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.rocks
1 Rise of fluid in Capillaries
2 Additional pressure of arbitrary curvature
3 Ca illar Pressure effect in Porous Media
4 Capillary Pressure Hysteresis
5 measurement of Capillary Pressure
6 Application of Capillary Pressure
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1 Rise of fluid in Capillaries
1) Capillary pressure of gas-liquid system
If a Capillary tube is placed in
a large open vessel continuingliquid , liquid will rise in the
tube above the height of the
.
This rise in height is duo to the
attractive force (adhesion
tension) between the tube and
-
e qu an e sma we g
of the column of liquid in the tube..
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cos2
= r
Definition: The ressure difference betweennon-wet phase and wet phase is called capillary
ressure.expressed by Pc.
- .
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2 Ca illar ressure in oil-water s stem
pc=
2 cos
( )r
=
Fig.3-21 Pressure relations in Capillary tube
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3)Property of capillary pressure
A. The capillary pressure exists in capillaryu e a up n any rec on
Fig.3-22 displacement of oil by water in Horizontal capillary
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3)Property of capillary pressure
PC is proportional to cos, and inverse
proportional to r;
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Figure 7.8 Capillary rise experiments for two porous
media of different grain sizes.
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,
is driving force of displacing oil by water;
If rock surface is oil-wet , capillary pressure
If rock surface is water-wet water can
automatically enter rock ; but if rock surface
- ,
rock .
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Drainage :A process displacing the-
wetting phase is known as drainage.
the non-wetting phase from a porous medium with
.
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Question: Why does the oil-water contact is atransitional zone?
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2. Additional pressure of arbitrary curvature
1) Derived equation (
Laplace equation can be derived by consideringthe mechanical equilibrium of the interface.
The work done in expanding the surface, by
,
work against the surface tension.
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'D
2p + += dRRBCdRRBDCBfA 21
11
'A'
CD
dR
++=RR
21
'B
C
1p
2R
1
AB=
B
11
BC= dRpBCABdRfABCDpW ==
2R
21 pppc =WZ =
BCABfABCD = +==11
21
RR
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2) Equation simplification in Several
spec a cases
.
R R R= =r
cos =
cP =
radius and the curvature radius
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If curved surface is cylindrical surface
1 2,R R r= =
1 1P
= + = =
1 2 2R R R r
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c. Ca illar ressure in conical ca illar
R1
=r1
/COS(+)
R2=r2/COS(-)
so:
cip
=
cos2
i
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D. ca illar ressure in cracks
2
2/cos
W=
1
cos2
== WRc
1
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F. The capillary pressure in packing of uniform
sp eres
+=
11pC
21
111 +=m
cp
=
m
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3 capillary effect in capillary tube
1) When the droplet (or bubble) is at the static state
cos22'
rRp
c==
cylindrical interface
rp
cz=''
2cos2
e cap ary pressure e ec :
.==rrr
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tube of constant diameter
'
'p =
''
''p =
'''''' 211 ''' =
==rRR
C
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3 When the dro let asses throu h
a throat of a pore
= '''2p C
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am n ec :
to a capillary tube of decreasing size ,a higherpressure drop is required to move the drop into
.
='''
2p C
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Capillary Pressure Hysteresis
Capillary Pressure Hysteresis by Contact
Fig.3-51 contact angle hysteresis
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Ca illar Pressure H steresis b the
sudden change in diameter
Fig3-52. the change in diameter
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Ca illar Pressure H steresis b the
gradual change in diameter
( ) +=
cos2
pr
( )tp
=
cos2
tr
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capillary hysteresis in actual rock
angle: 1A
Visual recedin= 2R
angle:
( )Rp == 2
cos2cos2
ttrr
( )A
+== 1
cos2cos2
PP
m
rr
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Semi-permeable Disk Method
Mercury injection method
Centrifuge method
The dynamic capillary-pressure method
The evaporation method
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Definition :
Capillary Pressure curve: The relationship
curve between ca illar ressure of reservoirrock and the wetting- phase saturation is called
.
sc =
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1) Semipermeable Disk Method
A. Normal pressure Semipermeable Disk Method
-
wetting phase is water
the maximum capillary pressure
is about 1atm
1) S i bl Di k M h d
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1) Semipermeable Disk Method
The bottom of the vessel
consists of a semi-
permeable plate, which
displaced from the sample
to pass through while
blocking the passage of
-
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1) Semipermeable Disk Method
P W
w
V VS
= =
P
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Principle and step of measurement:
placing the sample, initially saturated with awetting fluid, in a vessel filled with the non-wetting
fluid.
With the sample on the porous plate, thepressure of the non-wetting fluid is increased in
steps and the system is allowed to achieve
equilibrium after each pressure change. The volume of wettin hase dis laced at each
pressure is measured.
determined from the volume of wetting phase
pressure versus saturation relationship.
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typical curve
cP
%
20
12
4
(%)w
S
r, m
4.2 9 18 27 54
Fig.-1 capillary pressure curveFig. -2 pore size distribution curve
%
r
Fig.-3 pore volume accumulate distribution curve
1) Semipermeable Disk Method
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1) Semipermeable Disk Method
A. High pressure Semipermeable Disk Method
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Principle and step of measurement:
p ac ng e samp e, n a y sa ura e w awetting fluid, in a vessel filled with the non-wetting
u .
With the sample on the porous plate, thepressure of the non-wetting fluid is increased in
steps and the system is allowed to achieve
equilibrium after each pressure change. The volume of wettin hase dis laced at each
pressure is measured.
determined from the volume of wetting phase
pressure versus saturation relationship.
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This method use oil and water therefore more
nearly approaching actual wetting conditions.
The method gives a reliable estimate of the
irreducible wetting phase saturation.
Disadvantage:
The porous plate limits the maximum capillary
It takes too long to obtain the entire capillary
pressure curve y s me o .
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non-wetting phase mercury;
wetting phase air
mercury injection equipment
The sample chamber is evacuated, and
the pressure required for injection of each increment
.
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Princi le of measurement:
2
543
1 Nitrogen pressure; 2 pressure gauge;
mercury n ec on pump; samp e ce ;
5 vacuum system
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. . -
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Advantage of mercury injection method :.
The range of pressure is large.
Disadvantage of mercury injection method:
Core can no longer be used for other tests aftermercury injection.
The method also cannot be used to determine
mercury vapor is toxic, so strict safety precautions
.
3) Centrifuge method
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3) Centrifuge method
Measuring Principle and step:
e samp e sa ura e w a we ng u s p ace
in a centrifuge cup containing the non-wetting fluid
The sample is rotated at a series of constant
displaced at equilibrium at each velocity is measured
when the rotational velocity is increased.
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3 the centrifu e method
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2
=2 2 2P w r r =
2
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The centrifuge method is fast
The method is good for determining the
irreducible water saturation.
It can simulate the process of water or gas
Disadvantage:.
. .
inability to obtain spontaneous imbibition
ca illar ressure curve.
the calculated water saturation at the core inlet is
an approximation,
4) Converting the laboratory data
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4) Converting the laboratory data
to reservoir conditions
p LLcL
cos= LLr
cos=
rpcR=
cR
RR
pr =
cLcRpp
cos=
The conversion between semi permeable disk method
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The conversion between semi-permeable disk method
and oil-water capillary pressure under reservoirconditions.
wgwgwg
wgwg
owow
owpppp
30cos72
cos
cos
cos=
==
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Swiirreducible saturation
of wetting fluidPt threshold displacement
,
onset of invasion of the
P median ressure,characteristic
of
corresponds to the nonwetting
hase saturation of 50% .
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E = Hgmax Hgmin Hgmax
WE: Mercury injection efficiency;
Hgmax
: max mum mercury sa ura on;
gm n
the oil recovery in a strongly water-wet oil reservoir
typical capillary pressure curve
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yp p y p
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typical capillary pressure curve
(a) Well sorted sample, with medium-size pores;(b) Nonsorted sample;
(c) Well sorted sample, with large pores;
,
(e) Poorly sorted sample, with more fine pores;
(f) Poorly sorted sample, with more large pores.
6 Application of Capillary Pressure curves
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6 Application of Capillary Pressure curves
1) Determining rock wettability
A. Determining by Wettability number
cos Two ogwo PW
= =
cos og Tog woP
W=1 complete wetting by water;
W=0 complete wetting by oil;
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B. Determining by apparent contact angle
P P cos arccoswo wo
To wo To woP P
= =
=00 complete wetting by water;wo
wo =90ocomplete wetting by oil;
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. e erm n ng y ona son s me o
Principle of Determination
by the curve of water displacing oil with the area
unclosed the curve of oil displacing water.
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.
0.7
2
ogA
> water-wet;A1
1log 0A < Oil-wet; A2
2
1log 0A
= intermediatewetting
-0.70 100
2 determinin the ore size distribution
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2 determinin the ore size distribution
of porous materials(
20
%
16
8
4
4.2 9 18 27 54
r, m
2 determinin the ore size distribution
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2 determinin the ore size distribution
of porous materials(
r = 2cosPT
Tpr .max =
Rmax: the largest pore size
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drainage capillary pressure curve
A. Calculation ofabsolute ermeabilit
B. Calculation of relative permeability
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u y ng o recovery
SS
max
=Hg
w
S
5) Studying initial static fluid distribution in
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5) Studying initial static fluid distribution in
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the oil water contact level 100% water
saturation lever) PT
the free water level PC=0
connate water saturation levelS
between 100% water saturation lever and
conna e wa er sa ura on eve
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level of fw=100% oractual transition zonethe height
=saturation level
1.0
0.8
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0.6
.
0.2
0
20 40 60 80 100Sw %
Pc(R)
HSwi
B
0 20 40 60 80 100
%
To convert capillary pressure data to
e g a ove ree wa er sur ace
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e g a ove ree wa er sur ace
cRh =
ca illar ressure at some articular
,
saturation for reservoir conditions,MPa
w,o ens ty o water an o at reservo rconditions of water and oilg/cm3)
xamp e : e cap ary orce curve as een
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xamp e : e cap ary orce curve as een
obtained from laboratory. if the water saturation is
, an e cap ary pressure s . a,
calculate the height of water saturation of 35%
p ane a ove ree wa er eve .
e a reservo r con ons ,
wo = 24 mN/m,
w = . g cm ,
o = 0.848 g / cm3,
a a mosp er c pressurewg= 72 mN/m.
Example 2: The air water capillary pressure curve isobtained by semi permeable diaphragm method in the
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obtained by semi-permeable diaphragm method in the
laboratory. When the water saturation is 50%, the capillary
cL . .
of water is 72 mN/m in surface conditions. While in the
reservoir conditions ,the interfacial tension between waterand oil is 24 mN/m.The water density is w = 1.088 g / cm3
and oil density is o = 0.848 g / cm3 .The altitude of free
wa er eve s - m. e reservo r roc s wa er-we , an e
contact angle between water and reservoir rock is assumed.
Calculate:
50% to the free water level.
50%.
e erm na ng c ness o o -wa er
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e erm na ng c ness o o -wa er
production
Pc1
2 2or cS P h
Pc2 1 1cw cS P h
Scw Sor
6.Avera in ca illar - ressure data
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The definition of J-function :
1
2( ) ( )cos
cW
J S
=
-
media that have the same pore structure but
di erent permeability and porosity will have
the same Leverett J-function.
Formula Derivation:
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1
==
cr r =
1 1
Kc cos2
2
=
2
2 = Kpc
c
( )2
=Kp
sJ cw
The characteristic of J-function :
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a b cd e
Water-gas system in laboratory: 70mN/m, =0 p J
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70mN/m, 0
-3
cp J
number
C
(50)
,
m2
. . . .
2 2.5 34.0 0.174 0.50
. . .
4 0.85 569 0.275 0.55 23
5.0
K
=Jc
%w
S
.
At reservoir conditions:= 2
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average porosity is 0.208Sw% J(sw) Pc(sw)
100 0.35 0.35
70 0.40 0.40
54 0.45 0.45
c
J44 0.60 0.59
30 1.45 1.43
20 3.15 3.12
%w
S
JJ 1028cos
( )Kpc .
208.0166
5.05.0 ===
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200/cm)
100
ure
k
1ryPres I displacement
0.1Capilla displacement trap hysteresis
Inhaledt
0.001
W
or
Mercury saturation (%)
1.0
0.8
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0.6
.
0.2
0
20 40 60 80 100Water saturation Sw %
Pc(R)
H
irreducible water saturation )Swi
B Producing oil and water( )100 producing water surf
(100 )
Pure water producing areasirreducible oil )
Sw=1-Sor
0 20 40 60 80 100
Water saturation %
Free water level