1. All students will pair up with their assigned partner (or a group of three as selected by the teacher) to compete AGAINST EACH OTHER!

2. All students will play EVERY ROUND and show work on a separate sheet of paper (to be turned in).

3. Students will keep score together – winner gets bonus credit.

JEOPARDY!Algebra 2 – Unit 3 Review

A Picture Is Worth A

Thousand Words

Word World!

3’s Company

200

300

500

700

100

300

500

200

500

1000

100

200

400

The Basics

We’re Done! Good Luck on the Test!!

Solve for x and y:

x + 2y = 11

2x – y = 2

100

x = 3, y = 4or

(3, 4)

100

x + 2y = 11 x + 2y = 11(2x – y = 2) 2 4x – 2y = 4

5x = 15 x = 3

Solve for x and y:

x = 2y – 3

y – 3x = –1

200

y – 3(2y – 3) = –1

-5y + 9 = -1y = 2

x = 2(2) – 3 = 1

x = 1, y = 2or

(1, 2)

200

x = 2y – 3

y – 3x = –1

Solve for x and y:

4x – 3y = 5

8x – 6y = 12

400

Since 0 = 2 can NEVER be true …

“NO SOLUTION” !

!!

400

( 4x – 3y = 5 ) –2 –8x + 6y = –10

8x – 6y = 12 8x – 6y = 12

0 = 2

The sum of two numbers is 24. The first number is 4 less than the second number. Find the two numbers.

200

Let x = first numberLet y = second number

x + y = 24x = y – 4

x = 10, y = 14

200

Brandon has a pocket full of nickels and dimes. If he has 20 coins worth $1.30 in his pocket, how many of each coin does he have?

300

Let N = # of nickelsLet D = # of dimes

( N + D = 20 ) –5 ( .05N + .10D = 1.30 )

100

N = 14, D = 6

300

Twyla is taking her friends to a concert. Tickets cost $8 for general admission and $10 for reserved seating. If Twyla buys 12 tickets for a total of $102, how many of each kind of ticket did she buy?

500

Let G = # of general tickets

Let R = # of reserved tickets

( G + R = 12 ) –88G + 10R = 102

G = 9, R = 3

500

The perimeter of a rectangle is 44. If the length is 6 more than the width, then find the length and the width.

700

Let L = length, W = width

2L + 2W = 44

L = W + 6

Substitute to get … 2(W + 6) + 2w = 44

L = 14, W = 8

700

Graph the following and identify the solution:y = 2x – 8 2y + x = 4

100

(4, 0)

100

y = 2x – 8 2y + x = 4 y = –½ x + 2

300

Graph the following and identify the solution:y 3x – 3 y –2x + 4

300

y 3x – 3 y –2x + 4

500

Graph the following and identify the solution:y –5 x 2y x + 4

500

y –5 x 2 y x + 4

200

Solve for x, y and z:

3x + 5y + z = 5 x – 2y = –9 2x = –10

200

x = –5

y = 2

z = 10

3x + 5y + z = 5 x – 2y = –9 2x = –10

500

Solve for x, y, and z:

2x – y = 2

2y – z = 8

3x + z = 9

500

x = 3

y = 4

z = 0

2x – y = 2

2y – z = 8 4x – 2y = 4

3x + z = 9 3x + 2y = 17 7x = 21

1000

Solve for x, y and z:

x – y + z = –2 3x + 2y + z = 6 2x + 3y – 2z = 10

x = 1

y = 2

z = –1

1000

x – y + z = –2 3x + 2y + z = 62x + 3y – 2z = 10