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5.2 Refraction

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    5.2UNDERSTANDING

    REFRACTION OF

    LIGHT

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    Learning outcome

    Explain refraction of light

    Define refractive index as

    determine the refraction index of a glassor perspex block

    State the refractive index , n, as

    describe phenomena due to refraction

    Solve problems involving the refraction of

    light

    !

    si

    si

    in

    r

    speed of light in vacuumspeed of light in a medium

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    REFRACTIONOF LIGHT

    Light can pass through transparent

    materials.

    If the two materials are of different

    optical densities, light will change

    direction at the boundary between

    them.

    This phenomenon is termed as the

    refraction of light.

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    IMPORTANTTERMINOLOGIES

    i

    r

    NormalIncident ray

    Ray in the

    first

    medium

    Line

    perpendicular tothe boundary

    Angle of

    incident

    Angle between

    incident ray and

    normal

    refracted rayRay in

    the

    second

    medium

    Angle of

    refractionAngle betweenrefracted ray and

    normal

    Medium 1

    Medium 2

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    BENDINGOFTHE LIGHT

    Normal

    Air

    Glass

    Normal

    Air

    Glass

    Light is not bent when it

    travels along the normal

    bent towards

    the normal

    bent away from

    the normal

    Enterdenser

    medium

    Enter less

    densemedium

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    REFRACTIVEINDEX

    speed of light in vacuum

    speed of light in a medium

    Normal

    Air

    Glass

    Light bends when travels

    between two mediums with

    different optical densities.

    This is due to the change inthe speed of light.

    Light travels faster in

    optically less dense medium

    and vice versa.

    The refractive index , n, of a

    medium is defined ass f li t i v c r ir

    s f li t i t i

    ( )sin

    sin ( )

    v ci

    r i

    !

    i

    r

    p

    q

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    THE LAWOFREFRACTION

    Normal

    Air

    Glass

    1.The incident ray, the

    refracted ray and the

    normal at the point of

    incidence all lie in thesame plane.

    2.The ratio of is a

    constant, where i is theangle of incidence and r

    is the angle of refraction.

    ( )s in

    sin ( )

    v a c u u mi

    n r m e d iu m!

    i

    r

    p

    q

    Snells Law

    s i n

    s i n

    pn

    q

    !

    sin

    sin

    i

    r

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    Worked Example pg 141

    (a) The speed of light in glass is 2.0 x 108 m s-1 and the

    speed of light in air is 3.0 x 108 m s-1. Calculate the

    refractive index of the glass

    (b) The refractive index of water is 1.3. What is the speed

    of light in water if its speed in air is 3.0 x 108

    m s-1

    .

    8

    8

    3.0 101.5

    2.0 10glass

    S peed of light in air xn

    S peed of light in glass x! ! !

    83.0 10

    1.3

    water

    S peed of light in airn

    S peed of light in water

    x

    v

    !

    !

    therefore v = 2.3 x 108

    m s-1

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    Worked Example pg 142

    (a)

    Air

    Clown

    glass

    Normal30o

    r

    Calculate the angle of

    refraction in crown glass.

    n=1.52

    (b)

    Air

    water

    Normal

    60o

    i

    Calculate the angle of

    incidence in water.

    n=1.33

    sinsin

    glassinr

    !

    sin301.52

    sin

    o

    r!

    r = 19.2o

    sin ( )sin

    waterr airn

    i!

    sin601.33

    sin

    o

    i!

    i = 40.6o

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    REAL DEPTHAND

    APPARENTDEPTH

    The legs appear to be shorter than

    their actual length.

    Why ?

    Refraction

    of light

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    RAYDIAGRAM

    Normal

    1. Draw the

    normal line

    2. Mark the

    position of

    image

    3. Two

    diverging

    lines from

    image

    4. Connect

    ray line

    from

    surface of

    water to

    object

    h

    H

    h = apparent depth , H = real depth

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    RELATIONSHIPBETWEEN

    REAL DEPTHAND

    APPARENTDEPTH

    Refractive index

    Re ,

    ,

    al depth Hn

    Apparent depth h!

    Apparent

    depth, h /cm

    Real depth, H /cm

    O

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    Worked Example pg 144

    (a) Due to the refraction of light

    (b)

    h 10 cm

    (c) Refractive index, n =H

    h10

    1.33h

    !

    h = 7.5 cm


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