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Test 5 Due: 11:59pm on Sunday, April 10, 2011 Note: You will receive no credit for late submissions. To learn more, read your instructor's Grading Policy [ Switch to Standard Assignment View] Exercise 24.49 A parallel-plate capacitor has the volume between its plates filled with plastic with dielectric constant . The magnitude of the charge on each plate is . Each plate has area , and the distance between the plates is . Part A Use Gauss's law to calculate the magnitude of the electric field in the dielectric. Express your answer in terms of the given quantities and appropriate constants. ANSWER: = Correct Part B Use the electric field determined in part A to calculate the potential difference between the two plates. Express your answer in terms of the given quantities and appropriate constants. ANSWER: = Correct Part C Use the result of part B to determine the capacitance of the capacitor. Express your answer in terms of the given quantities and appropriate constants. ANSWER: = Correct Problem 24.73 Capacitors in networks cannot always be grouped into simple series or parallel combinations. As an example, the figure (a) shows three capacitors , and in a delta network, so called because of its triangular MasteringPhysics: Assignment Print View http://session.masteringphysics.com/myct/assignmentPrintView?assignme... 1 of 17 5/12/2011 8:11 PM
Transcript
Page 1: 223

Test 5Due: 11:59pm on Sunday, April 10, 2011

Note: You will receive no credit for late submissions. To learn more, read your instructor's Grading Policy

[Switch to Standard Assignment View]

Exercise 24.49A parallel-plate capacitor has the volume between its plates filled with plastic with dielectric constant . The

magnitude of the charge on each plate is . Each plate has area , and the distance between the plates is

.

Part A

Use Gauss's law to calculate the magnitude of the electric field in the dielectric.

Express your answer in terms of the given quantities and appropriate constants.

ANSWER: =

Correct

Part B

Use the electric field determined in part A to calculate the potential difference between the two plates.

Express your answer in terms of the given quantities and appropriate constants.

ANSWER: =

Correct

Part C

Use the result of part B to determine the capacitance of the capacitor.

Express your answer in terms of the given quantities and appropriate constants.

ANSWER: =

Correct

Problem 24.73Capacitors in networks cannot always be grouped into simple series or parallel combinations. As an example,the figure (a) shows three capacitors , and

in a delta network, so called because of its triangular

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shape. This network has three terminals a, b, and cand hence cannot be transformed into a singleequivalent capacitor. It can be shown that as far asany effect on the external circuit is concerned, a deltanetwork is equivalent to what is called a Y network. Forexample, the delta network of the figure (a) can bereplaced by the Y network of the figure (b). (The name"Y network" also refers to the shape of the network.)The transformation equations that give , , and

in terms of , and , and are

.

Part A

For the network shown in the figure (c), determine the equivalent capacitance between the terminals at theleft end of the network. (Hint: Use the delta-Y transformation derived in the introduction. Use points a, b,and c to form the delta, and transform the delta into a Y. The capacitors can then be combined using therelationships for series and parallel combinations of capacitors.)

ANSWER: = 14.0Correct

Part B

Determine the charges of, and the potential differences across, each capacitor in the figure (c).

ANSWER: = 5.04×10−4

Correct

Part C

ANSWER: = 7.00Correct

Part D

ANSWER: = 2.30×10−4

Correct

Part E

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ANSWER: = 13.0All attempts used; correct answer displayed

Part F

ANSWER: = 2.80×10−4

Correct

Part G

ANSWER: = 10.0Correct

Part H

ANSWER: = 2.60×10−4

Correct

Part I

ANSWER: = 9.00Correct

Part J

ANSWER: = 2.50×10−4

Correct

Part K

ANSWER: = 12.0Correct

Part L

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ANSWER: = 1.50×10−5

Correct

Part M

ANSWER: = 2.50Correct

Problem 24.75Two square conducting plates with sides of length are separated by a distance . A dielectric slab with

constant with dimensions is inserted a distance into the space between the plates, as

shown in the figure .

Part A

Find the capacitance C of this system .

Express your answer in terms of the given quantities and appropriate constants.

ANSWER: =

Correct

Part B

Suppose that the capacitor is connected to a battery that maintains a constant potential difference

between the plates. If the dielectric slab is inserted an additional distance into the space between the

plates, show that the change in stored energy is

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Essay answers are limited to about 500 words (3800 characters maximum, including spaces).

ANSWER: My Answer:

Part C

Suppose that before the slab is moved by , the plates are disconnected from the battery, so that the

charges on the plates remain constant. Determine the magnitude of the charge on each plate.

Express your answer in terms of the given quantities and appropriate constants.

ANSWER: =

Correct

Part D

Show that when the slab is moved farther into the space between the plates, the stored energy changes

by an amount that is the negative of the expression for given in part B.

Essay answers are limited to about 500 words (3800 characters maximum, including spaces).

ANSWER: My Answer:

Part E

If is the force exerted on the slab by the charges on the plates, then should equal the work done

against this force to move the slab a distance . Thus . Show that applying this expression to

the result of part B suggests that the electric force on the slab pushes it out of the capacitor, while theresult of part D suggests that the force pulls the slab into the capacitor.

Essay answers are limited to about 500 words (3800 characters maximum, including spaces).

ANSWER: My Answer:

Part F

Figure24.16 in the textbook shows that the force in fact pulls the slab into the capacitor. Explain why theresult of part B gives an incorrect answer for the direction of this force.

Essay answers are limited to about 500 words (3800 characters maximum, including spaces).

ANSWER: My Answer:

Part G

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Calculate the magnitude of the force. (This method does not require knowledge of the nature of the fringingfield.)

Express your answer in terms of the given quantities and appropriate constants.

ANSWER:

=

Correct

Exercise 24.11A cylindrical capacitor has an inner conductor with a radius of 1.3 and an outer conductor with a radius of3.3 . The two conductors are separated by vacuum, and the entire capacitor has a length of 3.0 .

Part A

What is the capacitance per unit length?

Express your answer using two significant figures.

ANSWER: = 6.0×10−11

Correct

Part B

The potential of the inner conductor relative to that of the outer conductor is 350 . Find the charge

(magnitude and sign) on both conductors.

Enter your answers numerically separated by a comma. Express your answers using twosignificant figures.

ANSWER: = 6.3×10−11,−6.3×10−11

Correct

Exercise 24.13A spherical capacitor contains a charge of 3.50 when connected to a potential difference of 230 . If its

plates are separated by vacuum and the inner radius of the outer shell is 5.00 .

Part A

Calculate the capacitance.

ANSWER: = 15.2Correct

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Part B

Calculate the radius of the inner sphere.

ANSWER: = 3.66

All attempts used; correct answer displayed

Part C

Calculate the electric field just outside the surface of the inner sphere.

ANSWER: = 2.35×104

Correct

Exercise 24.23Suppose the 3 capacitor in Figure 24.10a in the textbook were removed and replaced by a different one,

and that this changed the equivalent capacitance between points and to 8 .

Part A

What would be the capacitance of the replacement capacitor?

ANSWER: = 57.0Correct

Exercise 24.30A parallel-plate vacuum capacitor has 8.10 of energy stored in it. The separation between the plates is

2.90 . If the separation is decreased to 1.85 ,

Part A

what is the energy now stored if the capacitor was disconnected from the potential source before theseparation of the plates was changed?

ANSWER: = 5.17Correct

Part B

What is the energy now stored if the capacitor remained connected to the potential source while theseparation of the plates was changed?

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ANSWER: = 12.7All attempts used; correct answer displayed

Problem 24.56Two capacitors are connected parallel to each other and connected to the battery with voltage 28 . Let

= 9.1 , = 4.9 be their capacitances. Suppose the charged capacitors are disconnected from the

source and from each other, and then reconnected to each other with plates of opposite sign together.

Part A

By how much does the energy of the system decrease?

Express your answer using two significant figures.

ANSWER: = 5.0×10−3

Correct

Problem 26.86An circuit has a time constant .

Part A

If the circuit is discharging, how long will it take for its stored energy to be reduced to of its initial

value?

Express your answer in terms of the variables , , and constant .

ANSWER: =

Correct

Part B

If it is charging, how long will it take for the stored energy to reach of its maximum value?

Express your answer in terms of the variables , , and constant .

ANSWER:

=

Correct

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Problem 26.88

Part A

Using the equation for the current in a discharging capacitor, derive an expression for the

instantaneous power dissipated in the resistor.

Express your answer in terms of the variables , , and .

ANSWER:

=

Correct

Part B

Integrate the expression for to find the total energy dissipated in the resistor.

Express your answer in terms of the variables , , and .

ANSWER:

=

Correct

Part C

Show that the total energy dissipated in the resistor is equal to the total energy initially stored in thecapacitor.

Essay answers are limited to about 500 words (3800 characters maximum, including spaces).

ANSWER: My Answer:

Problem 26.90: A Capacitor Burglar AlarmThe capacitance of a capacitor can be affected by dielectric material that, although not inside the capacitor, isnear enough to the capacitor to be polarized by the fringing electric field that exists near a charged capacitor.This effect is usually of the order of picofarads ( ), but it can be used with appropriate electronic circuitry to

detect a change in the dielectric material surrounding the capacitor. Such a dielectric material might be thehuman body, and the effect described above might be used in the design of a burglar alarm. Consider thesimplified circuit shown in the figure . The voltagesource has emf = 1000 , and the capacitor has

capacitance 10.0 . The electronic circuitry for

detecting the current, represented as an ammeter inthe diagram, has negligible resistance and is capableof detecting a current that persists at a level of at least1.00 for at least 200 after the capacitance has

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changed abruptly from to . The burglar alarm is

designed to be activated if the capacitance changes by10%.

Part A

Determine the charge on the 10.0- capacitor when it is fully charged.

ANSWER: = 1.00×10−8

Correct

Part B

If the capacitor is fully charged before the intruder is detected, assuming that the time taken for thecapacitance to change by 10% is short enough to be ignored, derive an equation that expresses the currentthrough the resistor as a function of the time since the capacitance has changed.

Express your answer in terms of the variables , , , ( ) and .

ANSWER: =

All attempts used; correct answer displayed

Part C

Determine the range of values of the resistance that will meet the design specifications of the burglar

alarm. (Hint: You will not be able to solve this part analytically but must use numerical methods. Express

as a logarithmic function of plus known quantities. Use a trial value of and calculate from the

expression a new value. Continue to do this until the input and output values of agree to within three

significant figures.)

Enter your answers numerically separated by a comma.

ANSWER: , = 7.15×106,7.01×107

Correct

Part D

What happens if is too small? Too large?

Essay answers are limited to about 500 words (3800 characters maximum, including spaces).

ANSWER: My Answer:

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Exercise 26.40A 12.8 capacitor is connected through a 0.890 resistor to a constant potential difference of 60.0

.

Part A

Compute the charge on the capacitor at the following times after the connections are made: 0, 5.0 , 10.0, 20.0 , and 100.0 .

Express your answers using two significant figures. Enter your answers numerically separated bycommas.

ANSWER: , , , , = 0,2.7×10−4,4.5×10−4,6.4×10−4,7.7×10−4

Correct

Part B

Compute the charging currents at the same instants.

Express your answers using two significant figures. Enter your answers numerically separated bycommas.

ANSWER: , , , , = 6.7×10−5,4.3×10−5,2.8×10−5,1.2×10−5,1.0×10−8

Correct

Exercise 26.41In the circuit shown in the figure both capacitors areinitially charged to 50.0 .

Part A

How long after closing the switch S will the potential across each capacitor be reduced to 10.0 ?

ANSWER: = 4.51

Correct

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Part B

What will be the current at that time?

ANSWER: = 0.125Correct

Exercise 26.45In the circuit shown in the figure each capacitor initiallyhas a charge of magnitude 3.20 on its plates.

Part A

After the switch is closed, what will be the current in the circuit at the instant that the capacitors have lost

80.0% of their initial stored energy?

ANSWER: = 12.4Correct

Exercise 31.7In each circuit described next, an ac voltage source producing a current is connected to an

additional circuit element.

Part A

The ac source is connected across a resistor . Sketch graphs of the current in the circuit and the

potential difference across the resistor as functions of time, covering one cycle of oscillation. Put bothgraphs on the same set of axes so you can compare them.

ANSWER:

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View Answer Requested

Part B

Do the same as in part A, except suppose the resistor is replaced by an inductor . Sketch the same

graphs as in part A, but this time across the inductor instead of the resistor.

ANSWER:

View Answer Requested

Part C

Do the same as in part A, except suppose the resistor is replaced by an capacitor . Sketch the same

graphs as in part A, but this time across the capacitor instead of the resistor.

ANSWER:

View Answer Requested

Part D

Sketch phasor diagram for resistor.

Draw the phasors with their tails at the dot. The orientation of your vectors will be graded. Theexact length of your vectors will not be graded.

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ANSWER:

View Correct

Part E

Sketch phasor diagram for inductor.

Draw the phasors with their tails at the dot. The orientation of your vectors will be graded. Theexact length of your vectors will not be graded.

ANSWER:

View Correct

Part F

Sketch phasor diagram for capacitor.

Draw the phasors with their tails at the dot. The orientation of your vectors will be graded. Theexact length of your vectors will not be graded.

ANSWER:

View Correct

Exercise 31.18You have a 200- resistor and a 6.00- capacitor. Suppose you take the resistor and capacitor and make

a series circuit with a voltage source that has a voltage amplitude of 30.0 and an angular frequency of 250

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. The current is given by , so .

Part A

Graph , versus for 0 to 27.0 .

ANSWER:

View Answer Requested

Part B

Graph , versus for 0 to 27.0 .

ANSWER:

View Answer Requested

Part C

Graph , versus for 0 to 27.0 .

ANSWER:

View Answer Requested

Part D

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What is at ?

ANSWER: = -25.1

Correct

Part E

What is at ?

ANSWER: = 2.45

Correct

Part F

What is at ?

ANSWER: = -27.5

Correct

Part G

What is at ?

ANSWER: = -22.9

Correct

Part H

What is at ?

ANSWER: = -7.23

Correct

Part I

What is at ?

ANSWER: = -15.6

Correct

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Score Summary:Your score on this assignment is 82%.You received 81.97 out of a possible total of 100 points.

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