8-2 Integration by Parts(Day 2)
Objective: Find an antiderivative using integration by parts.
Miss BattagliaAP Calculus
If u and v are functions of x and have continuous derivatives, then
Integration by Parts
LogsInverse TrigAlgebraicTrigExponential
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Derived from…
Try letting dv be the most complicated portion of the integrand that fits a basic integration rule. Then u will be the remaining factor(s) of the integrand.
Try letting u be the portion of the integrand whose derivative is a function simpler than u. Then dbv will be the remaining factor(s) of the integrand.
Note that dv always includes the dx of the original integrand.
Guidelines for Integration by Parts
Find
Integration by Parts
Find
Integration by Parts
Find
An Integrand with a Single Term
Find
Integration by Parts
1. For integrals of the form
let u = xn and let dv = eaxdx, sin ax dx, or cos ax dx 2. For integrals of the form
let u = lnx, arcsin ax, or arctan ax and let dv = xnd
3. For the integrals of the form
let u = sin bx or cos bx and let dv = eaxdx
Summary of Common Integrals Using Integration by Parts
Page 533 #33, 35, 37, 42, 55, 61, 63, 67, 119
Classwork/ Homework