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4.1.3 Example Solution Three

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Page 1: 4.1.3 Example Solution Three
Page 2: 4.1.3 Example Solution Three
Page 3: 4.1.3 Example Solution Three

Circuit NoLoad Group(column 1)

Description of load

(given list)

Current allowanceper unit(column 2)

Calculation

Demand (Amps)Demand (Amps)Demand (Amps)

Circuit NoLoad Group(column 1)

Description of load

(given list)

Current allowanceper unit(column 2)

Calculation

L1 L2 L3

1 A (i) 13 Lighting points3 A (1st 20)2 A (next 20) na 3.0

2 A (i) 14 Lighting points3 A (1st 20) na 3.0

3 A (i) 15 Lighting points3 A (1st 20) na 3.0

4 B (i)8 single +

4 double outlets10 A (1st 20)

8 + (4 x 2) = 16 socket points +1 (pool filterpump) = 17

10.0

5 B (i)7 single +

5 double outlets10 A (1st 20) 7 + (5 x 2) =

17 socket points 10.0

6 B (ii)

One 15 A single phase outlet

10 A(See note on group in Table C1, B (ii))

na 10.0

7 C Cook top 50% (or x 0.5) 4200/240 x 0.5 8.8

8 C Oven rating 50% (or x 0.5) 5200/240 x 0.5 10.8

9 B (i) Pool filter pump

Pump rating = 4.3 A so socket outlet to be used for pump supply.Socket will be part of circuit L1 so Included with circuit 4 calculations

Pump rating = 4.3 A so socket outlet to be used for pump supply.Socket will be part of circuit L1 so Included with circuit 4 calculations

na

10 D Air conditioner(23.6 A)

75% (or x 0.75) 23.6 x 0.75 17.7 17.7 17.7

11a F OPHWS bottom element Full load current 3600/240 15.0

11b F OPHWS top element Full load current Included

above 0.0

Total demand current per phaseTotal demand current per phaseTotal demand current per phaseTotal demand current per phaseTotal demand current per phase 40.7 39.5 46.5

Page 4: 4.1.3 Example Solution Three

Circuit NoLoad Group(column 1)

Description of load

(given list)

Current allowanceper unit(column 2)

Calculation

Demand (Amps)Demand (Amps)Demand (Amps)

Circuit NoLoad Group(column 1)

Description of load

(given list)

Current allowanceper unit(column 2)

Calculation

L1 L2 L3

1 A (i) 13 Lighting points3 A (1st 20)2 A (next 20) na 3.0

2 A (i) 14 Lighting points3 A (1st 20) na 3.0

3 A (i) 15 Lighting points3 A (1st 20) na 3.0

4 B (i)8 single +

4 double outlets10 A (1st 20)

8 + (4 x 2) = 16 socket points +1 (pool filterpump) = 17

10.0

5 B (i)7 single +

5 double outlets10 A (1st 20) 7 + (5 x 2) =

17 socket points 10.0

6 B (ii)

One 15 A single phase outlet

10 A(See note on group in Table C1, B (ii))

na 10.0

7 C Cook top 50% (or x 0.5) 4200/240 x 0.5 8.8

8 C Oven rating 50% (or x 0.5) 5200/240 x 0.5 10.8

9 B (i) Pool filter pump

Pump rating = 4.3 A so socket outlet to be used for pump supply.Socket will be part of circuit L1 so Included with circuit 4 calculations

Pump rating = 4.3 A so socket outlet to be used for pump supply.Socket will be part of circuit L1 so Included with circuit 4 calculations

na

10 D Air conditioner(23.6 A)

75% (or x 0.75) 23.6 x 0.75 17.7 17.7 17.7

11a F OPHWS bottom element Full load current 3600/240 15.0

11b F OPHWS top element Full load current Included

above 0.0

Total demand current per phaseTotal demand current per phaseTotal demand current per phaseTotal demand current per phaseTotal demand current per phase 40.7 39.5 46.5

Page 5: 4.1.3 Example Solution Three

Circuit NoLoad Group(column 1)

Description of load

(given list)

Current allowanceper unit(column 2)

Calculation

Demand (Amps)Demand (Amps)Demand (Amps)

Circuit NoLoad Group(column 1)

Description of load

(given list)

Current allowanceper unit(column 2)

Calculation

L1 L2 L3

1 A (i) 13 Lighting points3 A (1st 20)2 A (next 20) na 3.0

2 A (i) 14 Lighting points3 A (1st 20) na 3.0

3 A (i) 15 Lighting points3 A (1st 20) na 3.0

4 B (i)8 single +

4 double outlets10 A (1st 20)

8 + (4 x 2) = 16 socket points +1 (pool filterpump) = 17

10.0

5 B (i)7 single +

5 double outlets10 A (1st 20) 7 + (5 x 2) =

17 socket points 10.0

6 B (ii)

One 15 A single phase outlet

10 A(See note on group in Table C1, B (ii))

na 10.0

7 C Cook top 50% (or x 0.5) 4200/240 x 0.5 8.8

8 C Oven rating 50% (or x 0.5) 5200/240 x 0.5 10.8

9 B (i) Pool filter pump

Pump rating = 4.3 A so socket outlet to be used for pump supply.Socket will be part of circuit L1 so Included with circuit 4 calculations

Pump rating = 4.3 A so socket outlet to be used for pump supply.Socket will be part of circuit L1 so Included with circuit 4 calculations

na

10 D Air conditioner(23.6 A)

75% (or x 0.75) 23.6 x 0.75 17.7 17.7 17.7

11a F OPHWS bottom element Full load current 3600/240 15.0

11b F OPHWS top element Full load current Included

above 0.0

Total demand current per phaseTotal demand current per phaseTotal demand current per phaseTotal demand current per phaseTotal demand current per phase 40.7 39.5 46.5

Page 6: 4.1.3 Example Solution Three

Circuit NoLoad Group(column 1)

Description of load

(given list)

Current allowanceper unit(column 2)

Calculation

Demand (Amps)Demand (Amps)Demand (Amps)

Circuit NoLoad Group(column 1)

Description of load

(given list)

Current allowanceper unit(column 2)

Calculation

L1 L2 L3

1 A (i) 13 Lighting points3 A (1st 20)2 A (next 20) na 3.0

2 A (i) 14 Lighting points3 A (1st 20) na 3.0

3 A (i) 15 Lighting points3 A (1st 20) na 3.0

4 B (i)8 single +

4 double outlets10 A (1st 20)

8 + (4 x 2) = 16 socket points +1 (pool filterpump) = 17

10.0

5 B (i)7 single +

5 double outlets10 A (1st 20) 7 + (5 x 2) =

17 socket points 10.0

6 B (ii)

One 15 A single phase outlet

10 A(See note on group in Table C1, B (ii))

na 10.0

7 C Cook top 50% (or x 0.5) 4200/240 x 0.5 8.8

8 C Oven rating 50% (or x 0.5) 5200/240 x 0.5 10.8

9 B (i) Pool filter pump

Pump rating = 4.3 A so socket outlet to be used for pump supply.Socket will be part of circuit L1 so Included with circuit 4 calculations

Pump rating = 4.3 A so socket outlet to be used for pump supply.Socket will be part of circuit L1 so Included with circuit 4 calculations

na

10 D Air conditioner(23.6 A)

75% (or x 0.75) 23.6 x 0.75 17.7 17.7 17.7

11a F OPHWS bottom element Full load current 3600/240 15.0

11b F OPHWS top element Full load current Included

above 0.0

Total demand current per phaseTotal demand current per phaseTotal demand current per phaseTotal demand current per phaseTotal demand current per phase 40.7 39.5 46.5

Page 7: 4.1.3 Example Solution Three

Circuit NoLoad Group(column 1)

Description of load

(given list)

Current allowanceper unit(column 2)

Calculation

Demand (Amps)Demand (Amps)Demand (Amps)

Circuit NoLoad Group(column 1)

Description of load

(given list)

Current allowanceper unit(column 2)

Calculation

L1 L2 L3

1 A (i) 13 Lighting points3 A (1st 20)2 A (next 20) na 3.0

2 A (i) 14 Lighting points3 A (1st 20) na 3.0

3 A (i) 15 Lighting points3 A (1st 20) na 3.0

4 B (i)8 single +

4 double outlets10 A (1st 20)

8 + (4 x 2) = 16 socket points +1 (pool filterpump) = 17

10.0

5 B (i)7 single +

5 double outlets10 A (1st 20) 7 + (5 x 2) =

17 socket points 10.0

6 B (ii)

One 15 A single phase outlet

10 A(See note on group in Table C1, B (ii))

na 10.0

7 C Cook top 50% (or x 0.5) 4200/240 x 0.5 8.8

8 C Oven rating 50% (or x 0.5) 5200/240 x 0.5 10.8

9 B (i) Pool filter pump

Pump rating = 4.3 A so socket outlet to be used for pump supply.Socket will be part of circuit L1 so Included with circuit 4 calculations

Pump rating = 4.3 A so socket outlet to be used for pump supply.Socket will be part of circuit L1 so Included with circuit 4 calculations

na

10 D Air conditioner(23.6 A)

75% (or x 0.75) 23.6 x 0.75 17.7 17.7 17.7

11a F OPHWS bottom element Full load current 3600/240 15.0

11b F OPHWS top element Full load current Included

above 0.0

Total demand current per phaseTotal demand current per phaseTotal demand current per phaseTotal demand current per phaseTotal demand current per phase 40.7 39.5 46.5

Page 8: 4.1.3 Example Solution Three

Circuit NoLoad Group(column 1)

Description of load

(given list)

Current allowanceper unit(column 2)

Calculation

Demand (Amps)Demand (Amps)Demand (Amps)

Circuit NoLoad Group(column 1)

Description of load

(given list)

Current allowanceper unit(column 2)

Calculation

L1 L2 L3

1 A (i) 13 Lighting points3 A (1st 20)2 A (next 20) na 3.0

2 A (i) 14 Lighting points3 A (1st 20) na 3.0

3 A (i) 15 Lighting points3 A (1st 20) na 3.0

4 B (i)8 single +

4 double outlets10 A (1st 20)

8 + (4 x 2) = 16 socket points +1 (pool filterpump) = 17

10.0

5 B (i)7 single +

5 double outlets10 A (1st 20) 7 + (5 x 2) =

17 socket points 10.0

6 B (ii)

One 15 A single phase outlet

10 A(See note on group in Table C1, B (ii))

na 10.0

7 C Cook top 50% (or x 0.5) 4200/240 x 0.5 8.8

8 C Oven rating 50% (or x 0.5) 5200/240 x 0.5 10.8

9 B (i) Pool filter pump

Pump rating = 4.3 A so socket outlet to be used for pump supply.Socket will be part of circuit L1 so Included with circuit 4 calculations

Pump rating = 4.3 A so socket outlet to be used for pump supply.Socket will be part of circuit L1 so Included with circuit 4 calculations

na

10 D Air conditioner(23.6 A)

75% (or x 0.75) 23.6 x 0.75 17.7 17.7 17.7

11a F OPHWS bottom element Full load current 3600/240 15.0

11b F OPHWS top element Full load current Included

above 0.0

Total demand current per phaseTotal demand current per phaseTotal demand current per phaseTotal demand current per phaseTotal demand current per phase 40.7 39.5 46.5

Page 9: 4.1.3 Example Solution Three

Circuit NoLoad Group(column 1)

Description of load

(given list)

Current allowanceper unit(column 2)

Calculation

Demand (Amps)Demand (Amps)Demand (Amps)

Circuit NoLoad Group(column 1)

Description of load

(given list)

Current allowanceper unit(column 2)

Calculation

L1 L2 L3

1 A (i) 13 Lighting points3 A (1st 20)2 A (next 20) na 3.0

2 A (i) 14 Lighting points3 A (1st 20) na 3.0

3 A (i) 15 Lighting points3 A (1st 20) na 3.0

4 B (i)8 single +

4 double outlets10 A (1st 20)

8 + (4 x 2) = 16 socket points +1 (pool filterpump) = 17

10.0

5 B (i)7 single +

5 double outlets10 A (1st 20) 7 + (5 x 2) =

17 socket points 10.0

6 B (ii)

One 15 A single phase outlet

10 A(See note on group in Table C1, B (ii))

na 10.0

7 C Cook top 50% (or x 0.5) 4200/240 x 0.5 8.8

8 C Oven rating 50% (or x 0.5) 5200/240 x 0.5 10.8

9 B (i) Pool filter pump

Pump rating = 4.3 A so socket outlet to be used for pump supply.Socket will be part of circuit L1 so Included with circuit 4 calculations

Pump rating = 4.3 A so socket outlet to be used for pump supply.Socket will be part of circuit L1 so Included with circuit 4 calculations

na

10 D Air conditioner(23.6 A)

75% (or x 0.75) 23.6 x 0.75 17.7 17.7 17.7

11a F OPHWS bottom element Full load current 3600/240 15.0

11b F OPHWS top element Full load current Included

above 0.0

Total demand current per phaseTotal demand current per phaseTotal demand current per phaseTotal demand current per phaseTotal demand current per phase 40.7 39.5 46.5

Page 10: 4.1.3 Example Solution Three

Circuit NoLoad Group(column 1)

Description of load

(given list)

Current allowanceper unit(column 2)

Calculation

Demand (Amps)Demand (Amps)Demand (Amps)

Circuit NoLoad Group(column 1)

Description of load

(given list)

Current allowanceper unit(column 2)

Calculation

L1 L2 L3

1 A (i) 13 Lighting points3 A (1st 20)2 A (next 20) na 3.0

2 A (i) 14 Lighting points3 A (1st 20) na 3.0

3 A (i) 15 Lighting points3 A (1st 20) na 3.0

4 B (i)8 single +

4 double outlets10 A (1st 20)

8 + (4 x 2) = 16 socket points +1 (pool filterpump) = 17

10.0

5 B (i)7 single +

5 double outlets10 A (1st 20) 7 + (5 x 2) =

17 socket points 10.0

6 B (ii)

One 15 A single phase outlet

10 A(See note on group in Table C1, B (ii))

na 10.0

7 C Cook top 50% (or x 0.5) 4200/240 x 0.5 8.8

8 C Oven rating 50% (or x 0.5) 5200/240 x 0.5 10.8

9 B (i) Pool filter pump

Pump rating = 4.3 A so socket outlet to be used for pump supply.Socket will be part of circuit L1 so Included with circuit 4 calculations

Pump rating = 4.3 A so socket outlet to be used for pump supply.Socket will be part of circuit L1 so Included with circuit 4 calculations

na

10 D Air conditioner(23.6 A)

75% (or x 0.75) 23.6 x 0.75 17.7 17.7 17.7

11a F OPHWS bottom element Full load current 3600/240 15.0

11b F OPHWS top element Full load current Included

above 0.0

Total demand current per phaseTotal demand current per phaseTotal demand current per phaseTotal demand current per phaseTotal demand current per phase 40.7 39.5 46.5

Page 11: 4.1.3 Example Solution Three

Circuit NoLoad Group(column 1)

Description of load

(given list)

Current allowanceper unit(column 2)

Calculation

Demand (Amps)Demand (Amps)Demand (Amps)

Circuit NoLoad Group(column 1)

Description of load

(given list)

Current allowanceper unit(column 2)

Calculation

L1 L2 L3

1 A (i) 13 Lighting points3 A (1st 20)2 A (next 20) na 3.0

2 A (i) 14 Lighting points3 A (1st 20) na 3.0

3 A (i) 15 Lighting points3 A (1st 20) na 3.0

4 B (i)8 single +

4 double outlets10 A (1st 20)

8 + (4 x 2) = 16 socket points +1 (pool filterpump) = 17

10.0

5 B (i)7 single +

5 double outlets10 A (1st 20) 7 + (5 x 2) =

17 socket points 10.0

6 B (ii)

One 15 A single phase outlet

10 A(See note on group in Table C1, B (ii))

na 10.0

7 C Cook top 50% (or x 0.5) 4200/240 x 0.5 8.8

8 C Oven rating 50% (or x 0.5) 5200/240 x 0.5 10.8

9 B (i) Pool filter pump

Pump rating = 4.3 A so socket outlet to be used for pump supply.Socket will be part of circuit L1 so Included with circuit 4 calculations

Pump rating = 4.3 A so socket outlet to be used for pump supply.Socket will be part of circuit L1 so Included with circuit 4 calculations

na

10 D Air conditioner(23.6 A)

75% (or x 0.75) 23.6 x 0.75 17.7 17.7 17.7

11a F OPHWS bottom element Full load current 3600/240 15.0

11b F OPHWS top element Full load current Included

above 0.0

Total demand current per phaseTotal demand current per phaseTotal demand current per phaseTotal demand current per phaseTotal demand current per phase 40.7 39.5 46.5

Page 12: 4.1.3 Example Solution Three

Circuit NoLoad Group(column 1)

Description of load

(given list)

Current allowanceper unit(column 2)

Calculation

Demand (Amps)Demand (Amps)Demand (Amps)

Circuit NoLoad Group(column 1)

Description of load

(given list)

Current allowanceper unit(column 2)

Calculation

L1 L2 L3

1 A (i) 13 Lighting points3 A (1st 20)2 A (next 20) na 3.0

2 A (i) 14 Lighting points3 A (1st 20) na 3.0

3 A (i) 15 Lighting points3 A (1st 20) na 3.0

4 B (i)8 single +

4 double outlets10 A (1st 20)

8 + (4 x 2) = 16 socket points +1 (pool filterpump) = 17

10.0

5 B (i)7 single +

5 double outlets10 A (1st 20) 7 + (5 x 2) =

17 socket points 10.0

6 B (ii)

One 15 A single phase outlet

10 A(See note on group in Table C1, B (ii))

na 10.0

7 C Cook top 50% (or x 0.5) 4200/240 x 0.5 8.8

8 C Oven rating 50% (or x 0.5) 5200/240 x 0.5 10.8

9 B (i) Pool filter pump

Pump rating = 4.3 A so socket outlet to be used for pump supply.Socket will be part of circuit L1 so Included with circuit 4 calculations

Pump rating = 4.3 A so socket outlet to be used for pump supply.Socket will be part of circuit L1 so Included with circuit 4 calculations

na

10 D Air conditioner(23.6 A)

75% (or x 0.75) 23.6 x 0.75 17.7 17.7 17.7

11a F OPHWS bottom element Full load current 3600/240 15.0

11b F OPHWS top element Full load current Included

above 0.0

Total demand current per phaseTotal demand current per phaseTotal demand current per phaseTotal demand current per phaseTotal demand current per phase 40.7 39.5 46.5

Page 13: 4.1.3 Example Solution Three

Circuit NoLoad Group(column 1)

Description of load

(given list)

Current allowanceper unit(column 2)

Calculation

Demand (Amps)Demand (Amps)Demand (Amps)

Circuit NoLoad Group(column 1)

Description of load

(given list)

Current allowanceper unit(column 2)

Calculation

L1 L2 L3

1 A (i) 13 Lighting points3 A (1st 20)2 A (next 20) na 3.0

2 A (i) 14 Lighting points3 A (1st 20) na 3.0

3 A (i) 15 Lighting points3 A (1st 20) na 3.0

4 B (i)8 single +

4 double outlets10 A (1st 20)

8 + (4 x 2) = 16 socket points +1 (pool filterpump) = 17

10.0

5 B (i)7 single +

5 double outlets10 A (1st 20) 7 + (5 x 2) =

17 socket points 10.0

6 B (ii)

One 15 A single phase outlet

10 A(See note on group in Table C1, B (ii))

na 10.0

7 C Cook top 50% (or x 0.5) 4200/240 x 0.5 8.8

8 C Oven rating 50% (or x 0.5) 5200/240 x 0.5 10.8

9 B (i) Pool filter pump

Pump rating = 4.3 A so socket outlet to be used for pump supply.Socket will be part of circuit L1 so Included with circuit 4 calculations

Pump rating = 4.3 A so socket outlet to be used for pump supply.Socket will be part of circuit L1 so Included with circuit 4 calculations

na

10 D Air conditioner(23.6 A)

75% (or x 0.75) 23.6 x 0.75 17.7 17.7 17.7

11a F OPHWS bottom element Full load current 3600/240 15.0

11b F OPHWS top element Full load current Included

above 0.0

Total demand current per phaseTotal demand current per phaseTotal demand current per phaseTotal demand current per phaseTotal demand current per phase 40.7 39.5 46.5

Page 14: 4.1.3 Example Solution Three

Circuit NoLoad Group(column 1)

Description of load

(given list)

Current allowanceper unit(column 2)

Calculation

Demand (Amps)Demand (Amps)Demand (Amps)

Circuit NoLoad Group(column 1)

Description of load

(given list)

Current allowanceper unit(column 2)

Calculation

L1 L2 L3

1 A (i) 13 Lighting points3 A (1st 20)2 A (next 20) na 3.0

2 A (i) 14 Lighting points3 A (1st 20) na 3.0

3 A (i) 15 Lighting points3 A (1st 20) na 3.0

4 B (i)8 single +

4 double outlets10 A (1st 20)

8 + (4 x 2) = 16 socket points +1 (pool filterpump) = 17

10.0

5 B (i)7 single +

5 double outlets10 A (1st 20) 7 + (5 x 2) =

17 socket points 10.0

6 B (ii)

One 15 A single phase outlet

10 A(See note on group in Table C1, B (ii))

na 10.0

7 C Cook top 50% (or x 0.5) 4200/240 x 0.5 8.8

8 C Oven rating 50% (or x 0.5) 5200/240 x 0.5 10.8

9 B (i) Pool filter pump

Pump rating = 4.3 A so socket outlet to be used for pump supply.Socket will be part of circuit L1 so Included with circuit 4 calculations

Pump rating = 4.3 A so socket outlet to be used for pump supply.Socket will be part of circuit L1 so Included with circuit 4 calculations

na

10 D Air conditioner(23.6 A)

75% (or x 0.75) 23.6 x 0.75 17.7 17.7 17.7

11a F OPHWS bottom element Full load current 3600/240 15.0

11b F OPHWS top element Full load current Included

above 0.0

Total demand current per phaseTotal demand current per phaseTotal demand current per phaseTotal demand current per phaseTotal demand current per phase 40.7 39.5 46.5

Page 15: 4.1.3 Example Solution Three

Circuit NoLoad Group(column 1)

Description of load

(given list)

Current allowanceper unit(column 2)

Calculation

Demand (Amps)Demand (Amps)Demand (Amps)

Circuit NoLoad Group(column 1)

Description of load

(given list)

Current allowanceper unit(column 2)

Calculation

L1 L2 L3

1 A (i) 13 Lighting points3 A (1st 20)2 A (next 20) na 3.0

2 A (i) 14 Lighting points3 A (1st 20) na 3.0

3 A (i) 15 Lighting points3 A (1st 20) na 3.0

4 B (i)8 single +

4 double outlets10 A (1st 20)

8 + (4 x 2) = 16 socket points +1 (pool filterpump) = 17

10.0

5 B (i)7 single +

5 double outlets10 A (1st 20) 7 + (5 x 2) =

17 socket points 10.0

6 B (ii)

One 15 A single phase outlet

10 A(See note on group in Table C1, B (ii))

na 10.0

7 C Cook top 50% (or x 0.5) 4200/240 x 0.5 8.8

8 C Oven rating 50% (or x 0.5) 5200/240 x 0.5 10.8

9 B (i) Pool filter pump

Pump rating = 4.3 A so socket outlet to be used for pump supply.Socket will be part of circuit L1 so Included with circuit 4 calculations

Pump rating = 4.3 A so socket outlet to be used for pump supply.Socket will be part of circuit L1 so Included with circuit 4 calculations

na

10 D Air conditioner(23.6 A)

75% (or x 0.75) 23.6 x 0.75 17.7 17.7 17.7

11a F OPHWS bottom element Full load current 3600/240 15.0

11b F OPHWS top element Full load current Included

above 0.0

Total demand current per phaseTotal demand current per phaseTotal demand current per phaseTotal demand current per phaseTotal demand current per phase 40.7 39.5 46.5

Page 16: 4.1.3 Example Solution Three

Circuit NoLoad Group(column 1)

Description of load

(given list)

Current allowanceper unit(column 2)

Calculation

Demand (Amps)Demand (Amps)Demand (Amps)

Circuit NoLoad Group(column 1)

Description of load

(given list)

Current allowanceper unit(column 2)

Calculation

L1 L2 L3

1 A (i) 13 Lighting points3 A (1st 20)2 A (next 20) na 3.0

2 A (i) 14 Lighting points3 A (1st 20) na 3.0

3 A (i) 15 Lighting points3 A (1st 20) na 3.0

4 B (i)8 single +

4 double outlets10 A (1st 20)

8 + (4 x 2) = 16 socket points +1 (pool filterpump) = 17

10.0

5 B (i)7 single +

5 double outlets10 A (1st 20) 7 + (5 x 2) =

17 socket points 10.0

6 B (ii)

One 15 A single phase outlet

10 A(See note on group in Table C1, B (ii))

na 10.0

7 C Cook top 50% (or x 0.5) 4200/240 x 0.5 8.8

8 C Oven rating 50% (or x 0.5) 5200/240 x 0.5 10.8

9 B (i) Pool filter pump

Pump rating = 4.3 A so socket outlet to be used for pump supply.Socket will be part of circuit L1 so Included with circuit 4 calculations

Pump rating = 4.3 A so socket outlet to be used for pump supply.Socket will be part of circuit L1 so Included with circuit 4 calculations

na

10 D Air conditioner(23.6 A)

75% (or x 0.75) 23.6 x 0.75 17.7 17.7 17.7

11a F OPHWS bottom element Full load current 3600/240 15.0

11b F OPHWS top element Full load current Included

above 0.0

Total demand current per phaseTotal demand current per phaseTotal demand current per phaseTotal demand current per phaseTotal demand current per phase 40.7 39.5 46.5


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