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A Basketball Player Throws Up a Ball 5

Date post: 05-Nov-2015
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A Basketball Player Throws Up a Ball 5
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A basketball player throws up a ball 5.00 m away from the basket 1.00 s left in the game. He releases the ball at a height of 3.2 the oor at an angle of 45 degrees. The basket is 3.00 m high. If is released with an initial velocity of 10.00 m/s, and the player shooter, will the ball beat the buzzer if it goes in? Givens: x (distance traveled)=5m y (distance traveled)=0.6m initial velocity=10m/s Cos (45)=(x rate)/(10m/s) Solve for the x rate. The x rate=10 cos (45)=7.1 m/s Now we have x rate and x distance. Plug into the distance=rate*ti formula: 5m= (7.1m/s)*(time) Solving for time, we get time=5/7.1=0.704s 3.0 5.0
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3.0 meters 5.0 meters A basketball player throws up a ball 5.00 m away from the basket with 1.00 s left in the game. He releases the ball at a height of 3.2 m above the floor at an angle of 45 degrees. The basket is 3.00 m high. If the ball is released with an initial velocity of 10.00 m/s, and the player is a good shooter, will the ball beat the buzzer if it goes in?

Givens:x (distance traveled)=5my (distance traveled)=0.6minitial velocity=10m/sCos (45)=(x rate)/(10m/s)Solve for the x rate. The x rate=10 cos (45)=7.1 m/sNow we have x rate and x distance. Plug into the distance=rate*time formula:5m= (7.1m/s)*(time)Solving for time, we get time=5/7.1=0.704sIt takes the ball only 0.704s to reach the basket so yes, the ball will beat the buzzer.


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