1.Warm-Up 4/21
D
36+
36β
26
46
Rigor:You will learn how to evaluate, analyze, graph
and solve exponential functions.
Relevance:You will be able to solve population problems and
solve half-life chemistry problems using exponential functions.
3-1 Exponential Functions
Algebraic Functions are functions are solved using algebraic operations.Transcendental Functions are functions that can not be expressed in terms of algebraic operations. They transcend Algebra.
Exponential and Logarithmic Functions are transcendental functions.
Example 1a: Sketch and analyze the graph of the function. Describe its domain, range, intercepts, asymptotes, end behavior, and where the function is increasing, or decreasing.π (π₯ )=3π₯
x y
β 3 0.04
β 2 0.11
β 1 0.33
0 1
1 3
2 9
3 27
Domain:Range:y-intercept:Asymptotes:End Behavior:
Increasing/Decreasing:
(ββ ,β)(0 ,β)
(0 ,1)π¦=0
limπ₯βββ
π (π₯)=0 limπ₯ββ
π (π₯)=βand
Increasing :(ββ ,β)
Example 1b: Sketch and analyze the graph of the function. Describe its domain, range, intercepts, asymptotes, end behavior, and where the function is increasing, or decreasing.π (π₯ )=2βπ₯
x y
β 3 8
β 2 4
β 1 2
0 1
1 .5
2 .25
3 .125
Domain:Range:y-intercept:Asymptotes:End Behavior:
Increasing/Decreasing:
(ββ ,β)(0 ,β)
(0 ,1)π¦=0
limπ₯βββ
π (π₯)=β limπ₯ββ
π (π₯)=0and
Decreasing :(ββ, β)
Example 2a: Use the graph of to describe the transformation of the function. Then sketch both functions.
π (π₯ )=2π₯+1
x y
β 4 .125
β 3 .25
β 2 .5
β 1 1
0 2
1 4
2 8
π (π₯ )=2π₯
x y
β 3 .125
β 2 .25
β 1 .5
0 1
1 2
2 4
3 8
π (π₯ )= π (π₯+1)The graph of is the graph of translated 1 unit to the left.
Example 2b: Use the graph of to describe the transformation of the function. Then sketch both functions.
h (π₯ )=2βπ₯
x y
β 3 8
β 2 4
β 1 2
0 1
1 .5
2 .25
3 .125
π (π₯ )=2π₯
x y
β 3 .125
β 2 .25
β 1 .5
0 1
1 2
2 4
3 8
h (π₯ )= π (β π₯)The graph of is the graph of reflected in the y-axis.
Example 2c: Use the graph of to describe the transformation of the function. Then sketch both functions.
π (π₯ )=β3(2)π₯
x y
β 3 β .375
β 2 β .75
β 1 β 1.5
0 β 3
1 β 6
2 β 12
3 β 24
π (π₯ )=2π₯
x y
β 3 .125
β 2 .25
β 1 .5
0 1
1 2
2 4
3 8
π (π₯ )=β3 π (π₯)The graph of is the graph of reflected in the x-axis and expanded vertically by a factor of 3.
Example 3a: Use the graph of to describe the transformation of the function. Then sketch both functions.
π (π₯ )=π4π₯
x y
β 3 6.1x10β6
β 2 3.4x10β4
β 1 .01832
0 1
1 54.598
2 2981
3 162755
π (π₯ )=ππ₯
x y
β 4 .01832
β 3 .04979
β 2 .13534
β 1 .36788
0 1
1 2.7183
2 7.3891
3 20.086
4 54.598
π (π₯ )= π (4 π₯ )The graph of is the graph of compressed horizontally by a factor of 4.
Example 3b: Use the graph of to describe the transformation of the function. Then sketch both functions.
π (π₯ )=πβπ₯+3
x y
β 3 23.086
β 2 10.389
β 1 5.7183
0 4
1 3.3679
2 3.1353
3 3.0498
π (π₯ )=ππ₯
x y
β 3 .04979
β 2 .13534
β 1 .36788
0 1
1 2.7183
2 7.3891
3 20.086
π (π₯ )= π (βπ₯ )+3The graph of is the graph of reflected in the y-axis andtranslated 3 units up.
Example 3c: Use the graph of to describe the transformation of the function. Then sketch both functions.
π (π₯ )=12ππ₯
x y
β 3 .02489
β 2 .06767
β 1 .18394
0 .5
1 1.3591
2 3.6945
3 10.043
π (π₯ )=ππ₯
x y
β 3 .04979
β 2 .13534
β 1 .36788
0 1
1 2.7183
2 7.3891
3 20.086
π (π₯ )=12π (π₯ )
The graph of is the graph of compressed vertically by a factor of .
Example 4: Krysti invest $300 in an account with 6% interest rate, making no other deposits or withdrawals. what will Krystiβs account balance be after 20 years if the interest is compounded:
a. semiannually?
b. Monthly?
c. Daily?
π΄=π (1+ ππ )
ππ‘
P = 300, r = 0.06, t = 20
n = 2π΄=300(1+ 0.06
π )π(20)
π΄=300(1+ 0.062 )
2 (20 )
π΄β978.61
n = 12π΄=300(1+ 0.06
12 )12(20)
π΄β993.06
n = 365π΄=300(1+ 0.06
365 )365(20)
π΄β995.94
Example 5: Suppose Krysti invest $300 in an account with 6% interest rate, making no other deposits or withdrawals. What will Krystiβs account balance be after 20 years if the interest is compounded continuously?
π΄=π ππ π‘P = 300, r = 0.06, t = 20
π΄=300π.06 (20)
π΄β996.04
a. 1.42% annually
b. 1.42% continuously
Example 6: Mexico has a population of approximately 110 million. If Mexicoβs population continues to grow at the described rate, predict the population of Mexico in 10 and 20 years.
π=π 0πππ‘
N0 = 110,000,000
r = 0.0142
,t = 10 and t = 20
π=π 0 (1+π )π‘
π=110,000,000 (1+0.0142 )10 π=110,000,000 (1+0.0142 )20
π β126,656,869 π β145,836,022 k = 0.0142
π=110,000,000π0.0142(10)
π β126,783,431π=110,000,000π0.0142(20)
π β146,127,622
ββ1math!
3-1 Assignment: TX p166, 4-32 EOE Test Corrections Due Friday 4/25Chapter 3 test Thursday 5/1