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Vectors and the Geometry
of Space
Chapter 1
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Vector and its Operations
Lesson 1
Objective:
At the end of the lesson you should be able to:
1. Define vector.
2. Find a vector , its magnitude and its direction.
3. Use the fundamental operations of vectors.
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Vectors
Definition:
Vectoris a quantity with magnitude and direction.
Example: displacement, velocity , weight, force
How to find a vector?
1. Given two points in the xy-plane
2. Given two points in the xyz-plane
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"!"! bayyxxv
yxPyxP
,)(),(
),(,),(
1212
222111
"!"! cbazzyyxxv
zyxzyx
,,)(,)(),(
),,(,),,(
121212
22221111
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The components of the vector in the two dimensional
space are a and b. While in the three dimensional space,the components are a, b, and c.
Addition of Vectors (Graphical Method)
1. Triangle Law 2. Parallelogram Law
The sum is the resultant vector.
u+vv
u
u+v
v
u
v
u
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Addition/Subtraction of Vectors (Analytical Method)
Given two vectors a and b where a =< > and b= < >
a+b= < > and b-a=< >
Likewise ifa = < > and b = < >
a+b=< > and b-a= < >
Magnitude of a Vector
The magnitude or length is indicated as
"!!
"!!
321
2
3
2
2
2
1
21
2
2
2
1
,,,)()()(
,,)()(
aaavaaav
aav
aav
For two and three dimensional vectors respectively.
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21
,aa21
,bb
2211 , baba 2211 , abab
332211,, bababa
321 ,, aaa 321 ,, bbb
332211 ,, ababab
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Multiplication by a Scalar(c)
A vector can be multiplied by a scalar quantity c . If vectora=< > then ca = < > or if vector
a= < > then ca = < >.
Properties of Vectors
1. a+b= b +a 2. a+(b+c)= (a+b)+c
3. a+0= a 4. a+(-a) = 0
5. 1a=a 6. c(a+b)= ca + cb
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21, aa 21,caca
321 ,, aaa 321 ,, cacaca
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The Forms of a Vector
A vector in two dimensional takes the i andj form .For
example, a = 2i 4j, in component form this can be
written as, a= .
A vector in three dimensional space takes the i, j, and k
form. For example, a =-3i+ 6j- k , in component form
this can be written as,a = < -3, 6, -1>.
Any vector can be represented by a small bold letter or it
could be represented by with an arrow above the
letter.a
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Examples
a) C( 3,-5) and D( -6, 2)
b) b) C ( 1, 3, 4) and D ( 5 , -1, 0)
find the components of the vector CD and itsmagnitude.
a) v= = = -9i + 7j
b) v= < (5-1), (-1-3),(0-4)>= < 4, -4, -4> =4i- 4j- 4k
1307)9(
22!!
v
1. Given are two points C and D
34)4()4(4222 !!v
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Examples
2. Given a= < 1, 2, 3> and b = < -1, 3, -6> find the
following:
a) 2a +b b) b3
2
Solution:
a) 2a + b = 2 + = =
"!"! 4,2,3
26,3,1
3
2
3
2bb)
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Solve 21 and 22 on page 841!!
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Unit Vector
Definition
A unit vector (u) is a vector whose length is one. For
instance, i ,j , and k are all unit vectors.
In general ifa # 0 then the unit vector that has the same
direction as a is
a
a
au !!
1
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Do problems 24 and 25 on page 841
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Example 1: Unit Vector
Find the unit vector that has the same direction as the given
vector:
a) v = < 3,-6 > b) a= 5j- k
Solution
a)
45
6,36,3
6,3
1 "!"
"
!u
b)26
1,5,01,5,0
1,5,0
1 "!"
"!u
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The Dot Product
Definition
If a = and b = then the dot
product ofa and b is given by
"321 ,, aaa " 321 ,, bbb
332211
321321 ,,,,babababa
bbbaaaba!y
"y"!y
Example 2: Give the dot product of the following:
.4,1,36,3,2)
5,18,4)
"y"
"y"
b
a
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Answers:
a) 36)5(8)1(45,18,4 !!"y"
b)
212436
)4(61)3()3(24,1,36,3,2
!!
!"y"
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Solve more problems on page 848
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Angle Formed Between Two Vectors
Theorem
If is the angle between the vectors a and b, thenU
U!y cosbaba
Corollary
If is the angle between the nonzero vectors a and
b, then
U
ba
ba y!Ucos
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Direction Angles and Direction Cosines of a Vector
Definition
The direction angle of a nonzero vectora are the
angles in the interval [ 0, ] that a makes
with the positive x, y, and z axes.
KFE and,, T
z
y
xE
F
K
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Use the following formulas to find the direction cosines
"!
!K!F!U
321
321
,,
cos,cos,cos
aaaawhere
a
a
a
a
a
a
and the direction angles are
a
a
a
a
a
a312111
cos,
cos,
cos
!K!F!U
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Example 3: Angle Between Two Vectors
1. Find the angle between the two vectors a = < 1, -2, 3 >
and b = < 0, 5 , 9 >.
Solution
01
22222
8.7340.0cos
40.0
45.42
17
10614
27100cos
9503)2(1
9,5,03,2,1cos
!!U
!!
!U
"y"!
y!U
ba
ba
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Example 4: Direction Angles
2. Find the direction angles of vector b =3i + 4j + 5 k.
Solution
01
1
222
1
65424.0cos
50
3cos
543
3cos
5,4,3
!!E
!
!E
"!
b
What are the values of ?KF and
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YourAnswers?
011
01
45707.0cos
07.
7
5cos
5.55
07.7
4cos
!!!K
!!F
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Orthogonal Vector
Definition
Two vectors a and b are orthogonal if .
Recall that and if the angle is
90 degrees its cosine is 0 hence the dot product between
vectors a and b is 0.
Look at some examples!!
0!yba
U!y cosbaba
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Example 5: Orthogonal and Parallel Vectors
Find out whether the two vectors are orthogonal or parallel.
1. a = and b =
2. u = < 1,-1,2 > and v =
Solution
1. The two vectors are not parallel ( parallel only if they
have the same direction i.e., the components of the
vectors are the same or b=
ka ).
The two vectors are orthogonal.
05831,4,35,2,1 !!"y"!yba
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2. 52121,1,22,1,1 !"!y"!y vu
The two vectors are not orthogonal neither they are
parallel.
Do some more problems on page 849 nos.
23 a, d and 24 a , c.
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Remember!
The dot product is a scalar.
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Cross Product
Definition
Ifa = and b= then the cross
product ofa and b is the vector
"321 ,, aaa "
321 ,, bbb
"!v
!v
!"v"!v
122113312332
122113312332
321
321
321321
,,
)()()(
,,,,
bababababababa
babakbabajbabaiba
bbb
aaa
kji
bbbaaaba
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Theorem
If is the angle between a and b then .U U!vsi
nbaba
The cross product is the vector that is perpendicular to
both a and b.
Corollary
Two nonzero vectors are parallel if and only if
Take note that if sine of these angles are 0.
Also the magnitude of the cross product is equal to the
area of the parallelogram determined by a and b.
0!vba
T!U!U or0
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a
b
U
Usinb
Using Figure 1, A = baba v!U)sin(
Figure 1
For a parallelepiped (rectangular solid) volume is
determined by using scalar triple product i.e.,
If V = 0, then three vectors are co-planar.
)( cbaV vy!
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Example 6: Cross Product
1. Find the cross product given a = and
b = .Verify whether it is orthogonal to both a and b.
Solution
kjikjiba
kji
ba
32)03()01()02(
130
0211,3,00,2,1
!!v
"!v"!v
Then to verify whether orthogonal to both a and b,
00
330022
1,3,03,1,20,2,13,1,2
0)()(
!
!
"y"!"y"
!yv!yv bbaaba
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2. Find the volume using the scalar triple product given
a=
i+
j
k, b=
i-j+
kandc =
-i+
j+
k.
Solution
4022)(
11
111
11
111
11
111
111
111
111
)(
!!vy
!
!vy
cba
cba
The volume of the parallelepiped is 4 cu. units.
More problems can be found on page 857. Practice
by solving some of them!
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Torque
Torque is the turning effect when a force is acting on a
rigid body at a point given by a position vectorr.It is defined
to be the cross product of the position and force vectors
i.e.,
U!v!X
v!X
sinFrFr
Fr
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Example 7: Torque
A bicycle pedal is pushed by a foot with a 60 N force asshown. The shaft of the pedal is 18 cm long. Find the
magnitude of the torque about P.
60 N
P
P
JoulesNm
Nm
64.1064.1080sin)60(18.0
)1070sin(6018.0
0
00
!!!X
!X
010
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Solve36 and 37 on page 857!