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DATA INTERPRETATIONFOR CAT,MAT,GMAT, & OTHER
COMPETITIVE EXAMINATIONS AFTERSCHOOL ± DEVELOPING CHANGE MAKERS
CENTRE FOR SOCIAL ENTREPRENEURSHIPPGPSE PROGRAMME ±
World¶ Most Comprehensive programme in socialentrepreneurship & spiritual entrepreneurship
OPEN FOR ALL FREE FOR ALL
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11/12/2010 AFTERSCHOOOL centre for social entrepreneurship 2www.afterschoool.tk
DATA INTERPRETATION
Dr. T.K. Jain.
AFTERSCHOOOLCentre for social entrepreneurship
Bikaner
M: 9414430763
www.afterschoool.tk
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What was the ratio of males tofemales in the rural area of
Ganga Nagar in theyear 2001?
(chart on next slide)
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Answer
72% of males + 47.27 of females = 60.39% of (males + females)
OR
85.34% of males +68.54% of females = 77.80%of (males + females) Solve these and get the answer: .72 m + .4727f = .6039 m + .6039 f
1.1376m = 1.27754 f M / F = 1.27754/1.1376 Or : 1277: 1136 answer
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Percentage urban population of
males in Bikaner is what per cent of the percentage
female population of rural areathere in theyear 2001?
(chart on next slide)
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Solution«
% of male population in rural areas :
(average ± female%) / (male % - Female %)
= (46.38 ± 28.83) / (61.92 ± 28.83) =53%
Thus female are 47% in rural areas.
Similarly for urban areas :
= (76.17 ± 65.62)/(85.38 ± 65.62) = 53.4%
Thus 53.4% / 53% gives answer : 1.0072answer
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In a certain code, ELEPHANT
is written asWLDFSCOC. How will
AGGARWAL be writtenin the same code?
First of reverse the word ELEPHANT : it is : TNAHPELE. Add 3 infirst digit and deduct 2 from next digit and so on. We get :LAWRAGGA from AGGARWAL. Now solve it :
OYZPDEJY. Answer
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What is the trend in the number of retirees(who have opted for VRS) in the age group 50
- 55 from 1994 to 1996?
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solution
In 1994, 55+ are 2000 which is 60% and in1996, 55+ are 1000, which is 40%. Thus totalnumber of retirees in 1994 and 1996 are :
2000*100/60 = 3333 and 1000*100/40 = 2500 The number of retirees in 50 to 55 are 20% of
total number in each of these years : thus it is666 in 1994 and 500 in 1996. thus there is atrend of decrease in these two years. Answer
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What was the percentage
change in the break-up figurefrom 1990 to 1998 of the
retirees under VRS in the 55 +age group?
Solve it based on the graph of theprevious question.
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Solution.
It was 80% (or .8) in 1990 and it reached30% in 1998. thus it decreased by .5 from.8.
The change in % is .5/.8 *100 = 62.5%answer
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Which group showed the largest
percent change in per cent break-up from 1990 to 1998?
(solve from the graph of the previousquestion).
The group in 55+ age group showed the
largest % change from 1990 to 1998.answer (solve by observation).
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How many more employees in the 46 - 50 agegroup had opted for VRS in 1996 as compared
to 1990?
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SOLUTION.
IN 1990, 55+ ARE 2400, WHICH IS 80%OF TOTAL, THUS 5% WILL BE 2400*5/80
=150 IN 1996, 55+ ARE 1000, WHICH IS 40%,
SO 15% (46 TO 50 ARE 15%) WILL BE :1000*15/40 = 375
THUS THERE IS INCREASE OF (375 ±150) = 225 ANSWER
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In which match did we have maximumdifference in the scores of the two teams?
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Solution«
In the 9th match, the first innings score was200 and the second innings score was140, thus the difference was 60 runs,which is the highest difference out of thegiven data. Answer
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What is the number of engineering studentsappearing in CAT in 2008. Compare this
with the data of 2004?
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Answer «
In 2008, the number of engineeringstudents was 70,000 in 2004, it was also70000. thus there is no change in the dataof the two year, but the students fromother discipline have increased and so the% of students from engineering faculty has
decreased out of the total number of students
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If the revenue of the company increases by 100% from
1998 to 2003 and revenue from biscuits is 100 crores
more than any other product in 2003, then what is the
revenue earned by company by selling shampoo
products in 1998?
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solution
Sale in 2003 of biscuits is 20% more thanother items. Thus difference of 20% isequal to 100 crores. Thus total of 2003 is500 Crores.
The sale in 1998 = 500 * 100/200 = 250.be 9
Thus sale of shampoo in 1998 should be10% of 250 = 25 answer
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During which year were the sales as
a proportion of equity the highest?
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Solution«
In 1991, the sales was 90 crores, butequity was only 10 crores, thus sales was10 times equity. Thus this is the highestout of all the 4 years that we have for review here.
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What is the total distance travelled bythe train over this 3-hour period?
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Solution«
Distance travelled =
= UT + ½ FT ̂ 2
U = starting speed = 35 T = time
F = total acceleration / total time.
= (71 ± 35) / (3 hours)= 12
= 35*3 + ½ (12 * 3*3)
= 159 ANSWER
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What is the growth rate of sales at primary
level as per the table below (75 ± 80 )
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Solution«
It has increased from 42 to 68000 andthere is growth of approx. 26000/42000which is 60% approx.
Thus per annum growth rate is 12%approx. answer
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by what percent was the total investment in the two
districts more in 96 as compared to 95?
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Solution
The total investment (combined in the twodistricts) was approx. 10000 in 1995,which increased by 1800 approx.
Thus growth rate is 18% answer
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The total number of silver-coloured cars sold
in Metro H is approximately what percentage of
that in Metro M?
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Solution «
Total sale of silver cars in metro H is 172and in metro M it is 192,
172/192 * 100 = 90% approx. answer
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By what percentage production of other states
is more than that of the of Mãharashtra?
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Solution
It is 25000 in other states and 20000 inMaharastra.
Thus it is more by 5000. Thus it is 25% of maharastra answer
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Approximately what perceptage of the total
producation is shared by the other states
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solution
Total production is 143000 approx.
Production in other states is 25000
25000/143000 * 100 = 17.5% approx.
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If 85% of E type cars produced during 1996 and
1997 are being sold by the company, then how
many E type cars are left by the company
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solution
In 1996 90000 cars of E type wereproduced and in 1997 we had productionof 50000 cars of type E.
Thus 15% of this 21000 is left out with thecompany.
Th t t l d ti b fi i i 1997
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The total production by five companies in 1997
is what per cent of the total production by
companies B &.D in 1996?
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solution
Total for 1997 for 5 companies = 185
For 1996 : for
B + D = 95 Thus 185/95 * 100 = 200% approx.
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Which year had the highest per cent increase inproduction over the previous year?
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Solution«
In % the highest growth is in 1999, whichis 75% appro.
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Cars of which colour are 20% lesspopular than white coloured cars?
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Solution«
White car is 26% in demand 20 less (it isabsolute ± not comparative), = 6%, thusgolden car is the car which is having 6%popularity. Answer
If i 1997 th l ti f ill D i i d b 10%
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If in 1997 the population of village D is increased by 10%
and the population of village G is reduced by 5% from
1995. population of village G in 1995 was 9000, what is the
total population BPL of villages D and G in 1997?
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solution
Population of D + 10200 + 1020 = 11220
Take 58% of it : 6500
Population of G = 9000 ± 450 = 8550 Take 51% of this : 4300
Add these : 10800 answer
In which years was the amount of
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In which years was the amount of profit the maximum?
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Solution «
Try for 1998 and 1997, it is 27.5% 0f 150in 1998 and 20% of 190 in 1997, thus it ishighest in 1998. answer.
H th i d th 10
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How many months experienced more than 10 per
cent increase in crude oil price over the earlier
month?
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Solution«
We find 4 months with more than 10%increase
Answer
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lb. numbers of torture eases exceeded the
number of molestation cases by:
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Solution«
The number of cases of molestation isapproximately : 24000 approx.
The number of cases of torture is : 25000approx. Thus this number is 1000 morethan the cases of molestation.
Thus this is : 1000/24000 * 100
= 4% approx. answer
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Numbers of ITPA (Immoral Traffic
Prevention Act) cases registeredin A.P. exceeded the casesregistered in Rajasthan by:
See the graph and solve it :
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Graph :
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Solution «
The number of cases in Rajasthan isapprox. 8000 but in AP it is approx. 10000.
Thus the number of cases in AP is 2000more than those in Rajasthan.
2000/8000 *100 = 25% answer
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Consumption of cola in 1984: 75million, in 1998 : 115 million.
If Coke¶s sales for 1998 had been
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If Coke s sales for 1998 had been30 million bottles, then, with the
distribution shown in the chartremaining the same, the total salesin 1998 would be greater or lower
than the actual value by whatpercentage?
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Solution «.
Coke were sold 14% of total sales. Totalsale was 115 million, so the sale of cokewas : 14% of 115 = 15.6 million approx.
Sale as per chart : 15.6 million but actualsale (as per question): 30 million.
Thus sales as per chart is less by 14.4
million in comparison to the actual sales.
Thus it is : 14.4/30 *100 = 48% approx.
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lf Coke¶s share were to increase by
10% in 1999 with total salesremainiaig the same, what would
be the percentage reduction in the
total share of other. Sale of coke in 1998 was 16.1, it increased by
10% so sale in 1999 should be : 17.71 thus it
would increase by 1.61 million. The sale of others would reduce by 1.61, which is 1.61/88.9* 100 = 1.62% ans
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If kinetic shows same growth for
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If kinetic shows same growth for next 2 years, then what would be
the sale in 2000?
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Solution
Sale of kinetic in 1997 was :
104000,
Sale of Kinetic in 1998 :
113580
Growth rate is : 9580/104000 * 100
= 9.2% the same growth will continue in
next 2 years also 113580 * 1.092 *1.092 = 135440 answer
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assuming the scooter market grows
by 5% for next 2 years and marketshare of LML and others remain
the same, then the market share of
Bajaj shall be
61%
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assuming the scooter market
grows by 5% for next 2 yearsand market sale of LML andothers remain the same as in
1998, then the market share of Bajaj shall be
Total sale in 1998 was : 1262699 and itwill increase by 5% so it will increase to :1262699 +631349 = 1894048.
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Solution «
The increase in sale is solely due to salein Bajaj, so the market share of Bajajshould be :
(61% of 1262699 + 631349)/ 1894048*100
74% answer
Which company has the maximum
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Which company has the maximumratio of ad spend to cigarette sales?
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Solution
For godfrey philips :
Ad spent : 50 against sales of : 1300
Thus it is : 3.84% For ITC it is 173/ 6700 = 2.58%
VST : 15/1400 = 1.05% approx.
STC = 19/600 = 3.166% Thus highest is in Godfrey Philips. Answer
I hi h h i f
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In which year was the ratio of denudation the highest?
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Solution
1996 : 1.2/3.2 * 100 = 33%
1993 : 2/8 *100 = 25%
1995 : 2/5.2 *100 = 38% So highest ratio is in 1995 answer
Which year witnessed the least
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Which year witnessed the leastincrease in reserve against the
previous year?
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Solution
Solve by observation. It is the least in1991 when it is close to 10% the least.
The highest growth is in 1990, when itgrows by 66% over the previous year. Answer
C it tili ti hi h t f
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Capacity utilisation was highest for which vehicle and when?
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Solution
By observation : motor cycles in 1999have capacity utilisation about 98%, whichis the highest for all. Answer.
What is the rate of growth of share
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What is the rate of growth of shareof Asia in total business of
Kingfisher as per data given below
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solution
Earlier Asian region accounted for :
5.4 + 11.1 = 16.5%
Now Asian region accounts for : 7.6 + 17.9 = 25.5%
It has grown from 16.5% to 25.5% that
means it has increased by 9%.
If 6(A¶s capital) = 8 (B¶s Capital) =
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( p ) ( p )10 (C¶s Capial), what is the ratio of
their capital ?
Take LCM of 6, 8 and 10. The LCM is :
120 Now 6A = 120, so A = 20
8B = 120, so B = 15
10C = 120, so C = 12 Ratio is : 20: 15:12 answer.
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If A :B = 3:4, B:C =5:6, C :D =11:9, what is the ratio of A:D?
A/B * B/C * C/D = A/D,
SO WRITE :
¾ * 5/6 * 11/9
WE GET : 55/ 72 OR 55: 72 ANSWER
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Which of the following stocks had most variationsbetween opening and closing stocks?
Stocks Open High Low Close
7UP 49.16 49.8 49.16 49.16
ABATEX 0.91 0.91 0.91 0.91
ABCTRANS 3.3 3.39 3.14 3.35
ACADEMY 9.46 9.93 9.93 9.46
ACCESS 15.98 16.4 15.36 15.52
ACENINS 0.95 0.95 0.95 0.95
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Solution
Access has the most variation betweenthe opening and closing stocks : variationsof .46 answer.
The result of an exam is given below Out of 1000
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The result of an exam is given below. Out of 1000students who appeared(i) 658 failed in Physics
(ii) 166 failed in Physics and Chemistry(iii) 372 failed in Chemistry, 434 failed in Physics
and Maths
(iv) 590 failed in Maths, 126 failed in Maths andChem Assume all students failed in at least one subject.
How many failed in Physics but not in
Mathematics? Physics : 658, Physics+maths = 434
Physics but not maths : 658-434= 224 ans.
If proteins and sugar are consumed in the ratio
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1:4, how many grams of proteins will be
required for a 200m jog?
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Solution«
If we take 100 gram protein, we will take400 gram suger. The calorie intake is : 125+400 = 525
650/525 * 100 = 123.8
Thus 123.8 gram of protein must beconsumed for 600 m jug.
In the previous question, which
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p qfood has the least number of
calorie per kg? A,B,C and D are the four foods. D has
maximum share of suger, but B has least
share of Fat which gives least calorie per gram. On calculation, we find that B givesthe least calorie per kg.
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Based on previous table, how
many more kg of food C isrequired for a 100 m. run than
for 100 m. walk?
4.3 times
Food A and C are mixed in ratio of
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1:2, what % of calorie come from
protein ?
26.67%
(take 100 g A and 200 g C, total proteinyou get is 40 + 40 = 80. thus you are ableto get 80 g protein out of 300 gram of totalintake. This is 26.67% answer)
In which year was actual Net revenue as a
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ypercentage of estimated plan size highest?
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Solution
Solve it and find that it is highest in 1994-95 which is 58% approx.
3808/6515*100 =58% approx.
A survey of moviegoers from five cities A to E : first
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A survey of moviegoers from five cities A,to E : first
column gives the percentage of viewers in each city
who watch less than 1 movie a week. The second
column gives the total number of viewers who watchone or more movies per week. How many viewers in
city C watch less than one movie a week?
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Solution
85/100 * 2400 = 2040
How many students with 2-3 years of work
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y y
experience did not prefer marketing?
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solution
Total students in 2-3 year experience :1080
Total students who opted for marketing :
(270 + 150 ) = 420
Thus there were 660 (1080 ± 420)answer.
The export of diamonds in 1996-97 was _______timesthe export of all other gems and jewellery put together
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the export of all other gems. and jewellery put together including sales to foreign, tourist.
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Solution «
14917/3300 = 4.5 times approx.
What is the change (in percentage) in the share of public issues in between August µ97 and
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public issues in between August 97 andDecember µ97?
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Solution
In august it was 24% approx.
(207 / 852 * 100)
In December it was 545/5042 * 100 =10.8%
Thus there is decline of 13.2 points.
With reference to the table below what is the cost
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With reference to the table below, what is the costincurred in the new µcoding¶ stage?
S
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Solution«
18 * 10 * 1000 = 180000 answer
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Excluding Latin America, what was the sale of
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electronics items in 2003 (figures in bracket show
annual growth rate)?
l ti
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solution
114200 US$ million answer.
(add 13000 * 100/ 90 + 42000 * 100/95 +49000 * 100/98 + 9000 * 100/92) answer
What part of the total electricity produced in 2002
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What part of the total electricity produced in 2002was contributed by Nuclear power plants?
S l ti
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Solution:
13.32%
=312 / (980+1050+312) * 100 answer
For which crop, we had maximumi d ti d
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area, maximum production and
maximum change in 94-2004?
S l ti
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Solution..
Maximum area : maize (UL), maximumproduction : cant be determined, andmaximum change in area in maize (UL).
We cant know about production from thisgraph.
In which year is the profit per rupee
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In which year is the profit per rupeeof equity the highest?
S l ti
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Solution«
Divide profit by equity:
It is highest in 1991 : 6/10 = .6, which isthe highest. Answer.
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What was average yearlypopulation of Argentina (in millions)
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population of Argentina (in millions)
from 1995 through 1997?Population of South America in1995 = 150 millions
Population in 1995 : 37.5 million. Add16.7% growth, it becomes : 43.7 and add
14% growth, it becomes 49.88. theaverage of these three numbers is 43.7.answer.
Use relevant data from last
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Use relevant data from last
question and tell : What is thefemale population of Peru (inmillions) in the year 2000?
Peru¶s population in 1995 is 12 million (8%of 150). We add growth it it. Thepopulation of 2000 is 22.36 ml. Now sex
ratio is 46%, so female population shouldbe 10.28 million. Answer.
The diagram in the left show marketing in green
and systems in blue. Marketing is further
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y g
classified in right pie chart. Green and maroon
colour on right are what % of the systems?
11
if in the previous graph, the actual
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p g p ,values are reduced by half, then
the maroon and blue combined isby what % more than red in the
left pie chart?
28% approximate.
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The result of an exam is given below. Out of 1000students who appeared
(i) 658 failed in Physics
(ii) 166 failed in Physics and Chemistry
(iii) 372 failed in Chemistry, 434 failed in Physics andMaths
(iv) 590 failed in Maths, 126 failed in Maths and Chem
Assume all students failed in at least one subject.
Th number of students who failed in all the threesubjects is (1) 178 (2) 73 (3) 106 (4) 126
Solution
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Solution«.
=1000- ((658 - (166+434)) +(372 -(166+126)) +(590 -(434+126))+(166+434+126)) = 106
answer.
solution
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solution
Which of these had least cost per
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room?
Solution
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Solution..
Divide the cost by the number of rooms
We get Royal Holidays with minimum costof .41.
FEI: black: 1997, white : 1998.Which country had maximum
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Which country had maximum
changein FEI?
soluton
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soluton
Just by observation, we find the answer :China
Graph shows market shares, what
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is the growth rate of company A?
Solution
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Solution
Data inadequate ± as we don¶t know aboutvolume or price.
Graph shows market shares, what isthe growth rate of company A if total
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the growth rate of company A, if total
volume has increased by 100% andvalue by 50%?
solution
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solution
Inadequate information ± as we don¶tknow whether the growth rate is in termsof volume or price?
Graph shows market shares, what is theannual growth rate of company A (in terms
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annual growth rate of company A (in termsof volume), if total volume has increased by
100% and value by 50%?
Solution
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Solution«
Suppose total volume was 100 in 1991,then the company A had 25. in 2001 totalvolume should be 200, company A should
have 50. Thus there is growth of 25 on 25= 100% growth. Divided by 10 years, weget annual growth rate of 10%. Answer.
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A, B, C and D are 4 villages on a straight road inthat order, given that B is equidistant from A andC while C is equidistant from B and D. Two girlsReena and Sheena decide to walk from A to D,covers the distance walking at 3 km/hr and
Sheena covers the first lap (upto B) at either 1 or 4 km/ hr and then walked at the other speed till
she meets Reena. Thereafter they walk together to D at Reena µs speed. Where did Sheena meetReena?
Solution
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Solution«
Suppose the total distance is 120 km. We have threegaps of 40 km each.
The average speed of seena from A to C is : ¼ + 1/1= 5/4 multiply it by ½, we get 5/8 reverse it : 8/5 = 1.6km per hour. Thus Seena should first travel by 1 kmper hour and then by 4 km per hour. Till Seena reachC, (80/1.6) = 50 hours ± Reena should cover 50 * 3 =150 km. Thus as per the logic they will never be ableto meet (If she starts with the speed of 1 km per hour) Thus there is inadequate information. If shestarts with the speed of 4 km per hour, there is apossibility that she can meet from B to C. «
Continued
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Continued«
If Seena starts at 4 km per hour, then she isahead of Reena. Seena will take 10 hours tocover the distance from A to B. now she willmove at 1 km per hour. And now Reena willmeet her. By the time Reena reaches B, Seenais at : 3.33 km from B. Now Reena will meet her at 3.33 / (3-1) = 1.66 hours. Thus they will meetbetween B and C. Now they will move @ 3 kmper hour. Thus from B to D, they will take 80/3 =
26.6 hours to complete the journey as per our asumptions. We need exact distance tocalculate the point where they met.
Data sufficiency question:
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In terms of m, y is what percent of x?
(A) m > 0
(B) x is m percent of y
(1) (A) or (B) alone, but not by other statement
(2) Either statement
(3) Both statements together (4) Cannot be answered
Rolling 6 dice it is found that :
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Rolling 6 dice, it is found that :
1. 3 dice show same numbersand rest show different numbers2. only one dice show 6
3. only 1 dice show 1, what ismaximum and minimum no.
greater than 3? Minimum = 1, maximum = 5.
A watch reads 4.30. if minute handpoints east in which direction will
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points east, in which direction will
the hour hand point?
North east
.333 of a number is .001 of
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another number, what is theratio of the two numbers?
Let us assume the 1st number to be 3, it
.33 is 1. now the second number is 1000 Thus ratio is 3: 1000 or 1:333 answer.
Or
Let us assume the 1st
number to be x. thefirst solution is .33X the second number is: .33x / .001, solving it we get : 333 x
Thus the ratio is 1: 333 answer.
1.5 of a number is 6 times another number, what is the ratio of the two
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number, what is the ratio of the two
numbers?
Let us assume the first number to be 100.
1.5 of this number is 150. This is 6 times another number, so divide
it by 6, we get : 25
The ratio is 100 : 25 Or 4:1 answer.
Shabnam wants to go to IIM, shestarts from her home which is East
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starts from her home, which is East
facing. She comes to a crossing.The road ahead takes to a hospital,
the road to left takes to Gujarat
University, in which direction is IIMfrom her home?
South ± East
A taxi goes 20 Km north, turns right
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and goes 30 km then turns rightagain and goes 35 km. Now
turning left goes 15 km. Finally
turns left and again goes 15 km. inwhich direction and how far is thetaxi from the original starting
position? 45 km east from the starting point.
a to f are 6 members in a family.There are 2 couples D is brother
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There are 2 couples. D is brother
of F and both are lighter than B,who is mother of D and lighter thanE. C is a lady and is neither the
heaviest or the lightest in thefamily. E is lighter than C. the
grandfather is the heaviest. E is a
man. Show the family diagram andas per weight also.
Solution«
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Solution«
The grandfather is A, and couples are AC(A is man, C women), EB (E is man and Bis woman) and we have two kids : F and
D. The relation as per weight is clear. The
heaviest is A, followed by C, E B and then
we have D and F. we don¶t know who islighter among D and F.
A t F b f f il Th
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A to F are members of a family. There are
1doctor, 1advocate, 1engineer, 1housewife,2 students in the family. There are 2
couples. F is the father of E and is doctor. Ais girl student and her husband is not an
advocate. B is the grandmother of D and ishousewife. Her husband is an engineer. Dis sister of E. What is the profession of A¶s
husband?
Solution«
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Solution«
A¶s husband is a doctor by profession.
P starts crossing the fielddi ll ft lki h lf
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diagonally after walking half way
he turns right. Walks samedistance turns left. Which direction
is he facing now?
p
q
R
S
NORTHSOUTH
From the original position, P & Qmove clock wise and cover half
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move clock wise and cover half
distance. R & S move anticlockwise and move one side distance.Both the groups then cross over
diagonally opposite direction. If original configerationis PSQR, what
is new configuration?p
S
R
Q
Solution«
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RQSP
From the original position, P & R
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move diagonally opposite corners.
Then they move one side anticlockwise and clock wise respectivley. S
and Q move two sides each clockwise and anticlock wise. Where isP now?
pr
QS
NORTHSOUTH
SOLUTION
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SOUTH WEST CORNER POSITION.
From the original position, P & Rmove diagonally opposite corners
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move diagonally opposite corners.
Then they move one side anticlockwise and clock wise respectivley. Sand Q move two sides each clock
wise and anticlock wise.Who is atnorth west corner now?
p
s
R
Q
NORTH SOUTH
SOLUTION
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R
Is X > 3?1. x^2 ± 8x +12 < =0
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2. x^2 ± 2x ± 8 < = 0 No answer is possible as we cannot draw
the answer from either statement.
Formula :[ - b + - sqrt (b^2 - 4ac) ]/ 2a
= 8 + 4 / 2 and ( 8 ± 4) / 2
We get x = 6 and 2
(2 + sqrt(4 +32) /2 = 4 and - 2 we get x = -2 and 4 from second equation.
Is sqrt x > 1/x ?
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q
1. x > 0
2 x < 0
Try from .04 and 4 we cant get the
answer.
Answer cannot be drawn from either statement.
The sum of an infinite GP : p,1,1/p, 1/p^2 «. Is a / 2, what is the
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value of p? Sum of infinite GP = a / (1 ± r)
P / ( 1 ± 1/p) = a / 2
2p = (ap ± a) /p
2p^2 = ap ± a
P^2 = ap ± a / 2
P = sqrt ((ap ± a ) / 2 )
If : (3+5+7««nth term) /(5+8+11«.10th term) = 7 , what is
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n ? Sum of AP = n/2 (2a + (n-1)d)
A = first term
D = difference = sum of the denominator series is 185
Numerator series / 185 = 7, so numerator
series total = 1295 =n/2 (6 + (n-1) 2) = `1295
Continued«
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n/2 (6 + (n-1) 2) = ̀ 1295 =n (6 + 2n ± 2) = 2590
=6n + 2n^2 ± 2n = 2590
2n^2 +4n ± 2590 = 0 [ - b + - sqrt (b^2 - 4ac) ]/ 2a
= (( -4 + sqrt(16 + 20720)) / 4
=( - 4 + 144) / 4 =35 answer
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A vending machine has 5 switchesfor coke,7up,maza,limca,pepsi.
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, p, , ,p p
Each switch gives 2 differentdrinks. Each drink can be obtainedfrom 2 switches. If two switches are
pressed, if there is common drink,nothing will come out, otherwise
you will get the drink desired. Press
the right combination for getting thedrink. .
1+3 = 7up and maza, 1+2 =k i 1 4 li k
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coke, pepsi, 1+4 = limca,coke,maza, pepsi switch 1,2,3,4,5don¶t give 7up, limca,coke,
maza, pepsi respectivley.
What is 2+3?
Maza + Limca+ 7up c,m,p,7up Coke maza pepsi, limca, 7up
Answer : pepsei, limca, 7 up
Solution «
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Prepare a matrix of rows and columns withdrinks in one side and switch in one sideto know the right combination.
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What should you turn on for limca +coke ?
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coke ?
2,3
1,2,3,5
1,3,4
2,3,4
Answer : 1,2,3,5
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7up pepsi coke maza limca
1 x x y Y x
2 y x x x
3 Y x x x y
4 x y x x Y
5 x x y y x
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How many integers N are theresuch : r < n < s?
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1. s-r = 5 2. r & s are not integers
Both the statements are required.
What is the time differencebetween NY and London?
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between NY and London?
1. departure time at NY is 9 amand arrival time at London is 10
am (both local times)2. flight time is 5 hours.
Both the statements are required.
X says to Y : ³ I am 3 times as oldas you were 2 years ago.´ how old
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y y g
is x?1. Y¶s age 17 years from now is
same as X¶s present age
2. X¶s age nine years from now is 3times Y¶s present age
Answer can be drawn only from the 1st
statement.
In a row of poles, one pole is 11th
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from either side. How many polesare there is in the row :
10 poles before and 10 after
Total we have 10 + 10 + 1 = 21 answer.
A,B,C are standing in a queue.
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g q
There are 5 persons between A andB and 8 persons between B and C.if there are 3 persons ahead of C
and 21 persons after A, what couldbe the minimum number of persons
in the queue?
Answer is : 28 answer
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Maximum 36 vehicles are markedin a parking lot in a single row
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in a parking lot in a single row.
After the first car, there is onemore bike. After the 2nd car thereare 2 bikes and after 3rd car, thereare 3 bikes and so on. How manybikes are there in the second row?
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A performance review table isincomplete with some more
d t il
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details«
Additional information
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Half the workers were either excellent or good.
40% of the workers were females.
One third of the male workers wereaverage.
How many students are both female and
excellent
Solution«
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avg good
excelle
nt total
male 16 22 10 48
female 24 8 0 32
total 40 30 10 80
answer
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Zero
In which month was the greatest absolute changein market value for any share recorded?
(black bar = XYZ white bar = ABC )
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(black bar = XYZ, white bar = ABC )
SOLUTION«
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MARCH (by observation, we find the shareprices of XYZ have increased by some17 points)
The average market value of XYZ.shares is, by what percent less or
th th f ABC? (bl k
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more than the same for ABC? (black
bar = XYZ, white bar = ABC )
SOLUTION
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ABC is approx. 75
XYZ is approx. 103
The difference is : 28
28/75 *100
=36% approx. answer.
(black bar = XYZ, white bar = ABC ), market capitalisation
means no. of shares * market price. Both companies have
1000 shares. What is the maximum market capitalisation of
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any company over the period?
Solution«
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The highest price visible is of ABC of 68 inthe month of April.
68 *1000 gives us 68000. thus highest
market capitalisation possible is 68000 for ABC.
Which Lok Sabha had minimumseats?
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Solution«
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We have to calculatethe number for eachloksabha. We findthat it is least in the
first lok sabha itself. Itis 499 for the firstyear.
498.8662132500
502.9585799
523.6486486521.3270142
544.4126074
543.6893204
550
517.2413793
544.6927374
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What will be next in the series:4, 5, 9,18,34 «
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Options:
43, 59, 50, 49
Solution«
4 + 1, = 5, 5 + 4 = 9, 9 + 9 = 18«. So on,we can see that only square values inseries are added ± thus the next value to
be added will be 25, so 34 + 25 = 59 .
What will be the next in the series :66,36,18 «
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Options: 3,6,8,9 Solution:
6 * 6 = 36,
3 * 6 = 18
1 * 8 = 8
So next number will be 8 .
What will be the next in the series :21,25,33,49,81,..
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Options: 145,111,113,127 Solutions
Look at the differences : 4,8,16,32 so on. Itis a series :
Thus next number will be : 81 + 64 = 145
ans
What will be the next in the series :12,32,72,152 «
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Options : 313, 312, 315, 512
Solution:
Look at the difference :
20,40,80,160«
Thus next number shouold be :
152 + 160 = 312 answer.
DATA SUFFICIENCY QUESTION: Vishaltakes morning train to his office from Bikaner to
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takes morning train to his office from Bikaner to
Delhi. His colleague Tarun joins him on theway. There are three stations A,B,C on the way
(not necessarily in this order), What is the
sequence of these stations?
STATEMENTS: `1. Tarun joins at B 2. Mr. Jitesh who travels between A & C is
with Vishal and never travels with Tarun.
Solution«
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Both the statements are inadequate toanswer : as we don¶t know out of A and Cwhich comes earlier. There is not
confirmed information in the question.
Data sufficiency question«What is the value of prime number
X?
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X?
X ^2 + x is a two digit number greater
than 50 X^3 is a three digit number
Solution«
Both the statements are required to givethe answer. ± as 7 is the only primenumber which fulfills both the conditions.
DATA SUFFICIENCY QUESTION: Vishaltakes morning train to his office from Bikaner
to Nokha and was delayed by 40 minutes
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to Nokha and was delayed by 40 minutesdue to engine trouble. What is the distance
beteween bikaner and Nokhastatements :
1. Engine trouble developed after 40 kmfrom Bikaner and speed reduced by 1/4th of
the original speed2. engine trouble developed after 2 hours of
journey and speed reduced by 1/4th.
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Read this table carefully and answer: Whatper cent of Karnataka¶s railway network has
broad gauge tracks?
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solution
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Total rail network in Karnakatak : 552 Thus 365/552 *100 gives 66.12% answer.
Read it and answer If the share of system software in the
total remains same 1990 as in 1988; and in 1990, the total
exports is Rs. 9,000 the system software export in 1990 is
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Solution«
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2800 / 6300 * 9000 = 4000 answer
Read it and answer If the share of system software in
the total remains same 1990 as in 1988; and in 1990,
the total exports is Rs. 9,000 the financial software
export in 1990 is
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Solution
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Answer cannot be determined.
y ow many mes as s o vbharati and Primary channel) commercialearnings increased over the given period?
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Solution«
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AIR revenue increased from 6.26 to 81over the period of time.
Thus it has increased by : 12.9 times.
81 has been arrived by adding 37.3 and43.7 (both the channels).
If 50 units each of A and B areproduced, which machine has been
poorly utilised?
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poorly utilised?
solution
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Except in machine 2nd, all the macines arehaving 100% capacity utilisation.
You can see this for machine 1 as : 50 * 3
+ 50 * 4 = 350 Answer = 2nd machine
I go 2 km towards east, I turnright and go 1 KM then I
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g gagain turn right and I go 1
KM. In which direction am I
now from my starting point? Answer: south east
A three CM cube has beenpainted red on all its sides. It is cut
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into one CM cubes. How manycubes will be there with one side
painted red?
26 cubes will have one or more sides painted,
out of these, some will be having 2 sides paintedand some 3 sides painted. The number of cubeshaving only one side painted will be : 6 answer.
X+y+z > 0, is Z > 1?Data sufficiency:
1) : Z > x +y, 2) : X+Y < 1
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) y, )
Both the statements are not sufficient
X+y+z > 0, is Z > 0?Data sufficiency:
1) : Z > x +y, 2) : X+Y < 1
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) y, )
1st statement alone is sufficient to answer the question.
Question on assumptions
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: ³If you are beautiful, we will catch your beauty. If you are not, we will make
you beautiful.´ ²An advertisement of a
photo Studio.
I. How to look beautiful, is a problem
of youngsters?
II. Nobody desires to be beautiful
Answer «.
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Only the first assumption is validassumption.
Question on assumption«
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The integrated steel plants in India would no longer have to depend on imports for
continuous casting refractories.
I; Continuous casting refractories are.needed by India.
II. Continuous casting refractors are in
demand.
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What is the missing number?
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Solution«
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Based on logic : 4+ 1 ± X = 4
SO X = 1.
FIND THE MISSING VALUE (hereinstead of 41 read 42)
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SOLUTION«
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The answer is 7, 7 * 4 = 28 and 7+4 = 11. answer
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On rolling 6 dice, it is found that: I. Three of the dice show the same
number. The rest show different numbers.
II. Only one dice shows 6. III. Not more than 3 dice show 4 or more.
What is the minimum possible total of
numbers on the faces if the three diceshow the same number 2?
Answer«
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The answer should be 21 with thefollowing breakup :
Three dice of 2 each One dice each of 4,5,6.
Total them up = 21. answer.
Question on puzzle
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On rolling 6 dice, it is found that: I. Three of the dice show the same
number. The rest show different numbers.
II. Only one dice shows 6. III. Not more than 3 dice show 4 or more.
What is the maximum total if 4 of the dice
show less than 4?
Solution«
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Answer is 22 with the followingcombination:
Three 3 = 3* 3 = 9 One each of 2,5,6 = 13
Total 22. answer.
Puzzle«
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On rolling 6 dice, it is found that:
I. Three of the dice show the same
number. The rest show different numbers. II. Only one dice shows 6.
III. Not more than 3 dice show 4 or more.
If only 1 dice shows 1, what is themaximum number of dice with numbersgreater than 4?
Solution«
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Answer is 2.
Puzzle «
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On rolling 6 dice, it is found that: I. Three of the dice show the same
number. The rest show different numbers.
II. Only one dice shows 6. If only 1 dice shows 1, what is the
maximum number of dice with numbers
greater than 4?
Solution«.
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We can take as under :
6,5,5,5,4,1,
Thus answer is 4.
After his.oftlce, in the evening, aman walks facing the sun. He turns
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first to his right, then to his left andagain to his left and then to hisright. In which direction is he
moving now?
Solution«
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He is moving towards west. You cancancel two left movements and two rightmovements by each other.
Starting from a point, Jitendrawalked 12 m towards North, he
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turned right and waked 10 m, heagain turned right and walked 12m,
then he turned left and walked 5 m.How far is he now and whichdirection from the starting point?
Solution«
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15 m. east
What is the all India annual growth rate
in demand of X as the following table?
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Solution«
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A compound growth rate of 14.14 willmake 146.54 to 283.9 in 5 years.
146.54* (1.1414)^5 = 283.9
Out of these, which region hadhighest growth rate?
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Solution
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The highest growth in the East section (in%)
In absolute terms, the highest growth rate
is in South region
WHAT IS THE NET DEMAND ATB?
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SOLUTION
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THE NET DEMAND AT B IS 1200 ± (250 + 550) = 400. ANSWER.
FOUR FRIENDS ARE SITTING IN A ROW TO BE PHOTOGRAPHED.
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D IS TO THE RIGHT OF B. C IS NEXTTO B. A IS AT ONE EXTREME. B IS NOTIN MIDDLE. THERE IS ONLY ONEPERSON TO THE LEFT OF C.
WHAT IS THE EXACT ORDER OFSITTING ARRANGEMENT?
SOLUTION
ND
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PUT C IN 2ND POSITION FROM LEFT AND A AND B IN EXTREME POSITIONS
ADCB Answer.
Four friends are beingphotographed?
D IS TO THE RIGHT OF B C IS NEXT
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D IS TO THE RIGHT OF B. C IS NEXTTO B. A IS AT ONE EXTREME. B IS NOTIN MIDDLE. IN THE PHOTO THAT WETAKE, THERE IS ONLY ONE PERSONTO THE LEFT OF C.
WHAT IS THE EXACT ORDER OFSITTING ARRANGEMENT?
SOLUTION
NOW WE HAVE TO PUT C AT 2ND
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NOW WE HAVE TO PUT C AT 2ND
POSITION FROM LEFT FROMOBSERVER¶S PERSPECTIVE.
A AND B ARE AT THE TWO ENDS. SITTING ARRANGEMENT IS :
ACDB.
ANSWER.
There were 6 cars in an exhibition. Alto was to the immediate right of
Swift. Spark was between
b d d I di I10 t
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ambassador and Indica. I10 was atone of the extreme ends. If youtake the third car from your right(when you observe these cars),then you find a car whose name
starts from I. What is the 3rd
car from your left?
Solution«
It ill b ith k ift
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It will be either spark or swift (draw the maps and solve it).
6 friends are getting photographed.They are sitting in a row. A and C
itti t th D i t th
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are sitting together. D is to theimmediate right of B. C is in the 2nd
position from left (when you
observe them), E and F are in themiddle. There are three persons to
the left of E. A is to the right of
maximum number of persons.What is the correct sitting order?
SOLUTION«.
Th t l ti i
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The correct solution is : ACEFDB
ARGUMENT«.
Sh ld th b ld t?
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Should there be world government? A 1. yes, it will help in eliminating tensions
A 2: no ± then only developed countries
will dominate. ANSWER :
Both the arguments are logicalarguments«
QUESTION ON BLOODRELATION«
R ³h i th h b d f X h i
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Ram says: ³he is the husband of X, who isthe daughter of Y, who is daughter of Z,who is my father.´. What is the relationbetween Ram and Y.
ANSWER :
Ram and Y are brother and Sister.
QUESTION ON CODING :
A COMPUTER USES FOLLOWING
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A COMPUTER USES FOLLOWINGSYSTEM WHILE SOLVING:
Input : 23, 09, 320, 90, 12,
1st step: 320, 23, 09, 90, 12 2nd step : 320,90,23,09,12
3rd step & Output: 320,90,23,12,09
In how many step will following input besolved : 90,121,94,23,233,898,22,400?
Solution«
I t 90 121 94 23 233 898 22 400?
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Input : 90,121,94,23,233,898,22,400? 1st step: 898, 90,121,94,23,233,22,400
2nd step: 898,400, 90,121,94,23,233,22,
3rd
step: 898,400,233, 90,121,94,23,22, 4th step: 898,400,233,121,90,94,23,22.
5th step: 898,400,233,121,94,90,23,22
Thus the question is solved in 5 steps. Answer.
SYLLOGISM
1 ll t
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1. : all rooms are stones 2. all stones are diamonds
Conclusion:
1. All rooms are diamonds2. All diamonds are rooms
3. All stones are rooms
4. No conclusion can be drawn
Answer
Onl 1st concl sion can be dra n
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Only 1st conclusion can be drawn
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Answer
Only 1st conclusion can be drawn
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Only 1st conclusion can be drawn
Read the information carefully: A,D, F,M are girls
A,D,E,F,G,H, are intelligentB C D E F G h d ki
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B,C,D,E,F,G, are hardworkingC,D,E,G,H,M are honest
A,B,C,D,E,F,M,H are ambitiousBoys play Cricket, Girls playChess
name the persons, who areambitious chess players.
solution
A D F M are the ambitious chess players
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A,D,F,M are the ambitious chess players
Read the information carefully: A,D, F,M are girls
A D E F G H are intelligent
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A,D,E,F,G,H, are intelligentB,C,D,E,F,G, are hardworkingC,D,E,G,H,M are honest
A,B,C,D,E,F,M,H are ambitious
Boys play Cricket, Girls play Chessname the persons, who are the chessplayers, who are neither honest, nor
hardworking, ambitious , intelligent?
Answer
None
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None
Read the information carefully: A,D, F,M are girls
A D E F G H are intelligent
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A,D,E,F,G,H, are intelligentB,C,D,E,F,G, are hardworking
C,D,E,G,H,M are honest
A,B,C,D,E,F,M,H are ambitiousBoys play Cricket, Girls play Chessname the persons, make a cricket team
of hardworking, intelligent and honestplayers
Solution«
E and G
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E and G.
2^a = 3^b = 6^-c , what
is value of 1/a +1/b +1/c?
L t l hi h
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Let us assume a value which we can equate with all these values. (use log table for solving this question).
Let us take all these values equal to 1. thus value of A, B and C are equal to Zero. Thus the answer is Zero.
We can also assume these values to be equal to 6.
A = 2.6, B =1.65 and C = -1
Now putting these values: ½.6 +1/1.65 ² 1
Log T + Log (T-3) = 1,
what is T?
We know that Log 10 = 1 (Log 10 )
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We know that Log 10 = 1. (Log 10
10 )
In log, we multiply, where the symbol is +.
Thus t * (t-3) = 10 ; T^2 -3T =10;
T^2 -3t -10 = 0
T^2 ² 5T + 2T -10 = 0
T (T-5) +2 (T-5); T-5 = 0 or T =5; T+2 =0
T = 5 or -2
Thus T = 5 answer.
Sum of 2 numbers is 52 and their difference is 2.
what are the numbers?X Y 52
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X + Y = 52
X ²Y = 2
A
dd these: 2
X =54; X =
27
Y = 25 answer.
Diagonal of rectangle is 5 CM. One of its side is 4
CM. Its area is ?L t fi d th th id
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Let us find the other side.
As per pythogorus rules, other
side is sqare root of (5^2-4^2) =
square root of (25-16) = square
root of 9
Other side is 3.
Area = 4*3 =12 answer.
Fourth part of a number exceeds the sixth part by
4. what is the number?
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X / 4 ² X /6 = 4
(6X-4X) / 24 = 4
2X = 96 X = 48 answer.
twice the smaller number is
less than twice the greater
one by 18 and 1/3 of smaler
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one by 18 and 1/3 of smaler and 1/5 of greater number
are together 21. What are
numbers? Bigger number = X , smaller no. = Y
2X-2Y = 18; 1/5 X + 1/3Y = 21
Let us multiply second eqation by 10, we get: 2X + 10/3
Y = 210. Subtract this equation from 1st. We get -16/3 Y
= -192 Y = 192 *3/16 = 36. thus smaller number is 36. Putting
this in first equation, we get 2X = 90 or X = 45 answer.
.
is five times the sum of its
digits. If 9 is added to it,
digits are reversed What is
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digits are reversed. What is the number? Let us assume unit digit to be X & digit
at tenth place to be Y.
The number is : 10Y +X
10Y +X= 5 (X +Y)
(10Y +X ) +9 = 10X +Y or 9y-9X = -9 or
Y-X =-1 10Y ² 5Y=5X-X or 5Y = 4X or Y = 4 and
X = 5 thus number is 45.
Solve such uestion b o tions.
Find the fraction which is equal to ½ when both its
numerator and denominator
are increasd by 2 and is
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are increasd by 2 and is equal to ¾ when both are
increased by 12? Options: 3
/8,
5/8, 3
/8,
2/3
Try from options. First option
gives you answer. If you add 2 in
each, you get 5/10 (which is ½)
and if you add 12 in both the
digits, you get 15/20 (which is ¾).
Thus option 1 gives answer.
If X: Y = 3:4, value of
x^2y +xy^2 :x^3+y^3?
Putting X = 3 and Y = 4
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Putting X = 3 and Y = 4.
36+48: 27+64
84:91
(divide b
oth the numb
ers by 7).
= 12:13 answer.
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2s-p:3t-p then which is true:
p^2= 6st or p =6st or 2p
=3st
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=3st Try from options.
Let us assume that P = 6. and as
per first option, St = 6. Let us try putting values in s and t and if we get correct answer , we get answer. S = 2, T = 3 or 4:9
We get next ratios as : -2: 3(which is subduplicate ratio of 2s:3t) thus this is the answer.
ABOUT AFTERSCHOOOL
Afterschoool conducts three year integratedPGPSE ( ft l 12th l ith IAS / CA /
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y gPGPSE (after class 12th along with IAS / CA /
CS) and 18 month PGPSE (Post GraduateProgramme in Social Entrepreneurship) along
with preparation for CS / CFP / CFA /CMA /
FRM. This course is also available online
also. It also conducts workshops on social
entrepreneurship in schools and colleges all
over India ² start social entrepreneurship
club in your institution today with the helpfrom afterschoool and help us in developing
society.
Why such a programme?
To promote people to take up
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To promote people to take up
entrepreneurship and help develop
the society
To enable people to take upfranchising and other such options
to start a business / social
development project
To enable people to take up social development as their mission
To enable people to promote
Who are our supporters?
Afterschoolians our past
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Afterschoolians, our past
beneficiaries, entrepreneurs
and social entrepreneurs are
supporting us.
You can also support us ² not
necessarily by money ² but by
being promotor of our concept and our ideas.
About AFTERSCHOOOL PGPSE ²
the best programme for
developing great entrepreneurs
Most flexible adaptive but rigorous
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Most flexible, adaptive but rigorous
programme
Available in distance learning mode
Case study focused- latest cases Industry oriented practical
curriculum
Designed to make you entrepreneurs
² not just an employee
Option to take up part time job ² so
earn while you learn
Workshops from
AFTERSCHOOOL
IIF, Delhi
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IIF, Delhi
CIPS, Jaipur
ICSI Hyderabad Branch
Gyan Vihar , Jaipur
Apex Institute of Management,Jaipur
Aravali Institute of Management,Jodhpur
Xavier Institute of Management,Bhubaneshwar
Pacific Institute, Udaipur
Engineering College, Hyderabad
Flexible Specialisations:
Spiritualising business and society
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p g y
Rural development and transformation
HRD and Education, Social Development
NGO and voluntary work
Investment analysis,microfinance and inclusion
Retail sector , BPO, KPO
Accounting & Information system (with CA / CS /CMA)
Hospital management and Health care Hospitality sector and culture and heritage
Other sectors of high growth, high technology and social relevance
Salient features:
The only programme of its kind (in the whole world)
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No publicity and low profile course
For those who want to achieve success in life ² not just a degree
Indepth knowledge and expertise
Professional approac: World class approach Strong intellectual and business capabilities
Flexible ² you may stay for a month and continue the rest of the education by distance mode. / you may attend weekend classes
Scholarships for those from poor economic b
ackground Latest and constantly changing curriculum ² keeping pace with the time
Placement for those who are interested
Admissions open throughout the year
Latest and most advanced technologies, books and
Components
Pedagogy curriculum and approach based on IIMAhmedabad and ISB Hyderabad (the founder is alumnus
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Ahmedabad and ISB Hyderabad (the founder is alumnus from IIMA & ISB Hyderabad)
Meditation, spiritualisation, and self development
Essential softwares for business
Business plan, Research projects
Participation in conferences / seminars Workshops on leadership, team building etc.
Written submissions of research projects/articles / papers
Inter view of entrepreneurs, writing biographies of entrepreneurs
Editing of journals / newsletters
Consultancy / research projects Assignments, communication skill workshops
Participation in conferences and seminars
Group discussions, mock inter views, self development diaryng
Mind Power Training & writing workshop (by Dr. T.K.Jain)
Pedagogy
Case analysis,
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y ,
Articles from Har vard Business Review
Quiz, seminars, workshops, games,
Visits to entrepreneurs and industrial visits
Presentations, Latest audio-visuals
Group discussions and group projects
Periodic self assessment
Mentoring and counselling
Study exchange programme (with institutions out of India)
Rural development / Social welfare projects
Branches
AFTERSCHOOOL will shortly
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AFTERSCHOOOL will shortly open its branches in important cities in India including Delhi,
Kota, Mumbai, Gurgaon and other important cities. Afterschooolians will be responsible for managing and
developing these branches ² and for promoting social entrepreneurs.
Case Studies
We want to write case studies
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We want to write case studies
on social entrepreneurs, first
generation entrepreneurs,
ethical entrepreneurs. Please help us in this process. Help us
to be in touch with
entrepreneurs, so that we may develop entrepreneurs.
Basic values at
afterschoool
Share to learn more
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Interact to develop yourself
Fear is your worst enemy
Make mistakes to learn
Study & discuss in a group
Criticism is the healthy route to mutual support and help
Ask fundamental questions : why,
when, how & where? Embrace change ² and compete with
yourself only
www.afterschoool.tksocial entrepreneurship for
better society
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