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1 - Taylor Expansion

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Taylor Series Lecture 9 Adha Imam Cahyadi, Dr.Eng Control and Instruments Lab JTETI, UGM All continuous functions which vanish at x = a are approximately equal at x = a, but some are more approximately equal than others Taylor, Brook (1715) "Proposition VII, Theorem 3, Corollary 2" (in Latin). Methodus Incrementorum Directa et Inversa. London. pp. 21-23.
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  • Taylor Series

    Lecture 9

    Adha Imam Cahyadi, Dr.EngControl and Instruments Lab

    JTETI, UGM

    All continuous functions which vanish at x = aare approximately equal at x = a,but some are more approximately equal than others

    Taylor, Brook (1715)

    "Proposition VII, Theorem 3, Corollary 2" (in Latin).Methodus Incrementorum Directa et Inversa. London. pp. 21-23.

  • Without the aid of CALCULATOR..... , compute!

    = 10

    Now, how would you solve for this!

    g = 2

  • Moral of the stories Not all of mathematical problems are

    solvable! (including the ones in Engineering)!

    In many cases it is unavoidable to computethe approximate

    About our class today It is dedicated to give alternative solutions of

    the both cases!

    It is important for your live -> you have to dedicate yourselves too to this class!

  • Why study mathematics?

    It is foundation of science

    It has been used in so many areas: economics, engineering, social science, etc

    Example?

  • Robots almost do nothing but math

    (Robotics researchers)

    And Also!

  • History

    Zenos paradox by ancient GreekPhilosoper of Elea

    Method of Exhaustion byArchimedes

    Brook Taylor 1715 found theSeries

    Collin Mc. Laurin found thespecific form of Taylor Series

  • Theorem

    What does it mean?

    Example

  • Illustration of Taylor polynomial

    0-th order Taylor is just a constant

    The first order is a linear function

    How about higher order?

  • Taylor Expansion for exp(x)

  • Taylor Polynomial of Polynomial function

    Consider the following function, f(x)=1+x+x^2+x^3

    Find its Taylor Polynomial!

  • Here is the answer

  • Newton Binomial

    How to compute (1+x)^n ?

    Newton Binomial


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