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Greasy Gus jumps in hisun-started car. In 1.76s,he and the car accelerateat a constant ratethrough the open door 10meters away.

vi = 0 m/s vf =ti = 0 s tf = 1.76 s Xi = 0 mXf = 10 m

vf =11.36 m/s

Greasy Gus’ final velocity

Calculate the timerequired for Greasy Gusto reach a velocity of 20m/s and distance Gustravels.

Greasy Gus’ time to reach 20 m/s

vi = 0 m/s tf = ti = 1.76 s a =Xf = 10 mVf = 11.36 m/s

a = 6.45 m/s2

Find Greasy Gus’ acceleration rate first

vi = 0 m/s tf = ti = 0 s Xf = Xi = 0 mVf = 20 m/s a = 6.45 m/s2 tf = 3.1 s

Greasy Gus’ time to reach 20 m/s

Create X vs. t, V vs. t, anda vs. t graphs for GreasyGus’ journey to the 20 metermark. Include time points 0,1, 2, 3, & 4 s.

Area = ½ (25.84 m/s)( 4 s) = 51.68 m

Slope = (25.84 m/s)/(4 s) = 6.46 m/s2

Area = (6.46 m/s2)(4 s) = 25.84 m/s

Slope = 0/4 = 0 m/s3

How far away (Xf ) is GreasyGus’ Hideout if it took thesonic “BEEP” nine seconds to besent out and return to Batfink’sear? Youcan assume themagnitude of the 340 m/s velocity

ofthe sound is constant.

Xf

How far away is Gus’ Hideout?

Vi = 340 m/s tf = 4.5 s Vf = 340 m/s Xf =ti = 0 s tf = 9 s Xi = 0 ma = 0 m/s2 Sound wave has to travel twice the distance! Xf = 1530 m

Create X vs. t, V vs. t, and a

vs. t graph for the soundwave . Include time points0, 1, 2, 4.5, 7, 8, & 9 s.

Area = ( 340 m/s) x(4.5 s) = 1530 m

Area = ( -340 m/s) x(4.5 s) = -1530 m

Slope = -340-340/.1 = -6800 m/s2

Area = (-6800 m/s2) (.1 s) = -680 m/s

Slope = 0/9 = 0 m/s

Karate and Batfink are trapped

in tires and roll off the edge of

the cliff 135m in height.

Solution:

vi = 0 m/s tf =ti = 0 s Vf =Yi = 0 mYf = -135 m g = -9.8 m/s2

tf = 5.25 s

How long can they spend in the air?

The calculate the distancethey have fallen when theyreach a velocity of 40 m/s.

Solution:

vi = 0 m/s tf =vf = 40 m/s ΔY =ti = 0 s Yi = 0 m g = -9.8 m/s2

ΔY = -81.63 m

Displacement while reaching 40 m/s.

Create X vs. t, V vs. t, and a

vs. t graphs for Batfink’s-135 meters journey. Include time points 0, 1, 2,

3, 4, & 5 s.