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5-minute check 50.26 in. 12.3 SURFACE AREA OF PYRAMIDS AND CONES May 3, 2013.

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Page 1: 5-minute check 50.26 in. 12.3 SURFACE AREA OF PYRAMIDS AND CONES May 3, 2013.

5-minute check

50.26 in

Page 2: 5-minute check 50.26 in. 12.3 SURFACE AREA OF PYRAMIDS AND CONES May 3, 2013.

12.3 SURFACE AREA OF PYRAMIDS AND CONES

May 3, 2013

Page 3: 5-minute check 50.26 in. 12.3 SURFACE AREA OF PYRAMIDS AND CONES May 3, 2013.

12.3 Objective(s)

• Students will find surface areas of pyramids and cones.

• Why? So you can find the surface area of a volcano, as seen in Ex 33.

• Mastery is 80% or better on 5-minute checks and practice problems.

Page 4: 5-minute check 50.26 in. 12.3 SURFACE AREA OF PYRAMIDS AND CONES May 3, 2013.

Concept Dev-Finding the surface area of a pyramid

• A pyramid is a polyhedron in which the base is a polygon and the lateral faces are triangles with a common vertex. The intersection of two lateral faces is a lateral edge. The intersection of the base and a lateral face is a base edge. The altitude or height of a pyramid is the perpendicular distance between the base and the vertex.

Page 5: 5-minute check 50.26 in. 12.3 SURFACE AREA OF PYRAMIDS AND CONES May 3, 2013.

More on pyramids

• A regular pyramid has a regular polygon for a base and its height meets the base at its center. The slant height of a regular pyramid is the altitude of any lateral face. A nonregular pyramid does not have a slant height.

Page 6: 5-minute check 50.26 in. 12.3 SURFACE AREA OF PYRAMIDS AND CONES May 3, 2013.

Pyramid Arena

Page 7: 5-minute check 50.26 in. 12.3 SURFACE AREA OF PYRAMIDS AND CONES May 3, 2013.

Ex. 1: Finding the Area of a Lateral Face

• Architecture. The lateral faces of the Pyramid Arena in Memphis, Tennessee, are covered with steal panels. Use the diagram of the arena to find the area of each lateral face of this regular pyramid.

Page 8: 5-minute check 50.26 in. 12.3 SURFACE AREA OF PYRAMIDS AND CONES May 3, 2013.
Page 9: 5-minute check 50.26 in. 12.3 SURFACE AREA OF PYRAMIDS AND CONES May 3, 2013.

Hexagonal Pyramids

• A regular hexagonal pyramid and its net are shown at the right. Let b represent the length of a base edge, and let l represent the slant height of the pyramid. The area of each lateral face is 1/2bl and the perimeter of the base if P = 6b. So the surface area is as follows:

Page 10: 5-minute check 50.26 in. 12.3 SURFACE AREA OF PYRAMIDS AND CONES May 3, 2013.

Hexagonal Pyramid

S = (Area of base) + 6(Area of lateral face)

S = B + 6( ½ bl)

S = B + (6b)l

S = B + Pl

Substitute

Rewrite 6( ½ bl) as ½ (6b)l.

Substitute P for 6b

Surface Area of a Regular Pyramid

The surface area S of a regular pyramid is:

S = B + ½ Pl, where B is the area of the base, P is the perimeter of the base, and l is the slant height.

Page 11: 5-minute check 50.26 in. 12.3 SURFACE AREA OF PYRAMIDS AND CONES May 3, 2013.

Ex. 2: Finding the surface area of a pyramid

• To find the surface area of the regular pyramid shown, start by finding the area of the base.

• Use the formula for the area of a regular polygon,

½ (apothem)(perimeter). A diagram of the base is shown to the right.

Page 12: 5-minute check 50.26 in. 12.3 SURFACE AREA OF PYRAMIDS AND CONES May 3, 2013.

Ex. 2: Finding the surface area of a pyramid

After substituting, the area of the base is ½ (3 )(6• 6), or

54 square meters.3

3

Page 13: 5-minute check 50.26 in. 12.3 SURFACE AREA OF PYRAMIDS AND CONES May 3, 2013.

Surface area• Now you can find the surface area by using

54 for the area of the base, B.

Page 14: 5-minute check 50.26 in. 12.3 SURFACE AREA OF PYRAMIDS AND CONES May 3, 2013.

Think….Ink….Share

• Find the surface area of pyramid with a base edge of 40ft and a height of 21ft.

• Remember the formula S= B + 1/2Pl• Answer 580 square feet per Lateral Face• 1600 + 580*4 = 3920 sq ft

Page 15: 5-minute check 50.26 in. 12.3 SURFACE AREA OF PYRAMIDS AND CONES May 3, 2013.

Part 1

• HW Page 814• #1-9 all

Page 16: 5-minute check 50.26 in. 12.3 SURFACE AREA OF PYRAMIDS AND CONES May 3, 2013.

Finding the Surface Area of a Cone• A circular cone, or cone, has a circular base

and a vertex that is NOT in the same plane as the base. The altitude, or height, is the perpendicular distance between the vertex and the base. In a right cone, the height meets the base at its center and the slant height is the distance between the vertex and a point on the base edge.

Page 17: 5-minute check 50.26 in. 12.3 SURFACE AREA OF PYRAMIDS AND CONES May 3, 2013.

Finding the Surface Area of a Cone• The lateral surface of a cone consists of all

segments that connect the vertex with points on the base edge. When you cut along the slant height and like the cone flat, you get the net shown at the right. In the net, the circular base has an area of r2 and the lateral surface area is the sector of a circle.

Page 18: 5-minute check 50.26 in. 12.3 SURFACE AREA OF PYRAMIDS AND CONES May 3, 2013.

More on cones . . .

• You can find the area of this sector by using a proportion, as shown below.

Area of sectorArea of circle =

Arc lengthCircumference Set up proportion

Area of sectorl2 =

2r

2lSubstitute

Area of sector = l2 •2r

2lMultiply each side by l2

Area of sector = rl Simplify

The surface area of a cone is the sum of the base area and the lateral area, rl.

Page 19: 5-minute check 50.26 in. 12.3 SURFACE AREA OF PYRAMIDS AND CONES May 3, 2013.

Theorem

• Surface Area of a Right Cone• The surface area of a right cone is • S = r2 + rl, where r is the radius of the base

and l is the slant height

Page 20: 5-minute check 50.26 in. 12.3 SURFACE AREA OF PYRAMIDS AND CONES May 3, 2013.

Ex. 3: Finding the surface area of a cone

• To find the surface area of the right cone shown, use the formula for the surface area.

S = r2 + rl Write formula

S = 42 + (4)(6) Substitute

S = 16 + 24 Simplify

S = 40 Simplify

The surface area is 40 square inches or about 125.7 square inches.

Page 21: 5-minute check 50.26 in. 12.3 SURFACE AREA OF PYRAMIDS AND CONES May 3, 2013.

Think….Ink….Share

• Find the surface area of a cone with a radius of 6m and a height of 8m.

• Answer 96 m2

Page 22: 5-minute check 50.26 in. 12.3 SURFACE AREA OF PYRAMIDS AND CONES May 3, 2013.

ExIt slips

• What was the objective for today?

Students will find surface areas of pyramids and cones.

Why? So you can find the surface area of a volcano, as seen in Ex 33.

Mastery is 80% or better on 5-minute checks and practice problems.

Page 23: 5-minute check 50.26 in. 12.3 SURFACE AREA OF PYRAMIDS AND CONES May 3, 2013.

Home work

• Page 814-815• # 10-24 TODO….ALL


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