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1Vector and Its Operations Lesson 1

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    Vectors and the Geometry

    of Space

    Chapter 1

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    Vector and its Operations

    Lesson 1

    Objective:

    At the end of the lesson you should be able to:

    1. Define vector.

    2. Find a vector , its magnitude and its direction.

    3. Use the fundamental operations of vectors.

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    Vectors

    Definition:

    Vectoris a quantity with magnitude and direction.

    Example: displacement, velocity , weight, force

    How to find a vector?

    1. Given two points in the xy-plane

    2. Given two points in the xyz-plane

    UTP/JBJ 1

    "!"! bayyxxv

    yxPyxP

    ,)(),(

    ),(,),(

    1212

    222111

    "!"! cbazzyyxxv

    zyxzyx

    ,,)(,)(),(

    ),,(,),,(

    121212

    22221111

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    The components of the vector in the two dimensional

    space are a and b. While in the three dimensional space,the components are a, b, and c.

    Addition of Vectors (Graphical Method)

    1. Triangle Law 2. Parallelogram Law

    The sum is the resultant vector.

    u+vv

    u

    u+v

    v

    u

    v

    u

    UTP/JBJ 2

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    Addition/Subtraction of Vectors (Analytical Method)

    Given two vectors a and b where a =< > and b= < >

    a+b= < > and b-a=< >

    Likewise ifa = < > and b = < >

    a+b=< > and b-a= < >

    Magnitude of a Vector

    The magnitude or length is indicated as

    "!!

    "!!

    321

    2

    3

    2

    2

    2

    1

    21

    2

    2

    2

    1

    ,,,)()()(

    ,,)()(

    aaavaaav

    aav

    aav

    For two and three dimensional vectors respectively.

    UTP/JBJ 4

    21

    ,aa21

    ,bb

    2211 , baba 2211 , abab

    332211,, bababa

    321 ,, aaa 321 ,, bbb

    332211 ,, ababab

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    Multiplication by a Scalar(c)

    A vector can be multiplied by a scalar quantity c . If vectora=< > then ca = < > or if vector

    a= < > then ca = < >.

    Properties of Vectors

    1. a+b= b +a 2. a+(b+c)= (a+b)+c

    3. a+0= a 4. a+(-a) = 0

    5. 1a=a 6. c(a+b)= ca + cb

    UTP/JBJ 5

    21, aa 21,caca

    321 ,, aaa 321 ,, cacaca

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    The Forms of a Vector

    A vector in two dimensional takes the i andj form .For

    example, a = 2i 4j, in component form this can be

    written as, a= .

    A vector in three dimensional space takes the i, j, and k

    form. For example, a =-3i+ 6j- k , in component form

    this can be written as,a = < -3, 6, -1>.

    Any vector can be represented by a small bold letter or it

    could be represented by with an arrow above the

    letter.a

    UTP/JBJ 6

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    Examples

    a) C( 3,-5) and D( -6, 2)

    b) b) C ( 1, 3, 4) and D ( 5 , -1, 0)

    find the components of the vector CD and itsmagnitude.

    a) v= = = -9i + 7j

    b) v= < (5-1), (-1-3),(0-4)>= < 4, -4, -4> =4i- 4j- 4k

    1307)9(

    22!!

    v

    1. Given are two points C and D

    34)4()4(4222 !!v

    UTP/JBJ 7

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    Examples

    2. Given a= < 1, 2, 3> and b = < -1, 3, -6> find the

    following:

    a) 2a +b b) b3

    2

    Solution:

    a) 2a + b = 2 + = =

    "!"! 4,2,3

    26,3,1

    3

    2

    3

    2bb)

    UTP/JBJ 8

    Solve 21 and 22 on page 841!!

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    Unit Vector

    Definition

    A unit vector (u) is a vector whose length is one. For

    instance, i ,j , and k are all unit vectors.

    In general ifa # 0 then the unit vector that has the same

    direction as a is

    a

    a

    au !!

    1

    UTP/JBJ 9

    Do problems 24 and 25 on page 841

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    Example 1: Unit Vector

    Find the unit vector that has the same direction as the given

    vector:

    a) v = < 3,-6 > b) a= 5j- k

    Solution

    a)

    45

    6,36,3

    6,3

    1 "!"

    "

    !u

    b)26

    1,5,01,5,0

    1,5,0

    1 "!"

    "!u

    UTP/JBJ 10

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    The Dot Product

    Definition

    If a = and b = then the dot

    product ofa and b is given by

    "321 ,, aaa " 321 ,, bbb

    332211

    321321 ,,,,babababa

    bbbaaaba!y

    "y"!y

    Example 2: Give the dot product of the following:

    .4,1,36,3,2)

    5,18,4)

    "y"

    "y"

    b

    a

    UTP/JBJ 11

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    Answers:

    a) 36)5(8)1(45,18,4 !!"y"

    b)

    212436

    )4(61)3()3(24,1,36,3,2

    !!

    !"y"

    UTP/JBJ 12

    Solve more problems on page 848

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    Angle Formed Between Two Vectors

    Theorem

    If is the angle between the vectors a and b, thenU

    U!y cosbaba

    Corollary

    If is the angle between the nonzero vectors a and

    b, then

    U

    ba

    ba y!Ucos

    UTP/JBJ 13

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    Direction Angles and Direction Cosines of a Vector

    Definition

    The direction angle of a nonzero vectora are the

    angles in the interval [ 0, ] that a makes

    with the positive x, y, and z axes.

    KFE and,, T

    z

    y

    xE

    F

    K

    UTP/JBJ 14

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    Use the following formulas to find the direction cosines

    "!

    !K!F!U

    321

    321

    ,,

    cos,cos,cos

    aaaawhere

    a

    a

    a

    a

    a

    a

    and the direction angles are

    a

    a

    a

    a

    a

    a312111

    cos,

    cos,

    cos

    !K!F!U

    UTP/JBJ 15

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    Example 3: Angle Between Two Vectors

    1. Find the angle between the two vectors a = < 1, -2, 3 >

    and b = < 0, 5 , 9 >.

    Solution

    01

    22222

    8.7340.0cos

    40.0

    45.42

    17

    10614

    27100cos

    9503)2(1

    9,5,03,2,1cos

    !!U

    !!

    !U

    "y"!

    y!U

    ba

    ba

    UTP/JBJ 16

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    Example 4: Direction Angles

    2. Find the direction angles of vector b =3i + 4j + 5 k.

    Solution

    01

    1

    222

    1

    65424.0cos

    50

    3cos

    543

    3cos

    5,4,3

    !!E

    !

    !E

    "!

    b

    What are the values of ?KF and

    UTP/JBJ 17

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    YourAnswers?

    011

    01

    45707.0cos

    07.

    7

    5cos

    5.55

    07.7

    4cos

    !!!K

    !!F

    UTP/JBJ 18

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    Orthogonal Vector

    Definition

    Two vectors a and b are orthogonal if .

    Recall that and if the angle is

    90 degrees its cosine is 0 hence the dot product between

    vectors a and b is 0.

    Look at some examples!!

    0!yba

    U!y cosbaba

    UTP/JBJ 19

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    Example 5: Orthogonal and Parallel Vectors

    Find out whether the two vectors are orthogonal or parallel.

    1. a = and b =

    2. u = < 1,-1,2 > and v =

    Solution

    1. The two vectors are not parallel ( parallel only if they

    have the same direction i.e., the components of the

    vectors are the same or b=

    ka ).

    The two vectors are orthogonal.

    05831,4,35,2,1 !!"y"!yba

    UTP/JBJ 20

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    2. 52121,1,22,1,1 !"!y"!y vu

    The two vectors are not orthogonal neither they are

    parallel.

    Do some more problems on page 849 nos.

    23 a, d and 24 a , c.

    UTP/JBJ 21

    Remember!

    The dot product is a scalar.

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    Cross Product

    Definition

    Ifa = and b= then the cross

    product ofa and b is the vector

    "321 ,, aaa "

    321 ,, bbb

    "!v

    !v

    !"v"!v

    122113312332

    122113312332

    321

    321

    321321

    ,,

    )()()(

    ,,,,

    bababababababa

    babakbabajbabaiba

    bbb

    aaa

    kji

    bbbaaaba

    UTP/JBJ 22

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    Theorem

    If is the angle between a and b then .U U!vsi

    nbaba

    The cross product is the vector that is perpendicular to

    both a and b.

    Corollary

    Two nonzero vectors are parallel if and only if

    Take note that if sine of these angles are 0.

    Also the magnitude of the cross product is equal to the

    area of the parallelogram determined by a and b.

    0!vba

    T!U!U or0

    UTP/JBJ 23

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    a

    b

    U

    Usinb

    Using Figure 1, A = baba v!U)sin(

    Figure 1

    For a parallelepiped (rectangular solid) volume is

    determined by using scalar triple product i.e.,

    If V = 0, then three vectors are co-planar.

    )( cbaV vy!

    UTP/JBJ 24

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    Example 6: Cross Product

    1. Find the cross product given a = and

    b = .Verify whether it is orthogonal to both a and b.

    Solution

    kjikjiba

    kji

    ba

    32)03()01()02(

    130

    0211,3,00,2,1

    !!v

    "!v"!v

    Then to verify whether orthogonal to both a and b,

    00

    330022

    1,3,03,1,20,2,13,1,2

    0)()(

    !

    !

    "y"!"y"

    !yv!yv bbaaba

    UTP/JBJ 25

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    2. Find the volume using the scalar triple product given

    a=

    i+

    j

    k, b=

    i-j+

    kandc =

    -i+

    j+

    k.

    Solution

    4022)(

    11

    111

    11

    111

    11

    111

    111

    111

    111

    )(

    !!vy

    !

    !vy

    cba

    cba

    The volume of the parallelepiped is 4 cu. units.

    More problems can be found on page 857. Practice

    by solving some of them!

    UTP/JBJ 26

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    Torque

    Torque is the turning effect when a force is acting on a

    rigid body at a point given by a position vectorr.It is defined

    to be the cross product of the position and force vectors

    i.e.,

    U!v!X

    v!X

    sinFrFr

    Fr

    UTP/JBJ 27

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    Example 7: Torque

    A bicycle pedal is pushed by a foot with a 60 N force asshown. The shaft of the pedal is 18 cm long. Find the

    magnitude of the torque about P.

    60 N

    P

    P

    JoulesNm

    Nm

    64.1064.1080sin)60(18.0

    )1070sin(6018.0

    0

    00

    !!!X

    !X

    010

    UTP/JBJ 28

    Solve36 and 37 on page 857!


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