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8/8/2019 5.2 Refraction
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5.2UNDERSTANDING
REFRACTION OF
LIGHT
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Learning outcome
Explain refraction of light
Define refractive index as
determine the refraction index of a glassor perspex block
State the refractive index , n, as
describe phenomena due to refraction
Solve problems involving the refraction of
light
!
si
si
in
r
speed of light in vacuumspeed of light in a medium
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REFRACTIONOF LIGHT
Light can pass through transparent
materials.
If the two materials are of different
optical densities, light will change
direction at the boundary between
them.
This phenomenon is termed as the
refraction of light.
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IMPORTANTTERMINOLOGIES
i
r
NormalIncident ray
Ray in the
first
medium
Line
perpendicular tothe boundary
Angle of
incident
Angle between
incident ray and
normal
refracted rayRay in
the
second
medium
Angle of
refractionAngle betweenrefracted ray and
normal
Medium 1
Medium 2
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BENDINGOFTHE LIGHT
Normal
Air
Glass
Normal
Air
Glass
Light is not bent when it
travels along the normal
bent towards
the normal
bent away from
the normal
Enterdenser
medium
Enter less
densemedium
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REFRACTIVEINDEX
speed of light in vacuum
speed of light in a medium
Normal
Air
Glass
Light bends when travels
between two mediums with
different optical densities.
This is due to the change inthe speed of light.
Light travels faster in
optically less dense medium
and vice versa.
The refractive index , n, of a
medium is defined ass f li t i v c r ir
s f li t i t i
( )sin
sin ( )
v ci
r i
!
i
r
p
q
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THE LAWOFREFRACTION
Normal
Air
Glass
1.The incident ray, the
refracted ray and the
normal at the point of
incidence all lie in thesame plane.
2.The ratio of is a
constant, where i is theangle of incidence and r
is the angle of refraction.
( )s in
sin ( )
v a c u u mi
n r m e d iu m!
i
r
p
q
Snells Law
s i n
s i n
pn
q
!
sin
sin
i
r
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Worked Example pg 141
(a) The speed of light in glass is 2.0 x 108 m s-1 and the
speed of light in air is 3.0 x 108 m s-1. Calculate the
refractive index of the glass
(b) The refractive index of water is 1.3. What is the speed
of light in water if its speed in air is 3.0 x 108
m s-1
.
8
8
3.0 101.5
2.0 10glass
S peed of light in air xn
S peed of light in glass x! ! !
83.0 10
1.3
water
S peed of light in airn
S peed of light in water
x
v
!
!
therefore v = 2.3 x 108
m s-1
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Worked Example pg 142
(a)
Air
Clown
glass
Normal30o
r
Calculate the angle of
refraction in crown glass.
n=1.52
(b)
Air
water
Normal
60o
i
Calculate the angle of
incidence in water.
n=1.33
sinsin
glassinr
!
sin301.52
sin
o
r!
r = 19.2o
sin ( )sin
waterr airn
i!
sin601.33
sin
o
i!
i = 40.6o
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REAL DEPTHAND
APPARENTDEPTH
The legs appear to be shorter than
their actual length.
Why ?
Refraction
of light
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RAYDIAGRAM
Normal
1. Draw the
normal line
2. Mark the
position of
image
3. Two
diverging
lines from
image
4. Connect
ray line
from
surface of
water to
object
h
H
h = apparent depth , H = real depth
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RELATIONSHIPBETWEEN
REAL DEPTHAND
APPARENTDEPTH
Refractive index
Re ,
,
al depth Hn
Apparent depth h!
Apparent
depth, h /cm
Real depth, H /cm
O
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Worked Example pg 144
(a) Due to the refraction of light
(b)
h 10 cm
(c) Refractive index, n =H
h10
1.33h
!
h = 7.5 cm