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1 Demodulation of DSB-SC AM Signals Suppose that the DSB-SC AM signal u(t) is transmitted through an...

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1 Demodulation of DSB-SC AM Signals Suppose that the DSB-SC AM signal u(t) is tra nsmitted through an ideal channel (with no channel distortion and no noise) Then the received signal is equal to the mo dulated signal, Suppose we demodulate the received signal b y 1. Multiplying r(t) by a locally generated sinusoid cos (2f c t + ). 2. We pass the product signal through an ideal lowpas s filter with bandwidth W ) 2 cos( ) ( ) ( ) ( ) ( ) ( t f t m A t c t m t u t r c c
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Page 1: 1 Demodulation of DSB-SC AM Signals Suppose that the DSB-SC AM signal u(t) is transmitted through an ideal channel (with no channel distortion and no noise)

1

Demodulation of DSB-SC AM Signals

Suppose that the DSB-SC AM signal u(t) is transmitted throu

gh an ideal channel (with no channel distortion and no noise)

Then the received signal is equal to the modulated signal,

Suppose we demodulate the received signal by

1. Multiplying r(t) by a locally generated sinusoid cos(2fct + ).

2. We pass the product signal through an ideal lowpass filter with band

width W

)2cos()()()()()( tftmAtctmtutr cc

Page 2: 1 Demodulation of DSB-SC AM Signals Suppose that the DSB-SC AM signal u(t) is transmitted through an ideal channel (with no channel distortion and no noise)

2

Demodulation of DSB-SC AM Signals The multiplication of r(t) with cos(2fct + ) yields

Since the frequency content of m(t) is limited to W Hz, where

W << fc, the lowpass filter can be designed to eliminate the signal components centered at 2 fc and to pass the signal components centered at f = 0

)4cos()(2

1)cos()(

2

1

)2cos()2cos()()2cos()(

tftmAtmA

tftftmAtftr

ccc

cccc

Frequency-domain representation of the DSB-SC AM demodulation.

Page 3: 1 Demodulation of DSB-SC AM Signals Suppose that the DSB-SC AM signal u(t) is transmitted through an ideal channel (with no channel distortion and no noise)

3

Demodulation of DSB-SC AM Signals Consequently, the output of the ideal lowpass filter

Note that m(t) is multiplied by cos() So the power in the demodulated signal is decreased by a factor of cos2 Thus, the desired signal is scaled in amplitude by a factor that depends

on the phase of the locally generated sinusoid

1. When 0, the amplitude of the desired signal is reduced by the factor cos()

2. If = 45, the amplitude of the signal is reduced by and the power is reduced by a factor of two

3. If = 90, the desired signal component vanishes

)cos()(2

1)( tmAty cl

2

Page 4: 1 Demodulation of DSB-SC AM Signals Suppose that the DSB-SC AM signal u(t) is transmitted through an ideal channel (with no channel distortion and no noise)

4

Demodulation of DSB-SC AM Signals

The preceding discussion demonstrates the need for a phase-coherent or synchronous demodulator for recovering the message signal m(t) from the received signal

That is, the phase of the locally generated sinusoid should ideally be equal to 0 (the phase of the received-carrier signal)

A sinusoid that is phase-locked to the phase of the received carrier can be generated at the receiver in one of two ways

Page 5: 1 Demodulation of DSB-SC AM Signals Suppose that the DSB-SC AM signal u(t) is transmitted through an ideal channel (with no channel distortion and no noise)

5

Demodulation of DSB-SC AM Signals One method is to add a carrier component into the transmi

tted signal.

We call such a carrier component "a pilot tone." Its amplitude Ap is selected to be significantly smaller than those of the

modulated signal u(t). Thus, the transmitted signal is a double-sideband, but it is no longer a s

uppressed carrier signal

Addition of a pilottone to a DSB-AM signal.

Page 6: 1 Demodulation of DSB-SC AM Signals Suppose that the DSB-SC AM signal u(t) is transmitted through an ideal channel (with no channel distortion and no noise)

6

Demodulation of DSB-SC AM Signals

At the receiver, a narrowband filter tuned to frequency fc, filters out the

pilot signal component

Its output is used to multiply the received signal, as shown in below

We may show that the presence of the pilot signal results in a DC comp

onent in the demodulated signal

This must be subtracted out in order to recover m(t)

Use of a pilot tone to demodulate aDSB-AM signal.

Page 7: 1 Demodulation of DSB-SC AM Signals Suppose that the DSB-SC AM signal u(t) is transmitted through an ideal channel (with no channel distortion and no noise)

7

Demodulation of DSB-SC AM Signals

Adding a pilot tone to the transmitted signal has a disadvantage It requires that a certain portion of the transmitted signal po

wer must be allocated to the transmission of the pilot

As an alternative, we may generate a phase-locked sinusoidal carrier from the received signal r(t) without the need of a pilot signal This can be accomplished by the use of a phase-locked loo

p, as described in Section 6.4.

Page 8: 1 Demodulation of DSB-SC AM Signals Suppose that the DSB-SC AM signal u(t) is transmitted through an ideal channel (with no channel distortion and no noise)

8

Conventional Amplitude Modulation A conventional AM signal consists of a large carrier component,

in addition to the double-sideband AM modulated signal The transmitted signal is expressed as

The message waveform is constrained to satisfy the condition that |m(t)| 1

We observe that Acm(t) cos(2fct) is a double-sideband AM signal and Accos(2fct) is the carrier component

)2cos()](1[)( tftmAtu cc

A conventional AM signal in the time domain

Page 9: 1 Demodulation of DSB-SC AM Signals Suppose that the DSB-SC AM signal u(t) is transmitted through an ideal channel (with no channel distortion and no noise)

9

Conventional Amplitude Modulation As we will see later in this chapter, the existence of th

is extra carrier results in a very simple structure for the demodulator

That is why commercial AM broadcasting generally employs this type of modulation

As long as |m(t)| 1, the amplitude Ac[1 + m(t)] is always positive This is the desired condition for conventional DSB AM tha

t makes it easy to demodulate, as we will describe On the other hand, if m(t) < -1 for some t , the AM signal is ov

ermodulated and its demodulation is rendered more complex

Page 10: 1 Demodulation of DSB-SC AM Signals Suppose that the DSB-SC AM signal u(t) is transmitted through an ideal channel (with no channel distortion and no noise)

10

Conventional Amplitude Modulation m(t) is scaled so that its magnitude is always less than unity

It is convenient to express m(t) as

where m,(t) is normalized such that its minimum value is -1 and

The scale factor a is called the modulation index, which is generally a constant less than 1

Since |m(t)| 1 and 0 < a < 1, we have 1 + amn( t ) > 0 and the modulated signal can be expressed as

which will never be overmodulated

)()( tamtm n

)(max

)()(

tm

tmtmn

)2cos()](1[)( tftamAtu cnc

Page 11: 1 Demodulation of DSB-SC AM Signals Suppose that the DSB-SC AM signal u(t) is transmitted through an ideal channel (with no channel distortion and no noise)

11

Spectrum of the Conventional AM Signal The spectrum of the amplitude-modulated signal u(t) is

Obviously, the spectrum of a conventional AM signal occupies a bandwidth twice the bandwidth of the message signal

)()(2

)()(2

)2cos()2cos()()(

ccc

cncnc

cccnc

ffffA

ffMffMaA

tfAFtftamAFfU

Conventional AM in both the time and frequency domain.

Page 12: 1 Demodulation of DSB-SC AM Signals Suppose that the DSB-SC AM signal u(t) is transmitted through an ideal channel (with no channel distortion and no noise)

12

Power for the Conventional AM Signal

A conventional AM signal is similar to a DSB when m(t) is su

bstituted with 1 + amn(t)

DSB-SC : The power in the modulated signal

where Pm denotes the power in the message signal

Conventional AM :

where we have assumed that the average of mn(t) is zero

This is a valid assumption for many signals, including audio signals.

mc

u PA

P2

2

2/

2/

222/

2/

2 )](1[1

lim)](1[1

limT

T nT

T

T nT

m dttmaT

dttamT

P

Page 13: 1 Demodulation of DSB-SC AM Signals Suppose that the DSB-SC AM signal u(t) is transmitted through an ideal channel (with no channel distortion and no noise)

13

Power for the Conventional AM Signal Conventional AM,

The first component applies to the existence of the carrier, and this component does not carry any information

The second component is the information-carrying component Note that the second component is usually much smaller than the first c

omponent (a < 1, |mn(t)| < 1, and for signals with a large dynamic range, Pmn << 1)

This shows that the conventional AM systems are far less power efficient than the DSB-SC systems

The advantage of conventional AM is that it is easily demodulated

nmm PaP 21nm

ccu Pa

AAP 2

22

22

Page 14: 1 Demodulation of DSB-SC AM Signals Suppose that the DSB-SC AM signal u(t) is transmitted through an ideal channel (with no channel distortion and no noise)

14

Demodulation of Conventional DSB-AM Signals

The major advantage of conventional AM is the ease in which the signal can be demodulated

There is no need for a synchronous demodulator Since the message signal m(t) satisfies the condition |m(t)| < 1, the envelope

(amplitude) 1+m (t) > 0 If we rectify the received signal, we eliminate the negative values without af

fecting the message signal, as shown in below The rectified signal is equal to u(t) when u(t) > 0, and zero when u(t) < 0 The message signal is recovered by passing the rectified signal through a lo

wpass filter whose bandwidth matches that of the message signal The combination of rectifier and lowpass filter is called an envelope detecto

r

Page 15: 1 Demodulation of DSB-SC AM Signals Suppose that the DSB-SC AM signal u(t) is transmitted through an ideal channel (with no channel distortion and no noise)

15

Demodulation of Conventional DSB-AM Signals The output of the envelope detector is of the form

where gl represents a DC component and g2 is a gain factor due to the signal demodulator.

The DC component can be eliminated by passing d(t) through a transformer, whose output is g2m(t).

The simplicity of the demodulator has made conventional DSB-AM a practical choice for AM-radio broadcasting Since there are billions of radio receivers, an inexpensive implementati

on of the demodulator is extremely important The power inefficiency of conventional AM is justified by the fact that

there are few broadcast transmitters relative to the number of receivers Consequently, it is cost-effective to construct powerful transmi

tters and sacrifice power efficiency in order to simplify the signal demodulation at the receivers

)()( 21 tmggtd


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