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Prog_2 course- 2014 2 bytes team Kinan keshkeh IT Engineering-Damascus University 3 rd year
Prog_2 course- 2014
2 bytes team
Kinan keshkeh
IT Engineering-Damascus University
3rd year
Record
Data Structure:
Data Structure are divided into :
Complex types
Simple types
Records
• (char,integer,Boolean .... )
• User design type :
• Type mytype=1.. 100 ;
var x : mytype;
Definition
Records are complex type which enables us to
combine a set of simple variables in one Data
structure named Record ....
Example: ( car’s information ) type
engine
production year
Example(2): date (year.. Month... Day).....
How we can define Records ?
Ex:
• Type person=record
fname: string ;
lname: string;
age: integer;
end;
Note : we can define a record in one of its fields
• Type employee=record
address: string;
salary: real;
per: person;
end ;
fname lname age
fname
per salary address
lname age
• var Emp :array[1..100] of employee
Define variable of type record
• Note : you can define a matrix records
person
employee •var y:employee
•var x:person
Using records :
Read record’s data :
readln(x);
Readln(y);
{ True }
readln(x.fname);
readln( y.address);
readln(y.per.age);
{ False }
Read matrix of records
• for i=1 to 50 do
• begin
readln(Emp[i].salary);
readln(Emp[i].per.fname);
……………………………….
……………………………….
end;
• Var Emp : array[1..100] of employee;
Write record’s data
{↔ writeln(y.per.fname);}
<<<Using with >>>
With y do Begin writeln(address); writeln(per.name); with per do begin writeln(fname); writeln(age); writeln(lname); end; end;
In matrix of records
For i:=1 to 75 do
with Emp[i] do
begin
readln(address);
writeln(per.age);
……………………………….
……………………………….
end;
salary:=50000;
Exercise : We have (record) of complex number :
1. Write procedure to input this number
2. Write procedure to print this number
3. Write procedure to combine two numbers
4. Write function to calculate Abs of number
Let’s go ....
Program prog2_bytes
Uses wincrt
Type complex=record
re,Img : real;
end;
Procedure Inputcom(var c:complex);
Begin
with c do
Begin
writeln(‘enter the real part ‘);
readln(re);
writeln(‘enter the Img part ‘);
readln(Img);
end;
End;
Procedure printcom( c: complex);
Begin
With c do
If Img<>0 then
Writeln(‘z= ‘,re:5:2,Img:5:2,’i’);
Else writeln(‘z=‘,re:5:2);
end;
End;
Procedure sumcom( a , b: complex ; var c:complex);
Begin
with c do
begin
re:=a.re+b.re;
Img:=a.Img+b.Img;
end;
End;
Function Abscom(c : complex):real;
Begin
Abscom:=sqrt(sqr(c.re)+sqr(c.Img));
End;
Var x,y,z:complex;
Begin
Inputcom(x);
Inputcom(y);
Sumcom(x ,y ,z );
Printcom(z);
Writeln(‘|z|=‘,Abscom(z:5:2));
End.
Homework: يىظف وانًطهىب كتاتح تشَايج عاو nنذٌُا ششكح تحىي
:تاستخذاو اإلجشائٍاخ وانتىاتع ورنك نهقٍاو تانًهاو انتانٍح
ادخال انثٍاَاخ انتانٍح عٍ يىظفً انششكح:
,انًذٌُح )انعُىاٌ انًفصم, تاسٌخ انعًم ,انشاتة ,االسى { }(سقى انثُاء ,انشاسع
طثاعح تٍاَاخ انًىظفٍٍ عهى شكم جذول
تشتٍة انسجالخ تصاعذٌا حسة االسى وطثاعح انسجالخ انًشتثح
سُح تانخذيح نهتقاعذ 25إحانح انًىظفٍٍ انزٌٍ عًهىا يٍ ساتثهى % 25يع خصى
Additional demand for creative
:قشسخ انششكح استخذاو يىظف جذٌذ وانًطهىب
ادخال تٍاَاخ انًىظف إنى انجذول دوٌ األخالل تتشتٍة انثحث عٍ انًىقع انًُاسة فً ) انسجالخ فٍه
( انسجم يثاششج
+3.5
+2.5
+4
+2.5
+2.5
Revision Practice
المطلوب كتابة إجرائية و تابع لحساب المضاعف المشترك األصغر والقاسم المشترك األكبر لعددين
program prog_2bytesteam;
procedure Lcm(a,b:integer; var c:integer);
var i,L,temp : integer;
begin
if (a>b) then
begin
temp:=a;
a:=b;
b:=temp;
end;
i:=1;
L:=a;
while( L mod b <> 0) do
begin
i:=i+1;
L:=a*i;
end;
c:=L;
end;
program prog_2bytesteam;
function Lcm(a,b:integer):integer;
var i,L,temp:integer;
begin
if (a>b) then
begin
temp:=a;
a:=b;
b:=temp;
end;
i:=1;
L:=a;
while( L mod b <> 0) do
begin
i:=i+1;
L:=a*i;
end;
Lcm:=L;
end;
program prog_2bytesteam;
procedure gcd(a,b:integer; var c:integer);
begin
while( a <> b ) do
if (a>b) then
a:=a-b
else
b:=b-a;
c:=a;
end;
program prog_2bytesteam;
function gcd(a,b:integer):integer;
begin
while( a <> b ) do
if (a>b) then
a:=a-b
else
b:=b-a;
gcd:=a;
end;
Group : group link
Mobile phone- Kinan : 0994385748
Facebook account : kinan’s account
2 bytes team
