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PoTLQ2004 Distance rotection on arallel lines 1

Power Transmission and Distribution

Power AutomationProgress. Its that simple.

Consultant Power System Protection

Gustav Steynberg

PTD PA13 Nuremberg

Phone: +49 911 433 7012

Fax: +49 911 433 8301

Email: Gustav.Steynberg@siemens.com

SIPROTEC 4

Proteccin de Distancia

en lneas paralelas

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PoTLQ2004 Distance rotection on arallel lines 2

Power Transmission and Distribution

Power AutomationProgress. Its that simple.

Proteccin de lneas multi-circuitoacoplamiento mutuo, clases de redes

Z0M

Z0M

Z0M

Redes clase 1:

Circui tos paralelos con fuentes de secuenciapositiva y cero comunes

Redes clase 2:

Circuitos paralelos con fuente de secuenciapositiva comn pero fuente de secuencia ceroaislada

Redes clase 3:

Circui tos paralelos con fuentes de secuenciaposi tiva y cero aisladas

Line 1

Line 2

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PoTLQ2004 Distance rotection on arallel lines 3

Power Transmission and Distribution

Power AutomationProgress. Its that simple.

Inductancia mutua entre dos conductores ytierra

[]

500400300200100AL[m]

X0M

1.0

0.8

0.6

0.4

0.2

X0M= 0.1884 ln [ /km ]931

AL

= 100 m

AL

X0M

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PoTLQ2004 Distance rotection on arallel lines 4

Power Transmission and Distribution

Power AutomationProgress. Its that simple.

Acoplamiento de secuencia cero,reactancia mutuacalculada entre dos lneas areas de 110 kV

3.5

3.0

2.5

3.5

3.0

2.5

15.0

7

10.6

7 1

2.8

7

18.0

7

d

110 kV overhead line

mutual reactance in the zero-sequence system

0 100 200 300 400 500

0

0.1

0.2

0.3

0.4

0.5

0.6

0.7

0.8

0.9

without earth-wirewith earth-wire on one systemearth-wire on both systems

= 100 m

d [m]

X0M[/km]

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PoTLQ2004 Distance rotection on arallel lines 5

Power Transmission and Distribution

Power AutomationProgress. Its that simple.

Impedancias medidas sin compensacin delnea paralela

xl

0.2 0.4 0.6 0.8 1.0

50

100

150

200

ZZL

%

Z2

Z2

Z1

Z1

85 %

l

x

Z1

Z2Z0M

ZE

ZL= 0.86

Z0M

3 ZL= 0.65

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P T i i d Di t ib ti

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7/14PoTLQ2004 Distance rotection on arallel lines 7

Power Transmission and Distribution

Power Automation

Progress. Its that simple.

Impacto del acoplamiento mutuo en la medicinde distancia (relevador en la lnea sana)

Z2 Ia2,IE2

Ia1,IE1

x I - x

I

3

x)-(I2

3

x+)+(x)-I(2=con

+

= E20M0M

E1E2E2aLa2

E2

L

Ea2

a2 IIII

II

ZZZZU

ZZ

UZ

E2a2 II = E2E1 xx2I

I

=Icon y

( )

43421

errorL

E

L

0M

L

E

L

E

L2

+1

3x

+

+1

+1x-2I

=

Z

Z

Z

Z

Z

Z

Z

Z

ZZ

( )

L

E

L

0M

L

E

L2

1

3x1x-2I

=

Z

Z

Z

Z

Z

Z

ZZ

+

+

+

Power Transmission and Distribution

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8/14PoTLQ2004 Distance rotection on arallel lines 8

Power Transmission and Distribution

Power Automation

Progress. Its that simple.

Compensacin por lnea paralela;Conexin en el caso del relevador 7SA52

7SA52

7SA52

Line 1

Line 2

Power Transmission and Distribution

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9/14PoTLQ2004 Distance rotection on arallel lines 9

Power Transmission and Distribution

Power Automation

Progress. Its that simple.

Impacto de la compensacin mutua en la medicinde distancia en el relevador de la lnea fallada

Z1

I

Ia2,IE2

x

Ia1,IE1

k Z

Z02

0M

L

=3 :

43421E202E101a1

R1

++=

III kkU

Z

compensacin mutua

Z1 = x ZL (distancia correcta a la falla)Z

Z Z Z

Z

Z

Z

Z

1

L a1 E E10M

E2

a1E

L

E10M

L

E2

=

x( + +3

)

+ +

3

I I I

I I I

Power Transmission and Distribution

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10/14PoTLQ2004 Distance rotection on arallel lines 10

Power Transmission and Distribution

Power Automation

Progress. Its that simple.

Impacto de la compensacin mutua en la medicinde distancia en el relevador de la lnea sana

4444444 34444444 21

x)-(2I

x

x-2I

3

++1

Z3)

x

x-2I-

x-2I

x(

+x)-(2I= L

L

0M

L

E

L

0M

L2

Z

Z

Z

Z

Z

Z

ZZ

Ia2 =

IE2con

error

43421

E1

L

0ME2

L

Ea2

a2

2

3++

=

III

Z

Z

Z

Z

UZ

compensacin mutua

E2E1 x

x-2I

=II

E20M0M

E1E2Ea2La2 3

x)-(I2-3

x+)+(x)-I(2= IIII ZZ

ZZU

L

0M

L

E

L

0M

L

E

L2

3x

x-2I

++1

3x+)+(1x)-(2I

=

Z

Z

Z

Z

Z

Z

Z

Z

ZZ

I

Z2

I a1, I E1

I a2, I E2

x

Power Transmission and Distribution

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Power Transmission and Distribution

Power Automation

Progress. Its that simple.

Impedancias medidas con la compensacin delnea paralela

100

90

80

70

60

50

40

30

20

10

0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1.0

2

4

6

8

10

12

14

16

18

20Z

ZL

x

l

E1E2

E1

E2

2 l- xx

=

Z2

Z1

l

x

Z1

Z2

ZE

ZL= 0.86

Z0M

3 ZL= 0.65

E2

E1

ZL= Line impedance

Power Transmission and Distribution

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12/14PoTLQ2004 Distance rotection on arallel lines 12

Power Automation

Progress. Its that simple.

Proteccin de lneas paralelas, error de medicinen relevadores de distancia (K0=0.66 y K0M=0.4)

D

EP

E, phZ=

k0M

1 + k0ZL= 24 % of ZL

Fault at the end of the line:in-feed to positive and zero-sequence system at the sameline end

Ph-E

D

EP

EZ=

k0M

1 +k0ZL=24 % of ZL

Fault at the end of the line:one breaker open, transformer star-point earth and relay atopposite line ends

Ph-E

D

EP

EZ=

3 k0M1 +k0

ZL=Z0M

ZL= 40 % of ZLZ0

Fault at the end of the line:in-feed to positive and zero-sequence system

at opposite line ends

Ph-E

D Z= ZL = 10 % of ZL

Z0M

Z0L

1 +k0

k0M Fault at the end of the line:parallel line isolated and earthed on both ends

Ph-E

Power Transmission and Distribution

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13/14PoTLQ2004 Distance rotection on arallel lines 13

Power Automation

Progress. Its that simple.

Medicin de distancia en lneas paralelas

85%

120%

62%

70%

85%

55%

117%

164%

85%

ajuste de zona en % de la lneadependiendo del estado de switcheo

ajuste al85% encaso de:

K0 = 0.77

K0 = 1.44

K0 = 0.264

alcance de zona dependiente del ajuste del factorK0 y el estado de swi tcheo de la lnea(ejemplo: lnea de 400kV: K0 = 0.77, K0M = 0.70

Power Transmission and Distribution

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14/14PoTLQ2004 Distance rotection on arallel lines 14

Power Automation

Progress. Its that simple.

Falla a tierra en lnea de doble circuito, error de lamedicin de distancia con infeed en ambos lados

1,0

= fault location = apparent fault location

0,5

1

2

320

40

20

40

%

+X

(underreach)

-X(overreach)

measuring error

1 Single-sided in-feed, B= 0

2 Double-sided in-feed, B= A3 Double-sided in-feed, B= 5 A

x

l

D

A BPh-E

15 m

5 m

6.4

0m

Tower geometry

conductor: St Al 340/110 mm2

earth-wire: St 70 mm

2

residualcompensation = 0.84factorresidualcompensation = 0.68factor

ZE

ZL

Z0M

3 ZL