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142261 Mark Scheme Unit f334 Chemistry of Materials January

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  • 5/28/2018 142261 Mark Scheme Unit f334 Chemistry of Materials January

    1/17

    Oxford Cambridge and RSA Examinations

    GCE

    Chemistr B SaltersAdvanced GCE

    Unit F334: Chemistry of Materials

    Mark Scheme for January 2013

  • 5/28/2018 142261 Mark Scheme Unit f334 Chemistry of Materials January

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    OCR (Oxford Cambridge and RSA) is a leading UK awarding body, providing a wide range ofqualifications to meet the needs of candidates of all ages and abilities. OCR qualificationsinclude AS/A Levels, Diplomas, GCSEs, Cambridge Nationals, Cambridge Technicals,Functional Skills, Key Skills, Entry Level qualifications, NVQs and vocational qualifications inareas such as IT, business, languages, teaching/training, administration and secretarial skills.

    It is also responsible for developing new specifications to meet national requirements and theneeds of students and teachers. OCR is a not-for-profit organisation; any surplus made isinvested back into the establishment to help towards the development of qualifications andsupport, which keep pace with the changing needs of todays society.

    This mark scheme is published as an aid to teachers and students, to indicate the requirementsof the examination. It shows the basis on which marks were awarded by examiners. It does notindicate the details of the discussions which took place at an examiners meeting before markingcommenced.

    All examiners are instructed that alternative correct answers and unexpected approaches in

    candidates scripts must be given marks that fairly reflect the relevant knowledge and skillsdemonstrated.

    Mark schemes should be read in conjunction with the published question papers and the reporton the examination.

    OCR will not enter into any discussion or correspondence in connection with this mark scheme.

    OCR 2013

  • 5/28/2018 142261 Mark Scheme Unit f334 Chemistry of Materials January

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    F334 Mark Scheme

    1

    Annotat ions used in the detailed Mark Scheme (to include abbreviations and subject-specific conventions).

    Annotat ion Meaning

    / alternative and acceptable answers for the same marking point

    separates marking points

    not answers which are not worthy of credit and which will CON a correct answer

    ignore statements which are irrelevant and will NOT CON a correct answer

    allow answers that can be accepted

    ( ) words which are not essential to gain credit

    __ underlined words must be present in answer to score a mark

    ecf error carried forward

    AW alternative wording (replaces the old or words to that effect)

    ora or reverse argument

    Annotat ions used in scoris:

    Annotat ion Meaning

    correct response

    incorrect response

    benefit of the doubt

    benefit of the doubt notgiven

    error carried forward

    information omitted

    Ignore

    Reject

  • 5/28/2018 142261 Mark Scheme Unit f334 Chemistry of Materials January

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    F334 Mark Scheme

    2

    Question Answer Marks

    1 (a) (i)

    C

    C N

    O

    H2CO CH2

    H2C CH2

    H2C CH2

    N

    H

    H

    all correct 2 marks amide link only

    2 ALLOW

    any correc

    mixtures o

    CONH

    Cs and Hs

    IGNOREbrackets

    (ii) CONH circled 1 ALLOWadjacent

    (iii) 1,6-diamino hexane ORhexane -1,6-diamine

    2 If butaneALLOWIGNORE commasALLOW 1,6-hexa

    (b) (i)

    HO

    C

    CH2

    CH2

    CH2

    CH2

    CH2

    NH2

    O

    1 ALLOWany form

    ALLOWcyclic am

    N

    O

  • 5/28/2018 142261 Mark Scheme Unit f334 Chemistry of Materials January

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    F334 Mark Scheme

    3

    Question Answer Marks

    (ii) condensationANDwater is eliminated/formed/lost

    IFcyclic amide in 1b(i) THENaddition AND hydrolysis (of ring) /water added

    1 addition or additALLOWsmall moany other named s

    (c) (i) (polymer) chains/molecules are (highly) ordered/alignedAW 1 ALLOW labelleddchains by using pa

    AWmeans other egstacked closely aarranged regularl

    (ii)

    PPA chainsareclosertogether ORA

    so intermolecular bondsin PPA will be strongerORmore hydrogen bonds in PPAORmore intermolecular bonds in PPA ORA

    more energy/heatwill be required tobreak the intermolecular bondsORmelt the polymer OR allowchains to move over each other ORA

    3 AS ALWAYSintewith intermolecula

    NOTmore areas otogether NOTjustNOTEALL 3 mark

    ALLOWany nam

    NOT higher temp

    (iii) cold-drawing 1 NOTco-polymerisIGNOREnecking

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    F334 Mark Scheme

    4

    Question Answer Marks

    (d) (i) 1. elimination 2. addition 3. addition

    3IGNOREnucleop

    (ii) can be used in step 3AW 1 NOT step 2

    ALLOW can be sol

    can be use

    can be rec

    (e) acidified dichromate 1 IGNORE

    metal catio

    name of ac

    wrong form

    oxidation s

    ALLOWH2SO4/HDO NOT ALLOW

    Total 17

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    F334 Mark Scheme

    5

    Question Answer Marks

    2 (a)COOH / carboxyl / carboxylic acid group is a proton/H+donor / loses H+

    2 correct equation sALLOWgives H+

    Mark separately

    (b) (i) CH2OHCOOH + NaOH CH2OHCOONa + H2O 1 ALLOW

    CH2OHCOONa+

    Na+ CH2OHCOO

    IGNOREstate symNOTCH2OHNaC

    (ii) 1. moles of NaOHused in titration= 16.00/1000 x 0.250= 0.00400

    6 There are severalafter point 2, the the concentration

    If final answer isticks where the m

    2.ALLOWby imp

    The marks are awboldORthe correworking (but no mis wrong)

    4. Award if 76 use

    2. moles of glycolic acid used in titration= answer from 1, scaled by ratio in equation in 2bi

    0.00400

    CHECK equation in 2(b)(i)

    3A. moles of glycolic acid in 250 cm3= (answer from 2)x 10= 0.0400 mol

    OR3B. mass of glycolic in 25 cm3

    = (answer from 2)x Mrof glycolic acid 0.304 gOR3C. concentration of glycolic acid

    = (answer from 2) x 1000/25 0.16 mol dm-3

    4. Mrof glycolic acid = 76.(0)

  • 5/28/2018 142261 Mark Scheme Unit f334 Chemistry of Materials January

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    F334 Mark Scheme

    6

    Question Answer Marks

    5A. moles of glycolic acid in 100 cm3

    = (answer from 3A) x 100/14 0.286 molOR5Bi. mass of glycolic acid in 250 cm3

    = (answer from 3A) x Mrof glycolic acid 3.04 g

    OR5Bii.mass of glycolic in 250 cm3

    = (answer from 3B) x 10 = 3.04 gOR5C. concentration of undiluted glycolic acid

    = (answer from 3C) x 250/142.86 mol dm-3

    ALLOWecf for instepALLOW AcnegonALLOWanswers

    The following on tcorresponding coof working or lack21.7 scores 61.22 scores 5 (er12.2 scores 5 (er2.17 scores 5 (er3.04 scores 5 (erthese to other sf Omark less

    If one of the answnumber of ticks

    6. mass of glycolic acid in 100 cm3undiluted= (answer from 5A) x Mrof glycolic acid

    OR = (answer from5B)x 100/14

    OR = (answer from 5C/10) x Mrof glycolic acid

    = 21.7 (3 sf)ANDcorrect comment

    (c) (i)

    H3C

    O

    O CH2CH2CH2CH3

    butyl ethanoate

    ester link correct

    2 IGNORE where this includedALLOWadjacent

    ALLOWbutyletha

    (ii) butan-1-ol

    concentrated sulfuric acid/hydrochloric acid

    2 MUST HAVEnumDO NOT ALLOWALLOWformula fIGNOREspelling clear

  • 5/28/2018 142261 Mark Scheme Unit f334 Chemistry of Materials January

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    F334 Mark Scheme

    7

    Question Answer Marks

    (iii) ethanoic acid:hydrogen bonding IGNOREpd-pd

    compound D:pd-pd hydrogen bonding is CON

    instantaneous dipole induced dipole / id-id in both

    3 ALLOWpd-pALLOW Van

    (d) (i) The answer requires a comment for a carboxylic acid AND analcohol so award ONE mark from each section below:

    CARBOXYLIC ACID(strong) peak at 1743 (cm1) shows C=O in ester not acidORno peak 1700 1725 (cm1) shows no C=O in acidORno broad peak at 2500 3200 (cm1) shows no OH in acid

    ALCOHOLno peak greater than 3000 / in range 3200 3600 (allow 3640) sono OH in alcohol

    2 answers may

    to score eachwhich it is fou

    ALLOW carboethanoic acid

    FOR OHALFOR C=OAL

    (ii) peak at m/z73:CH3COOCH2/ C3H5O2positive charge on any formula

    species lost:CH2CH2CH3/ C3H7 (NO charge)

    3 ALLOW any cfor both answALLOWC4H9

    IFC4H9O+giv

    THEN specie

    (e) (i) nucleophilicaddition 2

  • 5/28/2018 142261 Mark Scheme Unit f334 Chemistry of Materials January

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    F334 Mark Scheme

    8

    Question Answer Marks

    (ii)

    H C H

    O

    -C N

    H C H

    OH

    CN

    H C H

    O-

    CN

    H+or H2O or HCN

    HCHO with bond polarity correct CNwith lone pair of electrons on C

    both curly arrows correct (lower one must be from C of CN) intermediate ion correct gain of H+from water, HCNor directto form the cyanohydrin

    5

    ALLOW CNALLOWve c

    IGNOREany intermediate

    Total 28

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    F334 Mark Scheme

    9

    Question Answer Marks

    3 (a) (i)repeating unit in DNA is a nucleotide

    formed from pentose/sugar/deoxyribose, phosphateand a baseAW

    2 mark separate

    ALLOW

    names fof base

    a namedIGNOREribosfor two marksmakes up the

    (ii) proteins are formed from amino acid(s) 1

    (iii) proteins have moreamino acids than the bases/nucleotides inDNA

    from which to construct many unique/different/morestructures/arrangements/combinations to carry genetic data AW

    2 ALLOWactuaacids in proteDNA

    (b)

    N N

    CH3

    O

    O

    HDNA chain

    DNA chaincorrect formula completed for adenineANDboth H bonds betweencorrect atoms correct polarities for one hydrogen bond lone pair for one hydrogen bond

    3

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    F334 Mark Scheme

    10

    Question Answer Marks

    (c) (i)

    HN CH C

    CH2

    HN

    O

    OH

    CCH2C

    O

    CHN

    O

    CH

    OH

    H3C

    CH3

    ANY TWO of the THREE CORRECT chiral Cs ONLY

    1

    (ii) arrows as in (d) (i) 1 IGNOREextraends of chainAny other arro

    (iii)

    H2N C C

    H2C

    H O

    O-

    OH

    correct amino acid (see opposite)

    correct formula of ion

    2 IGNOREany ALLOWany cIGNORE spec

    and left

    IGNORE

    added

    negati

    COO

    NO ecfIFanion formeamino acid

    (iv) secondary:

    folding/twisting of polypeptide/amino acid chains/primary structure

    tertiary:further/final folding OR3D shape/structure

    2

    ALLOW(alphpleated sheet

    ALLOWovera

    Total 14

  • 5/28/2018 142261 Mark Scheme Unit f334 Chemistry of Materials January

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    F334 Mark Scheme

    11

    Question Answer Marks

    4 (a) (i)

    O O SS

    O

    O

    O

    O

    O

    O

    2-

    x

    xx

    x x

    xx

    xx

    xx

    xx

    xx

    xx

    x

    xx

    xx

    xx

    xx

    correct inside oval (around peroxy Os) rest correct

    2

    ALLOWanot

    second mark

    (ii) (NH4)2S2O8 1 ALLOW

    with co

    S2O8(N

    (b) S2O82(is the stronger oxidising agent) because

    S2O82 hasa more positiveEovalue indicates a greatertendency AW to gain/attract/accept electrons/to

    be reduced

    ORA ie:S2O8

    2 (is the stronger oxidising agent) because Cr2O72 hasa less

    positive/ more negativeEovalue

    indicates a smaller tendency AW to gain/attract/accept electrons/tobe reducedORindicates a greatertendency AW to lose electrons/to beoxidised

    2 without refere

    only scores 1

    NOT higher fboth statemen

    (c) (i) S2O82+ 2I 2SO4

    2+ I2correct equation balanced

    1 IGNOREstate

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    F334 Mark Scheme

    12

    Question Answer Marks

    (ii)

    1. use filter of complementarycolour to iodine/solution

    2. zero colorimeter with water

    3. measure absorbance readings of standard solutions/solutionsof known concentration (of iodine)

    4. plot calibration graph

    5. take absorbance readings of the reacting mixture atknown/certain times AW (must refer to time may state unitsof time)

    6. convert absorbance readings to iodine concentrations usingthe calibration curve

    QWC:In order to gain the mark for point 3, 5 or 6, absorbance must beusedANDspelled correctly at least once

    6 Using starchCANNOT gaiALLOW

    filter/wabsorp

    green/

    suitab

    orange/yellowNOT solvent

    IGNORErefe

  • 5/28/2018 142261 Mark Scheme Unit f334 Chemistry of Materials January

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    F334 Mark Scheme

    13

    Question Answer Marks

    (iii)

    t1/2t1/2

    suitable graph sketched

    construction lines to determine half-lives from graph

    constant half-life (means first order)

    3 graph should decreasingfrcurve will do)

    at least twosshown on gra

    dependent on(numbers on s

    (d) (i) homogeneous, reactants and catalyst/Fe3+are in the same phase /state

    1 MUSTmentioIGNORE'redoNOT'substratALLOW all in

    (ii) Fe2+ 1s22s22p6 3s23p63d6Fe3+ 1s22s22p63s23p63d5

    correct number of EXTRAelectrons added14(Fe2+) and 13(Fe3+) both fully correct

    2 IGNORE 4s0

  • 5/28/2018 142261 Mark Scheme Unit f334 Chemistry of Materials January

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    F334 Mark Scheme

    14

    Question Answer Marks

    (iii) 1. Fe3+reacts with/oxidises IORA

    2Fe3+ + 2I 2Fe2+ + I2

    explanation:

    the EoofFe3+/Fe2+half-cell is more posit ive / less negativethan that of the I/ I2

    half-cell ORAAW

    2. Fe2+reacts with/reduces S2O82ORA

    S2O82

    + 2Fe2+ 2SO4

    2 + 2Fe

    3+

    explanation:the EoofS2O8

    2/SO42half-cell is more positivethan that of

    the Fe3+/Fe2+half-cell ORAAW

    QWC: to gain the explanation mark for either 1or 2, the datahas to be linked correctly to the reaction

    6 IGNORE refevariable valen

    ALLOWEoof

    ALLOWEoof

    NOTEIf answer starmark but ecf sget 5 marks

    (e) (i) Rate = k x [S2O82

    ] x [I

    ] 2 IGNOREstate

    (ii) uses one of the 3 sets of results:1. k = 2.0 x 105/ (0.075 x 0.040)2. k = 4.0 x 105/ (0.150 x 0.040)3. k = 1.0 x 105/ (0.075 x 0.020)

    k = 0.0067

    mol1dm3s1

    3 ecf from part eALLOWstandCorrect numefor calculation

    NO ecf from f

    ALLOWany nNOT 0.006 N

    ALLOWunits

    (iii) 2.0 x 105mol dm3s1

    2 Mark separate

    Total 31

  • 5/28/2018 142261 Mark Scheme Unit f334 Chemistry of Materials January

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