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2008 Science (Physics) Section A

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2008 Science (Physics) Section A . Questions, Answers and Comments. If you are using topical TYS (2002-2010 - version). What did the examiner say?. Mass, Weight and Density. Easy chapter to score Must know definition of mass, weight, gravitational field and gravitational field strength - PowerPoint PPT Presentation
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2008 Science (Physics) Section A Questions, Answers and Comments
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Page 1: 2008 Science (Physics) Section A

2008 Science (Physics)Section A

Questions, Answers and Comments

Page 2: 2008 Science (Physics) Section A

If you are using topical TYS (2002-2010 - version)

Qn in 2008 Paper Topical TYS (Section A)

1 Topic 4(6) – Mass, weight density (Q4)

2 Topic 13(5) - Electromagnetic Spectrum (Q3)

3 Topic 7(11) – Energy, Work, Power (Q6)

4 Topic 15(4) – Static Electricity (Q1)

5 Topic 12C(5) – Light - Lens (Q2)

6 Topic 10(7) – Thermal Properties of Matter (Q2)

7 Topic 1(6) – Measurements – Vectors (Q1)

8 Topic 18(8) – Practical Electricity (Q4)

9 Topic 17(13) – DC Circuit (Q4)

Page 3: 2008 Science (Physics) Section A

What did the examiner say?

Page 4: 2008 Science (Physics) Section A

Mass, Weight and Density• Easy chapter to score

• Must know definition of mass, weight, gravitational field and gravitational field strength

• Must be able to compare mass and weight

• Formula : w = mg (note: m is in kg while g, the gravitational field strength depends on the location)

• Formula : density = (note: be careful with formula of volume and mass)

Page 5: 2008 Science (Physics) Section A

ANS: Mass = density x volume = 5.5 x 20 = 110 g

ANS: mass = 110 g

(mass does not change with location)

Page 6: 2008 Science (Physics) Section A

ANS: w = mg = x 1.6

= 0.176 N

Mass must be in kg.

Page 7: 2008 Science (Physics) Section A

Electromagnetic Spectrum

• EM waves – are all transverse waves; – travel with speed of 3 x 108 m/s in vacuum

• Application

Page 8: 2008 Science (Physics) Section A

(a) Infrared (b) Microwave(satellite TV is not the same as TV communication which uses radio wave. Radio wave is easily absorbed and cannot make it to the satellite) (c) Gamma rays

Page 9: 2008 Science (Physics) Section A

Kinematics

• Define speed and velocity

• Formula

(if object is decelerating, then v will be smaller than u and a will be negative)

Average speed = total distance travelled total time taken

(total time would also include the rest time in the journey)

Page 10: 2008 Science (Physics) Section A

Kinematics

• acceleration of free-fall for a body near the earth is 10 m/s2.

(if air resistance is ignored, all objects will fall at the same acceleration of 10 m/s2 which means that their velocity will increase by 10 m/s every second)

Page 11: 2008 Science (Physics) Section A

Kinematics

• Speed-Time Graph

• Area under speed – time graph = distance travelled by object

Page 12: 2008 Science (Physics) Section A

Kinematics

Page 13: 2008 Science (Physics) Section A

Time = distance / speed = 600/40 = 15 s

(Do not stop the graph at 15 s)

a = (v – u) / t t = (v – u) / a = (40 – 0)/8 = 5 s

Page 14: 2008 Science (Physics) Section A

KE = ½ mv2

= ½ (300) (40)2

= 240 000 J

Don’t forget to square the velocity

*must calculate acceleration first before force can be calculated (since F = ma)

a = v - u t = (0 – 40) / 8 = - 5 m/s2

F = ma = 300 x 5 = 1500 N

Don’t mix up initial and final velocity

Page 15: 2008 Science (Physics) Section A

Note details in diagram like the kind of charges

The high voltage supply is used to charge the metal

plate and metal grid to become +ve and

– ve respectively

Page 16: 2008 Science (Physics) Section A

Don’t get mixed up with magnetism and use unlike ‘poles’

The dust particles will gain negative charge from the metal grid and get attracted to the positive metal plate.This is because unlike charges attract.

Answer must consist of the ‘description’ part and ‘explanation’ part.

“Like charges repel” / “unlike charges attract” can be used to explain most electrostatic qn

Page 17: 2008 Science (Physics) Section A

What else you need to know

• How to draw electric field of a point charge• Define electric field

Page 18: 2008 Science (Physics) Section A

Focal length = 1.8 cm – 1.9 cm

Accuracy is very important! Only a small range is accepted by examiner.

Don’t forget to add

arrows!

Page 19: 2008 Science (Physics) Section A

refractive index of glass = speed of light in air speed of light in glass

1.5 = 3 x 108 / v

v = 3 x 108 / 1.5

= 2 x 108 m/s

Remember: the larger speed is at the top

Refractive index is always bigger than 1

Many made mistake here!

Page 20: 2008 Science (Physics) Section A

Take note that the solid in the ice pack melts at 1oC, not 0oC

Page 21: 2008 Science (Physics) Section A

The temperature of the solid in the ice pack will remain at 1oC (its melting point) until all of it has melted). Remember: Temperature of a substance does not change during change of state.

This is because when the solid in the ice pack melts, it will absorb heat from the surrounding food and cools it down. For solid that does not melt, less heat is absorbed from the food.

When an object cools down, it is because it loses heat. There is no such thing as absorbing “coldness”.

Page 22: 2008 Science (Physics) Section A

What else you need to know?

• Which processes below absorb energy and which one releases energy to the environment?

Boiling melting evaporation freezing condensation

Page 23: 2008 Science (Physics) Section A

Vector quantity has direction but scalar quantity does not have direction.

No need to give specific example of scalar or vector.

No need to mention similarity that both have magnitude since

qn ask for ‘difference ‘ . If qn says ‘compare’, must also state

similarity.

Page 24: 2008 Science (Physics) Section A

• Must draw ARROWS !!!• Must label the forces, not the length of the line.• Can check ans by using Pythagoras Theorem.

Magnitude = 5 N

5 N

3 N

4 N

5 N 3 N

4 N

Page 25: 2008 Science (Physics) Section A

What else must you take note of for vector questions?

• Bring long ruler and protractor for Physics paper

• Use their diagram if it is provided in the qn(e.g. 2009 QA3, 2010 QB14)The angle have been measured for you,

just continue on the lines drawn. Your line can be longer or shorter than theirs.

Page 26: 2008 Science (Physics) Section A

A device that protects an appliance by stopping current larger than its rated value from entering it. (Same as a fuse but it is re-usable)

Solenoid will always be magnetised when current pass through it but it will only attract armature if magnetic field is strong enough. Remember: current pass through coil, it does not pass through iron core.

Purpose of spring is to pull the armature back to original when it is no longer attracted by solenoid.

This button enable the circuit to be close again after it is broken by the circuit breaker.

Page 27: 2008 Science (Physics) Section A

• When current flows in the solenoid, it gets magnetised. • When the current is larger than its rated value, the

magnetic field is strong enough to attract the armature.• The springy metal will break contact with the iron

armature. • The circuit remains open until the reset button is pressed

to push the springy metal to touch the armature again.

This point is often not mentioned by students.

What’s wrong with this answer?• When current flows in the solenoid, it becomes

magnetised and attracts the armature…….

4 mark question so you must have 4 or more points. Organise each point as a complete sentence to make it easier for examiner to award marks.

Page 28: 2008 Science (Physics) Section A

This will ensure that when the circuit breaker blows, the appliance will be isolated from high potential / will not be ‘live’ / will not be connected to high potential and that will protect the user from electrocution.

A very common question, must memorise answer. Check out the ‘Common Questions Asked in Practical Electricity’ in the Wikispaces and ensure that you can answer all of them.

Page 29: 2008 Science (Physics) Section A

This means that the lamp is operating at its rated power. (It is possible that some appliance is operating at a power that is less that its rated value. This is when the voltage supplied is less than the operating voltage.)

Parallel circuit hence the voltage across the lamp and resistor is the same. Since they are also parallel to the battery, their voltage will be the same as the emf of the battery

P = V I24 = 12 x I I = 24/12 = 2 A

Must state formula

Page 30: 2008 Science (Physics) Section A

V = R I12 = 3 x II = 12/3 = 4 A

RE = V I = 12 (2 + 4 ) = 2 Ω

Effective resistance means total resistance

Total voltage = EMF of battery

Total current = current that enters battery

4 A

2 A

R (bulb) = V/I = 12/2 = 6 Ω

1/RE = 1/R1 + 1/R2

= 1/6 + 1/3

= 3/6

RE = (3/6)-1

= 2 Ω

Don’t forget to invert the ans to get RE

Page 31: 2008 Science (Physics) Section A

Go on to try other year’s paper!


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