3
1763 N/mm 2 × 1,3 = 2292 N/mm 2 ø 8 0 n = –––––––– V c · 1000 � · D n = –––––––– 200 · 1000 � · 80 a p = –––––––– (D – d) 2 a p = –––––––– (80 – 72) 2 A = a p · f · z A = 4 mm · 0,2 mm · 5 n = 800 1/min a p = 4 mm A = 4 mm 2 h = f z · sin κ h = 0,2 mm · sin90 º h = 0,2 mm k c1.1 h mc 2 · � · n · M c 60s 2 · � · 800 min -1 · 348,3 Nm 60s d m 2 0,076 m 2 1160 0,2 0,26 k c = –––––––– k c = –––––––– k c = 1763 N/mm 2 F c = A · k c = b · h · kc F c = 4 mm 2 · 2292 N/mm 2 F c = 9,17 kN M c = F c ––––– M c = 9167,3 N ––––––– M c = 348,3 Nm P c = –––––––––– – P c = ––––––––––– ––––––––––– – P c = 29,2 kW Tools with ISO elements | Technical appendix | Calculation of cutting forces, boring Calculation of cutting forces, boring (simplified) ø 7 2 p r e d r i l l e d Boring tool ø 80 mm; Z = 5; pre-drilled ø 72 mm κ = 90° Material: EN-GJL-250 k c1.1 * = 1160 mc = 0.26 v c 200 m/min f z = 0.2 mm Blunting 30 % Example calculation: Note: The efficiency of the main spindle drive is not taken into account. Appropriate power calculations can be made by MAPAL. Basic formula Calculation Result * Value for cutting force calculation, WTO GmbH 1. Spindle speed 2. Cutting depth 3. Cutting cross section 4. Chipping thickness 5. Specific cutting force without blunting factor 6. Cutting force 7. Cutting torque d m = average diameter in metres 8. Cutting power with 30 % blunting: 174
![INDEX [akutboken.se] · othematom.....174 otits externa ..... 175 otits media.....176 . index 6 sinuit ...](https://static.documents.pub/doc/80x56/5c79f34409d3f2f93e8b874f/index-othematom174-otits-externa-175-otits-media176-index.jpg)
