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1st Yr Semi Honors Exam Reviewer

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!  A.M.D.G.  Ateneo de Manila High School Mathematics Subject Area Name: ______________ ___________ SY 11–12 CN: ________ Section: 1 - A B O 3 rd Term Exam Reviewer ! Multiple Choice. Encircle the letter of the correct answer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y x  y x  = ! " # = ! ! $ B. 2 4 2 4 8 y x  y x  = + ! " = + # C. 5 3 3 7 y x  y x  = ! " # = ! + $ D. 2 3 x  y  = ! " = #  7. What is the solution set of 3 3 x y  x y  + = ! " # # = # $ ?  A. { } B. C. {( , ) | 3 } x y x y   + = D. {(0,0)}  8. At what point do the graphs of 2x – 3y = 38 and 2x + 3y = -22 intersect?  A. (-4, 10) B. (4, -10) C. (-4, 30) D. (4, -30) SHORT ANSWERS. Provide what is being asked for below. ! ! "#!!$%B*!&1!*%+!'>(11?0>(@A'*!&,,A1*>B*+@8! ! =#!$%B*!&1!*%+!+HAB*&(.!()!B!,&.+!0+>0+.@&'A,B>!*(!*%+!,&.+!/>B0%+@!M+,(-!&)!*%+6!&.*+>1+'*!B*!*%+!6?B3&18! ! ! ! T!"! ! ! ! ! ! !!!!T=! ! ! ! ! ! ! ! ! ! ! ! ! ! ! ! !
Transcript
Page 1: 1st Yr Semi Honors Exam Reviewer

8/2/2019 1st Yr Semi Honors Exam Reviewer

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 A.M.D.G.

 Ateneo de Manila High School

Mathematics Subject Area Name: _________________________ 

SY 11–12 CN: ________ Section: 1 - A B O

3rd Term Exam Reviewer

!

Multiple Choice. Encircle the letter of the correct answer."#!$%&'%!()!*%+!)(,,(-&./!0(&.*1!,&+!(.!*%+!,&.+!23!4!56!7!28!

! ! 9#!1 1

,3 2

! "# $% &

! ! :#!1 1

,3 2

! "#$ %

& '! ! ;#!

1 1,

3 2

! "#$ %

& '! ! <#!

1 1,

3 2

! "# #$ %

& '!

=#!$%&'%!()!*%+!)(,,(-&./!'>(11?0>(@A'*1!'(.*B&.1!0(&.*! ( )3, 4! 8!

! ! 9#!C!3!D! ! ! :#!$!3!E! ! ;#!E!3!D! ! ! <#!D!3!C!

!

2#!D)!F0G!HI!,&+1!&.!HAB@>B.*!DDG!&.!-%&'%!HAB@>B.*!@(+1!FHG!?0I!,&+8!

! ! 9#!JD! ! ! :#!JDD! ! ! ;#!JDDD! ! ! <#!JDK!

!

5#!$%&'%!()!*%+!)(,,(-&./!%B1!B!/>B0%!*%B*!&1!0B>B,,+,!*(!*%+!3?B3&18!

! ! 9#!6!7!3! ! ! :#!6!7!?3!! ! ;#!6!7!2! ! ! <#!3!7!5!

!

L#!$%B*!&1!*%+!1,(0+!()!B!,&.+!0+>0+.@&'A,B>!*(!*%+!,&.+!@+1'>&M+@!M6!23!N!6!4O!7!P8!

! ! 9#!?2! ! ! :#!?"Q2! ! ! ;#!"Q2! ! ! <#!2!

!

R#!$%&'%!()!*%+!)(,,(-&./!&1!B.!&.'(.1&1*+.*!161*+S8!

! ! 9#!2 8

2 8

y x  

y x  

= !"#

= ! !$B.

2 4

2 4 8

y x  

y x  

= +!"

= +#C.

5 3

3 7

y x  

y x  

= !"#

= ! +$D.

2

3

x  

y  

=!"

=# 

7. What is the solution set of  3

3

x y  

x y  

+ =!"

# # = #$?

 A. { } B. ! C. {( , ) | 3}x y x y    + = D. {(0,0)}  

8. At what point do the graphs of 2x – 3y = 38 and 2x + 3y = -22 intersect?

  A. (-4, 10) B. (4, -10) C. (-4, 30) D. (4, -30)

SHORT ANSWERS. Provide what is being asked for below.!!

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4

4

y x  = ! + , find the coordinates of D

algebraically.

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5. Find the values of x, y and z given the system.

1 2 15

2 2 111

1 1 2

1

x y z  

x y z  

x y z  

!+ + = "#

##

" " =$##

+ " =#%

 

 APPLICATION. Solve the following word problems by showing a representation, equation,solution and answer.

1.  The cost of producing a certain number of bracelets follows a linear behavior. If it costs P135 toproduce 10 bracelets and P282 to produce 52 bracelets, how much will it cost to produce 150

bracelets?

2.  If the numerator of a fraction is increased by one and the denominator is increased by 2, its valuebecomes 2/3. However, if 2 is subtracted from the numerator and the denominator is decreased by 1,

its value becomes 1/3. Find the original fraction.!

!

$??'@'-($.!ABA#C',A,!

!

<[!$\9Z!D]!9]^_<#!

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!

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a! "! =! 2! 5! L! R!

6! "Q=! =Q2! 2Q5! 5QL! LQR! RQW!

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 0 2 ( 1) (m - 3)

0 (2 3) (3 4)

y k x 

k x m y  

= ! + +"#

= ! ! + +$ 

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B#  $%B*!BS(A.*!@&@!%+!1+*!B1&@+!0+>!@B68!

M#  \(-!SA'%!S(.+6!@&@!%+!%BY+!M+)(>+!%+!1*B>*+@!*%+!1'%+S+8!

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4 3 2 6 4 3x y xy x y xy x y x y    ! + + ! !  

2. Subtract 24 5x x  ! !)>(S!

25 4x x  ! !

!

2#!dA,*&0,6! (2 3 )a b ! -&*%!(5 4 )b c  ! !

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x x  x  

+ !

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