+ All Categories
Home > Documents > 4/2003 Rev 2 I.3.4 – slide 1 of 24 Session I.3.4 Part I Review of Fundamentals Module 3Interaction...

4/2003 Rev 2 I.3.4 – slide 1 of 24 Session I.3.4 Part I Review of Fundamentals Module 3Interaction...

Date post: 30-Mar-2015
Category:
Upload: rita-solley
View: 214 times
Download: 2 times
Share this document with a friend
Popular Tags:
24
4/2003 Rev 2 I.3.4 – slide 1 of 24 Session I.3.4 Part I Review of Fundamentals Module 3 Interaction of Radiation with Matter Session 4 Photon Interactions IAEA Post Graduate Educational Course Radiation Protection and Safety of Radiation Sources
Transcript
Page 1: 4/2003 Rev 2 I.3.4 – slide 1 of 24 Session I.3.4 Part I Review of Fundamentals Module 3Interaction of Radiation with Matter Session 4Photon Interactions.

4/2003 Rev 2 I.3.4 – slide 1 of 24

Session I.3.4

Part I Review of Fundamentals

Module 3 Interaction of Radiation with Matter

Session 4 Photon Interactions

IAEA Post Graduate Educational CourseRadiation Protection and Safety of Radiation Sources

Page 2: 4/2003 Rev 2 I.3.4 – slide 1 of 24 Session I.3.4 Part I Review of Fundamentals Module 3Interaction of Radiation with Matter Session 4Photon Interactions.

4/2003 Rev 2 I.3.4 – slide 2 of 24

In this session we will discuss photon interactions including:

Photoelectric effect Compton scattering Pair production

Overview

Page 3: 4/2003 Rev 2 I.3.4 – slide 1 of 24 Session I.3.4 Part I Review of Fundamentals Module 3Interaction of Radiation with Matter Session 4Photon Interactions.

4/2003 Rev 2 I.3.4 – slide 3 of 24

Photoelectric Effect

Page 4: 4/2003 Rev 2 I.3.4 – slide 1 of 24 Session I.3.4 Part I Review of Fundamentals Module 3Interaction of Radiation with Matter Session 4Photon Interactions.

4/2003 Rev 2 I.3.4 – slide 4 of 24

Photoelectric Effect

-Example: Eincident photon = 80 keV

Ebinding energy = 20 keVEphotoelectron = 60 keV

Ephotoelectron = Eincident photon – Ebinding energy

Page 5: 4/2003 Rev 2 I.3.4 – slide 1 of 24 Session I.3.4 Part I Review of Fundamentals Module 3Interaction of Radiation with Matter Session 4Photon Interactions.

4/2003 Rev 2 I.3.4 – slide 5 of 24

Photoelectric Effect

The photoelectric effect is predominant for:

Low energy photons High atomic number “Z” materials

Probability is proportional to: Z4

E3

Page 6: 4/2003 Rev 2 I.3.4 – slide 1 of 24 Session I.3.4 Part I Review of Fundamentals Module 3Interaction of Radiation with Matter Session 4Photon Interactions.

4/2003 Rev 2 I.3.4 – slide 6 of 24

Photoelectric Effect

Page 7: 4/2003 Rev 2 I.3.4 – slide 1 of 24 Session I.3.4 Part I Review of Fundamentals Module 3Interaction of Radiation with Matter Session 4Photon Interactions.

4/2003 Rev 2 I.3.4 – slide 7 of 24

Compton Scattering

incidentphoton (Eip)

scatteredphoton (Esp)

scatteredelectron (Ese)

loosely boundelectron (Eie)

Page 8: 4/2003 Rev 2 I.3.4 – slide 1 of 24 Session I.3.4 Part I Review of Fundamentals Module 3Interaction of Radiation with Matter Session 4Photon Interactions.

4/2003 Rev 2 I.3.4 – slide 8 of 24

Compton Scattering

Eie = moc2 Ese = mc2

Eip =hcip

E*sp =hcsp

Conservation of Energy: hcip

+ moc2 = hcsp

+ mc2

Page 9: 4/2003 Rev 2 I.3.4 – slide 1 of 24 Session I.3.4 Part I Review of Fundamentals Module 3Interaction of Radiation with Matter Session 4Photon Interactions.

4/2003 Rev 2 I.3.4 – slide 9 of 24

Compton Scattering

Pse = mv

Pip = hip

P*sp = hsp

Conservationof Momentum:

hip

= hsp

cos + mv cos

0 = hsp

sin + mv sin

horizontal

vertical

Pie = 0

Page 10: 4/2003 Rev 2 I.3.4 – slide 1 of 24 Session I.3.4 Part I Review of Fundamentals Module 3Interaction of Radiation with Matter Session 4Photon Interactions.

4/2003 Rev 2 I.3.4 – slide 10 of 24

Compton Scattering

(1 - cos) = sp - ip =h

moc

Solving both the energy and momentum equations yields:

The energy transferred to the scattered electron is:

Ese = Eip – Esp = -hcip

hcsp

Page 11: 4/2003 Rev 2 I.3.4 – slide 1 of 24 Session I.3.4 Part I Review of Fundamentals Module 3Interaction of Radiation with Matter Session 4Photon Interactions.

4/2003 Rev 2 I.3.4 – slide 11 of 24

Compton Scattering

Substituting E =hc

into the momentum equations gives the energy of the scattered photon:

Esp =1 + (1 - cos)

Eip

moc2

Eip

moc2 = rest mass energy of the electron = 0.511 MeV

Page 12: 4/2003 Rev 2 I.3.4 – slide 1 of 24 Session I.3.4 Part I Review of Fundamentals Module 3Interaction of Radiation with Matter Session 4Photon Interactions.

4/2003 Rev 2 I.3.4 – slide 12 of 24

Compton Scattering

Esp =1 + (1 - cos)

Eip

moc2

Eip For simplicity let

Eip

moc2= f

Esp =1 + f (1 - cos)

Eip

Page 13: 4/2003 Rev 2 I.3.4 – slide 1 of 24 Session I.3.4 Part I Review of Fundamentals Module 3Interaction of Radiation with Matter Session 4Photon Interactions.

4/2003 Rev 2 I.3.4 – slide 13 of 24

Compton Scattering

When = 90º, Esp = the energy of the scattered photon is reduced

When = 180º, Esp = the energy of the scattered photon is minimum

When = 0º, Esp = Eip there is no interaction

Eip

(1+f)

Eip

(1+2f)

Page 14: 4/2003 Rev 2 I.3.4 – slide 1 of 24 Session I.3.4 Part I Review of Fundamentals Module 3Interaction of Radiation with Matter Session 4Photon Interactions.

4/2003 Rev 2 I.3.4 – slide 14 of 24

Compton Scattering

Example 1: A low energy photon (10 keV) scattered by 90º and 180º

f = 10 keV/511 keV = 0.02; cos 90º = 0; cos 180º = -1

Esp =1 + 0.02 (1 - 0)

10 keV= 10/1.02 = 9.8 keV

Esp =1 + 0.02 (1 - -1)

10 keV= 10/1.04 = 9.6 keV

the scattered electron

receives only 2-4% of the

incident energy

Page 15: 4/2003 Rev 2 I.3.4 – slide 1 of 24 Session I.3.4 Part I Review of Fundamentals Module 3Interaction of Radiation with Matter Session 4Photon Interactions.

4/2003 Rev 2 I.3.4 – slide 15 of 24

Compton Scattering

Example 2: A high energy photon (1000 keV) scattered by 90º and 180º

f = 1000 keV/511 keV = 1.96; cos 90º = 0; cos 180º = -1

Esp =1 + 1.96 (1 - 0)

1000 keV= 1000/2.96 = 340 keV

Esp =1 + 1.96 (1 - -1)

1000 keV= 1000/4.92 = 200 keV

the scattered electron receives

about 66-80% of the incident

energy

Page 16: 4/2003 Rev 2 I.3.4 – slide 1 of 24 Session I.3.4 Part I Review of Fundamentals Module 3Interaction of Radiation with Matter Session 4Photon Interactions.

4/2003 Rev 2 I.3.4 – slide 16 of 24

Compton Scattering

Example 3: What is the maximum energy of a photon scattered through 90º and 180º for a very high energy incident photon

If f = Eip/511 keV >> 1 then (1 + f) f

1 + f

Eip

f

EipEsp = = 511 keV= =

Eip

Eip

511

(90º)

(180º)1 + 2f

Eip

2f

EipEsp = = = = = 255 keV

511

2

Eip

2Eip

511

Page 17: 4/2003 Rev 2 I.3.4 – slide 1 of 24 Session I.3.4 Part I Review of Fundamentals Module 3Interaction of Radiation with Matter Session 4Photon Interactions.

4/2003 Rev 2 I.3.4 – slide 17 of 24

Compton Scattering

E =hc

h = 6.62 x 10-34 J-secc = 3 x 108 m/sec

E =(6.62 x 10-34 J-sec)(3 x 108 m/sec)

(1.6 x 10-19 J/eV)(103 eV/kev)

E = 1.24 x 10-9 keV-m (m)

The energy of a photon relative to its wavelength:

Page 18: 4/2003 Rev 2 I.3.4 – slide 1 of 24 Session I.3.4 Part I Review of Fundamentals Module 3Interaction of Radiation with Matter Session 4Photon Interactions.

4/2003 Rev 2 I.3.4 – slide 18 of 24

Pair Production

Photon converted into two particles

(energy into mass)

electron (-)positron (+)

Page 19: 4/2003 Rev 2 I.3.4 – slide 1 of 24 Session I.3.4 Part I Review of Fundamentals Module 3Interaction of Radiation with Matter Session 4Photon Interactions.

4/2003 Rev 2 I.3.4 – slide 19 of 24

Pair Production

The rest mass energy of a positive or negative electron is 0.511 MeV

To create these two particles requires a minimum energy of 2 x 0.511 MeV = 1.02 MeV

Page 20: 4/2003 Rev 2 I.3.4 – slide 1 of 24 Session I.3.4 Part I Review of Fundamentals Module 3Interaction of Radiation with Matter Session 4Photon Interactions.

4/2003 Rev 2 I.3.4 – slide 20 of 24

Pair Production

A positron cannot exist at rest. It combines with an electron. The two particles annihilate each other converting mass back into energy.

Since the rest mass energy of each particle is 0.511 MeV, the two photons created must each possess an energy of 0.511 MeV. Two photons must be created, traveling in opposite directions, to satisfy the Law of Conservation of Momentum.

Page 21: 4/2003 Rev 2 I.3.4 – slide 1 of 24 Session I.3.4 Part I Review of Fundamentals Module 3Interaction of Radiation with Matter Session 4Photon Interactions.

4/2003 Rev 2 I.3.4 – slide 21 of 24

Photon Energy (MeV)

PairProduction

Compton

Photoelectric

Combined

Pro

bab

ility

WATER

Photon Interactions

Page 22: 4/2003 Rev 2 I.3.4 – slide 1 of 24 Session I.3.4 Part I Review of Fundamentals Module 3Interaction of Radiation with Matter Session 4Photon Interactions.

4/2003 Rev 2 I.3.4 – slide 22 of 24

Photon Energy (MeV)Pair

Production

Compton

Photoelectric

Combined

Pro

bab

ility

LEAD

K shellBindingEnergy

Photon Interactions

Page 23: 4/2003 Rev 2 I.3.4 – slide 1 of 24 Session I.3.4 Part I Review of Fundamentals Module 3Interaction of Radiation with Matter Session 4Photon Interactions.

4/2003 Rev 2 I.3.4 – slide 23 of 24

Summary

We have discussed Photon Interactions including:

Photoelectric Effect low energy photons photon electron

Compton Scattering medium energy photons photon electron + new photon

Pair Production photon ( 1.02 MeV) photon e- + e+ 2 photons (0.511 MeV each)

Page 24: 4/2003 Rev 2 I.3.4 – slide 1 of 24 Session I.3.4 Part I Review of Fundamentals Module 3Interaction of Radiation with Matter Session 4Photon Interactions.

4/2003 Rev 2 I.3.4 – slide 24 of 24

Where to Get More Information

Cember, H., Johnson, T. E., Introduction to Health Physics, 4th Edition, McGraw-Hill, New York (2008)

Martin, A., Harbison, S. A., Beach, K., Cole, P., An Introduction to Radiation Protection, 6th Edition, Hodder Arnold, London (2012)

Jelley, N. A., Fundamentals of Nuclear Physics, Cambridge University Press, Cambridge (1990)

Firestone, R.B., Baglin, C.M., Frank-Chu, S.Y., Eds., Table of Isotopes (8th Edition, 1999 update), Wiley, New York (1999)


Recommended