < 100

• Besides the pole – pair , the high passresponse has a double zero at ω = 0

Page 8: 1) Active Filters, Part I 2) Active Filters, Part IIkentesar/ELEN457/ELEN457_4.pdfActive Filters High-pass KRC filter • At high frequencies, the equal component design becomes too

Kamran Entesari, ELEN 457 Texas A & M University

Active Filters

• The band pass response (pole pairs + one zero at origin +one zero at infinity)

• The notch response (pole pairs + zero pairs at imaginary axis)

HN = HLP + HHP = 1 - HBP

• The all pass response ( 2 poles + 2 zeroes )

HAP = HLP – HBP +HHP = 1 – 2 . HBP

Page 9: 1) Active Filters, Part I 2) Active Filters, Part IIkentesar/ELEN457/ELEN457_4.pdfActive Filters High-pass KRC filter • At high frequencies, the equal component design becomes too

Kamran Entesari, ELEN 457 Texas A & M University

Active Filters

4 ) Single op amp second order active filters

KRC or Sallen-Key filters

The second order passive low pass filter has an asymptotic Slope of 40 dB / dec at high frequencies. , but does not have Sufficient flexibility to control the magnitude of the filterAround ω = ω0

• We use positive feedback to bolster the magnitude of the filter response around ω0

Page 10: 1) Active Filters, Part I 2) Active Filters, Part IIkentesar/ELEN457/ELEN457_4.pdfActive Filters High-pass KRC filter • At high frequencies, the equal component design becomes too

Kamran Entesari, ELEN 457 Texas A & M University

Active Filters

Low-pass KRC filter

• K and Q (or BW) are dependent to component ratios• ω0 is dependent to component products

Equal component KRC circuit: R1 = R2 = R, C1 = C2 = C

Design Equations: RC = 1/ ω0 , K = 3 – (1/Q)

Unity gain KRC circuit: K =1, R1 = mR, R2 = R, C1 =nC, C2 = C

Design Equations: ω0 = 1 / [(mn)1/2. RC] , Q = (mn)1/2 / (m+1)

Page 11: 1) Active Filters, Part I 2) Active Filters, Part IIkentesar/ELEN457/ELEN457_4.pdfActive Filters High-pass KRC filter • At high frequencies, the equal component design becomes too

Kamran Entesari, ELEN 457 Texas A & M University

Active Filters

High-pass KRC filter

• At high frequencies, the equal component design becomes too sensitive to the tolerance of the K when K =2. A slight mismatch, causing intolerable departure ofQ from the desired value and filter oscillation.

• KRC filter are used for Qs below 10

Again, two specific designs are equal componentAnd unity gain design.

Page 12: 1) Active Filters, Part I 2) Active Filters, Part IIkentesar/ELEN457/ELEN457_4.pdfActive Filters High-pass KRC filter • At high frequencies, the equal component design becomes too

Kamran Entesari, ELEN 457 Texas A & M University

Active Filters

Band-pass KRC filter

Typical design approach for Q > 0.4: R1 = R2 = R4 = R, C3 = C5 = C

Page 13: 1) Active Filters, Part I 2) Active Filters, Part IIkentesar/ELEN457/ELEN457_4.pdfActive Filters High-pass KRC filter • At high frequencies, the equal component design becomes too

Kamran Entesari, ELEN 457 Texas A & M University

Active Filters

Band-reject KRC filter

Twin T-network provides alternative pathsthrough which vi can reach the amplifier’s Input:

Low-freq. path: R – RHigh-freq. path: C – C

At intermediate frequencies the two paths provideOpposing phase angles, indicating a tendencyFor signals to cancel each other.

Design Equations: RC = 1/ ω0 , K = 4 – (1/Q)

Page 14: 1) Active Filters, Part I 2) Active Filters, Part IIkentesar/ELEN457/ELEN457_4.pdfActive Filters High-pass KRC filter • At high frequencies, the equal component design becomes too

Kamran Entesari, ELEN 457 Texas A & M University

Active Filters

Multiple feedback filters:

• For LP filter: Y1 and Y3 must be conductance and Y5 must be capacitor

• For BP filter: Y1 or Y3 must be capacitors

• For HP filter: Y1, Y3 and either Y4 or Y5 must be capacitors as

Low-pass filter

Page 15: 1) Active Filters, Part I 2) Active Filters, Part IIkentesar/ELEN457/ELEN457_4.pdfActive Filters High-pass KRC filter • At high frequencies, the equal component design becomes too

Kamran Entesari, ELEN 457 Texas A & M University

Active Filters

Band-pass filter

High-pass filter

Page 16: 1) Active Filters, Part I 2) Active Filters, Part IIkentesar/ELEN457/ELEN457_4.pdfActive Filters High-pass KRC filter • At high frequencies, the equal component design becomes too

Kamran Entesari, ELEN 457 Texas A & M University

Active Filters

4 ) State Variable and Biquad filters

Second order filters using one op amp use near minimum components.

Drawbacks: Wide component spreads, Awkward tuning capabilities. High sensitivityTo component variation, particularly to gain, limit these filters to Q < 10.

State Variable and Biqaud filters are less sensitive to passive component variables Easier to tune, and do not require extravagant component spreads. They provide More than one filter response, simultaneously.

State Variable (KHN) filters:

• Two integrators and a summing amplifier to provide the second – order low pass, band pass and high pass responses

• By using a forth op amp, we can synthesize the notch response or the all pass response

Page 17: 1) Active Filters, Part I 2) Active Filters, Part IIkentesar/ELEN457/ELEN457_4.pdfActive Filters High-pass KRC filter • At high frequencies, the equal component design becomes too

Kamran Entesari, ELEN 457 Texas A & M University

Active Filters

Inverting SV filter:

Typical design approach : R5 = R4 = R3, R6 =R7 = R, C1 = C2 = C

Page 18: 1) Active Filters, Part I 2) Active Filters, Part IIkentesar/ELEN457/ELEN457_4.pdfActive Filters High-pass KRC filter • At high frequencies, the equal component design becomes too

Kamran Entesari, ELEN 457 Texas A & M University

Active Filters

Non- inverting SV filter:

• The BP response is generated by integrating HP response and the LP response isGenerated by integrating the BP response

• The SV filters can easily yield dependable Q’s in the range of hundreds

Page 19: 1) Active Filters, Part I 2) Active Filters, Part IIkentesar/ELEN457/ELEN457_4.pdfActive Filters High-pass KRC filter • At high frequencies, the equal component design becomes too

Kamran Entesari, ELEN 457 Texas A & M University

Active Filters

The Biquad (Tow-Thomas) filter with notch response:

Three cases:

1) R4 = ∞ , ωz = ω0, H0N = -(R5 / R4)2) Switch Left: ωz > ω0, H0N = - (R5ωz

2)/(R2ω02)

3) Switch Right; ωz , ω0, H0N =- (R5 / R2)

We will use the low – and high –pass notches to synthesize a class of higher order filters known as elliptic filters


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