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5 - 1CH110: Chapter 5
CH110 Chapter 5CH110 Chapter 5Chemical ReactionsChemical Reactions
Chemical ChangesChemical Changes
Chemical EquationsChemical Equations
Types of ReactionsTypes of Reactions
Oxidation-ReductionOxidation-Reduction
MolesMoles
Energy in Chemical ReactionsEnergy in Chemical Reactions
Reaction RatesReaction Rates
5 - 2CH110: Chapter 5
What is Chemistry?What is Chemistry?““The study of The study of MatterMatter and its and its ChangesChanges.”.”
Physical ChangesPhysical Changes =
Changes in a Physical PropertyPhysical Property
Chemical ChangesChemical Changes =
Changes in a Chemical PropertyChemical Property
Appearance: Appearance: •melting, freezing, evaporation…melting, freezing, evaporation…•stretching, molding, cutting…stretching, molding, cutting…
Chemical Composition: Chemical Composition:
5 - 3CH110: Chapter 5
Change in the Chemical CompositionChange in the Chemical Composition
Burning of Magnesium
Chemical ChangesChemical Changes
Rusting of Iron
Decomposing of wood
Souring of Milk
Examples:Examples:
5 - 4CH110: Chapter 5
Chemical ReactionsChemical Reactions
• Color Color changechange
• Gas formedGas formed
• Solid precipitate formedSolid precipitate formed
• Temperature ChangeTemperature Change
• Gives heat = exothermicGives heat = exothermic
• Gets cold = endothermicGets cold = endothermic
5 - 6CH110: Chapter 5
Mg + O2 MgO +
Energy
Chemical Reactions Chemical Reactions
Shows how the Chemical change occurs.Shows how the Chemical change occurs.Shows how the Chemical change occurs.Shows how the Chemical change occurs.
ReactantsReactants
C3H8 + O2 CO2 + H2O + Energy
Fe + O2 Fe2O3
ProductsProductsProductsProducts
5 - 7CH110: Chapter 5
Chemical equationsChemical equations
Chemist’s shorthand to describe a reaction.
•ReactantsReactants •ProductsProducts
•The state of all substancesThe state of all substances
HH2 2 + O+ O22 HH22O + EO + E(g)(g) (g)(g) (g)(g)
•Any conditions Any conditions usedused in the reaction in the reaction
heatheat
•Same # & type atoms on each sideSame # & type atoms on each side• Law of Conservation of MatterLaw of Conservation of Matter
22 22
(g) (l) (s) (aq)(g) (l) (s) (aq)(g) (l) (s) (aq)(g) (l) (s) (aq)
5 - 8CH110: Chapter 5
Balancing EquationsBalancing Equations
___W10 + ___B8 ___WBWB___W10 + ___B8 ___WBWB
•ReactantsReactants •ProductsProducts
Making Hot dogs:How many packages wieners & buns to buy so none is left over.
44 55 4040
5 - 12CH110: Chapter 5
NaPO
MgCl
Balancing EquationsBalancing Equations
Na3PO4 + MgCl2 MgMg33(PO(PO44))22 + NaCl + NaCl Na3PO4 + MgCl2 MgMg33(PO(PO44))22 + NaCl + NaCl
•ReactantsReactants •ProductsProducts
Step 1Step 1: Count atoms of each element on both sides of equation.
31412
1 2831
5 - 13CH110: Chapter 5
NaPO
MgCl
Balancing EquationsBalancing Equations
Na3PO4 + MgCl2 MgMg33(PO(PO44))22 + NaCl + NaCl Na3PO4 + MgCl2 MgMg33(PO(PO44))22 + NaCl + NaCl
•ReactantsReactants •ProductsProducts31412
1 2831
- - not balancednot balanced
- - not balancednot balanced
Step 2Step 2: Determine which atoms are not balanced.
- - not balancednot balanced
- - not balancednot balanced
- - not balancednot balanced
5 - 14CH110: Chapter 5
NaPO
MgCl
Balancing EquationsBalancing Equations
Na3PO4 + MgCl2 MgMg33(PO(PO44))22 + NaCl + NaCl Na3PO4 + MgCl2 MgMg33(PO(PO44))22 + NaCl + NaCl
•ReactantsReactants •ProductsProducts31412
1 2831
- - not balancednot balanced
- - not balancednot balanced
- - not balancednot balanced
- - not balancednot balanced
- - not balancednot balanced
Step 3: Step 3: Balance elements with #’s in front of formulas until all balanced.
(Never change the formulas!)(Never change the formulas!)
5 - 15CH110: Chapter 5
Hints:Hints:
•Start with a metal in a complex compound, or an element that only appears in one formula. (ie Mg here)
NaPO
MgCl
Balancing EquationsBalancing Equations
Na3PO4 + MgCl2 MgMg33(PO(PO44))22 + NaCl + NaCl Na3PO4 + MgCl2 MgMg33(PO(PO44))22 + NaCl + NaCl
•ReactantsReactants •ProductsProducts31412
1 2831
- - not balancednot balanced
- - not balancednot balanced
- - not balancednot balanced
- - not balancednot balanced
- - not balancednot balanced66
66
6633
33
22
66
11
88
22
66
5 - 16CH110: Chapter 5
Hints:Hints:
•Start with an element that only appears in one formula on both sides of the equation.
•Leave oxygen until last.
Balancing EquationsBalancing Equations
C2H6 + O2 COCO22 + H + H22OOC2H6 + O2 COCO22 + H + H22OO
•ReactantsReactants •ProductsProductsC
H
O
5 - 17CH110: Chapter 5
Balancing EquationsBalancing Equations
C2H6 + O2 COCO22 + H + H22OOC2H6 + O2 COCO22 + H + H22OO
C
H
O
C
H
O
•ReactantsReactants •ProductsProducts
Step 1Step 1: Count atoms of each element on both sides of equation.
2
6
2
2
6
2
1
2
3
1
2
3
5 - 18CH110: Chapter 5
C2H6 + O2 COCO22 + H + H22OOC2H6 + O2 COCO22 + H + H22OO
Balancing EquationsBalancing Equations
•ReactantsReactants •ProductsProducts
2
6
2
2
6
2
1
2
3
1
2
3
Step 2Step 2: Determine which atoms are not balanced.
- - not balancednot balanced
- - not balancednot balanced
- - not balancednot balancedC
H
O
C
H
O
5 - 19CH110: Chapter 5
2
6
2
2
6
2
- - not balancednot balanced
- - not balancednot balanced
C2H6 + O2 COCO22 + H + H22OOC2H6 + O2 COCO22 + H + H22OO
22
Balancing EquationsBalancing Equations
•ReactantsReactants •ProductsProducts
1
2
3
1
2
3
- - not balancednot balanced
Step 3: Step 3: Balance one element at a time with coefficients in front of formulas until all balanced.
(Never change the formula!)(Never change the formula!)
22
55
33
66
77
3.53.5
77
C
H
O
C
H
O
5 - 20CH110: Chapter 5
C
H
O
C
H
O
C2H6 + O2 COCO22 + H + H22OOC2H6 + O2 COCO22 + H + H22OO
22
Balancing EquationsBalancing Equations
•ReactantsReactants •ProductsProducts
2
6
2
2
6
2
1
2
3
1
2
3
22
55
33
66
77
3.53.5
77
Can’t have 3.5 O3.5 O22 , so multiply equation by 2!
5 - 21CH110: Chapter 5
3.53.5C2H6 + O2 COCO22 + H + H22OOC2H6 + O2 COCO22 + H + H22OO
22
Balancing EquationsBalancing Equations
C
H
O
C
H
O
•ReactantsReactants •ProductsProducts
2
6
2
2
6
2
1
2
3
1
2
3
44
55
66
66
77
77
77
Can’t have 3.5 O3.5 O22 , so multiply equation by 2!
22
44 44
1212 1212
1414 1414
5 - 22CH110: Chapter 5
Types of Chemical ReactionsTypes of Chemical Reactions
Complete:Complete:CC33HH8 8 + 5O+ 5O22 3CO 3CO22 + 4H + 4H22O O
CombustionCombustion
Incomplete:Incomplete:2C2C33HH8 8 + 7O+ 7O22 6CO + 8H 6CO + 8H22OO
CC33HH8 8 + 2O+ 2O22 3C + 4H 3C + 4H22O O
5 - 23CH110: Chapter 5
Types of Chemical ReactionsTypes of Chemical Reactions
CombinationCombination
DecompositionDecomposition
Single Replacement: Substitution Single Replacement: Substitution
Double Replacement: Metathesis Double Replacement: Metathesis
AA + + BBX X BB + + AAX X AA + + BBX X BB + + AAX X
A + B A + B C C A + B A + B C C
C C A + B A + B C C A + B A + B
AXAX + + BYBY BBXX + + AAYY AXAX + + BYBY BBXX + + AAYY
5 - 24CH110: Chapter 5
Combination ReactionsCombination Reactions
2H2H2 2 + O+ O22 2H 2H22O O
Formation of Acid RainFormation of Acid Rain
SO3 + H2O H2SO4SO3 + H2O H2SO4
Exposion of Hydrogen BalloonExposion of Hydrogen Balloon
Rusting of IronRusting of Iron
4 Fe + 3 O4 Fe + 3 O22 2 Fe 2 Fe22OO334 Fe + 3 O4 Fe + 3 O22 2 Fe 2 Fe22OO33
A + B A + B C C A + B A + B C C
5 - 25CH110: Chapter 5
Decomposition ReactionsDecomposition Reactions
Heating Egg ShellsHeating Egg Shells
CaCOCaCO3 3 CaO + CO CaO + CO22
2 H2 H22OO22 2 H 2 H22O + OO + O222 H2 H22OO22 2 H 2 H22O + OO + O22
Blood with Blood with peroxideperoxide
C C A + B A + B C C A + B A + B
5 - 26CH110: Chapter 5
Single Replacement Single Replacement ReactionsReactions
Iron Deposits on an Aluminum PanIron Deposits on an Aluminum Pan
Al + FeClAl + FeCl3 3 Fe + AlCl Fe + AlCl33 Al + FeClAl + FeCl3 3 Fe + AlCl Fe + AlCl33
AA + + BBX X BB + + AAX X AA + + BBX X BB + + AAX X
5 - 27CH110: Chapter 5
Activity series of metalsActivity series of metalspotassiumsodium
potassiumsodium
calciumcalcium
magnesiumaluminum
zincchromium
magnesiumaluminum
zincchromium
ironnickel
tinlead
ironnickel
tinlead
coppersilver
platinumgold
coppersilver
platinumgold
Hydrogen
Al + FeAl + Fe+3+3 Fe + Al Fe + Al+3+3Al + FeAl + Fe+3+3
Fe + Al Fe + Al+3+3
Fe + HFe + H++ Fe Fe+3+3 + H + H22 Fe + HFe + H++
Fe Fe+3+3 + H + H22
incr
easi
ng
rea
ctiv
ity
Element give e’s to ion
lower on list
Element give e’s to ion
lower on list
5 - 28CH110: Chapter 5
Double Replacement ReactionDouble Replacement Reaction
BaClBaCl22(aq)(aq) + + NaNa22SOSO44(aq) (aq) BaBaSOSO44(s)(s) + 2 + 2NaNaClCl(aq)(aq)
AXAX + BY + BY B BXX + + AAY Y AXAX + BY + BY B BXX + + AAY Y
BaBa+2+2 ClCl-1-1
NaNa+1 +1 SOSO44-2-2
Insoluble PrecipitateInsoluble PrecipitateFormed Formed
5 - 29CH110: Chapter 5
Predict the products:
AgNOAgNO33(aq)(aq) + MgClMgCl22(aq)(aq)
AgAg++ NONO33
--
MgMg+2 +2 ClCl--
AgAgClCl(s)(s)
Double Replacement ReactionDouble Replacement ReactionAXAX + + BYBY BBXX + + AAYY AXAX + + BYBY BBXX + + AAYY
Write correct formulas then balance as needed
22 22 + Mg(NO+ Mg(NO33))2(aq)2(aq)
5 - 30CH110: Chapter 5
Oxidation and reductionOxidation and reductionREDOXREDOX
Where reactants Where reactants exchange electronsexchange electrons - -
Examples:Examples:
•All types of All types of batteriesbatteries
alkaline, NiCad, car batteriesalkaline, NiCad, car batteries
•Rusting and corrosionRusting and corrosion
•MetabolismMetabolism
•Antioxidants (Vit C, E prevent oxidation)Antioxidants (Vit C, E prevent oxidation)
5 - 31CH110: Chapter 5
Oxidation and reductionOxidation and reductionREDOXREDOXWhere reactants Where reactants exchange electronsexchange electrons - -
LEOLEO the lion says GER GER LEOLEO the lion says GER GER
ReductionReduction = Gaining electrons
GER: GGain EElectrons RReduction
OxidationOxidation = Losing electronsLEO: LLose EElectrons
OOxidation
5 - 32CH110: Chapter 5
Oxidation and reductionOxidation and reduction
2 Na2 Na(s)(s) + ClCl2 (g2 (g) 2 Na2 NaClCl2 Na2 Na(s)(s) + ClCl2 (g2 (g) 2 Na2 NaClCl
1-1-1+1+
Assign Oxidation States:Assign Oxidation States:
00 00For simple ions,
Ox state = charge.charge.
For simple ions,
Ox state = charge.charge.
For element in natural form
Ox State = 00.
For element in natural form
Ox State = 00.
5 - 33CH110: Chapter 5
Oxidation and reductionOxidation and reduction
2 Na2 Na(s)(s) + ClCl2 (g2 (g) 2 Na2 NaClCl2 Na2 Na(s)(s) + ClCl2 (g2 (g) 2 Na2 NaClCl
1-1-1+1+
Who’s loosing or gaining electrons?Who’s loosing or gaining electrons?
00 00
Loses Loses 1 e1 e- - = LEO= LEO
GainsGains 1 e1 e--=GER=GER
Na loses e- (LEO) Na gets oxidizedoxidizedNa loses e- (LEO) Na gets oxidizedoxidized
Cl gains e- (GER) Cl gets reducedreduced Cl gains e- (GER) Cl gets reducedreduced
5 - 35CH110: Chapter 5
Oxidation and reductionOxidation and reduction
2 Na2 Na(s)(s) + ClCl2 (g2 (g) 2 Na2 NaClCl2 Na2 Na(s)(s) + ClCl2 (g2 (g) 2 Na2 NaClCl
1-1-1+1+
Who’s loosing or gaining electrons?Who’s loosing or gaining electrons?
00 00
• NaNa loses e- (LEO) so NaNa gets oxidizedoxidized• Na Na causedcaused ClCl to get reducedto get reduced• NaNa is the is the Reducing agentReducing agent
• NaNa loses e- (LEO) so NaNa gets oxidizedoxidized• Na Na causedcaused ClCl to get reducedto get reduced• NaNa is the is the Reducing agentReducing agent
Loses Loses 1 e1 e- - =LEO=LEO
GainsGains 1 e1 e- - =GER=GER
5 - 36CH110: Chapter 5
Oxidation and reductionOxidation and reduction
2 Na2 Na(s)(s) + ClCl2 (g2 (g) 2 Na2 NaClCl2 Na2 Na(s)(s) + ClCl2 (g2 (g) 2 Na2 NaClCl
1-1-1+1+
Who’s loosing or gaining electrons?Who’s loosing or gaining electrons?
00 00
Loses Loses 1 e1 e- - =LEO=LEO
GainsGains 1 e1 e- - =GER=GER
• ClCl gains e- (GER) so ClCl gets reducedreduced • Cl Cl causedcaused NaNa to get oxidizedto get oxidized
• ClCl is the is the Oxidizing agentOxidizing agent
• ClCl gains e- (GER) so ClCl gets reducedreduced • Cl Cl causedcaused NaNa to get oxidizedto get oxidized
• ClCl is the is the Oxidizing agentOxidizing agent
5 - 39CH110: Chapter 5
1 pair =1 pair =
1 dozen =1 dozen =
1 mole =1 mole =
1 pair =1 pair =
1 dozen =1 dozen =
1 mole =1 mole =
The MoleThe Mole
1 mol eggs___
6.02 x 106.02 x 102323eggseggs
1 mol eggs___
6.02 x 106.02 x 102323eggseggs
1 mol Au_______
6.02 x 106.02 x 102323 Au atoms Au atoms
1 mol Au_______
6.02 x 106.02 x 102323 Au atoms Au atoms
_____1 mole H_____1 mole H22O_____ O_____
6.02 x 106.02 x 102323 H H22O moleculesO molecules
_____1 mole H_____1 mole H22O_____ O_____
6.02 x 106.02 x 102323 H H22O moleculesO molecules
22
1212
6.02 x 106.02 x 102323
602,000,000,000,000,000,000,000.602,000,000,000,000,000,000,000.
5 - 40CH110: Chapter 5
1 car ___1 car ___
4 wheels4 wheels
The Mole & FormulasThe Mole & Formulas
1 mol cars_
4 mol wheels4 mol wheels1 doz cars1 doz cars
4 doz wheels4 doz wheels
1 mole H1 mole H22O O
2 mol H2 mol H
1 mole H1 mole H22O O
1 mol O1 mol O
5 - 41CH110: Chapter 5
= wheels= wheels= wheels= wheels
1 car ___1 car ___
4 wheels4 wheels
The Mole & FormulasThe Mole & Formulas
1 mol cars_
4 mol wheels4 mol wheels1 doz cars1 doz cars
4 doz wheels4 doz wheels
4 doz wheels
1doz cars
5 doz cars5 doz cars
120 doz20 doz20 doz20 doz
2 mol H
1 mol H2O
5 mol H5 mol H22OO
1
10 10 10 10 = mol H= mol H= mol H= mol H
5 - 42CH110: Chapter 5
1 mole = MW in g’s 1 mole = MW in g’s The Mole & Molecular MassThe Mole & Molecular Mass
1 mol S_
32 g S32 g S
1 mol S_
32 g S32 g S
1 mole S = 32 g S1 mole S = 32 g S1 mole S = 32 g S1 mole S = 32 g S
32 g S32 g S
1 mol S
32 g S32 g S
1 mol S
1 mol C
12 g C12 g C
1 mol C
12 g C12 g C
1 mole C = 12 g C1 mole C = 12 g C1 mole C = 12 g C1 mole C = 12 g C
12 g C12 g C
1 mol C
12 g C12 g C
1 mol C
5 - 43CH110: Chapter 5
The Mole & Molecular MassThe Mole & Molecular Mass 1 mol H2O_
18.0 g H18.0 g H22OO
1 mol H2O_
18.0 g H18.0 g H22OO 1 mole H1 mole H22O has:O has:1 mole H1 mole H22O has:O has:
1.0 g H =
1 mol H
2 mol H 2 mol H
1
2.0 g H2.0 g H2.0 g H2.0 g H
16.0 g O =
1 mol O
1 mol O 1 mol O
1
16.0 g O16.0 g O16.0 g O16.0 g O
18.0 g H18.0 g H22OO
1 mol H2O
18.0 g H18.0 g H22OO
1 mol H2O
18.0 g18.0 g18.0 g18.0 g
5 - 44CH110: Chapter 5
Molecular MassMolecular MassFind the MW of Glucose; CFind the MW of Glucose; C66HH1212OO66Find the MW of Glucose; CFind the MW of Glucose; C66HH1212OO66
1.0 g H =
1 mol H
12 mol H 12 mol H
1
12.0 g H12.0 g H12.0 g H12.0 g H
16.0 g O =
1 mol O
6 mol O 6 mol O
1
96.0 g O96.0 g O96.0 g O96.0 g O
180.0 g C180.0 g C66HH1212OO66
1 mol CC66HH1212OO66
180.0 g C180.0 g C66HH1212OO66
1 mol CC66HH1212OO66
12.0 g C =
1 mol C
6 mol C 6 mol C
172.0 g C72.0 g C72.0 g C72.0 g C
5 - 45CH110: Chapter 5
1 mol H2O =
18 g H2O
Mass to Mole ConversionsMass to Mole Conversions
How many moles of water are in How many moles of water are in 36 g H36 g H22O?O?
How many moles of water are in How many moles of water are in 36 g H36 g H22O?O?
What should the What should the answeranswer look like? look like?
What is What is UniqueUnique to the problem? to the problem?
36 g H36 g H22O O
1
mol Hmol H22OO2.02.02.02.0
5 - 46CH110: Chapter 5
1 mol H2O
18 g H2O
Mass to Mole ConversionsMass to Mole Conversions
How many moles of H are in How many moles of H are in 36 g H36 g H22O?O?
How many moles of H are in How many moles of H are in 36 g H36 g H22O?O?
What should the What should the answeranswer look like? look like?
What is What is UniqueUnique to the problem? to the problem?
36 g H36 g H22O O
1
molmol H H4.04.04.04.0 2 mol H =
1 mol H2O
5 - 47CH110: Chapter 5
180 g Gluc =
1 mol Gluc
Mole to Mass ConversionsMole to Mass Conversions
How many g’s of Glucose (CHow many g’s of Glucose (C66HH1212OO66) )
are in 5 mol Glucose?are in 5 mol Glucose?What should the What should the answeranswer look like? look like?
What is What is UniqueUnique to the problem? to the problem?
5 mol Gluc5 mol Gluc
1
g Glucoseg Glucose900900900900
5 - 48CH110: Chapter 5
Moles in Chemical EquationsMoles in Chemical Equations
2 Na2 Na(s)(s) + ClCl2 (g2 (g) 2 Na2 NaClCl
2 mol Na
1 mol Cl1 mol Cl22
2 mol Na
1 mol Cl1 mol Cl22
2 mol Na
2 mol NaCl
2 mol Na
2 mol NaCl
1 mol ClCl22
2 mol NaCl2 mol NaCl
1 mol ClCl22
2 mol NaCl2 mol NaCl
How many gs of ClCl2 2 are needed to are needed to
produce 2.5 mol NaCl?produce 2.5 mol NaCl?
How many gs of ClCl2 2 are needed to are needed to
produce 2.5 mol NaCl?produce 2.5 mol NaCl?
5 - 49CH110: Chapter 5
Moles in Chemical EquationsMoles in Chemical Equations2 Na2 Na(s)(s) + ClCl2 (g2 (g) 2 Na2 NaClCl
1 mol Cl2
70.9 g Cl2
1 mol Cl2
70.9 g Cl2
1 mol ClCl22
2 mol NaCl2 mol NaCl
1 mol ClCl22
2 mol NaCl2 mol NaCl
How many gs of ClCl2 2 are needed to are needed to
produce 2.5 mol NaCl?produce 2.5 mol NaCl?
How many gs of ClCl2 2 are needed to are needed to
produce 2.5 mol NaCl?produce 2.5 mol NaCl?• Identify any conversion factors.
•How should the answer look?
2.5 mol NaCl2.5 mol NaCl = g= g
• What is unique to the problem?
88.62588.625
= = 8989 g g
1 mol ClCl22
2 mol NaCl2 mol NaCl
1 mol ClCl22
2 mol NaCl2 mol NaCl
70.9 g Cl2
1 mol Cl2
70.9 g Cl2
1 mol Cl2
5 - 50CH110: Chapter 5
HH22OOHH22OO
more stablemore stablemore stablemore stable
Energy in Chemical ReactionsEnergy in Chemical Reactions
Exothermic reactionExothermic reactionExothermic reactionExothermic reaction
--H= heat of reactionH= heat of reaction
En
erg
y
Rxn Progress
Reactants
Products
EEactact= Activation Energy= Activation Energy
(Gets hot)(Gets hot)
HH22 + O + O22HH22 + O + O22
2H2H22 + O + O222H2H22 + O + O22 2H2H22O + EnergyO + Energy2H2H22O + EnergyO + Energy
5 - 51CH110: Chapter 5
Exothermic ReactionsExothermic ReactionsE
ner
gy
Rxn Progress
2Mg + O2 2MgO + Energy
2H2 + O2 2H2O + Energy
CHCH44 + 2O + 2O22 COCO22 + 2H + 2H22O +O + 213 kcal213 kcal
5 - 53CH110: Chapter 5
more stablemore stablemore stablemore stable
Energy in Chemical ReactionsEnergy in Chemical Reactions
Endothermic reactionEndothermic reactionEndothermic reactionEndothermic reaction
H= heat of reactionH= heat of reactionEn
erg
y
Rxn Progress
Reactants
Products
EEactact== Activation Energy Activation Energy
(Gets cold)(Gets cold)
5 - 55CH110: Chapter 5
En
erg
y
Rxn Progress
2H2(g) + O2(g) 2H2O + Energy2H2(g) + O2(g) 2H2O + Energy
Just because something has the potential to reactJust because something has the potential to react doesn’t mean it will do so immediately.doesn’t mean it will do so immediately.Just because something has the potential to reactJust because something has the potential to react doesn’t mean it will do so immediately.doesn’t mean it will do so immediately.
HH2(g)2(g) + OO2(g)2(g) may may
stay together for stay together for
lifetime without lifetime without
reacting to form reacting to form
water.water.
HH2(g)2(g) + OO2(g)2(g) may may
stay together for stay together for
lifetime without lifetime without
reacting to form reacting to form
water.water.
Reaction RatesReaction Rates
5 - 56CH110: Chapter 5
Oxidation: Paper burningburning Oxidation: Paper burningburning
Paper turning Paper turning yellowyellowPaper turning Paper turning yellowyellow
Oxidation: Nails rustingrustingOxidation: Nails rustingrusting
Reaction RatesReaction Rates
Fast:Fast:
Slow:Slow:
5 - 57CH110: Chapter 5
They have to have enough E.
Reaction RatesReaction Rates
For reactants to make products:For reactants to make products:
•Molecules must collidecollide
(solvents really help)(solvents really help)
•They have to be alignedaligned correctly.
(Parked cars don’t collide)(Parked cars don’t collide)
5 - 59CH110: Chapter 5
Reaction RatesReaction Rates
Factors that increase reaction rate:Factors that increase reaction rate:1.1. More Reactants:More Reactants:
More cars More cars More collisions More collisions
8 blocks:8 blocks:34 surfaces34 surfaces
8 blocks:8 blocks:24 surfaces24 surfaces
More surface area More surface area More collisions More collisions
5 - 60CH110: Chapter 5
Reaction RatesReaction Rates
Factors that increase reaction rate:Factors that increase reaction rate:2.2. Higher Temperature:Higher Temperature:
Faster cars Faster cars More collisions More collisions
More Energy More Energy More collisions More collisions
5 - 61CH110: Chapter 5
Reaction RatesReaction Rates
Factors that increase reaction rate:Factors that increase reaction rate:3.3. Adding a Catalyst:Adding a Catalyst:
Lower ELower Eactact More collisions More collisions
Uncatalysed reactionUncatalysed reaction
5 - 62CH110: Chapter 5
Alter the reaction mechanism Alter the reaction mechanism but not change the productsbut not change the products
Uncatalysed reactionUncatalysed reaction
Catalysed reactionCatalysed reaction
Lower activation energy
A catalyst will:A catalyst will:
EnzymesEnzymes are biological catalysts.EnzymesEnzymes are biological catalysts.
CatalystsCatalysts