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Vector calculus
and
different coordinate systems
UNIT I-INTRODUCTION
S.Krishnaveni AP/EEE 1
Objective
Broadly, the study of Physics improves one‟s ability to
think logically about the problems of science and
technology and obtain their solutions. The present course
is aimed to offer a broad aspect of those areas of Physics
which are specifically required as an essential background
to all engineering students for their studies in higher
semesters.
Learning outcomes
At the end of the course, the students will have sufficient
scientific understanding of electromagnetic fields and
waves.
Three-Dimensional
Coordinate Systems
In this section, we will learn about:
Aspects of three-dimensional coordinate systems.
VECTORS AND THE GEOMETRY OF SPACE
S.Krishnaveni AP/EEE 3
COORDINATE SYSTEMS
• RECTANGULAR or Cartesian
• CYLINDRICAL
• SPHERICAL
Choice is based on
symmetry of problem
Examples: Sheets - RECTANGULAR
Wires/Cables - CYLINDRICAL
Spheres - SPHERICAL
To understand the Electromagnetics, we must know basic vector algebra and
coordinate systems. So let us start the coordinate systems.
S.Krishnaveni AP/EEE 4
Cylindrical Symmetry Spherical Symmetry
Visualization (Animation) S.Krishnaveni AP/EEE 5
Orthogonal Coordinate Systems:
3. Spherical Coordinates
2. Cylindrical Coordinates
1. Cartesian Coordinates
P (x, y, z)
P (r, θ, Φ)
P (r, Φ, z)
x
y
z P(x,y,z)
Φ
z
r x
y
z
P(r, Φ, z)
θ
Φ
r
z
y x
P(r, θ, Φ)
Rectangular Coordinates
Or
X=r cos Φ,
Y=r sin Φ,
Z=z
X=r sin θ cos Φ,
Y=r sin θ sin Φ,
Z=z cos θ S.Krishnaveni AP/EEE 6
Cartesian Coordinates
P(x, y, z)
Spherical Coordinates
P(r, θ, Φ)
Cylindrical Coordinates
P(r, Φ, z)
x
y
z P(x,y,z)
Φ
z
r x
y
z
P(r, Φ, z)
θ
Φ
r
z
y x
P(r, θ, Φ)
S.Krishnaveni AP/EEE 7
•The three lines are called the coordinate
axes.
•They are labeled:
– x-axis
– y-axis
– z-axis
COORDINATE AXES
S.Krishnaveni AP/EEE 8
•Curl the fingers of your right hand
around the z-axis in the direction of a 90° counterclockwise rotation
from the positive
x-axis to the positive y-axis.
– Then, your thumb
points in the positive
direction of the z-axis.
COORDINATE AXES
S.Krishnaveni AP/EEE 9
•The three coordinate axes determine
the three coordinate planes.
– The xy-plane contains
the x- and y-axes.
– The yz-plane contains
the y- and z-axes.
– The xz-plane contains
the x- and z-axes.
COORDINATE PLANES
S.Krishnaveni AP/EEE 10
•Look at any bottom corner of a room and call the corner the
origin.
3-D COORDINATE SYSTEMS
S.Krishnaveni AP/EEE 11
•The wall on your left is in the xz-plane.
•The wall on your right is in the yz-plane.
•The floor is in the xy-plane.
3-D COORDINATE SYSTEMS
•The x-axis runs along the intersection of the floor and the left wall.
•The y-axis runs along that of the floor and the right wall.
•The z-axis runs up from the floor toward the ceiling along the intersection of the two
walls.
S.Krishnaveni AP/EEE 12
•Now, if P is any point in space,
let:
– a be the (directed) distance from the yz-plane to P.
– b be the distance from the xz-plane to P.
– c be the distance from the xy-plane to P.
3-D COORDINATE
S.Krishnaveni AP/EEE 13
•We represent the point P by the ordered
triple of real numbers (a, b, c).
•We call a, b, and c the coordinates of P.
– a is the x-coordinate.
– b is the y-coordinate.
– c is the z-coordinate.
3-D COORDINATE SYSTEMS
S.Krishnaveni AP/EEE 14
•Thus, to locate the point (a, b, c), we can start at the origin O and proceed
as follows:
– First, move a units along the x-axis.
– Then, move b units
parallel to the y-axis.
– Finally, move c units
parallel to the z-axis.
3-D COORDINATE SYSTEMS
S.Krishnaveni AP/EEE 15
• The point P(a, b, c) determines a rectangular box.
• If we drop a perpendicular from P to the xy-plane, we get a point Q with
coordinates (a, b, 0).
– This is called
the projection of P
on the xy-plane.
•Similarly, R(0, b, c) and S(a, 0, c)
are the projections of P on the
yz-plane and xz-plane, respectively.
3-D COORDINATE S
S.Krishnaveni AP/EEE 16
•As numerical illustrations, the points
(–4, 3, –5) and (3, –2, –6) are plotted here.
3-D COORDINATE SYSTEMS
S.Krishnaveni AP/EEE 17
• we construct a rectangular box as shown,
where:
– P1 and P2 are
opposite vertices.
– The faces of the box
are parallel to the
coordinate planes.
3-D COORDINATE SYSTEMS
S.Krishnaveni AP/EEE 18
•If A(x2, y1, z1) and B(x2, y2, z1) are the vertices of the box, then
|P1A| = |x2 – x1|, |AB| = |y2 – y1|, |BP2| = |z2 – z1|
3-D COORDINATE SYSTEMS
Combining those equations, we get:
|P1P2|2 = |P1A|2 + |AB|2 + |BP2|
2
= |x2 – x1|2 + |y2 – y1|
2 + |z2 – z1|2
= (x2 – x1)2 + (y2 – y1)
2 + (z2 – z1)2
2 2 2
1 2 2 1 2 1 2 1( ) ( ) ( )PP x x y y z z
S.Krishnaveni AP/EEE 19
Cartesian coordinate system
• dx, dy, dz are infinitesimal displacements along X,Y,Z.
• Volume element is given by
dv = dx dy dz
• Area element is
da = dx dy or dy dz or dxdz
• Line element is
dx or dy or dz
Ex: Show that volume of a cube of edge a is a3.
P(x,y,z)
X
Y
Z
3
000
adzdydxdvVaa
v
a
dx
dy
dz
S.Krishnaveni AP/EEE 20
Cartesian Coordinates
Differential quantities:
Length:
Area:
Volume:
dzzdyydxxld ˆˆˆ
dxdyzsd
dxdzysd
dydzxsd
z
y
x
ˆ
ˆ
ˆ
dxdydzdv
S.Krishnaveni AP/EEE 21
AREA INTEGRALS
• integration over 2 “delta” distances
dx
dy
Example:
x
y
2
6
3 7
AREA = 7
3
6
2
dxdy = 16
Note that: z = constant
S.Krishnaveni AP/EEE 22
Cylindrical coordinate system
(r,φ,z)
X
Y
Z
r
φ
Z
S.Krishnaveni AP/EEE 23
Spherical polar coordinate system
• dr is infinitesimal displacement
along r, r dφ is along φ and
dz is along z direction.
• Volume element is given by
dv = dr r dφ dz
• Limits of integration of r, θ, φ
are
0<r<∞ , 0<z <∞ , o<φ <2π
φ is azimuth angle
Cylindrical coordinate system
(r,φ,z)
X
Y
Z
r φ
r dφ
dz
dr
r dφ
dr
dφ
S.Krishnaveni AP/EEE 24
Volume of a Cylinder of radius „R‟
and Height „H‟
HR
dzdrdr
dzddrrdvV
R H
v
2
0
2
0 0
Try yourself:
1) Surface Area of Cylinder = 2πRH .
2) Base Area of Cylinder (Disc)=πR2.
S.Krishnaveni AP/EEE 25
Differential quantities:
Length element:
Area element:
Volume element:
dzardadrald zrˆˆˆ
rdrdasd
drdzasd
dzrdasd
zz
rr
ˆ
ˆ
ˆ
dzddrrdv
Limits of integration of r, θ, φ are 0<r<∞ , 0<z <∞ , o<φ <2π
Cylindrical Coordinates: Visualization of Volume element
S.Krishnaveni AP/EEE 26
Spherically Symmetric problem
(r,θ,φ)
X
Y
Z
r
φ
θ
S.Krishnaveni AP/EEE 27
Spherical polar coordinate system (r,θ,φ)
• dr is infinitesimal displacement along r, r dθ is along θ and r sinθ dφ is along φ direction.
• Volume element is given by
dv = dr r dθ r sinθ dφ
• Limits of integration of r, θ, φ are
0<r<∞ , 0<θ <π , o<φ <2π
P(r, θ, φ)
X
Y
Z
r
φ
θ
dr P
r dθ
r sinθ dφ
θ is zenith angle( starts from +Z reaches up to –Z) ,
φ is azimuth angle (starts from +X direction and lies in x-y plane only)
r cos θ
r sinθ
S.Krishnaveni AP/EEE 28
Volume of a sphere of radius „R‟
33
0 0
2
0
2
2
3
42.2.
3
sin
sin
RR
dddrr
dddrrdvV
R
v
Try Yourself:
1)Surface area of the sphere= 4πR2 . S.Krishnaveni AP/EEE 29
Spherical Coordinates: Volume element in space
S.Krishnaveni AP/EEE 30
Points to remember
System Coordinates dl1 dl2 dl3
Cartesian x,y,z dx dy dz
Cylindrical r, φ,z dr rdφ dz
Spherical r,θ, φ dr rdθ r sinθdφ
• Volume element : dv = dl1 dl2 dl3
• If Volume charge density ‘ρ’ depends only on ‘r’:
Ex: For Circular plate: NOTE
Area element da=r dr dφ in both the
coordinate systems (because θ=900)
drrdvQv l
24
S.Krishnaveni AP/EEE 31
Quiz: Determine
a) Areas S1, S2 and S3.
b) Volume covered by these surfaces.
Radius is r,
Height is h,
X
Y
Z
r
dφ
S1 S2
S3
21
hr
dzrddrVb
rrddrSiii
rhdzdrSii
rhdzrdSia
Solution
h r
r
r h
h
)(2
..)
)(2
.3)
2)
)(1))
:
12
2
0 0
12
2
0
0 0
12
0
2
1
2
1
2
1
S.Krishnaveni AP/EEE 32
Coordinate Transformation
Cylindrical coordinate—Cartesian coordinate
S.Krishnaveni AP/EEE 33
Coordinate Transformation
Change of variables
Cylindrical coordinate—Cartesian coordinate
S.Krishnaveni AP/EEE 34
Coordinate Transformation
Change of variables
Spherical coordinate—Cartesian coordinate
S.Krishnaveni AP/EEE 35
Coordinate Transformation
Spherical coordinate—Cartesian coordinate
S.Krishnaveni AP/EEE 36
Metric Coefficients
S.Krishnaveni AP/EEE 37
Basic Orthogonal Coordinate Systems
S.Krishnaveni AP/EEE 38
Vector Analysis
• What about A.B=?, AxB=? and AB=?
• Scalar and Vector product:
A.B=ABcosθ Scalar or
(Axi+Ayj+Azk).(Bxi+Byj+Bzk)=AxBx+AyBy+AzBz
AxB=ABSinθ n Vector (Result of cross product is always
perpendicular(normal) to the plane
of A and B A
B
n
S.Krishnaveni AP/EEE 39
An orthogonal system is one in which te coordinates are
mutually perpendicular.
Examples of orthogonal coordinate systems include the
Cartesian, cylindrical and spherical coordinates.
There must be three independent variables. e.g: u1 , u2
and u3.
, and are unit vectors for each surface and the
direction normal to their surfaces.
ORTHOGONAL COORDINATE SYSTEM
1u
2u
3u
S.Krishnaveni AP/EEE 40
The cross product between the unit vector is:
While the dot product is:
•
2ˆ
1ˆ
3ˆ ,
1ˆ
3ˆ
2ˆ ,
3ˆ
2ˆ
1ˆ uuuuuuuuu
13ˆ
3ˆ
2ˆ
2ˆ
1ˆ
1ˆ
01ˆ
3ˆ
3ˆ
2ˆ
2ˆ
1ˆ
uuuuuu
uuuuuu
S.Krishnaveni AP/EEE 41
Vector Addition and
Subtraction
S.Krishnaveni AP/EEE 42
Product of Vector
• Multiplication by a scalar
• Dot (scalar) product
• Cross (vector)
S.Krishnaveni AP/EEE 43
Product of Vector
Multiplication by a scalar
Dot (scalar) product
S.Krishnaveni AP/EEE 44
Product of Vector
• Cross (vector) product
• A new product perpendicular to the plane containing the
two Vectors.
S.Krishnaveni AP/EEE 45
Gradient, Divergence and Curl
• Gradient of a scalar function is a
vector quantity.
• Divergence of a vector is a scalar
quantity.
• Curl of a vector is a vector
quantity.
f Vector
xA
A
.
The Del Operator
S.Krishnaveni AP/EEE 46
Gradient:
gradT: points the direction of maximum increase of the
function T.
Divergence:
Curl:
Operator in Cartesian Coordinate System
kz
Tj
y
Ti
x
TT ˆˆˆ
y zxV VV
Vx y z
ky
V
x
Vj
x
V
z
Vi
z
V
y
VV xyzxyz ˆˆˆ
kVjViVV zyxˆˆˆ
where
as
Fundamental theorem for
divergence and curl
• Gauss divergence
theorem:
• Stokes curl theorem
v s
daVdvV .).(
s l
dlVdaVx .).(
Conversion of volume integral to surface integral and vice verse.
Conversion of surface integral to line integral and vice verse. S.Krishnaveni AP/EEE 48
Operator in Cylindrical Coordinate System
Volume Element:
Gradient:
Divergence:
Curl:
dzrdrddv
zz
TˆT
rr
r
TT
1
1 1 z
r
V VV rV
r r r z
zV
rVrr
ˆr
V
z
Vr
z
VV
rV rzrz
11
zVVrVV zr ˆˆˆ
S.Krishnaveni AP/EEE 49
Operator In Spherical Coordinate System
Gradient :
Divergence:
Curl:
ˆT
sinrˆT
rr
r
TT
11
2
2
sin1 1 1
sin sin
rr V VVV
r r r r
ˆVrV
rr
ˆrVr
V
sinrr
VVsin
sinrV
r
r
1
111
ˆˆˆ VVrVV r S.Krishnaveni AP/EEE 50
The divergence theorem states that the total outward flux of a
vector field F through the closed surface S is the same as the
volume integral of the divergence of F.
Closed surface S, volume V,
outward pointing normal
Basic Vector Calculus
2
( )
0, 0
( ) ( )
F G G F F G
F
F F F
Divergence or Gauss’ Theorem
SV
SdFdVF
S.Krishnaveni AP/EEE 51
dSnSd
Oriented boundary L
n
Stokes’ Theorem
S L
ldFSdF
Stokes’s theorem states that the circulation of a vector field F around a
closed path L is equal to the surface integral of the curl of F over the
open surface S bounded by L
S.Krishnaveni AP/EEE 52
The following operations involving operator :
S.Krishnaveni AP/EEE 53